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COMEDK Mock Test - 4 - JEE MCQ


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30 Questions MCQ Test - COMEDK Mock Test - 4

COMEDK Mock Test - 4 for JEE 2025 is part of JEE preparation. The COMEDK Mock Test - 4 questions and answers have been prepared according to the JEE exam syllabus.The COMEDK Mock Test - 4 MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for COMEDK Mock Test - 4 below.
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COMEDK Mock Test - 4 - Question 1

A Carnot engine takes 5000 kcal of heat from a reservoir at 727°C and gives heat to a sink at 127°C. The work done by the engine is

Detailed Solution for COMEDK Mock Test - 4 - Question 1


⇒ W = 0.6Q = 3000 kcal = 12.6 × 106 J

COMEDK Mock Test - 4 - Question 2

Identify the pair of physical quantities that have same dimensions.

Detailed Solution for COMEDK Mock Test - 4 - Question 2


Decay constant λ has dimensions of [T-1] because of the relation dN/dt = -λN.
⇒ Velocity gradient and decay constant have same dimensions.

COMEDK Mock Test - 4 - Question 3

The stopping potential in the context of photoelectric effect depends on the following property of incident electromagnetic radiation:

Detailed Solution for COMEDK Mock Test - 4 - Question 3

Stopping potential changes linearly with frequency of the incident radiation.

COMEDK Mock Test - 4 - Question 4

An insulated container of gas has two chambers separated by an insulating partition. One of the chambers has volume V1 and contains ideal gas at pressure P1 and temperature T1. The other chamber has volume V2 and contains ideal gas at pressure P2 and temperature T2. If the partition is removed without doing any work on the gas, then the final equilibrium temperature of the gas in the container will be

Detailed Solution for COMEDK Mock Test - 4 - Question 4

As this is a simple mixing of gas, PV = nRT for adiabatic as well as isothermal changes.

The total number of molecules is conserved.

Final state = (n1 + n2)RT

COMEDK Mock Test - 4 - Question 5

Amplitude modulated wave is represented by VAM = 10[1 + 0.4cos(2π × 104t)] cos(2π × 107 t). The total bandwidth of the amplitude modulated wave is:

Detailed Solution for COMEDK Mock Test - 4 - Question 5

Bandwidth = 2 fm
= 2 × 104 Hz
= 20 × 103 Hz
= 20 kHz

COMEDK Mock Test - 4 - Question 6

A cylinder of fixed capacity of 44.8 litres contains helium gas at standard temperature and pressure. The amount of heat needed to raise the temperature of gas in the cylinder by 20.0°C will be:
(Given: gas constant R = 8.3 JK-1 mol-1)

Detailed Solution for COMEDK Mock Test - 4 - Question 6

No. of moles = 44.8/22.4 = 2
The gas is monatomic, so CV = 3/2 R.
ΔQ = nCvΔT
= 2 × 3/2 R × 20
= 60R
= 60 × 8.3
= 498 J

COMEDK Mock Test - 4 - Question 7

If , then the relative error in Z will be:

Detailed Solution for COMEDK Mock Test - 4 - Question 7


In case of error,

COMEDK Mock Test - 4 - Question 8

When ethanol is refluxed with conc. sulphuric acid at 160o it gives

COMEDK Mock Test - 4 - Question 9

Molarity of liquid HCl with density equal to 1.17 g/cc is

COMEDK Mock Test - 4 - Question 10

One mole of CO₂ contains

COMEDK Mock Test - 4 - Question 11

Which one of the following proteins transports oxygen in the blood stream?

COMEDK Mock Test - 4 - Question 12

White lead is

COMEDK Mock Test - 4 - Question 13

Orthophosphoric acid is

COMEDK Mock Test - 4 - Question 14

If a mixture containing 3 moles of hydrogen and 1 mole of nitrogen is converted completely into ammonia, the ratio of volumes of reactants and products at the same temperature and pressure would be

Detailed Solution for COMEDK Mock Test - 4 - Question 14

3H2 + N2 → 2NH3
∴ 3V 1V → 2V
Total initial volume = 3V + 1V = 4V
Final volume = 2V
Hence, ratio of initial and final volume will be 2 : 1

COMEDK Mock Test - 4 - Question 15

The equilibrium constant for the following reaction will be 3 A + 2 B → C

COMEDK Mock Test - 4 - Question 16

A system is said to be in thermodynamic equilibrium when it is in

COMEDK Mock Test - 4 - Question 17

If the truth values of statements p,q,r are True, True and False respectively

Statement-1: Statement ~(p∨q)∧(p∨~r)∧(~p∨~q) is false.

