Olympiad Test: Electricity and Circuits - Class 6 MCQ

The third lamp Z is connected parallel to X, so the current gets divided among X and Z. So both bulbs X and Z light dimmer and the bulb Y lights brighter than earlier because current through it increases.

Graphite is a conductor of electricity.

In X, the electrical energy is converted into sound energy. In Y, the electrical energy is converted into light energy. In Z, the electrical energy gets converted into heat energy. So, (C) is the correct option.

Key is a metallic object. When it is placed in between probes then current can easily flow in the circuit.

Bulb Q is fused because its filament is broken and as it is fused the circuit is broken. So none of the bulb will glow.

The direction of current will be PQRS because the current flows from positive terminal of the cell to the negative terminal.

Statement 1:  In an electric circuit, the direction of current is taken to be from the negative to the positive terminal of the electric cell. This statement is wrong. In an electric circuit, the direction of current is taken to be from the positive to the negative terminal of the electric cell.
Statement 2: A current can flow only when its path forms a closed loop. This statement is true

Brightness of bulb can be increased by increasing the current through the bulb. This can be achieved by connecting a similar battery in the same order.