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MCQ: Speed, Time and Distance - 3 - SSC CGL MCQ


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15 Questions MCQ Test - MCQ: Speed, Time and Distance - 3

MCQ: Speed, Time and Distance - 3 for SSC CGL 2024 is part of SSC CGL preparation. The MCQ: Speed, Time and Distance - 3 questions and answers have been prepared according to the SSC CGL exam syllabus.The MCQ: Speed, Time and Distance - 3 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ: Speed, Time and Distance - 3 below.
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MCQ: Speed, Time and Distance - 3 - Question 1

A thief is spotted by a policeman from a distance of 300 meters. When the policeman starts chasing him, the thief also starts running. Given the speed of the thief is 6 km/hr and that of the policeman is 8 km/hr, how far would the thief have run before he is caught by the policeman?

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 1

Speed → Policeman : Thief = 8 : 6 = 4 : 3
Distance in the same time → Policeman : Thief = 4 : 3

Hence, option C is correct.

MCQ: Speed, Time and Distance - 3 - Question 2

If a girl walks from her house to school at the rate of 3 km per hour, she reaches the school 30 mins late than the scheduled time. However, if she walks at the rate of 5 km per hour, she reaches 30 mins earlier than the scheduled time. Find the distance of her school from her house.

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 2

Speed → Initial : New = 3 : 5
Time → Initial : New = 5 : 3

= 150 minutes = 2.50 hours
So the answer = 3 × 2.50 = 7.50 km
Hence, option D is correct.

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MCQ: Speed, Time and Distance - 3 - Question 3

Manoj runs at a speed of 3 m/s. In a 1500–meter race, Manoj gives Rahul a head start of 75 meters and still beats him by 75 meters. What is the speed at which Rahul was running?

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 3

Distance in same time → Rahul : Manoj = (1500 – 75 – 75) : 1500 = 9 : 10
Speed → Rahul : Manoj = 9 : 10

Hence, option B is correct.

MCQ: Speed, Time and Distance - 3 - Question 4

Samir and Mahesh start from Point Z and Point W respectively at 5:00 am. They start moving towards W and Z respectively. If Samir reaches W at 8:00 am and Mahesh reaches Z at 10:00 am, at what time do they meet?

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 4

Time → Samir : Mahesh = 3 hours : 5 hours = 3 : 5
Speed → Sanjay : Sagar = 5 : 3
Let the distance = 5 × 3 = 15 units

= 1 hours 52 minutes 30 seconds
So the answer = 5 am + 1 hours 52 minutes 30 seconds = 6:52:30 am
Hence, option D is correct.

MCQ: Speed, Time and Distance - 3 - Question 5

A person can cover 400 km by bus and 300 km by car in a total of 25 hours, where the ratio of the speed of bus to that of car is 2 : 1. If the speeds of the bus and the car increase by 25% and 50% respectively, what will be the time (in hours) taken to complete the same journey?

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 5

Let the speed of the bus = 2x km/hr
Speed of the car = x km/hr


x = 20
Speed of bus = 2x = 2 × 20 = 40 km/hr

Speed of car = x = 20 km/hr


Hence, option D is correct.

MCQ: Speed, Time and Distance - 3 - Question 6

In a 2 km race, A, B and C, are running at uniform speeds. If A beats B by 200 meters and B beats C by 600 meters, then by how many meters does A beat C?

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 6

Speed → A : B = 2000 : (2000 – 200) = 10 : 9
Speed → B : C = 2000 : (2000 – 600) = 10 : 7
Speed → A : C = 10 × 10 : 9 × 7 = 100 : 63

Hence, option D is correct.

MCQ: Speed, Time and Distance - 3 - Question 7

Arvind goes in his car from point R to S at a speed of 30 km/hr and Suresh goes on his car from S to R at a speed of 50 km/hr. The distance between point R and S is 240 km. If they start their journey at the same time, at what time did they start if both of them met at 2:30 PM?

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 7


Meeting time = 2:30 pm – 3 = 11:30 am
Hence, option D is correct.

MCQ: Speed, Time and Distance - 3 - Question 8

A can beat B by 200 m in a 1200 m race. When A and B run towards each other from the opposite ends of track UV, the difference between the distance traveled by them when they meet is 60 m. What is the length (in meters) of the track?

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 8

Ratio of the speed of A : B = 1200 : (1200 – 200) = 6 : 5

Hence, option D is correct.

