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Test: Basic Proportionality Theorem - Grade 10 MCQ


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5 Questions MCQ Test - Test: Basic Proportionality Theorem

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Test: Basic Proportionality Theorem - Question 1

In the given fig, P and Q are points on the sides AB and AC respectively of Δ ABC such that AP = 3.5 cm, PB = 7 cm, AQ = 3 cm and QC = 6 cm. If PQ = 4.5 cm, find BC.

Detailed Solution for Test: Basic Proportionality Theorem - Question 1


Therefore, by converse of Basic Proportionality Theorem, we have QP || CB
Hence, ∆AQP ~ ∆ACB [Using AA similar condition]

∴ 
⇒ 
⇒ 

Test: Basic Proportionality Theorem - Question 2

If a triangle and a parallelogram are on the same base and between same parallels, then what is the ratio of the area of the triangle to the area of parallelogram?

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Test: Basic Proportionality Theorem - Question 3

ΔABC ~ ΔPQR, ∠B = 50° and ∠C = 70° then ∠P is equal to​

Detailed Solution for Test: Basic Proportionality Theorem - Question 3

Similar triangles have corresponding angles equal. So Angle Q=Angle B = 50° and Angle R = Angle C = 70° . So by angle sum property, Angle P+Angle Q +Angle R = 180°
Angle P=180° - 50° - 70° = 60°

Test: Basic Proportionality Theorem - Question 4

Two congruent triangles are actually similar triangles with the ratio of corresponding sides as.​

Test: Basic Proportionality Theorem - Question 5

Which geometric figures are always similar?​

Detailed Solution for Test: Basic Proportionality Theorem - Question 5

It can be found that circles map one  onto another.So they are similar figures. A regular polygon is a polygon which has the same sides and equal measures of angles. So they are also similar.

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