SSC CGL Exam  >  SSC CGL Tests  >  MCQ: Right Prism - SSC CGL MCQ

MCQ: Right Prism - SSC CGL MCQ


Test Description

10 Questions MCQ Test - MCQ: Right Prism

MCQ: Right Prism for SSC CGL 2024 is part of SSC CGL preparation. The MCQ: Right Prism questions and answers have been prepared according to the SSC CGL exam syllabus.The MCQ: Right Prism MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ: Right Prism below.
Solutions of MCQ: Right Prism questions in English are available as part of our course for SSC CGL & MCQ: Right Prism solutions in Hindi for SSC CGL course. Download more important topics, notes, lectures and mock test series for SSC CGL Exam by signing up for free. Attempt MCQ: Right Prism | 10 questions in 15 minutes | Mock test for SSC CGL preparation | Free important questions MCQ to study for SSC CGL Exam | Download free PDF with solutions
MCQ: Right Prism - Question 1

The base of a prism is a right-angled isosceles triangle whose hypotenuse is 3√2 cm. If the height of the prism is 12 cm, find the volume of the prism?

Detailed Solution for MCQ: Right Prism - Question 1

Given:

Hypotenuse of base triangle = 3√2 cm

Height of prism = 12 cm

Formula used:

In a right angled triangle;

(Hypotenuse)2 = (Base)2 + (Height)

Area of triangle = (1/2) x Base x Height

Volume of Prism = Area of base x Height

Calculation:

In Isoceles triangle; two sides are equal.

Let the equal sides = a cm

(3√2)2 = a+ a2

⇒ 18 = 2a2

⇒ a2 = 9 cm2

⇒ a = 3 cm

Area of triangular base = (1/2) x 3 x 3

⇒ 9/2 cm2

Volume of Prism = 12 x (9/2) cm3

⇒ 54 cm3

∴ The volume of prism is 54 cm3.

MCQ: Right Prism - Question 2

How many edges does a triangular pyramid have ?

Detailed Solution for MCQ: Right Prism - Question 2

A triangular pyramid has 6 edges 

∴ The correct answer is 6

1 Crore+ students have signed up on EduRev. Have you? Download the App
MCQ: Right Prism - Question 3

A prism has a regular hexagonal base with side 12 cm. If the total surface area of prism is 1024√3 cm2, then what is the height (in cm) of prism?

Detailed Solution for MCQ: Right Prism - Question 3

Given:

A prism has a regular hexagonal base with side 12 cm. 

Total surface area of prism = 1024√3 cm2

Formula used:

TSA of Prism = Base Perimeter × height + 2 x Base Area.

Area of hexagon = 3√3a2/2 . a = side

Total Area of hexagon Base = 2 × 3√3a2/2  = 3√3a2 

Perimeter of hexagon = 6a 

Concept used:

Surface area of regular hexagonal prism = 6ah + 3√3a2 (Where a = each side of the hexagon and h = height of the prism)

Calculation:

Let the height of the prism be h.

​According to the concept,

6 × 12h + 3√3 x 122 = 1024√3

⇒ 72h + 432√3 = 1024√3

⇒ 72h = 592√3

⇒ h = 592√3 ÷ 72

∴ The height of the prism is 74/3√3 cm.

MCQ: Right Prism - Question 4

The base of a right prism is an equilateral triangle whose side is 10 cm. If height of this prism is 10√3 cm, then what is the total surface area of prism ?

Detailed Solution for MCQ: Right Prism - Question 4

Given:

The base of a right prism is an equilateral triangle whose side is 10 cm.

Height of this prism is 10√3
Concept used:

TSA of Prism = [2(area of triangular base)] + [3(Area of rectangular sides)]

Area of Equilateral Triangle = (√3/4)a2 

Area of rectangle = l × b

Calculation:

According to the concept,

⇒ Area of Equilateral Triangle = (√3/4)(10)2 = (100/4)√3 = 25√3

⇒ Area of rectangle = l × b = 10 × 10√3 = 100√3

Then,

TSA = [2(25√3)] + [3(100√3)]

⇒ TSA = 50√3 + 300√3

⇒ TSA = 350√3
∴ The total surface area of prism is 350√3.