Statement-2: For given truth values ~(p∨q) is false, (p∨~r)  is true, (~p∨~q) is false.

Detailed Solution for COMEDK Mock Test - 4 - Question 17

We have,

Hence, statement − 1 is True, Statement −2 is True: Statement−2 is a correct explanation for Statement − 1.

COMEDK Mock Test - 4 - Question 18

The equation of the normal to the curve parametrically represented by x=t2+3t−8 and y=2t2−2t−5
 at the point P(2,−1)  is:

Detailed Solution for COMEDK Mock Test - 4 - Question 18

Given that

Now, we know that

The equation of normal to the curve y=f(x) at (x1, y1) is

COMEDK Mock Test - 4 - Question 19

Let f:(−∞,0]→[1,∞) be defined a  then f(x) is

Detailed Solution for COMEDK Mock Test - 4 - Question 19

Because of √-x, domain of the function is x ≤ 0.

It proves that the function is one-one. 

f(x) is one-one and range is same as co-domain.

So, the function is injective as well as surjective.

COMEDK Mock Test - 4 - Question 20

Tangents are drawn from the point (α,β) to the hyperbola 3x2−2y2=6 and are inclined at angles θ and ϕ to the X
-axis. If  tanθ⋅tanϕ=2, then β2−2α2=

Detailed Solution for COMEDK Mock Test - 4 - Question 20

Given hyperbola is 3x2−2y2=6

We know that, the tangent to the hyperbola with slope m is

Tangents passes through the point (α,β), hence, we have

The roots of this equation are m1 and m2
Hence, by using product of roots

COMEDK Mock Test - 4 - Question 21

If  then which of the following is not true

Detailed Solution for COMEDK Mock Test - 4 - Question 21

Given,

On differentiating the above function with respect to x we get,

f(x) has a point of maxima at x=0, because the sign of the function f′(x) changes from positive to negative.

⇒ f(x)=0 has a maxima at x=0.
Now, applying the second derivative test, 

We have taken x=0 already and x=3/4 is not true for [x2(3−4x),x<0]. Therefore, we have to take x=e−4.

Now,

f′′(x)=e4 is positive and by the definition of maxima-minima of a function, the minima is at x=e−4

Now, we want to check the continuity of the f(x) at x=0

Hence, the function is continuous at x=0 and therefore, continuous for x∈R.

Now, when

Therefore. f(x) takes all the values from −∞ to +∞. Hence, f(x) has range R.

COMEDK Mock Test - 4 - Question 22

if  are non-coplanar unit vectors such that  are non-parallel, then the angle between  is

Detailed Solution for COMEDK Mock Test - 4 - Question 22

COMEDK Mock Test - 4 - Question 23

 is equal to

Detailed Solution for COMEDK Mock Test - 4 - Question 23

COMEDK Mock Test - 4 - Question 24

Assuming the sum and the products given below are defined, which of the following is false for matrices?

Detailed Solution for COMEDK Mock Test - 4 - Question 24

So, option (4) is correct.

COMEDK Mock Test - 4 - Question 25

If n is not a multiple of 3 then ωn + ω2n =

COMEDK Mock Test - 4 - Question 26

The function f(x) = tan x/x for x ≠ 0 ; f (0) = 1 at x = 0 is

COMEDK Mock Test - 4 - Question 27

COMEDK Mock Test - 4 - Question 28

If f : R → R is defined by f x = 2 x + | x | then f (3x) − f (-x)   − 4 x =

COMEDK Mock Test - 4 - Question 29

If f(x)   = e -1/x2 , x ≠ 0, and f(0) = 0 then f ′(0)    is

Detailed Solution for COMEDK Mock Test - 4 - Question 29

COMEDK Mock Test - 4 - Question 30

∫[(1)/(4x2+9)]dx =

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