UGC NET Exam  >  UGC NET Tests  >  CSIR NET Physical Science Mock Test - 4 - UGC NET MCQ

CSIR NET Physical Science Mock Test - 4 - UGC NET MCQ


Test Description

30 Questions MCQ Test - CSIR NET Physical Science Mock Test - 4

CSIR NET Physical Science Mock Test - 4 for UGC NET 2024 is part of UGC NET preparation. The CSIR NET Physical Science Mock Test - 4 questions and answers have been prepared according to the UGC NET exam syllabus.The CSIR NET Physical Science Mock Test - 4 MCQs are made for UGC NET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for CSIR NET Physical Science Mock Test - 4 below.
Solutions of CSIR NET Physical Science Mock Test - 4 questions in English are available as part of our course for UGC NET & CSIR NET Physical Science Mock Test - 4 solutions in Hindi for UGC NET course. Download more important topics, notes, lectures and mock test series for UGC NET Exam by signing up for free. Attempt CSIR NET Physical Science Mock Test - 4 | 55 questions in 180 minutes | Mock test for UGC NET preparation | Free important questions MCQ to study for UGC NET Exam | Download free PDF with solutions
CSIR NET Physical Science Mock Test - 4 - Question 1

“Svedberg Unit” is a unit of _________.

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 1

Svedberg unit (S/ Sv) is a unit for sedimentation coefficients. It offers a measure of size of the particle based on sedimentation rate under acceleration. It calculates how fast the particle settles to the bottom of the solution. Svedberg unit is a measure of time (exactly 10−13 seconds).

CSIR NET Physical Science Mock Test - 4 - Question 2

Tooth enamel is the hardest substance found in the human body. What is it made up of?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 2

The protective layer around your teeth, called enamel, is the strongest substance that our body produces. In fact, tooth enamel is stronger than any other substance on earth except for diamonds. It is comprised largely of calcium and phosphate mineral crystals, similar to the composition of our bones.

1 Crore+ students have signed up on EduRev. Have you? Download the App
CSIR NET Physical Science Mock Test - 4 - Question 3

Brass gets discoloured in air because of the presence of which of the following gases in air?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 3

It gets discolored in air because of presence of Hydrogen sulphide in the air Brass constitute zinc and copper and these two elements are Hydro sulphide is a colourless gas and if mixed with others, will get colourless. Because brass is metal it get react with sulphide.

CSIR NET Physical Science Mock Test - 4 - Question 4

Fresh fruit contains 68% water and dry fruit contains 20% water. How much dry fruit can be obtained from 100 kg of fresh fruits ?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 4

The fruit content in both the fresh fruit and dry fruit is the same.
Given, fresh fruit has 68% water.so remaining 32% is fruit content. weight of fresh fruits is 100 kg
Dry fruit has 20% water.so remaining 80% is fruit content. Let weight if dry fruit be y kg.
Fruit % in freshfruit = Fruit % in dryfruit
Therefore, 
We get, y = 40 kg.

CSIR NET Physical Science Mock Test - 4 - Question 5

 

X and Y are the two alloys which were made by mixing Zinc and Copper in the ratio 1:3 and 2:5 respectively. If 120 grams of alloy X,91 grams of alloy Y and 34 gram pure Zinc are melted and mixed to form another alloy Z, what is the ratio of Zinc and Copper in the new alloy Z?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 5

Total Zink =1/4×120+2/7×91+34
=30+26+34=90
Total Copper =3/4×120+5/7×91
=90+65=155
Ratio =90:155=18:31

CSIR NET Physical Science Mock Test - 4 - Question 6

Statement: Prime Minister Narendra Modi launched three mega flagship schemes aimed at transforming Urban India, including the much talked about Smart Cities proposal, with a whopping Rs.4 lakh crore kitty having been lined up for the projects. He also unveiled logo of the housing mission, which has his personal touch in the finalization of its design. Speaking at the event, Modi said, “The decision to make cities smart will be taken not by governments but by the people of the city, the local administration. Let there be competition between cities in development so that smart cities come up.”

Which of the following will be an effect of the initiative taken by the government? 

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 6

Note that we are talking about Smart Cities Mission. Thus, anything related to rural areas is beyond the scope. Whereas, in option (C), we focus only on urban development. Therefore, option (C) will be an effect of the statement.

CSIR NET Physical Science Mock Test - 4 - Question 7

Direction : Read the following graph carefully and answer the question given below.

