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Test: Pulse Shaping and Intersymbol Interference - Electronics and Communication Engineering (ECE) MCQ


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8 Questions MCQ Test - Test: Pulse Shaping and Intersymbol Interference

Test: Pulse Shaping and Intersymbol Interference for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Test: Pulse Shaping and Intersymbol Interference questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The Test: Pulse Shaping and Intersymbol Interference MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Pulse Shaping and Intersymbol Interference below.
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Test: Pulse Shaping and Intersymbol Interference - Question 1

Pulse Shaping in line coding is used for

Detailed Solution for Test: Pulse Shaping and Intersymbol Interference - Question 1

Pulse shaping is the process of changing the waveform of transmitted pulses. Its purpose is to make the transmitted signal better suited to its purpose or the communication channel, typically by limiting the effective bandwidth of the transmission.

*Answer can only contain numeric values
Test: Pulse Shaping and Intersymbol Interference - Question 2

Data rate of 12 kbps is to be transmitted over a channel of bandwidth 8 kHz by using Nyquist criterion pulses. The value of the roll-off factor ‘ α’ that can be used is ______. (Correct up to 2 decimal places)


Detailed Solution for Test: Pulse Shaping and Intersymbol Interference - Question 2

The transmission bandwidth for Nyquist criteria (raised cosine pulse) with roll-off factor α is given by:

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Test: Pulse Shaping and Intersymbol Interference - Question 3

The phenomenon of overlapping of adjacent bits due to pulse spreading is:

Detailed Solution for Test: Pulse Shaping and Intersymbol Interference - Question 3

Inter-symbol Interference:

  • This is the effect of dispersion on optical fibre.
  • Intersymbol interference occurs when the pulse spreading caused by dispersion causes the output pulses of a system to overlap.


Scattering:

  • Scattering is the loss of signal caused by the diffusion of a light beam, where the diffusion itself is caused by microscopic variations in the transmission medium.
  • Scattering typically happens when a light signal hits an impurity in the fibre.

Dispersion:

  • Dispersion is defined as pulse spreading in an optical fibre
  • As a pulse of light propagates through a fibre, elements such as numerical aperture, core diameter, refractive index profile, wavelength, and laser linewidth cause the pulse to broaden

Attenuation:

  • The attenuation of an optical fibre measures the amount of light lost between input and output
  • Total attenuation is the sum of all losses
  • For a given fibre, these losses are wavelength-dependent
*Answer can only contain numeric values
Test: Pulse Shaping and Intersymbol Interference - Question 4

An ideal band-pass channel 500 Hz - 2000 Hz is deployed for communication. A modem is designed to transmit bits at the rate of 4800 bits/s using 16-QAM. The roll-off factor of a pulse with a raised cosine spectrum that utilizes the entire frequency band is ________


Detailed Solution for Test: Pulse Shaping and Intersymbol Interference - Question 4

Concept: By using raised cosine pulse bandwidth required for M-ary modulation is   where α is called roll-off factor.
Application: Bandwidth = 2000 - 500 = 1500 Hz 
Bandwidth required for 16 QAM

Rb(1+α ) = 1500 x 4 = 6000
(1+α) = 6000/4800
α = 0.25

*Answer can only contain numeric values
Test: Pulse Shaping and Intersymbol Interference - Question 5

A speech signal is sampled at 8 kHz and encoded into PCM format using 8 bits/sample. The PCM data is transmitted through a baseband channel via 4-level PAM. The minimum bandwidth (in kHz) required for transmission is ________


Detailed Solution for Test: Pulse Shaping and Intersymbol Interference - Question 5

Baseband communication is given.
Minimum Bandwidth will be required if transmission of data takes place using sinc pulses and the bandwidth is given by:

Where Rb = n  fs
n = number of bits used to represent samples
fs = sampling rate.
Calculation:
In the Question, it is asked about minimum Bandwidth. ∴ we will consider that the transmission of data is taking place through sinc pulses.
Given fs = 8 kHz
n = 8 bits/sample
M = 4
Rb = nfs

Test: Pulse Shaping and Intersymbol Interference - Question 6

The bit rate of a digital communication system is R Kbits/sec. The modulation used is 32-QAM. The minimum band width for intersymbol interference free transmission is –

Detailed Solution for Test: Pulse Shaping and Intersymbol Interference - Question 6

For ISI free transmission according to Nyquist criterion for Baseband signal is:

But for Bandpass signal, the amplitude spectrum get shifted to some high frequency and B.W ≥ Rb
For M-ary signaling B.W 
Calculation:
Bit Rate Rb = R k bits/sec
32-ary signaling is used:

*Answer can only contain numeric values
Test: Pulse Shaping and Intersymbol Interference - Question 7

Consider binary data transmission at a rate of 56 kbps using baseband binary pulse amplitude modulation (PAM) that is designed to have a raised-cosine spectrum. The transmission bandwidth (in kHz) required for a roll-off factor of 0.25 is ________∙


Detailed Solution for Test: Pulse Shaping and Intersymbol Interference - Question 7

The bit rate of base baseband binary pulse amplitude modulation (PAM) with a raised-cosine spectrum is given as:

Where,
BW = Transmission Bandwidth of PAM signal.
α = Roll-off factor. (α < 1)
Calculation: 
Given: Bit rate = 56 kbps, α =.25
we know that,

B.W. = 28 × 1.25
B.W. = 35 kHz

Test: Pulse Shaping and Intersymbol Interference - Question 8

Four messages are band limited to W, W, 2W & 3W are to be multiplexed using TDM. The minimum B.W required for transmission is

Detailed Solution for Test: Pulse Shaping and Intersymbol Interference - Question 8

During sampling:
We sample at 2W. With this rate signal of bandwidth, W gets sampled properly.
The signal of bandwidth 2W is sampled properly by being fed twice in the commutator switch.
And signal with bandwidth 3W is fed thrice into the commutator switch in order to get sampled at an effective rate of 6W. So, the total bit rate is Rb = 14W
Now, the minimum bandwidth required is: Rb/2 = 7W.

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