NEET Mock Test - 5 - NEET MCQ

as the maximum current that can be drawn from a cell is for R =0 therefore, it is I = E/r.

• A cylindrical coil of many tightly wound turns of insulated wire with generally diameter of the coil smaller than its length is called a solenoid.
• A magnetic field is produced around and within the solenoid. The magnetic field within the solenoid is uniform and parallel to the axis of the solenoid.
• Strength of the magnetic field in a solenoid is given by -

Where,
N = number of turns, 
l = length of the solenoid,  
l = current in the solenoid
μ_o = absolute permeability of air or vacuum.
Now
we can see that the magnetic field inside the solenoid is 

And for unit length  (l = 1) the above equation can be modified as
B = μ₀NI
Hence option C is correct among all

We know that MI of a ring is mr²
Where m is mass of the ring and r is its radius
When we have ratio of I = 2:1
And ratio of r = 2:1
We get ratio of r² = 4:1
Thus to make this ratio 2:1 , that ratio of masses must be 1:2

Given Data,
Length of the piece of copper = l = 19.1 mm = 19.1 × 10^-3m
Breadth of the piece of copper = b = 15.2 mm = 15.2× 10^-3m
Tension force applied on the piece of cooper, F = 44500N
Area of rectangular cross section of copper piece,
Area = l× b
⇒ Area = (19.1 × 10-3m) × (15.2× 10-3m)
⇒ Area = 2.9 × 10^-4 m²
Modulus of elasticity of copper from standard list, η = 42× 10⁹ N/m2
By definition, Modulus of elasticity, η = stress/strain

⇒ Strain = F/Aη

⇒ Strain = 3.65 × 10^-3
Hence, the resulting strain is 3.65 × 10^-3

For the process C → A, ΔU = UA - UC = 0 - 80
⇒ ΔU = -80 J
and W = area ACED = area ACB + area ABED
∴ W = (1/2 × AB × BC) + (DE × DA)
∴ W = (1/2 × 2 × 60) + (2 × 30) = 120 J
Since, in this process the volume decreases, the work will be negative (w = 120 Joule). That is, the work will be done on the system. Now, by the first law of thermodynamics, we will have
Q = ΔU + W = -80 - 120 = -200 J
Since it is negative, this heat is given out by the system and work done in the whole cycle
= area ABC = (1/2 × 2 × 60) = 60 J
Since the cyclic process is traced anticlockwise, the net work will be done on the system.

Magnetic field part of a harmonic electromagnetic wave in vacuum
,B₀​=510×10⁻⁹T
Speed of light,
C=3×10⁸m/s
E=cB_o​=153N/C

Potential energy ∝ (Amplitude)² ∝ (Displacement)² P.E.is  maximum at maximum distance.
P.E. is zero at equilibrium point.
P.E. curve is parabolic.

We know that the efficiency of refrigeration for a refrigerator is T₂ / T₁ + T₂
Where T₁ is source temperature and T₂ is sink temperature
For refrigerator X we have T₁ = 298K and T₂ = 268K
Hence the efficiency of refrigeration = 268 / 298 - 268
= 268 / 30
= 8.93
For refrigerator Y we have T₁ = 293K and T₂ = 253K
Hence the efficiency of refrigeration = 253 / 293 - 253
= 253 / 40
= 6.35

This is because of inter-electronic replusions between lone pairs.

In the expression for equilibrium constant (Kp or Kc) species  state are not written (i.e., their molar concentrations are not taken as 1)
P₄ (s) + 5O₂ (g) ⇌ P₄O₁₀ (s)
Thus, Kc = 1/[O₂]⁵

Kohlrausch ’s Law states that at infinite dilution, each ion migrates independently of its co-ion and contributes to the total equivalent conductance of an eletrolyte a definite share which depends only on its own nature.
From this definition we can see that option (d) is the correct answer.

Combustion of hydrogen:
H₂ + ½ O₂→H₂O (H−O−H)
As water contains two O−H bonds.
So, combustion enthalpy of hydrogen is:
ΔH= Bond energy of reactant − Bond energy of the product − Enthalpy of vaporization. 
ΔH=x₁+2₂−2x₃−x₄

Put the things we need as reactant on LHS the product on RHS. To do that, we will apply equation S+I+D-2E-U.

Due to lanthanide contraction, Ag and Au have nearly same size.

The correct answer is option C
CaCO₃ ​→ CaO + CO_2​
K_p​ = k₁ ​= Pco₂​​
total pressure of container P
k_1​ = p
NH₄​HS → NH₃ ​+ H2​S
PNH_3​​ = PH_2​S ​= P0​
P_0​ + P₀​ = p (total pressure)
P0 ​= p/₂
k_2​ = kp ​= [P_NH3​​][P_H2​s​] p2₄​
NH₂​CoNH₂ ​→ 2NH₃ ​+ CO_2​
P_NH3​​ = 2P₀​        P_CO2​ ​= P0​
2P_0​ + P₀ ​= P

In lanthanide series, there is a regular decrease in the atomic as well as ionic radii of trivalent ions (M³⁺) as the atomic number increases. Although the atomic radii do show some irregularities but ionic radii decrease from La(103 pm) to Lu (86pm).

