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CAT Exam  >  CAT Tests  >  Test Level 2: Caselets - 1 (August 29) - CAT MCQ

Test Level 2: Caselets - 1 (August 29) - CAT MCQ


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10 Questions MCQ Test - Test Level 2: Caselets - 1 (August 29)

Test Level 2: Caselets - 1 (August 29) for CAT 2024 is part of CAT preparation. The Test Level 2: Caselets - 1 (August 29) questions and answers have been prepared according to the CAT exam syllabus.The Test Level 2: Caselets - 1 (August 29) MCQs are made for CAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test Level 2: Caselets - 1 (August 29) below.
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Test Level 2: Caselets - 1 (August 29) - Question 1
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Directions: Study the given information and answer the following question.
A talent hunt competition was being conducted by a TV Channel. As they were expecting variations in the type of talent, they appointed 7 different judges: Karan Johar, Geeta Basra, Himesh Reshamia, Anu Malik, Mika, Farah Khan and Pritam. In the first round, 6 contestants namely Rahul, Reema, Ram, Rita, Raju and Riya appeared before the panel for selection. Accidentally, the organisers forgot to mention the marks for which they were to be evaluated; therefore, each of the judges evaluated the contestants on a different total marks. The total marks for which the judges evaluated all the contestant were 100, 150, 50, 125, 150, 50 and 75 in the exact order of judges as mentioned above, respectively. The table mentioned below presents the percentage score of the contestants by each of the judges.

Q. What is the approximate average percentage of marks given by Karan Johar?

Detailed Solution for Test Level 2: Caselets - 1 (August 29) - Question 1

Total marks of Reema = 583
x% × 100 + 88% × 150 + 74% × 50 + 64% × 125 + 92% × 150 + 94% × 50 + 84% × 75 = 583
So, x + (88 + 44) + 37 + (64 + 16) + (92 + 46) + 47 + 63 = 583
So, x + 497 = 583
So, x = 583 - 497 = 86%
Now, average percentage of marks given by Karan Johar = (92 + 86 + 95 + 88 + 78 + 82)/6 = 521/6 = 87% (Approx)

Test Level 2: Caselets - 1 (August 29) - Question 2
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Directions: Study the given information and answer the following question.
A talent hunt competition was being conducted by a TV Channel. As they were expecting variations in the type of talent, they appointed 7 different judges: Karan Johar, Geeta Basra, Himesh Reshamia, Anu Malik, Mika, Farah Khan and Pritam. In the first round, 6 contestants namely Rahul, Reema, Ram, Rita, Raju and Riya appeared before the panel for selection. Accidentally, the organisers forgot to mention the marks for which they were to be evaluated; therefore, each of the judges evaluated the contestants on a different total marks. The total marks for which the judges evaluated all the contestant were 100, 150, 50, 125, 150, 50 and 75 in the exact order of judges as mentioned above, respectively. The table mentioned below presents the percentage score of the contestants by each of the judges.

Q. If the marks given by Mika and by Anu Malik to Ram are in the ratio of 3 : 2, then the marks given by Mika to Ram are what percentage of the marks given to Raju by Mika?

Detailed Solution for Test Level 2: Caselets - 1 (August 29) - Question 2

Total Marks obtained by Ram = 536
Sum of Marks Given by all Judges = 536
Ratio of marks given by Mika and Anu Malik = 3 : 2.
Let Marks given by Mika and Anu Malik be 3x and 2x, respectively.
Therefore, 95% × 100 + 70% × 150 + 86% × 50 + 3x + 2x + 96% × 50 + 60% × 75 = 536
So, 95 + 105 + 43 + 5x + 48 + 45 = 536
So, 336 + 5x = 536
So, x = 40
Therefore, marks obtained by Ram through Mika = 3 × 40 = 120
Marks given to Raju by Mika = 88% of 150 = 132
Therefore, Percentage of Ram's marks to Raju's marks as given by Mika = (120/132) × 100 = 90.9%

