JEE Exam  >  JEE Tests  >  Test: Units & Measurement - 2 - JEE MCQ

Test: Units & Measurement - 2 - JEE MCQ


Test Description

30 Questions MCQ Test - Test: Units & Measurement - 2

Test: Units & Measurement - 2 for JEE 2024 is part of JEE preparation. The Test: Units & Measurement - 2 questions and answers have been prepared according to the JEE exam syllabus.The Test: Units & Measurement - 2 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Units & Measurement - 2 below.
Solutions of Test: Units & Measurement - 2 questions in English are available as part of our course for JEE & Test: Units & Measurement - 2 solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Units & Measurement - 2 | 30 questions in 30 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
Test: Units & Measurement - 2 - Question 1

Physical quantities are:

Detailed Solution for Test: Units & Measurement - 2 - Question 1
  • A physical quantity is a physical property of a phenomenon, body, or substance, that can be quantified by measurement.
  • A physical quantity can be expressed as the combination of a magnitude expressed by a number – usually a real number – and a unit.
  • All these given above can be expressed as explained so these are physical quantity.
Test: Units & Measurement - 2 - Question 2

If radian correction is not considered in specific heat measurement. The measured value of specific heat will be:

Detailed Solution for Test: Units & Measurement - 2 - Question 2

If radian correction is not considered in specific heat measurement. The measured value of specific heat will be more than its actual value.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Units & Measurement - 2 - Question 3

A new unit of length is chosen such that the speed of light in vacuum is unity. What is the distance between the Sun and the Earth in terms of the new unit if light takes 8 min and 20 s to cover this distance?

Detailed Solution for Test: Units & Measurement - 2 - Question 3

► Time can be converted as t = (8 x 60) + 20s = 500 seconds
► Now speed given= 1 unit
We know speed = Distance / Time
which implies distance = Speed x Time
Hence, the distance becomes 1 x 500 = 500 units.

Test: Units & Measurement - 2 - Question 4

The length, breadth and thickness of a rectangular sheet of metal are 4.234 m, 1.005 m, and 2.01 cm respectively. Give the volume of the sheet to correct significant figures.

Detailed Solution for Test: Units & Measurement - 2 - Question 4

Length , l = 4,234 m
Breadth, b = 1.005 m
Thickness , t = 2.01 x 10-2 m
Volume = l x b x t
⇒ V = 4.234 x 1.005 x 0.0201 = 0.0855289 = 0.0855 m3 (significant figure = 3)

Test: Units & Measurement - 2 - Question 5

The number of significant digits in 2,076 is:

Detailed Solution for Test: Units & Measurement - 2 - Question 5

There are three rules for determining how many significant figures are in a number: 

  • Non-zero digits are always significant.
  • Any zeros between two significant digits are significant.
  • A final zero or trailing zeros in the decimal portion ONLY are significant.

Keeping these rules in mind, we can say that there are 4 significant digits.

Test: Units & Measurement - 2 - Question 6

Measurement of a physical quantity is essentially the:

Detailed Solution for Test: Units & Measurement - 2 - Question 6

The Measurement of a given quantity is essentially an act or result of comparison between a quantity whose magnitude (amount) is unknown, with a similar quantity whose magnitude (amount) is known, the latter quantity being called a Standard.

Test: Units & Measurement - 2 - Question 7

The relative error in a physical quantity raised to the power k is:

Detailed Solution for Test: Units & Measurement - 2 - Question 7

The relative error in a physical quantity raised to the power k is the k times the relative error in the individual quantity.

Suppose Z = A2,
Then,
ΔZ/Z = (ΔA/A) + (ΔA/A) = 2 (ΔA/A).
Hence, the relative error in A2 is two times the error in A.

Test: Units & Measurement - 2 - Question 8

The number of significant digits in 0.007 is:

Detailed Solution for Test: Units & Measurement - 2 - Question 8

There are three rules on determining how many significant figures are in a number:

  • Non-zero digits are always significant.
  • Any zeros between two significant digits are significant.
  • A final zero or trailing zeros in the decimal portion ONLY are significant.

So, keeping these rules in mind, there are 1 significant digit.

Test: Units & Measurement - 2 - Question 9

The number of significant digits in 48,923 is:

Detailed Solution for Test: Units & Measurement - 2 - Question 9

There are three rules on determining how many significant figures are in a number: 

  • Non-zero digits are always significant.
  • Any zeros between two significant digits are significant.
  • A final zero or trailing zeros in the decimal portion ONLY are significant.

Keeping these rules in mind, we can say that there are 5 significant digits.

Test: Units & Measurement - 2 - Question 10

Unit for a fundamental physical quantity is:

Detailed Solution for Test: Units & Measurement - 2 - Question 10

Unit is the reference used as the standard measurement of a physical quantity.