The following pie chart represents the distribution of the number of employees in different departments and table chart represents the ratio of the number of male to female in different departments. 
Total number of employees = 5600

The total number of male employees working in the sales department is what percent of the total number of employees working in all the departments?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 7

The total number of male employees working in the sells department 
Required

CSIR NET Physical Science Mock Test - 4 - Question 8

Select the option in which the given figure is embedded (rotation of the figure is not allowed).

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 8

The image embedded in given figure is as shown below:Hence,

CSIR NET Physical Science Mock Test - 4 - Question 9

Select the figure from among the given options that can replace the question mark (?) in the following series.

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 9

The pattern here is:
1) The triangle is moving from one corner to another and the point is moving in an anticlockwise direction. Also, the middle image is moving in a clockwise direction.
2) we can say that the missing image will look the same as that in figure 1.
Thus, options 2 and 3 are eliminated because the triangle is in the wrong place and facing in the wrong direction too.
And, option 4 is eliminated because the middle image is placed wrong. 

CSIR NET Physical Science Mock Test - 4 - Question 10

In the Venn diagram given below, the 'Circle' represents 'Officers', the 'Triangle' represents 'Married', the 'Rectangle' represents 'Salary above Rs. 50,000' and the 'Square' represents 'Post-Graduates'. The numbers given in the diagram represents number of persons of that particular category. How many single officers have salary above Rs. 50,000 but do NOT have a post-graduate degree?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 10

Here, we make a table as per the given data:

The number of single officers who have a salary above Rs. 50,000 but do NOT have a post-graduate degree means a common region of the rectangle and circle only.

Here, The number of single officers who have a salary above Rs. 50,000 but do NOT have a post-graduate degree is 10.
Hence, the correct answer is "10".

CSIR NET Physical Science Mock Test - 4 - Question 11

Hamid has three boxes of different fruits. Box A weighs kg more than Box B and Box C weighskg more than Box B. The total weight of 3 boxes is 48.75 kg. How many kilograms (kg) does Box A weigh?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 11

Given:
A = B + 2.5kg
C = B + 10.25kg
A + B + C = 48.75 kg
Solution:
B + 2.5 + B + B + 10.25 = 48.75
3B = 48.75 - 2.5 - 10.25
B = 36/3
B = 12 kg
A = 12 + 2.5 = 14.50 kg
Hence, the correct option is 4

CSIR NET Physical Science Mock Test - 4 - Question 12

The LCM and HCF of two numbers are 126 and 9, respectively. If one of the numbers is 18, then what is the other number?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 12

Given:
LCM = 126
HCF = 9
Concept used:
LCM = Lowest Common Factor
It is the product of the greatest power of each prime factor, involved in the numbers.
LCM × HCF = Product of two numbers
HCF = Highest Common Factor
It is the product of the smallest power of each common prime factor in the numbers.
Solution:
Let, the other number = m
126 x 9 = 18 x m
m = (126 x 9)/18
m = 63
Other number = 63
Hence, the correct option is 1.

CSIR NET Physical Science Mock Test - 4 - Question 13

The data given below shows the wickets took by various bowlers in a test series.

What is the mean(Correct up to two decimal places) of given data? 

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 13

Concept:
To find the mean using the direct method, for grouped data,

where xi is the classmark and fi are the frequencies. 
Classmark is the average of the lower limit and upper limit of any class interval.
Calculation:

We know that,

⇒ x̅ = 315/25 = 12.60
Hence, the mean is 12.60.

CSIR NET Physical Science Mock Test - 4 - Question 14

Study the given graph and answer the question that follows.

What is the difference between the total number of computers sold by dealer A on Monday, Tuesday and Friday and total number of computers sold by dealer B on Wednesday, Thursday and Saturday?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 14

Calculation:
The total number of computers sold by dealer A on Monday, Tuesday, and Friday = 75 + 80 + 78 = 233
The total number of computers sold by dealer B on Wednesday, Thursday, and Saturday = 60 + 80 + 75 = 215
Hence, difference between them = 233 - 215 = 18
∴ The difference between the total number of computers sold by dealer A on Monday, Tuesday and Friday and total number of computers sold by dealer B on Wednesday, Thursday and Saturday is 18.

