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Technical Test SSC JE: Electrical Engineering (EE)- 2 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test - Technical Test SSC JE: Electrical Engineering (EE)- 2

Technical Test SSC JE: Electrical Engineering (EE)- 2 for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Technical Test SSC JE: Electrical Engineering (EE)- 2 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Technical Test SSC JE: Electrical Engineering (EE)- 2 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Technical Test SSC JE: Electrical Engineering (EE)- 2 below.
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Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 1

If induction motor is direct switched-on then it will develop

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 2

Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across a 500V line then-

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Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 3

Which of the following characteristics of electrons determines the current in a conductor?

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 4

The current in the given circuit with a dependent voltage source is

Detailed Solution for Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 4

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 5

Three current i1, i2 and i3 are approaching a mode. If i1=10 sin (400 t + 60º) A and i2 = 10 sin (400 t +60º) A, then i3 is

Detailed Solution for Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 5

The three currents i1i_1, i2i_2, and i3i_3 are approaching a mode, meaning that they must satisfy the condition of Kirchhoff's Current Law (KCL) or some other boundary condition.

Given:

i1=10sin(400t+60)Ai_1 = 10 \sin(400 t + 60^\circ) \, \text{A} i2=10sin(400t+60)Ai_2 = 10 \sin(400 t + 60^\circ) \, \text{A}

Step 1: Analyze i1i_1 and i2i_2

Notice that both currents i1i_1 and i2i_2 are identical:

i1=i2=10sin(400t+60)Ai_1 = i_2 = 10 \sin(400 t + 60^\circ) \, \text{A}

Since they are identical, their sum will be:

i1+i2=10sin(400t+60)+10sin(400t+60)=20sin(400t+60)Ai_1 + i_2 = 10 \sin(400 t + 60^\circ) + 10 \sin(400 t + 60^\circ) = 20 \sin(400 t + 60^\circ) \, \text{A}

Step 2: Use Kirchhoff's Current Law (KCL)

If i1i_1, i2i_2, and i3i_3 are approaching a mode, and assuming they are meeting at a node (in a KCL sense), then:

i1+i2=i3i_1 + i_2 = i_3

Substituting the values:

i3=20sin(400t+60)Ai_3 = 20 \sin(400 t + 60^\circ) \, \text{A}

Final Answer:

-10 (sin 400t ) A
Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 6

The figure shows a network in which the diode is an ideal one

The terminal V-I characteristics of the network is given by

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Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 7

In a network made up of linear resistors and ideal voltage sources, values of all resistors are doubled. Then the voltage across each resistor is

Detailed Solution for Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 7

Even on changing the values of linear resistors, the voltage remains constant in case of ideal voltage source.

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 8

Consitor the following circuit

What is the value of the current I in the above circuit?

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Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 9

For the circuit shown in the given figure the current through L and the voltage across C2 are respectively

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Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 10

A unit impulse voltage is applied at t=0 to the RL circuit shown below while i (0-)= 1A. What isthe expression for i (t)?

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Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 11

It the circuit shown in the figure given below, the switch is opened at t = 0 after having been closed for a long time. What is the current through 50W resistor?

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Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 12

For the circuit shown in the given figure the current I is given by

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Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 13

The value of V in the circuit shown in the given figure is

where I = 3A

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Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 14

Capacitors charge and discharge in __________ manner.

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 15

Consider the circuit given below, what is the power delivered by the 24 V source?

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Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 16

A straight conductor of circular x-section carries a current.which one of the following statement is true in this regard?

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 17

A cast steel electromagnet has an air gap length of 0.3 cm. Find the ampere turns for the air gap to produce a flux density of 0.7 wb/m2 in the air gap

Detailed Solution for Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 17

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 18

A magnetic circuit requires 800 AT to produce a certain quantity of flux in the magnetic circuit. If the excitation coil has 100 turns and 5W resistance, the voltage to be applied in the excitingcoil is

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Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 19

The principle of dynamically induced emf is utilised in a

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 20

Lower the self inductance of the coil

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 21

Two coupled coils connected in series have an equivalent inductance of 16 mH or 8 mH depending on its inter connection. Then the mutual inductance M between the coil is

Detailed Solution for Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 21

 

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 22

The overall inductance of two coils connected in series, with mutual inductance aiding self inductance is L1, with mutual inductance opposing self inductance the overall inductance is L2 . The mutual inductance M is given by

Detailed Solution for Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 22

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 23

Power factor is highest in case of

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 24

The purpose of providing choke in a tube light is

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 25

Blinking of Fluorescent tube may be on account of

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 26

The current drawn by a 220 V dc motor of armature resistance 0.5W and back emf 200V is

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Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 27

A dc shunt generator when driven without connecting field winding shows an open circuit terminal voltage of 12V. When field winding is connected and excited the terminal voltage drop to zero because

Detailed Solution for Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 27

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 28

A dc series motor is accidently connected to single phase a.c. suply. The torque produced will be

Detailed Solution for Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 28

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 29

At 1200 rpm, the induced emf of a dc machine is 200 V. For an armature current of 15 A the electromagnetic torque produced would be

Detailed Solution for Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 29

Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 30

Determine the flux per pole for 6 pole dc machine having 240 wave connected conductors, which generates an open circuit voltage of 500 volt.Which is running at 1000 rpm

Detailed Solution for Technical Test SSC JE: Electrical Engineering (EE)- 2 - Question 30

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