  • The unit in which the fundamental quantities are measured are called fundamental unit.
  • Units used to measure derived quantities are called derived units.
Test: Units & Measurement - 2 - Question 11

The significant figures of a number ______.

Detailed Solution for Test: Units & Measurement - 2 - Question 11

Zeros occurring between non zero digits also contribute to the number accuracy and thus all the digits that contribute towards the accuracy of the number are considered significant.

Test: Units & Measurement - 2 - Question 12

The mass of a box measured by a grocer’s balance is 2.300 kg. Two gold pieces of masses 20.15 g and 20.17 g are added to the box. What is the difference in the masses of the pieces to correct significant figures?

Detailed Solution for Test: Units & Measurement - 2 - Question 12

Difference in masses = 20.17 – 20.15 = 0.02 g
In subtraction, the final result should retain as many decimal places as there are in the number with the least decimal places.

Test: Units & Measurement - 2 - Question 13

Horse power is unit of:

Detailed Solution for Test: Units & Measurement - 2 - Question 13
  • The horsepower (hp) is a unit in the foot-pound-second ( fps ) or English system, sometimes used to express the rate at which mechanical energy is expended.
  • It was originally defined as 550 foot-pounds per second (ft-lb/s).
  • A power level of 1 hp is approximately equivalent to 746 watt.
Test: Units & Measurement - 2 - Question 14

The number of significant digits in 8.1000 is:

Detailed Solution for Test: Units & Measurement - 2 - Question 14

Explanation

To determine the number of significant digits in the number 8.1000, we can follow a systematic approach based on the established rules of significant figures

 

1Identify non-zero digits. In the number 8.1000, the digits '8' and '1' are non-zero. According to the rules of significant figures, all non-zero digits are considered significant. Therefore, we have two significant digits from these numbers

2Examine the zeros. The zeros in the number 8.1000 need to be evaluated based on their position. The first zero appears after the '1', and since it is sandwiched between non-zero digits (1 and 0), it is significant

3Analyze trailing zeros. The last three zeros in 8.1000 come after the decimal point and follow the last non-zero digit (which is '1'). According to the rules, trailing zeros in a decimal number are significant. Therefore, these three zeros also count as significant digits

4Count the total significant digits. Adding the significant digits identified: 2 (from '8' and '1') + 1 (from the zero between '1' and '0') + 3 (trailing zeros) gives us a total of 5 significant digits

Test: Units & Measurement - 2 - Question 15

In SI system the fundamental units are:

Detailed Solution for Test: Units & Measurement - 2 - Question 15

The SI base units and their physical quantities are the metre for measurement of length, the kilogram for mass, the second for time, the ampere for electric current, the kelvin for temperature, the candela for luminous intensity, and the mole for amount of substance.

Test: Units & Measurement - 2 - Question 16

The dimensions of a physical quantity are:

Detailed Solution for Test: Units & Measurement - 2 - Question 16

The dimension of the units of a derived physical quantity may be defined as the number of times the fundamental units of mass, length and time appear in the physical quantity.

The expression for velocity obtained above is said to be its dimensional formula. Thus, the dimensional formula for velocity is [M0L1T​​​​​​-1].

Test: Units & Measurement - 2 - Question 17

The significant digits in 0.000532 are:

Detailed Solution for Test: Units & Measurement - 2 - Question 17

Significant Digits

Significant digits are the digits in a number that carry meaning contributing to its precision. They are used to indicate the reliability of a measurement.

Rules for determining significant digits:

  1. Non-zero digits are always significant.
  2. Zeros between non-zero digits are always significant.
  3. Leading zeros (zeros to the left of the first non-zero digit) are never significant.
  4. Trailing zeros in a number with a decimal point are significant.

Applying the rules to 0.000532:

  • The first non-zero digit is 5.
  • The digits following 5, which are 3 and 2, are non-zero and therefore significant.

So, the significant digits in 0.000532 are 5, 3, and 2.

The zeros before the 5 are leading zeros and do not contribute to the precision of the number, hence they are not significant.

Test: Units & Measurement - 2 - Question 18

One kilometer is equal to how many miles?

Detailed Solution for Test: Units & Measurement - 2 - Question 18

for an approximate result, divide the length value by 1.609

► One kilometer is equals to 0.62 miles.

Test: Units & Measurement - 2 - Question 19

Population of a town is reported as 157,900 . Which of the following statements correct?

Detailed Solution for Test: Units & Measurement - 2 - Question 19

157900  implies that the population is believed to be within the range of about 157850 to about 157950.

In other words, the population is 157900 ± 50. The “plus-or-minus 50” appended to this number means that we consider the absolute uncertainty of the population measurement to be 50 – (–50) = 100.