CSIR NET Physical Science Mock Test - 4 - Question 15

In the figure, PQR is tangent to the circle at Q. If AB || PR, ∠BQR = 50° then ∠AQB is equal to :

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 15

Given:
∠BQR = 50°
Calculation:
∠BQR = ∠QAB  (∵ PQR is a tangent)
By the property of alternate segment theorem
⇒ ∠QAB = 50°      ----- (i)
∠BQR = ∠QBA  (∵ AB || PR, Alternate interior angles)
⇒ ∠QBA = 50°       ----- (ii) 
In Δ ABQ,
From (i) and (ii)
⇒ ∠QAB + ∠QBA + ∠AQB = 180° (∵ Sum of all the interior angles of the triangle )
⇒ 50° + 50° + ∠AQB = 180°
⇒ ∠AQB = 180° - 100° = 80° 

CSIR NET Physical Science Mock Test - 4 - Question 16

The number of microstates of a gas of N particles in a volume V and of internal energy U, is given by (where a and b are positive constants). Its pressure P, volume V and temperature T, are related by-

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 16

Given:

The Boltzmann's entropy is

From combined I and II law of thermodynamics, we have

CSIR NET Physical Science Mock Test - 4 - Question 17

Area of a rectangle having vertices A,B,C, and D with position vectors respectively is-

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 17


So, the area of the rectangle is 2 square units.

CSIR NET Physical Science Mock Test - 4 - Question 18

Consider an electron in a b.c.c. lattice with lattice constant a. A single particle wavefunction that satisfies the Bloch theorem will have the form being -

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 18

For b. c. c lattice, primitive vertices are given as, 

Where, a is lattice constant. 
Now, according to Bloch theorem,

where

Which means, function is periodic w.r.t. translational vector 

Other functions are not periodic

CSIR NET Physical Science Mock Test - 4 - Question 19

Consider the four processes,

Which of the above is/are forbidden for free particles?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 19

For 
Proton is a stable particle, therefore it cannot decay. So the given process is forbidden. 
For 
From the process, the charge is not conserved (0 →+2), therefore this process is also forbidden. 
For 
Charge is conserved (+1 = +1) and spin is also conserved (0 = 0). Isospin is 1. 
Therefore this reaction is allowed through E. M. interaction. 
For  
Here, in reaction γ is involved, therefore, it is allowed for E. M. interaction.

CSIR NET Physical Science Mock Test - 4 - Question 20

In a classical model, a scalar (spin-o) meson consists of a quark and an antiquark bound by a potential, and b=100 MeV fm. If the messes of the quark and antiquark are negligible, the mass of the meson can be estimated as approximately-

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 20

Here, for a classical model, a scalar meson consists of a quark and an antiquark bound by a potential is given, For determination of minimum value of r, differentiation of equation (i) with respect to r is zero.

From question, b=100MeVfm and a=200MeVfm−1.

Now, substitute the value of r,a and b in equation (i),

From the question, the masses of the quark and antiquark are negligible. Therefore from energy conservation,

CSIR NET Physical Science Mock Test - 4 - Question 21

For a particular thermodynamic system the entropy S is related to the internal energy U and volume V by where c is a constant. The Gibbs potential G=U−TS+pV for this system is

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 21

Here, the entropy S is related to the internal energy U and volume V is given as,

According first law of thermodynamics,

Substitute the value of U from equation (1), we have

Now, Gibb's potential is given as,
G=U−TS+PV
Substitute the values of U,T and V from equation (1), (2) and (3) we get,

CSIR NET Physical Science Mock Test - 4 - Question 22

What should be the minimum energy of a photon for it to split an ∝ particle at rest into a tritium and a proton? (The masses of  are 4.0026 amu, 3.0161 amu and 1.0073 amu, respectively, and 1 amu ≈938MeV.)

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 22

Here, a photon splits an ∝ - particle at rest into a tritium and a proton. The reaction may be given as,

Therefore, the energy of the photon will be minimum only if the tritium and created at rest.

CSIR NET Physical Science Mock Test - 4 - Question 23

Let |l,m> be the simultaneous eigenstates of L2 and Lz. Here  is the angular momentum operator with cartesian components (Lx , Ly, Lz), l is the angular momentum quantum number and m is the azimuthal quantum number. The value of <1,0| (Lx + i Ly) |1,-1> is?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 23

 We know that the Ladder angular momentum is L+= Lx +i Ly.
Now we have the relation that <l,m' |L± |l,m  > = 
Now for our case
We further simplify it and get:

CSIR NET Physical Science Mock Test - 4 - Question 24

The state of a system is given by:whereform a orthonormal set. The probability of finding the system in the state |ϕ2> ?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 24

We have where A is a normalization constant.
Now first we have to find the normalization constant.
So, we can find it using 
Using the above expression, we get:

So, we get: 
We are given a statehose probability in we get:

CSIR NET Physical Science Mock Test - 4 - Question 25

Let be the angular and linear momentum operators, respectively, for a particle. The commutator [ Lx , pz ] gives?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 25

We have
Now 
Using the above identity, we get:

CSIR NET Physical Science Mock Test - 4 - Question 26

The pressure P of a system of N particles contained in a volume V at a temperature T is given by where n is the number density and a and b are temperature independent constants. If the system exhibits a gas-liquid transition, the critical temperature is

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 26


where,
For critical condition 
Putting the expressions for n we have:

From equation (i) and (ii) 

put the value of in equation (i)

CSIR NET Physical Science Mock Test - 4 - Question 27

Let the wavefunction of the electron in a hydrogen atom bewhere are the eigenstates of the hamiltonian in the standard nutation. The expectation value of the energy in this state is

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 27

We have:

This wave function is normalized as if we do:

The expectation value of the energy in this state is:

We can find the E's first we get:

corresponding all wavefunctions.
Now, we can find the expectation value to be:

Solving it we will get:

<E>=−5.1eV.

CSIR NET Physical Science Mock Test - 4 - Question 28

The temperature variation of the resistivity of 4 materials are shown in the following graphs. Which one is more sensitive make a temperature sensor?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 28

When there is minima or maxima in the graph of resistivity vs temperature,
Then it indicates that there will be two different temperatures for which the material will show the same resistivity.
That kind of resistivity variating materials are not suitable candidates for sensors as they can be misleading.
Hence the only resistivity profile that is suitable for the temperature sensor is given by the one that shows some monotonic behavior.

CSIR NET Physical Science Mock Test - 4 - Question 29

Consider the circuit shown in the figure below:

If the transistors in the figure (a) and (b) have the current gain of βdc of 100 and 10 respectively. Then they operate in the?

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 29

For the figure (a).
Applying KVL in the input circuit we get:
−10.7+10k×IB+0.7=0
Hence IB=1mA
Current gain is given as:

Therefore, IC=0.1A
Now applying KVL in the output circuit we get:
−10+0.1×2mA+VCE=0
Hence VCE=−190V.
The output junction voltage is given by 
VBC=VBE+VEC=0.7+190=190.7V
Hence both the input as well as output junctions are forward biased.
So the figure (a) is in saturation region.
Similarly,
For the figure (b).
Applying KVL in the input circuit we get:
−5+IB×10K+0.7=0
Hence IB=0.43mA
Current gain is given as:

Therefore, IC=4.3mA
Now applying KVL in the output circuit we get:
−10+4.3+VCE=0
Hence VCE=5.7V
The output junction voltage is given by 
VBC=VBE+VEC=0.7−5.7=−5V
Hence the input junction here is forward biased but the output one is reverse biased.
So the figure (b) is in active region.

CSIR NET Physical Science Mock Test - 4 - Question 30

In a spectrum resulting from Raman scattering, let IR denote the intensity of Rayleigh scattering and IS and lAS denote the most intense Stokes line and the most intense anti-Stokes line, respectively. The correct order of these intensities is

Detailed Solution for CSIR NET Physical Science Mock Test - 4 - Question 30

CONCEPT:

Rayleigh and Raman scattering:

  • Raman spectroscopy is a spectroscopic technique based on Raman scattering.
  • When a substance interacts with a laser beam (or any light wave), almost all of the light produced is Rayleigh scattered light (elastic process).
  • However, a small percentage (about 0.000001%) of this light is Raman scattered (inelastic process). Raman scattering is a process, where incident light interacts with molecular vibrations in a sample.
  • The photons from the laser beam interact with the molecules and excite the electrons in them.
  • The excited electrons immediately fall down to the ground level.
  • As electrons lose energy and fall down to the ground state, they emit photons.

There are three different scenarios of how light can be re-emitted after energy had been absorbed by an electron: 

  • An electron falls down to the original ground state and there is no energy change, therefore light of the same wavelength is re-emitted. This is called Rayleigh scattering.
  • After being excited, an electron falls to a vibrational level, instead of the ground level. This means the molecule absorbed a certain amount of energy, which results in light being emitted in a longer wavelength than the incident light. This Raman scatter is called “Stokes”.
  • If an electron is excited from a vibrational level, it reaches a virtual level with higher energy. When the electron falls down to the ground level, the emitted photon has more energy compared to the incident photon, which results in shorter wavelength. This type of Raman scatter is called “Anti-Stokes”.
View more questions
Information about CSIR NET Physical Science Mock Test - 4 Page
In this test you can find the Exam questions for CSIR NET Physical Science Mock Test - 4 solved & explained in the simplest way possible. Besides giving Questions and answers for CSIR NET Physical Science Mock Test - 4, EduRev gives you an ample number of Online tests for practice

Top Courses for UGC NET

Download as PDF

Top Courses for UGC NET