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AP EAMCET Mock Test - 6 - JEE MCQ


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30 Questions MCQ Test - AP EAMCET Mock Test - 6

AP EAMCET Mock Test - 6 for JEE 2025 is part of JEE preparation. The AP EAMCET Mock Test - 6 questions and answers have been prepared according to the JEE exam syllabus.The AP EAMCET Mock Test - 6 MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for AP EAMCET Mock Test - 6 below.
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AP EAMCET Mock Test - 6 - Question 1
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Figure show the circular coil carrying current l kept very close but not touching at a point A on a straight conductor carrying the same current I. The magnitude of magnetic induction at the centre of the circular coil will be

Detailed Solution for AP EAMCET Mock Test - 6 - Question 1
Magnetic induction at the centre of circular current carrying loop,

Magnetic induction at the centre O due to straight wire,

Net magnetic induction at O,

AP EAMCET Mock Test - 6 - Question 2
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In case of dimension of electric field and electric dipole moment the power of mass is respectively,

Detailed Solution for AP EAMCET Mock Test - 6 - Question 2
Electric field, E = F/q

Where, F = force and q = electric charge

Dimensions of E or [E] = [MLT-2]/[AT] = [MLT-0A-1]

Power of mass = 1

Electric dipole moment, m = l x A

Where, l = current and A = area

Dimensions of m = [M] = [A L2] = [M0L2T0A]

Hence, power of mass = 0

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AP EAMCET Mock Test - 6 - Question 3
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Two pendulums begin to swing simultaneously. The first pendulum makes nine full oscillations when the other makes seven. The ratio of the lengths of toe two pendulums is

Detailed Solution for AP EAMCET Mock Test - 6 - Question 3
As two pendulums begin to swing simultaneously, then n1T1 = n2T2 where, n1 and n2 are the number of oscillations of first and second pendulum respectively and T1 and T2 be their respective time periods.

The time period of a simple pendulum is given by

Where, I = length of the pendulum and g = acceleration due to gravity ⇒ T2 ∝ l …(ii)

So. from Eqs. (i) and (i), we get

Here, n1 = 9, n2 = 7

⇒

Hence, the ratio of pendulum lengths l1:l2 = 49.81.

AP EAMCET Mock Test - 6 - Question 4
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Light of wavelength ‘λ‘ is incident on a single slit of width 'a', and the distance between slit and screen is ‘D’. In diffraction pattern, if slit width is equal to the width of the central maximum, then 'D’ is equal to
Detailed Solution for AP EAMCET Mock Test - 6 - Question 4

The diffraction pattern due to a single slit is shown below

2y = 2Dλ/a gives the width of central maximumDλ/a. Where, λ = wavelength of incident light.

Here, a = 2y, then from Eq.(i), we get a = 2Dλ/a ⇒ D = a2/2λ.

AP EAMCET Mock Test - 6 - Question 5
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Six very long insulated (topper wires are bound together to form a cable. The currents carried by the wires are l1 = +10 A, l2 = - 13A , l3 = +10A, l4 = + 7A, l5 = 12A and l6 = 18A. The magnetic induction at a perpendicular distance of 10 cm from the cable is (μ0 = 4π x 10-7 Wb/A-m)
Detailed Solution for AP EAMCET Mock Test - 6 - Question 5
Net current due to all wires, inet = i1 + i2 + i3 + i4 + i5 + i6

Inet = 10 - 13 + 10 + 7 - 12 + 18 = 20A

We know, magnetic field due to an infinitely long straight conductor at a perpendicular distance r from it is given by

Where, i = current in wire and r = perpendicular distance.

B = 40μT

AP EAMCET Mock Test - 6 - Question 6
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The current i in a coil varies with time as shown in the figure. The variation of induced emf with time would be
Detailed Solution for AP EAMCET Mock Test - 6 - Question 6

i-t graph is a straight line with positive constant slope.

∴ di/dt = constant

⇒ e = −ve and constant For

i-t graph is a straight line with negative constant slope.

∴ di/dt = constant

⇒ e = + ve and constant

From this analysis, the variation of induced emf with time as shown in the figure below.

AP EAMCET Mock Test - 6 - Question 7
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An aircraft is moving with uniform velocity 150 m/s in space. If all the forces acting on it are balanced, then it will
Detailed Solution for AP EAMCET Mock Test - 6 - Question 7
As all the forces acting on the aircraft are balanced, so the net force on it will be zero, i.e., no external force act on it. Thus, the aircraft will keep moving with the same velocity of 150 m/s in the space.
AP EAMCET Mock Test - 6 - Question 8
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An LCR circuit is equivalent to a damped pendulum. In an LCR circuit, the capacitor is charged to Q0 and then connected to the L and R as shown below:

If a student plots graphs of the square of maximum charge on the capacitor with time (t) for two different values L1 and L2 (L1 > L2) of L, then which of the following represents this graph correctly?

(Plots are schematic and not drawn to scale)
Detailed Solution for AP EAMCET Mock Test - 6 - Question 8

If L is more, Q falls slower.

L1 > L2

⇒ curve for L2 will fall faster than curve for L1.

AP EAMCET Mock Test - 6 - Question 9
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Two point charges exert on each other a force F when they are placed r distance apart in air. When they are placed R distance apart in medium of dielectric constant K, they exert the same force. The distance R equals
Detailed Solution for AP EAMCET Mock Test - 6 - Question 9
In vacuum, force between charges is F1 while in medium is F2

AP EAMCET Mock Test - 6 - Question 10
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The compound X is tested by following tests and their result are:

What is the Compound X?
Detailed Solution for AP EAMCET Mock Test - 6 - Question 10

AP EAMCET Mock Test - 6 - Question 11
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A+2B→C, the rate equation for the reaction is given as

Rate =k[A][B]

If the concentration of A is kept the same but that of B is doubled what will happen to the rate itself?
Detailed Solution for AP EAMCET Mock Test - 6 - Question 11

The order of the overall reaction is 2.

