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Mock Test: Numerical Ability - 2 - AFCAT MCQ


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15 Questions MCQ Test - Mock Test: Numerical Ability - 2

Mock Test: Numerical Ability - 2 for AFCAT 2024 is part of AFCAT preparation. The Mock Test: Numerical Ability - 2 questions and answers have been prepared according to the AFCAT exam syllabus.The Mock Test: Numerical Ability - 2 MCQs are made for AFCAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Mock Test: Numerical Ability - 2 below.
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Mock Test: Numerical Ability - 2 - Question 1

The area of the Circular garden is 88704 m². Outside the garden a road of 7m width laid around it. What would be the cost of laying road at Rs. 2/m².

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 1

88704 = 22/7*r
r =168
Outer radius = 168+7 = 175
Outer area = 22/7*175 2 = 96250
Road area = 96250 – 88704 = 7546
Cost = 7546*2 = 15092

Mock Test: Numerical Ability - 2 - Question 2

The batting average of a batsman for 20 innings is 35 and the difference b/w the runs of best inning and worst inning is 50. If these two innings are not included the average becomes 32 for 18 innings. The best score of the batsman is.

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 2

Answer – c) 87 Explanation : 35*20 = 700.
Best(B) – Worst(W) = 50 700 – B – H = 18*32= 576. B+H = 124 and B-H = 50. So B =87

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Mock Test: Numerical Ability - 2 - Question 3

50 men could complete a work in 200 days. They worked together for 150 days, after that due to bad weather the work is stopped for 25 days. How many more workers should be employed so as to complete the work in time?

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 3

Let additional workers be P, (50*150)/(50*200) = 3/4 of the work is already completed and now only 1/4 of the work is to be done. So,
1/4 = ((50 + P) * 25)/50*200, solve for p, we get P = 50

Mock Test: Numerical Ability - 2 - Question 4

The maximum marks per paper in  3 subjects in Mathematics , Physics and Chemistry are set in the ratio 1 : 2 : 3 respectively. Giri obtained 40% in Mathematics, 60% in Physics and 35% in Chemistry papers. What is overall percentage marks did he get overall?

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 4

Answer – 1.44% Explanation : 40*1/100  : 60*2/100 : 35*3/100 = 0.4:1.2:1.05
Overall % =100* [0.4+1.2+1.05]/1+2+3 = 265/6 = 44.16 = 44%

Mock Test: Numerical Ability - 2 - Question 5

Mohan can do a work in 15 days. After working for 3 days he is joined by Vinod. If they complete the remaining work in 3 more days, in how many days can Vinod alone complete the work?

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 5

Total days Mohan worked = 3+3 = 6
6/15 = 2/5
So 3/5 = 3/x
x = 5

Mock Test: Numerical Ability - 2 - Question 6

A tradesman marks the price of his goods such that after allowing a discount of 25%, he earns a profit of 40%. What is the marked price of an article whose cost price is Rs.180?

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 6

S.P = (100+profit%)*cp /100 = 140*180/100 = 252
M.P – 25% of M.P = SP
X – 25/100 X = 252
X = 336

Mock Test: Numerical Ability - 2 - Question 7

The ratio of monthly income of A and B in the ratio is 6:5 and the ratio of their expenditure is 9:7.If each saves Rs.1500.Then the sum of their salary is

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 7

A)11,000
Explanation : 4500:3500 – e 1500:1500 – s 6000 + 5000 = 11000

Mock Test: Numerical Ability - 2 - Question 8

(2222.5 – 1680 * 0.75)*1.2 = ?

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 8

2222.5 – 1260 = 962.5; 962.5*1.2 = 1155

Mock Test: Numerical Ability - 2 - Question 9

The average age of a family of 5 members is 20 years. If the age of the youngest member is 10 years, what was the average age of the family at the birth of the youngest member?

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 9

At present the total age of the family = 5 × 20 =100
The total age of the family at the time of the birth of the youngest member,
= 100 - 10 - (10 × 4)
= 50
Therefore, average age of the family at the time of birth of the youngest member,
= 50/4 =12.5

Mock Test: Numerical Ability - 2 - Question 10

A man sells a TV set for Rs. 33000 and makes a profit of 10%. He sells another TV at a loss of 20%. If on the whole, he neither gains nor loses, find the selling price of the second TV set.

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 10

Let's denote the cost price of the first TV as CP1, the cost price of the second TV as CP2, and the selling price of the second TV as SP2.

The man makes a profit of 10% on the first TV, so we can write the selling price of the first TV as:

SP1 = CP1 + 10% of CP1
33000 = CP1 + 0.1 * CP1
33000 = 1.1 * CP1
CP1 = 33000 / 1.1
CP1 = 30000

He sells the second TV at a loss of 20%, so we can write the selling price of the second TV as:

SP2 = CP2 - 20% of CP2
SP2 = 0.8 * CP2

Since he neither gains nor loses on the whole, the total cost price equals the total selling price:

CP1 + CP2 = SP1 + SP2

We already know the values of CP1 and SP1, so we can substitute them in the equation:

30000 + CP2 = 33000 + SP2

We also know that SP2 = 0.8 * CP2, so we can substitute that as well:

30000 + CP2 = 33000 + 0.8 * CP2

Now, we can solve for CP2:

0.2 * CP2 = 3000
CP2 = 15000

Now that we have the cost price of the second TV, we can find its selling price using the relation we found earlier:

SP2 = 0.8 * CP2
SP2 = 0.8 * 15000
SP2 = 12000

So the selling price of the second TV set is Rs. 12000.

Mock Test: Numerical Ability - 2 - Question 11

What will be the ratio of simple interest earned by certain amount at the same rate of interest for 5 years and that for 15 years?

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 11

Simple Interest = PRT / 100
Here P = Principal, R = Rate of interest and T = time period
Hence, Simple Interest ∝ T
Required Ratio = (Simple Interest for 5 years) / (Simple Interest for 15 years)
⇒ T1/ T2 = 5 / 15
⇒ 1 / 3 = 1 : 3

Mock Test: Numerical Ability - 2 - Question 12

In a library 60% of the books are in Hindi, 60% of the remaining books are in English rest of the books are in Malayalam. If there are 4800 books in English, then the total number of books in Malayalam are?

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 12

D. 3200
Explanation: Let there are X books in the library.
Hindi books = 60% of X = 60X /100 = 0.6X Remaining Books = X – 0.6X = 0.4X English books = 40% of reaming books = 60% of 0.4X = 0.24X.
Malayalam Books = X-0.6X -0.24X = 0.16X Given, 0.24X = 4800
X = 4800/0.24 = 20000
Malayalam Books = 0.16X = 0.16*20000 = 3200.

Mock Test: Numerical Ability - 2 - Question 13

The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 13

The angle between hour and minute hand in 4:20 is 10 degrees.
For a minute, the hour hand rotates by 30/60 = 1/2 degrees.
hence, for 20 minutes it rotates by an angle of 20*1/2 = 10 degrees.

Mock Test: Numerical Ability - 2 - Question 14

The fourth proportional to 5, 8, 15 is:

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 14

Mock Test: Numerical Ability - 2 - Question 15

17, 98, 26, ?, 35, 80

Detailed Solution for Mock Test: Numerical Ability - 2 - Question 15

26 -17 = 9; 35 – 26 = 9
98 – 9 = 89

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