MCQ: Clock and Calendar - 2 - SSC CGL MCQ

A month can have 28, 29, 30 or 31 days.
So, all the options are true.
Hence, the correct answer is "More than one of the above".

Key Points

• The concept of days succeeding each other is based on a seven-day cycle in which each day follows the next in a fixed order.
• If today is Wednesday, tomorrow would be Thursday.
• Thus, the day after tomorrow would be Friday, a day not listed among the options.
• Therefore, given the context and the understanding of the sequence of days in a week, 'none of the above' is the correct answer.

Therefore, the correct answer is Option 4, 'None of the above'.

1076 → 1076 is completely divisible by 4.
1675 → 1675 is not completely divisible by 4.
1354 → 1354 is not completely divisible by 4.
1998 → 1998 is not completely divisible by 4.

Therefore, 1076 is a leap year.
Hence, ‘1076’ is the correct answer.

Statements:
I. Harish was born on an even date of the month → 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28
II. Harish’s birth date was a prime number → 2, 3, 5, 7, 11, 13, 17, 19, 23, 29
But we know that 2 is the smallest even prime number.
According to both statements we can say that on 2nd February 2000 Harish was born.
Hence, Option (1) is correct.

Logic: If we see carefully we can find that these dates have property yy² = dd² + mm²
3rd April, 2005 - 03/04/05  
(05)² = (03)² + (04)²
6th August, 2010 - 06/08/10
(10)² = (06)² + (08)²
5th December, 2013 - 05/12/13
(13)² = (05)² + (12)²
Similarly,
Independence day 2017 - 15 August 2017 - 15/08/17
By above logic: (17)² = (15)² + (08)²  
No other option satisfy the above condition. So, Indian Independence Day of 2017 has the same property.
Hence, option 1) is the correct answer.

The logic followed here is:
1600 years contain 0 odd day, 300 years contain 1 odd day. Also, 83 years contain 20 leap years and 63 ordinary years and therefore (40+0) odd days i.e., 5 odd days.
∴ 1983 years contain (0 + 1 + 5) i.e., 6 odd days.
Number of days from Jan. 1984 to 15th Oct. 1984
= (31 + 29 + 31 + 30 + 31 + 30 +31+ 31 + 30 + 15)
= 289 days = 2 odd days
∴ Total number of odd days = 6 + 2 = 1 odd days.
So, 15th Oct, 1984 was Monday.
Hence, the correct answer is "Monday".

Calculation:   
The angle between two digits = 30° 
⇒ At 2'o clock one hand will be on 12 and second hand will be on 2 So, 30° × 2 = 60° 
∴ At 2'o clock angles between hands will be 60°.
The correct option is 3 i.e. 60° 

From 9 pm to 12 am angle rotated = 90°
⇒ Angle rotated from 12 am to 6 am = 180°
⇒ Therefore , total angle rotated = (90 + 180)°
⇒ 270°
Hence Total angle rotated = 270° 

Given: 
Today is 12th of December.
So, this month is December and according to the calendar, next month after December is January.
Hence, the correct answer is "January".

Concept:
A leap year is a year that has 366 days instead of the usual 365 days. It occurs every four years, except for years that are divisible by 100 but not by 400.

1998 is not a leap year because it is not divisible by 4.
2002 is not a leap year because it is divisible by 100 but not by 400.
2014 is not a leap year because it is not divisible by 4.
2004 is a leap year because it is divisible by 4.
Therefore, 2004 is the only leap year.

The logic followed here is:
3 march 2020 was Tuesday
First of all we will check is 2020 is a leap year 2020/4
so, 2020 is a leap year therefore February has 29 days.
Now, we will check days between 4 Feb 2020 - 3 march 2020
i.e. 26 + 3 odd days
= 29/7( because week has 7 days )
remainder is 1 by dividing it
so we will -1 in Tuesday i.e. Monday
therefore 3 Feb 2020 is Monday
but, we have to find 3 Feb 2019
then we will do -1 in Monday
so, on 3 February 2019 is Sunday
Hence, Sunday is the correct answer.

Given - 
January 1, 2018 was Monday

Concept used - 
in a normal year number of days = 365
number of odd days = (365/7) = + 1

1 January 2018 = Monday
1 January 2019 = Monday + 1 = Tuesday
∴ January 1, 2019 = Tuesday  

Statement I: February 15 of this year was a Wednesday: We cannot get what is today’s date.
Statement II: Today is March 12: We can’t tell which day today is, it can be any day.
Taking both the statements together: We cannot tell whether it is Friday or not because we don’t know if the year is leap year or not.
Hence both the statements were not enough to give the answer.

Given:
⇒ January 20, 2030 = Sunday
⇒ January 22, 2030 = Tuesday
As, for each month dates 1, 8, 15, 22 and 29 comes on same week day.
⇒ January 1, 2030 = Tuesday
⇒ January 4, 2030 = Friday
⇒ January 4, 2029 = Thursday
As after every leap year, dates will move two days further and 2028 is a leap year. Leap year is a year which is divisible by 4 and having 366 days.
∴ January 4, 2028 = Tuesday

An ordinary year has 1 odd day and a leap year has 2 odd days.
January 1, 2023 – Sunday
January 1, 2024 – Monday
January 1, 2025 – Wednesday
January 1, 2026 – Thursday
January 1, 2027 – Friday
January 1, 2028 – Saturday
January 1, 2029 - Monday
January 1, 2030 - Tuesday
January 1, 2031 - Wednesday
January 1, 2032 - Thursday
January 1, 2033 - Saturday
January 1, 2034 - Sunday
Clearly, in year 2034 again the January 1st will on a Sunday.
Hence, ‘2034’ is the correct answer.