Test: General Organic Chemistry - NEET MCQ

The correct answer is option B
First of all, we should number the carbon atoms from right to left for the above molecule. According to IUPAC rule, we have to name the functional groups alphabetically. Hence, bromine which is attached to 3rd carbon is named as 3-bromo, chlorine which is attached to 7th carbon is named as 7-chloro and ethyl group which is also attached to 7th carbon is named as 7-ethyl. 5-(1,1-dimethyethyl) indicates that, 2 methyl groups are attached to the 1st carbon of ethyl group which is attached to the 5th carbon of the given molecule. 5-(2-methylpropyl) indicates that, a methyl group is attached to the 2nd carbon of propyl group which is attached to the 5th carbon of the given molecule. Finally, since the molecule has nine atoms and it is an alkane, the word nonane is added to the IUPAC name.
 

The IUPAC name of the given compound is 5, 6 - diethyl -2- methyldec - 4 - ene. 
The parent hydrocarbon contains 10 carbon atoms and a double bond. 
It is called dec-4-ene.
One methyl group is present on second carbon atom and two ethyl groups are present on fifth and sixth carbon atoms.

The correct answer is option D
The IUPAC name for the given compound is:
3-Bromo-4-(hepta-2,4,6-trienyl)cyclopenta-2,4-dien-1-oll
according to the rule of nearly attached halogen count first.so we count the the chain where bromo is near
 

7-Bromocycloheptane-1,3,5-triene

2- Ethyl -3-methylbut-2-ene-1, 4-dioic anhydride

All isomeric esters are metamers.

he most stable conformation of the molecule shown (with two iodine and two carboxylic acid groups attached to a central carbon) would be the anti conformation. In this conformation, the bulky groups (such as the iodine atoms and the carboxylic acid groups) are positioned opposite to each other to minimize steric repulsion. This arrangement reduces the overall energy of the molecule, making it the most stable configuration.

Therefore, for the structure shown, arranging the I and COOH groups opposite each other would yield the most stable anti-conformation.

The correct answer is Option A.

The correct answer is Option A.
No of asymmetric carbon atoms in 
2 - dimethylcyclohexane  = 2
3-methylcyclopentene = 1
3-methylcyclohexene = 1

The configuration in a compound is independent of its physical properties (optical activity)

The correct answer is Option B.
The 1st option has R configuration and 2nd has S configuration hence they are non super imposable mirror images of each other and are enantiomers.