All Courses
Get the App Signup / Login
Sign in Open App
CAT Exam  >  CAT Tests  >  Test: Speed, Time & Distance (March 12) - CAT MCQ

Test: Speed, Time & Distance (March 12) - CAT MCQ


Test Description

10 Questions MCQ Test - Test: Speed, Time & Distance (March 12)

Test: Speed, Time & Distance (March 12) for CAT 2024 is part of CAT preparation. The Test: Speed, Time & Distance (March 12) questions and answers have been prepared according to the CAT exam syllabus.The Test: Speed, Time & Distance (March 12) MCQs are made for CAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Speed, Time & Distance (March 12) below.
Solutions of Test: Speed, Time & Distance (March 12) questions in English are available as part of our course for CAT & Test: Speed, Time & Distance (March 12) solutions in Hindi for CAT course. Download more important topics, notes, lectures and mock test series for CAT Exam by signing up for free. Attempt Test: Speed, Time & Distance (March 12) | 10 questions in 20 minutes | Mock test for CAT preparation | Free important questions MCQ to study for CAT Exam | Download free PDF with solutions
Test: Speed, Time & Distance (March 12) - Question 1
Save

A train of 300 m is travelling with the speed of 45 km/h when it passes point A completely. At the same time, a motorbike starts from point A with the speed of 70 km/h. When it exactly reaches the middle point of the train, the train increases its speed to 60 km/h and motorbike reduces its speed to 65 km/h. How much distance will the motorbike travel while passing the train completely?

Detailed Solution for Test: Speed, Time & Distance (March 12) - Question 1

Speed of train while passing point

A = 70 x (5/18) m/s = VI

Speed of bike initially = 70 x (5/18) m/s = V2

Time taken by the bike to reach at the mid-point of the train = 1 5 0 /(V 2 - V I)

Again find out the new speeds of train and bike, and calculate the time taken by the bike to cover the rest 150 m distance relative to the train.

Test: Speed, Time & Distance (March 12) - Question 2
Save

Two riders on the horseback with a gun and a bullet proof shield were moving towards each other at a constant speed of 20 km/h and 5 km/h respectively. When they were 100 km apart, they started firing bullets at each other at the speed of 10 km/h. When a bullet of rider 1 hits the shield of rider 2, rider 2 fires a bullet and the process continues vice versa. Neglecting the time lag at the instant when the bullet hits the shield and the rider fires the shot, find the total distance covered by all the bullets shot by both the riders.

Detailed Solution for Test: Speed, Time & Distance (March 12) - Question 2

This question has actually got nothing to do with bullets initially. We can see that it takes them 4 hours to reach each other. And this is the same time for which bullets will cover some distance.
So, the total distance covered by the bullet = 4 x 1 0 = 40 km

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Speed, Time & Distance (March 12) - Question 3
Save

A train approaches a tunnel PQ which is 16 m long. Two rabbits A and B are standing at points which are 12 m and 8 m inside the tunnel with respect to the entrance P. When the train is x m away from P, A starts running towards P and B towards Q. Difference between the ratios of the speed of A to that of the train and the ratio of the speed of B to that of train is 1/8. How much can the distance x be, if both of them get caught at the ends of the tunnel?

Detailed Solution for Test: Speed, Time & Distance (March 12) - Question 3

Correct Answer :- c

Explanation : As D = S x T

D is directly proportional to S.

SA/ST = 12/x............(1)

SB/ST = 8/(x+16)........(2)

Subtract (1) from (2)

12/x - 8/(x+16) = 1/8

x = 48

Test: Speed, Time & Distance (March 12) - Question 4
Save

Refer to the data below and answer the questions that follow.
There is a race between Sagar and Sapna. Both of them Delhi. Sagar started on a bike with a speed of 40 km/h and Sapna has started in a car with a speed of 60 km/h from Mumbai to Delhi After 31/2 h of the journey there was a snag in the car She tried to repair the car but in vain After half an hour she got a lift for another 500 km in a truck, which was travelling with a speed of 45 km/h. From there Delhi was at a distance of 200 km on road, instead, Sapna took a shorter route which was only 100 km away from Delhi She started running at the speed of 30 km/h on the shorter route to reach Delhi.

Q. If there was no snag in the car, by how much distance Sapna would have defeated Sagar?
Detailed Solution for Test: Speed, Time & Distance (March 12) - Question 4

Total distance from Mumbai to Delhi = 910 km Time taken by Sapna to cover this distance, had there been no snag = 910/60

Since their speeds are in the ratio 3:2, Manoj would have covered [910 - (910 x 40)/60] km less than Sapna.