AP EAMCET Mock Test - 6 - Question 12
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The products obtained on heating LiNO3 will be
Detailed Solution for AP EAMCET Mock Test - 6 - Question 12

LiNO3 behaves differently from other alkali metal nitrates.

AP EAMCET Mock Test - 6 - Question 13
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Starch-iodide paper is used to test the presence of-
Detailed Solution for AP EAMCET Mock Test - 6 - Question 13

Iodides are readily oxidised in acidic solutions to free iodine; the free iodine can then be identified as it produces deep blue colouration with a starch solution.

AP EAMCET Mock Test - 6 - Question 14
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If 10 volume of H2O2 reacts completely with 100 ml of 2 N KMnO4, calculate the volume of H2O2 used in mL.
Detailed Solution for AP EAMCET Mock Test - 6 - Question 14

Volume strength of H2O2 = Normality × 5.6

According to law of equivalence.

N1V1(KMnO4) = N2V2(H2O2)

2 × 100 = 1.786 × V2

AP EAMCET Mock Test - 6 - Question 15
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The end product (Z) of the following reaction is
Detailed Solution for AP EAMCET Mock Test - 6 - Question 15

Step 1: Benzene diazonium chloride reacts with Cu/KCN to give cyanobenzene (X) and by-products N2  and KCl.

Step 2: Upon hydrolysis of cyanobenzene (X), it produces benzoic acid (Y).

Step 3:

Benzoic acid (Y) on further heating with soda lime in the presence of a base, NaOH
 undergoes decarboxylation to form a benzene ring (Z) and by-product Na2CO3.

Thus, the end product (Z) for the above reaction is an arene.

AP EAMCET Mock Test - 6 - Question 16
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Which of the following statements is false for the reaction H2 + Br2 →2HBr?

The rate law is 
Detailed Solution for AP EAMCET Mock Test - 6 - Question 16

The given reaction H2 + Br2 → 2HBr is a bi-molecular reaction, hence the molecularity is 2.

The order can be determined as 

If concentrate of Br2 is increased 4 times,

i.e., rate increases 2 times.
Hence, all the statements are correct.

AP EAMCET Mock Test - 6 - Question 17
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A heating coil is immersed in a 100 g sample of H2O (l) at 1 atm and 100oC in a closed vessel. In this heating process, 60% of the liquid is converted to the gaseous form at a constant pressure of 1 atm. The densities of liquid and gaseous water under these conditions are 1000 kg m−3 and 0.60 kg m−3, respectively. The magnitude of the work done for the process is -
Detailed Solution for AP EAMCET Mock Test - 6 - Question 17


60% water converted to gaseous form, so, the final volume:

= −105(100 × 10−3 + 0.04 × 10−3 − 0.1 × 10−3)
∣w∣ = 9994 J

AP EAMCET Mock Test - 6 - Question 18
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If  are unit vectors and then the value of is equal to
AP EAMCET Mock Test - 6 - Question 19
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If the roots of the equation (2k+1)x2 - (7k-3)x+k+2=0 are reciprocal of each other, the value of k is
AP EAMCET Mock Test - 6 - Question 20
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AP EAMCET Mock Test - 6 - Question 21
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If the slope of the normal to the curve x3 = 8a2y, a > 0, at a point in the first quadrant is - 2/3, then the point is
AP EAMCET Mock Test - 6 - Question 22
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AP EAMCET Mock Test - 6 - Question 23
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If the two roots of the equation x3-3x+2=0 are equal, roots are
AP EAMCET Mock Test - 6 - Question 24
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If (a, b), (c, d), (e, f) are the verices of a triangle such that a, c, e are in G.P. with common ratio r and b, d, f are in G.P. with common ratio's then the area of the triangle is
AP EAMCET Mock Test - 6 - Question 25
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The order of differential equation (d2y/dx2)2 = (1+dy/dx)1/2 is
AP EAMCET Mock Test - 6 - Question 26
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If the mean of a Poisson's Distribution is λ, then its standard deviation is
AP EAMCET Mock Test - 6 - Question 27
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If in a Δ A B C , 3 a = b + c then tanB/2 .tan C/2 is equal to
Detailed Solution for AP EAMCET Mock Test - 6 - Question 27

AP EAMCET Mock Test - 6 - Question 28
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The order of the differential equation y(dy/dx)=x/(dy/dx)+(dy/dx)3 is
AP EAMCET Mock Test - 6 - Question 29
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p and q are the roots of x2 + ax + b = 0, then equation whose roots are p2q, q2p is
Detailed Solution for AP EAMCET Mock Test - 6 - Question 29

p + q = - a, p.q = b
Now, p2 q + q2 p = pq(p + q)
= b(-a) = - ab
p2q . q2p = (pq)3 = b3
The required equation is
x2 - (p2q + q2p) x+ (p2q . q2p) = 0
x2 + abx + b3 = 0

AP EAMCET Mock Test - 6 - Question 30
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Consider A, B, C and D with position vectors 7î - 4ĵ + 7k̂, î - 6ĵ + 10k̂, -î -3ĵ + 4k̂ and 5î - ĵ + 5k̂ respectively. Then ABCD is a
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