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Test Level 2: Caselets - 1 (August 29) - Question 3
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Directions: Study the given information carefully to answer the question that follows:
In a college, there are 2400 students studying in different branches - Electronics, Mechanical, Electrical, IT, and Computer Science. The ratio of the number of boys to that of girls is 5 : 3. 12% boys study in the Electronics branch. 24% girls study in the Mechanical branch. The ratio of the number of boys to that of girls in the Electronics branch is 6 : 11. One-ninth of girls study in the Computer Science branch. 42% boys study in the IT branch. The number of girls studying in the IT branch is 10% of the boys studying in the same branch. The remaining girls study in the Electrical branch. The total number of students studying in the Computer Science branch is 285. 22% boys study in the Electrical branch. The remaining boys study in the Mechanical branch.

Q. What is the number of girls studying in the IT branch?

Detailed Solution for Test Level 2: Caselets - 1 (August 29) - Question 3

Total number of students = 2400
Ratio of the number of boys to that of girls = 5 : 3
Number of boys = (5/8) x 2400 = 1500
Number of girls = (3/8) x 2400 = 900
42% boys studying in IT = 42% of 1500 = 630
The number of girls studying in IT is 10% of the boys studying in the same branch = 10% of 630 = 63

Test Level 2: Caselets - 1 (August 29) - Question 4
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Directions: Study the given information carefully to answer the question that follows:
In a college, there are 2400 students studying in different branches - Electronics, Mechanical, Electrical, IT, and Computer Science. The ratio of the number of boys to that of girls is 5 : 3. 12% boys study in the Electronics branch. 24% girls study in the Mechanical branch. The ratio of the number of boys to that of girls in the Electronics branch is 6 : 11. One-ninth of girls study in the Computer Science branch. 42% boys study in the IT branch. The number of girls studying in the IT branch is 10% of the boys studying in the same branch. The remaining girls study in the Electrical branch. The total number of students studying in the Computer Science branch is 285. 22% boys study in the Electrical branch. The remaining boys study in the Mechanical branch.

Q. What is the total number of girls studying in the Electronics and Electrical branches?
Detailed Solution for Test Level 2: Caselets - 1 (August 29) - Question 4

Total number of students = 2400
Ratio of the number of boys to that of girls = 5 : 3
Number of boys = (5/8) × 2400 = 1500
Number of girls = (3/8) × 2400 = 900
12% boys studying in Electronics = 12% of 1500 = 180
24% girls studying in Mechanical = 24% of 900 = 216
Ratio of the number of boys to that of girls in Electronics = 6 : 11
Number of girls studying in Electronics = 11 × 30 = 330 [Number of boys studying in Electronics = 180]
One-ninth of girls studying in Computer Science = (1/9) × (900) = 100
42% boys studying in IT = 42% of 1500 = 630
The number of girls studying in IT is 10% of the boys studying in the same branch = 10% of 630 = 63
The remaining girls are studying in Electrical = 900 - (216 + 330 + 100 + 63) = 191
Total number of students studying in Computer Science = 285
Number of boys studying in Computer science branch = 285 - 100 = 185
22% boys studying in Electrical = 22% of (1500) = 330
Number of boys studying in Mechanical = 1500 - (180 + 100 + 630 + 185 + 330) = 75
Total number of girls studying in Electronics and Electrical = 330 + 191 = 521

Test Level 2: Caselets - 1 (August 29) - Question 5
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Directions: Read the following information and answer the question that follows.

Four actresses - Deepita, Anishka, Kiara and Shrashta have dedicated some of their crew members to look after their public relations image in some top news agencies - Paradigm, Zeanal, Suncast, Brewner, Regal, Tialife and Aborf.