Test: Speed, Time & Distance (March 12) - Question 5
Save

A train’s journey is disrupted due to an accident on its track after it has travelled 30 km. Its speed then comes down to 4/5th of its original and consequently it runs 45 min late. Had the accident taken place 18 km farther away, it would have been 36 min late. Find the original speed of the train.
Detailed Solution for Test: Speed, Time & Distance (March 12) - Question 5

Let the original speed be X km/h According to the question, 18/(4/5x) - 18/x = 9/60 hr

x = 30 km/h

Test: Speed, Time & Distance (March 12) - Question 6
Save

There are two swimmers A and B who start swimming towards each other from opposite banks of the lake. They meet at a point 900 ft from one shore for the first time. They cross each other, touch the opposite bank and return. They meet each other again at 300 ft from the other shore. What is the width of the lake?
Detailed Solution for Test: Speed, Time & Distance (March 12) - Question 6

Let us assume that the width of the lake = x. So, when one of the runners A covers 900 m, the other one B is covering (x - 900) m. To meet next time, A will be covering (x - 900 + 300) m whereas B will be covering (900 + X-300) m.
Now, 900/(x - 900) = (x - 900 + 300)/(x + 900 - 300)
Now use options to find the answer.

Test: Speed, Time & Distance (March 12) - Question 7
Save

Ramesh and Somesh are competing in a 100 m race. Initially, Ramesh runs at twice the speed of Somesh for the first fifty m. After the 50 m mark, Ramesh runs at l/4th his initial speed while Somesh continues to run at his original speed. If Somesh catches up with Ramesh at a distance of ‘N ’ m from the finish line, then N is equal to
Detailed Solution for Test: Speed, Time & Distance (March 12) - Question 7

This question gives us the freedom to assume any value of speeds of Ramesh and Somesh. Let us assume the initial speed of Somesh = 20 m/s, then the initial speed of Ramesh = 40 m/s. Till 50 m they are running with this speed only. Time taken by Ramesh in covering 50 m = 1.25 sec. In the same time Somesh is covering 25 m.
After this stage, speed of Somesh is 20 m/s, whereas speed of Ramesh = 10 m/s. Now relative speed = 10 m/s and distance = 25 m. At 75 m from the starting, both of them will be meeting.

Test: Speed, Time & Distance (March 12) - Question 8
Save

The ratio between the speeds of two trains is 7:8. If the second train runs 400 kms in 4 hours, then the speed of the first train is?
Detailed Solution for Test: Speed, Time & Distance (March 12) - Question 8

speed of second train = 400km in 4 hr 

 = 100km/hr

ratio of speeds is 7:8

7:8 = v:100

v = 87.5km/hr

Test: Speed, Time & Distance (March 12) - Question 9
Save

Two persons Prabhat and Vinay are walking around a circular park of the length 960 m. Prabhat walks at the rate of 80 m/min while Vinay walks at the rate of 60 m/min. If both of them start from the same starting point at the same time in the same direction, when will they be together?
Detailed Solution for Test: Speed, Time & Distance (March 12) - Question 9

Relative speed of Vinay and Prabhat will be 20 m/minute to cover the track of 960 m. It will take 48 minutes.

Test: Speed, Time & Distance (March 12) - Question 10
Save

Two cyclists start from the same place to ride in the same direction. Aflatoon starts at noon with a speed of 8 km/h and Bablajoon starts at 2 pm with a speed of 10 km/h. At what times Aflatoon and Bablajoon will be 5 km apart?
Detailed Solution for Test: Speed, Time & Distance (March 12) - Question 10

At 2 O’ clock Aflatoon has already covered 16 km @ 8 km/h, Bablajoon starts running in the same direction @ 10 km/h. The relative speed is 2 km/h. 

Therefore to be 5km apart bablajoon has to cover 11 km. relative speed=2km/hr, therefore for 11km it will take 5hr 30 min more.  Therefore they will meet at 7:30 the same day. And similarly 12.30 a.m. on the next day.

Information about Test: Speed, Time & Distance (March 12) Page
In this test you can find the Exam questions for Test: Speed, Time & Distance (March 12) solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Speed, Time & Distance (March 12), EduRev gives you an ample number of Online tests for practice

Top Courses for CAT

Download as PDF

Top Courses for CAT

Important Questions for Speed, Time & Distance (March 12)

Find all the important questions for Speed, Time & Distance (March 12) at EduRev.Get fully prepared for Speed, Time & Distance (March 12) with EduRev's comprehensive question bank and test resources. Our platform offers a diverse range of question papers covering various topics within the Speed, Time & Distance (March 12) syllabus. Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered. The questions are designed to challenge you and help you gain confidence in tackling the actual exam. Maximize your chances of success by utilizing EduRev's extensive collection of Speed, Time & Distance (March 12) resources.

Speed, Time & Distance (March 12) MCQs with Answers

Prepare for the Speed, Time & Distance (March 12) within the CAT exam with comprehensive MCQs and answers at EduRev. Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus. Access the best books, study materials, and notes curated by toppers to enhance your preparation. Stay updated with the exam date and receive expert preparation tips and paper analysis. Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.

Online Tests for Speed, Time & Distance (March 12)

Practice with a wide array of question papers that follow the exam pattern and syllabus. Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement. Access detailed solutions and explanations for each test to enhance your understanding of concepts. With EduRev's Online Tests, you can build confidence, boost your performance, and ace Speed, Time & Distance (March 12) with ease. Join thousands of successful students who have benefited from our trusted online resources.
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup