MHT CET Mock Test - 2 - JEE MCQ

We know that the force of gravitation is inversely proportional to square of the distance between the two bodies,

i.e. F∝ r^-2

Hence, when the distance between them will be doubled, the force will be reduced by 4 times

So, the ratio will be 4:1

The correct answer would be option B. Applying a very strong magnetic field.
Applying a very strong magnetic field to a metal we don’t know the electron emission.

Frequency=C/ λ
λ=h/P
frequency=C P/ h
f=(3×10⁸×3.3×10^-29)/6.6×10^-34
f=3× 10¹³/2
f=1.5×10¹³ Hz

Torque = Work = Energy =[ML²T^-2]


 

According to Gauss’s Law, the total number of electric field lines coming out of a charge q is =where εo is the absolute permittivity of air. Its value is 8.85 * 10^-12. Therefore the number of lines coming out from a 1C charge = 1/8.85 * 10^-12.

In series connection of cells total internal resistance=nr total resistance of circuit=nR current is same potential difference is different so,I=nv/nR+nr I=V/R+r current is same as before in parallel connection of cells total internal resistance=r/n total resistance of circuit=R/n total current=nI potential difference is same nI=V/r/n+R/n I=V/R+r current is same as before.

At the highest point of its flight, the vertical component of velocity is zero and the only horizontal component is left which is u_x = u cosθ
Given θ = 45⁰

NaBH₄ brings about reduction of carbonyls by hydrid e transfer mechanism at planar sp² carbon. Hence, if a chiral carbon is generated, racemic mixture is always produced.

[PtBrCl NH₃ Py] Pt²⁺ is dsp² hybridised & hence geometry is square planner & sq. planner complex with four different ligands shows geometrical isomerism.

Attractive forces tend to bring two atoms close to each other whereas repulsive forces tend to move them away. In hydrogen, the magnitude of the new attractive forces is greater than that of new repulsive forces. As a result, two atoms come close to each other and potential energy decreases. The atoms approach each other until the equilibrium stage is reached where the net force of attraction balances the force of repulsion and system acquires minimum energy. 

^–OCN is ambident ligand & it shows linkage isomerism.

The Effect of Catalysts on the Activation Energy Barrier. Catalysts provide a new reaction pathway in which a lower A.E. is offered. A catalyst increases the rate of a reaction by lowering the activation energy so that more reactant molecules collide with enough energy to surmount the smaller energy barrier.

(c) Close packing in two-dimensions can be Type I A A A ...... ty p e The second row may be ^ placed in contact with the first one such that the spheres of A the second row are exactly . above those of the first row.
The spheres of the two rows A are aligned horizontally as well as vertically. In this arrangement, each sphere is in contact with four of its neighbours.
Thus, its coordination number = 4 and is called square close packing in two-dimensions.
Atom A (•) is in contact with four others.

Type II ABAB... type The second row may be placed above the first in a staggered manner such that its spheres fit in the depressions of the first row.
First row arrangement: A type Second row arrangement: 8 type Third row arrangement: A type and so on There is less free space and packing is more efficient than the square close packing. Each sphere is in contact with six of its neighbours and coordination number = 6 in two-dimensions. It is called two dimensional hexagonal close-packing. Voids formed in this case are triangular in shape. If the apex of the triangles downward in the first row, it is upward in the second row.

The element with atomic number(Z) 17 & mass number (A) 35 is chlorine = 

Atomic no 24 is of Cr. Due to half filled orbital stability it doesnot follow Afbau rule so its configuration is 

(a) Edge length = a, Volume of one face = a³ Volume of six faces of a cube = 6a³ = V Radius = r

fee can be hexagonal closest packed (hep)

or cubic closest packed (ccp)

z = number of atoms in unit cell.

When both the solute and solvent are in solid state, then the solution is called a solid solution or solid sol.

Solid Sol includes gems, photochromic glass, alloys, ruby stone, coloured glass, vision glasses, etc.

Phosphinic acid is a monoprotic acid as it contains one P−OH bond while phosphonic acid is a diprotic acid as it contains two P−OH bonds.

The six noble gases are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). Their atomic numbers are, respectively, 2, 10, 18, 36, 54, and 86.

The number of elements for a matrix with the order m×n is equal to mn, where m is the number of rows and n is the number of columns in the matrix.

μ = (22 + 26 + 28 + 20 + 24 + 30)/6
= 150/6 
= 25
x(i) = (xi - μ)²
x(22) = (22-25)² = 9
x(26) = (26-25)² = 1
x(28) = (28-25)² = 9
x(20) = (20-25)² = 25
x(24) = (24-25)² = 1
x(30) = (30-25)² = 25
​
(xi - μ)²  = 70
Standard deviation : [(xi - μ)²]/N
= (70/6)^½
= 3.42

On comparing the given equations with: 
, we get: 

lim x→0 (1−cosx)/(xlog(1+x))
= lim x→0 {2sin² x/2}/[xlog(1+x)]
= lim x→0 {{2sin²x/2/(x/2)²}*/1/4}/[1/xlog(1+x)]
= lim x→0 [log(1+x)/x]1/2
= 2​

Arranging the given data in ascending order,
we have 34, 38, 42, 44, 46, 48, 54, 55, 63, 70
Here, Median M = (46+48)/2
=47
(∵ n = 10, median is the mean of 5th and 6th items)
∴ Mean deviation = ∑|xi−M|/n
=∑|xi−47|/10
= (13+9+5+3+1+1+7+8+16+23)/10
=8.6

n(S) = Total number of ways of pulling out socks

Let E be the event that they are of the same colour i.e. either both brown or both white.

Using trigonometric identities, we have
cos²x=cos²x-sin²x  -(1) and cos²x+sin²x =1 -(2)
cos²x=1-sin²x , substituting this in equation (1) we get 
cos²x=1-sin²x-sin²x=1-2sin²x
So,cos²x=1-2sin²x
2sin²x=1-cos²x