  • Not more than 9 crew members are dedicated to one agency by any actress.
  • Deepita and Shrashta have dedicated the greatest number of crew members an actress can send to Tialife and Zeanal, respectively.
  • Anishka, Kiara and Shrashta have dedicated 4, 5 and 2 members less than the number of crew members dedicated by Deepita to Tialife.
  • Sum of crew members of Deepita dedicated to Tialife and to Suncast is 17.
  • Number of crew members of Anishka dedicated to Regal, Kiara dedicated to Aborf and Shrashta dedicated to Paradigm as well as to Aborf is the same as the number of crew members of Deepita dedicated to Suncast.
  • Number of crew members of Shrashta dedicated to Tialife and to Suncast is the same and the number of crew members of Shrashta dedicated to Suncast and to brewner are consecutive numbers.
  • Number of crew members of Deepita, Anishka, Kiara and Shrashta dedicated to Brewner, Paradigm, Paradigm and Brewner, respectively is the same.
  • Sum of crew members of Shrashta dedicated to Brewner and to Regal is 11.
  • Shrashta has the greatest number of crew members dedicated to news agencies, while Deepita has 6 less and Kiara has 15 less.
  • Number of crew members dedicated by Shrashta to Regal is the same as the number of crew members of Kiara dedicated to Suncast and of Deepita dedicated to Paradigm.
  • Deepita has 7 members each, dedicated both to Zeanal and to Aborf.
  • Anishka has 10 crew members less than Deepita.
  • Crew members of Deepita dedicated to Aborf are the same as the crew members of Anishka dedicated to Brewner.
  • Anishka has 3 and 4 members dedicated to Zeanal and to Suncast, respectively. Kiara has 2 and 7 members dedicated to Zeanal and to Regal, respectively.
  • Number of crew members of Deepita dedicated to Regal is not the same as the number of crew numbers of Anishka dedicated to Aborf.

​​​​​​​Q. What is the difference between sum of crew members of Deepita and Anishka dedicated to Brewner and sum of crew members of Kiara and Shrashta dedicated to Aborf?
Detailed Solution for Test Level 2: Caselets - 1 (August 29) - Question 5

Tabulating the given information, we get

Sum of number of crew members of Deepita and Anishka dedicated to Brewner = 6 + 7 = 13
Sum of number of crew members of Kiara and Shrashta dedicated to Aborf = 8 + 8 = 16
Difference between both = 16 - 13 = 3

Test Level 2: Caselets - 1 (August 29) - Question 6
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Directions: Read the following information and answer the question that follows.

Four actresses - Deepita, Anishka, Kiara and Shrashta have dedicated some of their crew members to look after their public relations image in some top news agencies - Paradigm, Zeanal, Suncast, Brewner, Regal, Tialife and Aborf.

  • Not more than 9 crew members are dedicated to one agency by any actress.
  • Deepita and Shrashta have dedicated the greatest number of crew members an actress can send to Tialife and Zeanal, respectively.
  • Anishka, Kiara and Shrashta have dedicated 4, 5 and 2 members less than the number of crew members dedicated by Deepita to Tialife.
  • Sum of crew members of Deepita dedicated to Tialife and to Suncast is 17.
  • Number of crew members of Anishka dedicated to Regal, Kiara dedicated to Aborf and Shrashta dedicated to Paradigm as well as to Aborf is the same as the number of crew members of Deepita dedicated to Suncast.
  • Number of crew members of Shrashta dedicated to Tialife and to Suncast is the same and the number of crew members of Shrashta dedicated to Suncast and to brewner are consecutive numbers.
  • Number of crew members of Deepita, Anishka, Kiara and Shrashta dedicated to Brewner, Paradigm, Paradigm and Brewner, respectively is the same.
  • Sum of crew members of Shrashta dedicated to Brewner and to Regal is 11.
  • Shrashta has the greatest number of crew members dedicated to news agencies, while Deepita has 6 less and Kiara has 15 less.
  • Number of crew members dedicated by Shrashta to Regal is the same as the number of crew members of Kiara dedicated to Suncast and of Deepita dedicated to Paradigm.
  • Deepita has 7 members each, dedicated both to Zeanal and to Aborf.
  • Anishka has 10 crew members less than Deepita.
  • Crew members of Deepita dedicated to Aborf are the same as the crew members of Anishka dedicated to Brewner.
  • Anishka has 3 and 4 members dedicated to Zeanal and to Suncast, respectively. Kiara has 2 and 7 members dedicated to Zeanal and to Regal, respectively.
  • Number of crew members of Deepita dedicated to Regal is not the same as the number of crew numbers of Anishka dedicated to Aborf.