P4 is undergoing oxidation as well as reduction. As oxidation number of P₄ is 0 in reactant and it increases to +1 in H₂PO₂^- and decreases to -3 in PH₃

To match the correct individual with their contribution or hypothesis, let's review each person listed along with the contributions mentioned:
Robert May is best known for his pioneering work in theoretical ecology, particularly in the areas of population dynamics and stability in ecological communities. However, none of the choices directly mention these specific contributions. Among the options, the closest (though indirect) could be his theoretical work that touch upon aspects like species diversity estimations.
Alexander von Humboldt, known for his extensive work in biogeography, made critical observations on the geographic distributions of species. His work best correlates with the "Species-Area relationship," which describes how the number of species increases with the area surveyed.
Paul Ehrlich is famous for his work on population studies and environmental issues facing humanity. His statement about the planet's carrying capacity and potential biodiversity loss is widely known. The "Global species diversity at about 7 million" might closely relate to his biodiversity and population studies, though it's not his primary known work.
David Tilman is well-acclaimed for his experimental work on biodiversity and ecosystem productivity. The "Long term ecosystem experiment using outdoor plots" directly correlates with his experimental approach to studying the relationship between biodiversity and ecosystem functioning using field experiments.

Given these associations:
A (Robert May) might best fit with "Global species diversity at about 7 million" (III) though it's a rough fit.
B (Alexander von Humboldt) correlating with "Species-Area relationship" (I) is a much clearer connection.
C (Paul Ehrlich) and the "Global species diversity at about 7 million" (II) matches if we consider his general scope in biodiversity and population dynamics.
D (David Tilman) with "Long term ecosystem experiment using out door plots" (II) is an exact match for his field of work.

Looking at the options provided,
Option B: A-III, B-I, C-IV, D-II
This option aligns correctly as per the reasoning.
Therefore, the correct answer is Option B.     (NEET 2024)

In a dicot stem (e.g., In sunflower), hypodermis is made up of collenchyma, which may be green. In monocot stem  (e.g., maize), hypodermis is formed of non green sderenchyma tissue.

• Option (c) is the correct answer as autoimmune disorder is a condition where body defense mechanism recognises its own cells as foreign bodies. Sometimes, due to genetic and other unknown reasons, the body attacks self cells.
• Rheumatoid arthritis is an example where. This statement is incorrect. Rheumatoid arthritis (RA) is an autoimmune disorder where the immune system attacks the joints (attacks self cells ,synovial membrane), which are part of the body's own tissues. So, the body is indeed attacking its own cells in the case of RA.

So Statement I is correct but Statement II is incorrect.      (NEET 2022)

Standing crop is the amount of living biomass in an ecosystem. It indicates the productivity & luxuriance of growth. It is expressed in the form of number or biomass of organisms per unit area

Topic in NCERT: Trophic levels in an ecosystem

Line in NCERT: "each trophic level has a certain mass of living material at a particular time called as the standing crop."

The figure in the question shows formation of cross bridge between myosin head and actin filament. Next stage would be the figure showing the sliding/rotation of the head of myosin filament of the actin filament.

The given animal belongs to subphylum hemichordata. The name of the animal is Balanoglossus or acorn worm. In it, true notochord is absent but gill slits are present.

A represents polypeptide chain C which is removed prior to insulin formation

Topic in NCERT: Genetically engineered insulin

Line in NCERT: "insulin consists of two short polypeptide chains: chain a and chain b, that are linked together by disulphide bridges."

Rice is a staple food in many countries, particularly in Asia, but does not contain vitamin A or its immediate precursors. By inserting two genes from Daffodil and one gene from a bacterial species into rice plants, Swiss researchers have produced rice capable of synthesising β-carotene, the precursor of vitamin A. Vitamin A is required by all individuals as it is present in retina of eyes. Deficiency of vitamin A causes night blindness and skin disorders. This rice is called 'Golden rice' because of yellow colour of rice grains due to the presence of β-carotene.

The population density in a given habitat and at a particular time period, fluctuates due to the changes in four basic processes given below:-

1. Natality- It refers to the number of births take place in a population during a given period.

2. Mortality- It refers to the number of deaths take place in a population during a given period.

3. Immigration- It refers to the number of individuals of the same species have migrated into the habitat from somewhere else during a particular time period.

4. Emigration- It refers to the number of individuals of the same species have migrated out of the habitat during a given time period.

Natality and immigration add to the population density whereas mortality and emigration decrease the population density.

Topic in NCERT: Population Dynamics

Line in NCERT: "the density of a population in a given habitat during a given period, fluctuates due to changes in four basic processes, two of which (natality and immigration) contribute to an increase in population density and two (mortality and emigration) to a decrease."

In the given figure depicting the human respiratory system, the unidentified parts are as follows: A-Epiglottis, B-Alveoli, C- Bronchus, D-Diaphragm.

Line in NCERT: "Diagrammatic view of human respiratory system (sectional view of the left lung is also shown)"