MCQ: Right Prism - Question 5

The base of a right prism is a regular hexagon of a side 5 cm. If its height is 12√3 cm, then its volume (in cm3) is:

Detailed Solution for MCQ: Right Prism - Question 5

Given :- 

The base of a right prism is a regular hexagon of side 5 cm

height is 12 √3 cm

Concept :-

Prism is a part of cylinder so,

Volume of prism = Base × Height

As base of prism is shan so 

Volume of prism with base hexagonal = base area x height

Base area = Area of hexagonal is equal to area of 6 equilateral triangle = 6 x (√3/4) x side
Calculation :-


 

⇒ Base area = 6 x (√3/4) x 52 

⇒ Base area = 150 x (√3/4)

⇒ Volume = 150 x (√3/4) x 12√3

⇒ Volume = (1800 x 3)/4

⇒ Volume = 1350 cm3

∴ Volume = 1350 cm3

 

MCQ: Right Prism - Question 6

What is the number of faces in a triangular prism?

Detailed Solution for MCQ: Right Prism - Question 6

Formula used:

 Number of faces = Number of triangular bases + Number of lateral faces

Calculation:

According to question,

Number of faces = 2 (triangular bases) + 3 (lateral faces) = 5

∴ The correct answer is 5.

MCQ: Right Prism - Question 7

Find the surface area of a square prism with a 2 cm side and a 4 cm height.

Detailed Solution for MCQ: Right Prism - Question 7

Given : 

Side of Square Prism = 2 cm
Height of Square Prism = 4 cm

Formula used :

Area  = 2 x side of square Prism + 4 x side of square Prism × height 

Calculation :

Area = 2cm x 2cm + 4cm x 2cm x 4 cm
⇒ 40 cm

MCQ: Right Prism - Question 8

A prism has a regular hexagonal base with side 8 cm and the total surface area of the prism is 912√3 cm2, then what is the height of the prism?

Detailed Solution for MCQ: Right Prism - Question 8

Given:

The side of the prism = 8cm

The total surface area of the prism = 912√3 cm2

Formula used:

Area of the regular hexagon = 3√3/2 x side2

The total surface area of the prism = 2 × Area of the base + 6 × (Side of the base) × (Height of prism)

Calculation:

Let the height of the prism be h cm

Area of the regular hexagon = 3√3/2 x side2

⇒ 3√3/2 × 82

⇒ 96√3 cm2

The total surface area of the prism = 2 x Area of the base + 6 x (Side of the base) × (Height of prism)

⇒ 2 × 96√3 + 6 x 8 x h = 912√3

⇒ 6 x 8 x h = 720√3

⇒ h = 15√3

∴ The height of the prism is 15√3 cm

MCQ: Right Prism - Question 9

The lateral surface area of a right triangular prism is 288 cm2. If the lengths of the smaller bases are 6 cm and 8 cm respectively, find the height of the prism.

Detailed Solution for MCQ: Right Prism - Question 9

Length of the larger base = √(62 + 82) = 10 cm (Using Pythagoras theorem)

Let the length of the height of the prism be X cm.

Perimeter of the given prism = 6 cm + 8 cm + 10 cm = 24 cm

Area of the right triangular prism = Perimeter x Height

⇒ 24 x X = 288

⇒ X = 12 cm

MCQ: Right Prism - Question 10

The base of a right prism is a triangle whose sides are 8 cm, 15 cm and 17 cm, and its lateral surface area is 480 cm2. What is the volume (in cm3) of the prism?

Detailed Solution for MCQ: Right Prism - Question 10

Given:

The base of a right prism is a triangle whose sides are 8 cm, 15 cm and 17 cm

The lateral surface area of right prism 480 cm2

Formula Used:

Lateral surface area of prism = perimeter of base x height 

Volume of prism = Area of base x height 

Calculation:

Since base side length is 8, 15, 17 [which is a triplet]

It means the base is a right angled triangle 

Perimeter of triangle = 8 + 15 + 17 = 40 cm 

Let the height of the prime is h cm 

So, 40 x h = 480 

⇒ h = 12 cm 

Now, Area of base = (1/2) x 8 x 15 = 60 cm2

Volume of prism = area x height 

∴ Volume of prism = 60 x 12 = 720 cm3.

Information about MCQ: Right Prism Page
In this test you can find the Exam questions for MCQ: Right Prism solved & explained in the simplest way possible. Besides giving Questions and answers for MCQ: Right Prism, EduRev gives you an ample number of Online tests for practice

Top Courses for SSC CGL

Download as PDF

Top Courses for SSC CGL