Q. What is the sum of all the crew members of Anishka, Kiara and Shrashta?
Detailed Solution for Test Level 2: Caselets - 1 (August 29) - Question 6

Tabulating the given information, we get

Sum of all crew members of Anishka, Kiara and Shrashta = 34 + 35 + 50
Total crew members of Anishka, Kiara and Shrashta = 119

Test Level 2: Caselets - 1 (August 29) - Question 7
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Directions: Answer the question on the basis of the information given below.
Anisha has a big collection of tops. The top with her is of one or the other of the four brands namely Being Humane, Diesel, Fashion and Levis. The colour of the tops with her is either pink or green. Out of the tops with her, Anisha has bought only a few of them whereas the rest are gifted to her by one or the other of her six friends namely Ankita, Rajkumari, Usha, Hanshika, Sunita and Soha. Anisha does not know the exact number of tops gifted to her but she knows that the number of green tops of each brand gifted to her by each of her mentioned friends is at least 3 and at most 18. Further, the number of pink tops of each brand gifted to her by each of his mentioned friends is at least 7 and at most 25.

Anisha asked her boyfriend to help her determine the number of tops gifted to her by each of her mentioned friends. In turn, her boyfriend provided her with the information listed in the table given below:

Q. If the total number of tops with Anisha is 750 and the total number of tops bought by Anisha is the same as the total number of tops gifted to her by Ankita, then what is the least number of tops with Anisha that are neither bought by her nor gifted to her by Ankita?
Detailed Solution for Test Level 2: Caselets - 1 (August 29) - Question 7

It is given that the number of tops bought by Anisha is same as the total number of tops gifted to her by Ankita.
Therefore, at least 750 – 2 × 127 = 496 tops are there with Anisha that are neither bought by her nor gifted to her by Ankita.

Test Level 2: Caselets - 1 (August 29) - Question 8
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Directions: Answer the question on the basis of the information given below.
Anisha has a big collection of tops. The top with her is of one or the other of the four brands namely Being Humane, Diesel, Fashion and Levis. The colour of the tops with her is either pink or green. Out of the tops with her, Anisha has bought only a few of them whereas the rest are gifted to her by one or the other of her six friends namely Ankita, Rajkumari, Usha, Hanshika, Sunita and Soha. Anisha does not know the exact number of tops gifted to her but she knows that the number of green tops of each brand gifted to her by each of her mentioned friends is at least 3 and at most 18. Further, the number of pink tops of each brand gifted to her by each of his mentioned friends is at least 7 and at most 25.

Anisha asked her boyfriend to help her determine the number of tops gifted to her by each of her mentioned friends. In turn, her boyfriend provided her with the information listed in the table given below:

Q. If out of the pink tops gifted to Anisha by Ankita, Usha and Sunita, the number of tops of brand 'Fashion' is 4 more than the number of tops of brand 'Levis', then what is the number of pink tops of brand 'Levis' gifted to Anisha by Sunita?
Detailed Solution for Test Level 2: Caselets - 1 (August 29) - Question 8

The following table lists down the range of the total number of pink tops of brands 'Fashion' and 'Levis' gifted to Anisha by her mentioned friends.

It is given that out of the pink tops gifted to Anisha, the number of tops of brand 'Fashion' is 4 more than the number of tops of brand 'Levis'.
The only possibility is that the number of pink tops of brands 'Fashion' and 'Levis' gifted to Anisha by her mentioned friends is 35 and 31, respectively.
Therefore, the number of pink tops of brand 'Levis' gifted to Anisha by Sunita is 13.

Test Level 2: Caselets - 1 (August 29) - Question 9
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Directions: Read the following information carefully to answer the question given thereafter.
5500 candidates from four different cities A, B, C and D have cleared the bank exam. 500 male candidates from city A have cleared the exam. The number of male candidates who cleared the exam from city C is $11%5Cfrac%7B1%7D%7B9%7D$% less than that of male candidates who cleared the exam from city D. The total number of candidates who cleared the exam from city A is 250 less than the total number of candidates who cleared the exam from city B. The ratio of number of female students from city C who have cleared the exam to the total number of students from city D who have cleared the exam is 16 : 31. The total number of candidates who have cleared the exam from city D is 100 less than 3 times the number of female candidates from city A who have cleared the exam. 650 female candidates from city D have cleared the exam. The number of female candidates from cities A, B, C and D who have cleared the exam is 100 less than number of male candidates from cities A, B, C and D who have cleared the exam. The number of male candidates who cleared the exam from city B is 20% more than number of male candidates who cleared the exam from city A.

Q. How many male candidates from city C have cleared the exam?
Detailed Solution for Test Level 2: Caselets - 1 (August 29) - Question 9

Let number of male candidates from city C who have cleared the exam = 8x
Let number of female candidates from city C who have cleared the exam = 16z
Let total number of candidates from city A who have cleared the exam = y
Total number of candidates from city B who have cleared the exam = y + 250
Number of candidates from city D who have cleared the exam = 31z

The following table can be drawn as per the given information:

The total number of female candidates from all 4 cities who have cleared the exam is 100 less than the number of male candidates from all cities who have cleared the exam.
Let total number of female candidates from all 4 cities who have cleared the exam = a
Total number of male candidates from all 4 cities who have cleared the exam = a + 100
So,
a + a + 100 = 5500
a = 2700
a + 100 = 2800
Also,
500 + 600 + 8x + 9x = 2800
17x = 1700
x = 100
9x + 650 = 31z
Since x = 100,
z = 50
y = 1050
So, the table can be redrawn as follows:

Hence, number of male candidates from city C who have cleared the exam = 800

Test Level 2: Caselets - 1 (August 29) - Question 10
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Directions: Read the following information carefully to answer the question given thereafter.
5500 candidates from four different cities A, B, C and D have cleared the bank exam. 500 male candidates from city A have cleared the exam. The number of male candidates who cleared the exam from city C is $11%5Cfrac%7B1%7D%7B9%7D$% less than that of male candidates who cleared the exam from city D. The total number of candidates who cleared the exam from city A is 250 less than the total number of candidates who cleared the exam from city B. The ratio of number of female students from city C who have cleared the exam to the total number of students from city D who have cleared the exam is 16 : 31. The total number of candidates who have cleared the exam from city D is 100 less than 3 times the number of female candidates from city A who have cleared the exam. 650 female candidates from city D have cleared the exam. The number of female candidates from cities A, B, C and D who have cleared the exam is 100 less than number of male candidates from cities A, B, C and D who have cleared the exam. The number of male candidates who cleared the exam from city B is 20% more than number of male candidates who cleared the exam from city A.

Q. Out of the total candidates selected from city A, what percent were females?
Detailed Solution for Test Level 2: Caselets - 1 (August 29) - Question 10

Let number of male candidates from city C who have cleared the exam = 8x
Let number of female candidates from city C who have cleared the exam = 16z
Let total number of candidates from city A who have cleared the exam = y
Total number of candidates from city B who have cleared the exam = y + 250
Number of candidates from city D who have cleared the exam = 31z

The following table can be drawn as per the given information:

The total number of female candidates from all 4 cities who have cleared the exam is 100 less than the number of male candidates from all cities who have cleared the exam.
Let total number of female candidates from all 4 cities who have cleared the exam = a
Total number of male candidates from all 4 cities who have cleared the exam = a + 100
So,
a + a + 100 = 5500
a = 2700
a + 100 = 2800
Also,
500 + 600 + 8x + 9x = 2800
17x = 1700
x = 100
9x + 650 = 31z
Since x = 100,
z = 50
y = 1050
So, the table can be redrawn as follows:

Total candidates selected from city A = 1050
Required percent of females = 550 × (100/1050) = 52.38%

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