We can also say that the relative uncertainty is 100/157900, which we can also express as 1 part in 1579, or 1/1579 = 0.000633, or about 0.06 percent.

Test: Units & Measurement - 2 - Question 20

Derived units:

Detailed Solution for Test: Units & Measurement - 2 - Question 20

Derived units are units which may be expressed in terms of base units by means of mathematical symbols of multiplication and division.
Example: the SI derived unit of area is the square metre (m​​​​​​2), and the SI derived unit of density is the kilogram per cubic metre (kg/m3 or kg m​​​​​​-3).

The names of SI units are written in lowercase.

Test: Units & Measurement - 2 - Question 21

According to the principle of homogeneity of dimensions:

Detailed Solution for Test: Units & Measurement - 2 - Question 21

It would be more exact to say that "Quantities with the same units can be added and subtracted with no problem."

Quantities with the same dimensions can often be added and subtracted as long as the units are correctly converted.

Test: Units & Measurement - 2 - Question 22

There are 20 divisions in 4 cm of the main scale. The vernier scale has 10 divisions. The least count of the instrument is:

Detailed Solution for Test: Units & Measurement - 2 - Question 22

There are 20 divisions in 4 cm of main scale
⇒ 1 cm of main scale will have 20/4 = 5 divisions

Thus,  1 MSD  = 1/5 = 0.2 cm Vernier scale has 10 divisions 
Thus, L.C. = 0.2/10 = 0.02 cm 

Test: Units & Measurement - 2 - Question 23

Joule is the SI unit of:

Detailed Solution for Test: Units & Measurement - 2 - Question 23

The joule (symbol J), is a derived unit of energy in the International System of Units.

It is equal to the energy transferred to (or work done on) an object when a force of one newton acts on that object in the direction of its motion through a distance of one metre (1 newton metre or N⋅m).

Test: Units & Measurement - 2 - Question 24

If an equation is dimensionally consistent:

Detailed Solution for Test: Units & Measurement - 2 - Question 24

The principle of homogeneity of dimensions states that “For an equation to be dimensionally correct, the dimensions of each term on LHS must be equal to the dimensions of each term on RHS.”

Test: Units & Measurement - 2 - Question 25

An object has a length of 0.42 cm. Which of the following statements correct?

Detailed Solution for Test: Units & Measurement - 2 - Question 25

As no indication of its precision is given. In this case, all we have to go on is the number of digits contained in the data.

Thus the quantity “0.42 cm” is specified to 0.01 unit in 0.42, or one part in 42.

The implied relative uncertainty in this figure is 1/42, or about 2%.

Test: Units & Measurement - 2 - Question 26

The least count of any measuring equipment is:

Detailed Solution for Test: Units & Measurement - 2 - Question 26

The smallest value that can be measured by the measuring instrument is called its least count.

Measured values are good only up to this value. The least count error is the error associated with the resolution of the instrument.

Test: Units & Measurement - 2 - Question 27

Dimensional analysis can be used to:

Detailed Solution for Test: Units & Measurement - 2 - Question 27

Dimensional Analysis (also called Factor-Label Method or the Unit Factor Method) is a problem-solving method that uses the fact that any number or expression can be multiplied by one without changing its value. It is a useful technique.

Another use of dimensional analysis is in checking the correctness of an equation which you have derived after some algebraic manipulation. Even a minor error in algebra can be detected because it will often result in an equation which is dimensionally incorrect.

Test: Units & Measurement - 2 - Question 28

The result of rounding off 34.216 to 3 digits is:

Detailed Solution for Test: Units & Measurement - 2 - Question 28

The rules for rounding off are following:

  • If the first non-significant digit is less than 5, then the least significant digit remains unchanged.
  • If the first non-significant digit is greater than 5, the least significant digit is incremented by 1.
  • If the first non-significant digit is 5, the least significant digit can either be incremented or left unchanged.
  • All non-significant digits are removed.

So rounding off 34.216 upto 4 digits is 34.22 and upto 3 digits is 34.2

Test: Units & Measurement - 2 - Question 29

Resolution is:

Detailed Solution for Test: Units & Measurement - 2 - Question 29

Resolution is the smallest amount of input signal change that the instrument can detect reliably. This term is determined by the instrument noise (either circuit or quantization noise).

Test: Units & Measurement - 2 - Question 30

A dimensionally consistent equation:

Detailed Solution for Test: Units & Measurement - 2 - Question 30

If an equation fails this consistency test, it is proved wrong, but if it passes, it is not proved right.

Thus, a dimensionally correct equation need not be actually an exact (correct) equation, but a dimensionally wrong (incorrect) or inconsistent equation is definitely wrong.

Information about Test: Units & Measurement - 2 Page
In this test you can find the Exam questions for Test: Units & Measurement - 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Units & Measurement - 2, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE