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Maths Mock Test- 4 - Class 9 MCQ


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30 Questions MCQ Test - Maths Mock Test- 4

Maths Mock Test- 4 for Class 9 2024 is part of Class 9 preparation. The Maths Mock Test- 4 questions and answers have been prepared according to the Class 9 exam syllabus.The Maths Mock Test- 4 MCQs are made for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Maths Mock Test- 4 below.
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Maths Mock Test- 4 - Question 1

Three Statements are given below:
(I) In a, Parallelogram the angle bisectors of 2 adjacent angles enclose a right angle.
(II) The angle bisector of a Parallelogram form a Rectangle.
(III) The Triangle formed by joining the mid-points of the sides of an isosceles triangle is not necessarily an isosceles triangle. Which is True?

Maths Mock Test- 4 - Question 2

 Find the coordinates of the point equidistant from the points A(1, 2), B (3, –4) and C(5, –6).       

Detailed Solution for Maths Mock Test- 4 - Question 2

Let the point be P(x,y)

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Maths Mock Test- 4 - Question 3

The point (7, 0) lies

Detailed Solution for Maths Mock Test- 4 - Question 3

The point (7,0) lies on the positive direction of the x-axis.

Explanation:

  • The x-coordinate of the point is 7, and the y-coordinate is 0.
  • When the y-coordinate is 0, the point lies on the x-axis.
  • Since the x-coordinate is positive, the point is on the positive direction of the x-axis.

So, the correct answer is:

4. on the positive direction of x-axis

Maths Mock Test- 4 - Question 4

The area of a triangle is 150 cm2 and its sides are in the ratio 3 : 4 : 5. What is its perimeter?

Detailed Solution for Maths Mock Test- 4 - Question 4

Let coefficient of ratios be X
a = 3x
b = 4x
c = 5x

Using Heron's Formula,
s = (3+4+5)x/2 = 12x/2 = 6x



Now,
a = 5*3 = 15 cm
b = 5*4 = 20 cm
c = 5*5 = 25 cm

Perimeter = 15+20+25 = 60 cm

Maths Mock Test- 4 - Question 5

(5+√8)+(3−√2)(√2−6) is

Detailed Solution for Maths Mock Test- 4 - Question 5


And we know that the value of 11√2 is greater than 15 so it's value will be positive, And also sum or differences of rational and irrational is irrational

Maths Mock Test- 4 - Question 6

√8+2√32−5√2 is equal to

Detailed Solution for Maths Mock Test- 4 - Question 6

Maths Mock Test- 4 - Question 7

Every rational number is

Detailed Solution for Maths Mock Test- 4 - Question 7

Every rational number is a real number. Real Number is a set of numbers formed by both Rational and Irrational numbers are combined.

Maths Mock Test- 4 - Question 8

The surface area of a cube of side 27 cm is :

Detailed Solution for Maths Mock Test- 4 - Question 8

The surface area of a cube of side 27 cm can be found using the formula:Surface area of a cube = 6a^2, where a is the length of the side of the cube.Given:
Length of side of the cube = 27 cmSubstituting the value into the formula:Surface area of the cube = 6 × 27^2
Surface area of the cube = 6 × 729
Surface area of the cube = 4374 cm^2Therefore, the surface area of the cube of side 27 cm is 4374 cm^2, which corresponds to option C

Maths Mock Test- 4 - Question 9

Axiom and postulates are

Detailed Solution for Maths Mock Test- 4 - Question 9
Axioms and postulates are assumption that are taken bu euclid to prove several theorems , axioms and postulates can not be proved as they are universal truth .
Maths Mock Test- 4 - Question 10

In the given figure, ∠BAC = 400, ∠ACB = 900 and ∠BED = 1000, Then ∠BDE = ?

Detailed Solution for Maths Mock Test- 4 - Question 10


Maths Mock Test- 4 - Question 11

The angle which is equal to 8 times its complement is :

Maths Mock Test- 4 - Question 12

The class mark of class interval 60 – 70 will be

Detailed Solution for Maths Mock Test- 4 - Question 12
class mark = [lower class interval + upper class interval]/2

= (60+70)/2

= 130/2

= 65 

(if the intervals are of uniform width)
Maths Mock Test- 4 - Question 13

‘Lines are parallel if they do not intersect’ – is stated in the form of:

Detailed Solution for Maths Mock Test- 4 - Question 13

 According to the definition of parallel lines “lines are parallel if they do not intersect”. They are not intersecting. Definition: a statement that gives the exact meaning of the given word. Hence, 'lines are parallel if they do not intersect' is stated in the form of definition.

Maths Mock Test- 4 - Question 14

In a right-angled triangle where angle A = 90° and AB = AC. What are the values of angle B?

Detailed Solution for Maths Mock Test- 4 - Question 14

∵ In ∆ABC,
AB = AC
∴ ∠B = ∠C    ...(1)
| Angles opposite to equal sides of a triangle are equal
In ∆ABC,
∠A + ∠B + ∠C = 180°
| Sum of all the angles of a triangle is 180°
⇒ 90° + ∠B + ∠C = 180°
| ∵ ∠A = 90° (given)
⇒    ∠B + ∠C = 90°    ...(2)
From (1) and (2), we get
∠B = ∠C = 45°.

Maths Mock Test- 4 - Question 15

In the given figure, BO and CO are the bisectors of ∠B and ∠C respectively. If ∠A = 500, then ∠BOC = ?

Detailed Solution for Maths Mock Test- 4 - Question 15

a+b+c = 180
50+b+c= 180
b+c = 130 ............(1)
divide equation (1) by 2 
1/2(b+c) = 65...........(2)
now in triangle obc
o+1/2(b+c) = 180
o+65= 180 ( from (2))
o= 180-65= 115 

Maths Mock Test- 4 - Question 16

An exterior angle of a triangle is 800 and the interior opposite angles are in the ratio 1 : 3. Measure of each inte4rior opposite angle is :

Detailed Solution for Maths Mock Test- 4 - Question 16

Let the interior angles be x and 3x 

We know that exterior angle of triangle is equal to sum of interior opposite angles.

⇒ x+3x=80

⇒ 4x=80

⇒ x=20

So the angles are 

x=20

3x=3×20

= 60∘

Maths Mock Test- 4 - Question 17

The perimeter of a rhombus is 146 cm. One of its diagonals is 55 cm. The length of the other diagonal and area of the rhombus are​

Detailed Solution for Maths Mock Test- 4 - Question 17

Maths Mock Test- 4 - Question 18

If P(x) = 10x−4x2−3, then the value of p(0)+p(1) is

Detailed Solution for Maths Mock Test- 4 - Question 18

 

Maths Mock Test- 4 - Question 19

The coefficient of x3 in 2x+x2−5x3+x4 is

Maths Mock Test- 4 - Question 20

If both x - 2 and are the factors of px2 + 5x + r, then

Detailed Solution for Maths Mock Test- 4 - Question 20

Let f(x) = px2 + 5 x + r
If (x - 2) is a factor of f (x), then by factor theorem
f(2) = 0 | x - 2 = 0 ⇒ x = 2
⇒ p(2)2 + 5(2) + r = 0
⇒ 4p + r + 10 = 0    ...(1)

If  is a factor of f (x), then by factor theorem,

Subtracting (2) from (1), we get
3p - 3r = 0
⇒    p = r

Maths Mock Test- 4 - Question 21

In a triangle P, Q and R are the mid-points of the sides BC, CA and AB res. If AC = 21cm, BC = 29cm and AB = 30cm, find the perimeter of the quadrilateral ARPQ?

Maths Mock Test- 4 - Question 22

The bisectors of the angles of a Parallelogram enclose a

Maths Mock Test- 4 - Question 23

The graph of the lines x + y = 7 and x – y = 3 meet at the point :

Detailed Solution for Maths Mock Test- 4 - Question 23

x + y = 7 
x – y = 3
adding this two equation
2x = 10
x = 5
so y  = 2 
(5,2)

Maths Mock Test- 4 - Question 24

The graph of the equation y = x2 is :

Detailed Solution for Maths Mock Test- 4 - Question 24

In the graph of y = x2, the point (0, 0) is called the vertex. The vertex is the minimum point in a parabola that opens upward. In a parabola that opens downward, the vertex is the maximum point. We can graph a parabola with a different vertex.

Maths Mock Test- 4 - Question 25

If AB = 12 cm, BC = 16 cm and AB ⊥ BC, then radius of the circle passing through A,B and C is

Detailed Solution for Maths Mock Test- 4 - Question 25

Maths Mock Test- 4 - Question 26

In the figure, ABC is an equilateral triangle. Measure of angle BEC is

Maths Mock Test- 4 - Question 27

In the adjoining figure, BC = AD, CA⊥AB and BD⊥AB. The rule by which △ABC ≅ △BAD is

Maths Mock Test- 4 - Question 28

In the given figure, ABC is an equilateral triangle. The value of x+y is 

Maths Mock Test- 4 - Question 29

A polynomial containing three nonzero terms is called a ________.

Maths Mock Test- 4 - Question 30

If x + 2 is a factor of x3 – 2ax2 + 16, then value of a is

Detailed Solution for Maths Mock Test- 4 - Question 30

use factor theorem as x+2 is factor of
x³-2ax²+16 so put x = -2 and equate the equation to 0
so putting x = -2
(-2)³-2a(-2)²+16 =0
-8-8a+16=0
-8a = -8
a = 8/8= 1
So,
a = 1

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