MCQ: Speed, Time and Distance - 3 - Question 9

Sunny and Sandeep started running simultaneously from the same point in opposite directions on a circular track and met each other 12 minutes later after traveling a combined distance of 3.84 km. The speeds of Sunny and Sandeep are in the ratio 1 : 2. Find the time required for both of them to meet each other on a circular track of 2.4 km, if they start running simultaneously from the same point in the same direction.

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 9


Speed of Sunny : Sandeep = 1 : 2
Relative speed when running in the same direction


Hence, option B is correct.

MCQ: Speed, Time and Distance - 3 - Question 10

X, Y and Z start running at the same time in the same direction around a circular field. X completes a round in 168 seconds, Y in 224 seconds and Z in 280 seconds, all starting from the same point. After how many minutes will they meet again at the starting point?

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 10

Time taken to meet at the starting Point = LCM of 168, 224 and 280 = 3360 seconds

Hence, option C is correct.

MCQ: Speed, Time and Distance - 3 - Question 11

Rohit travels 20% of the journey by car, 60% of the journey by train and bus in the respective ratio of 3 : 2 and the remaining distance he covers on foot. The sum of the distance which he travels by car and by bus is 132 km. If the speed of car is 10 times his speed on foot, what is the ratio of the time taken by car to that by foot?

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 11

Distance covered by Car = 20%
Distance covered by Foot = 100 – 20% – 60% = 20%
Required time → Car : Foot

Hence, option A is correct.

MCQ: Speed, Time and Distance - 3 - Question 12

Anshul starts from point P and moves towards point Q at a speed of (b + 10) km/hour. Nidhi starts from point Q and moves towards point P at a speed of (b – 10) km/hour. If Nidhi starts moving 3 hours before Anshul and they meet at the mid–point of P and Q, find the time taken by Anshul to go from point P to point Q, if the distance between points P and Q is 720 km.

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 12


Let the time taken by Anshul = x hours
Time taken by Nidhi = x + 3 hours
(b + 10) × x = 360 ––––(1)
(b – 10) × (x + 3) = 360 ––––(2)
(b + 10) × x = (b – 10) × (x + 3)
bx + 10x = bx + 3b – 10x – 30
20x = 3b – 30

On applying in Eq1

(b + 10) × (b – 10) = 2400
b2 – 102 = 2400
b = 50
Speed of Anshul = b + 10 = 50 + 10 = 60 km/hr

Hence, option D is corect.

MCQ: Speed, Time and Distance - 3 - Question 13

Sanjay leaves place C at 5 am and reaches place D at 9 pm on the same day. Sagar leaves from place D at 7 am and reaches place C at 7 pm on the same day. At what time do they meet?

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 13

Time → Sanjay : Sagar = 16 hours : 12 hours = 4 : 3
Speed → Sanjay : Sagar = 3 : 4
Let the distance → 16 × 3 = 48 units
Distance covered by Sanjay till 7 am = 3 × 2 = 6 units
Remaining distance = 48 – 6 = 42 units
Reqd. time to cover 42 units

So the answer = 7 am + 6 hours = 1 pm
Hence, option A is correct.

MCQ: Speed, Time and Distance - 3 - Question 14

A beats B by 100 m in a 1000 m race, C beats D by 80 m in a 1280 m race. If B beats C by 240 m in a 1200 m race, by how much distance (in meters) A will beat D in a 2000 m race?

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 14

Speed → A : B = 1000 : (1000 – 100) = 10 : 9
Speed → C : D = 1280 : (1280 – 80) = 16 : 15
Speed → B : C = 1200 : (1200 – 240) = 5 : 4
Speed → A : C = 10 × 5 : 9 × 4 = 25 : 18
Speed → A : D = 25 × 16 : 15 × 18 = 40 : 27

Hence, option D is correct.

MCQ: Speed, Time and Distance - 3 - Question 15

In a race, A beats B by 300 meters, B beats C by 750 meters and A beats C by 900 meters. The distance (in km) over which the race has been conducted is:

Detailed Solution for MCQ: Speed, Time and Distance - 3 - Question 15

A beats B and C by 300 meters and 900 meters respectively.
In the time B covers the last 300 meters C covers 900 – 750 = 150 meters
Speed → B : C = 300 : 150 = 2 : 1

Hence, option B is correct.

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