KVS PGT Physics Mock Test - 2 - KVS PGT/TGT/PRT MCQ

The correct answer is Option 2, i.e., ‘spare’.
The word ‘castigate’ means ‘to subject to severe punishment.’ The word ‘spare’ has an opposite meaning of ‘to choose not to punish.’ Hence, the correct option is Option 2.

The error is in part 2 of the sentence. The sentence is in past tense and therefore the verb 'find' is incorrectly used. The correct form of the verb 'find' would be 'found'.

• 'मत्स्य' का पर्यायवाची है - मीन।
• मत्स्य शब्द के अन्य पर्यायवाची शब्द - जलजीवन, शफरी, मकर, मछली।

Key Points

अन्य विकल्प-

Additional Informationपर्यायवाची शब्द के अन्य उदाहरण -

• बहुवचन - कबूतर
• समानार्थी शब्द - कपोत
• लिंग - पुल्लिंग
• संज्ञा के प्रकार - जातिवाचक

चिड़िया

• बहुवचन - चिड़ियाँ
• समानार्थी शब्द - पंछी , पक्षी , परिंदा
• लिंग - स्त्रीलिंग
• संज्ञा के प्रकार - जातिवाचक

कोयल

• बहुवचन - कोयलें
• समानार्थी शब्द - कोकिल , कोकिला
• लिंग - स्त्रीलिंग
• संज्ञा के प्रकार - जातिवाचक

कौआ

• समानार्थी शब्द - काग , काक , कौवा
• विलोम शब्द - कौवी , कौवी
• लिंग - पुल्लिंग

The correct answer is Odisha.

Key Points

• The Tropic of Cancer is an imaginary line north from the Equator at an angle of 23.50 degrees.
• Tropic of Cancer passes through 16 countries, 3 continents, and 6 water bodies.
• It passes through 8 Indian states.
  

Additional Information

As the plane is frictionless, thus there will be only slipping and no rolling. So, for all of them acceleration will be ‘gsinθ’

Volume of water = Volume of the tank = Length * breadth * height = 5.6 * 8.2 * 12.8 = 587.776

Volume, correct up to 4 significant figure = 587.8

Let the tension between B and C be T

M=2kg

F−T=ma

10.2−T=ma

10.2−T=2×0.6

10.2−T=1.2

10.2−1.2=T

T=9N

If the TE = 0 that means KE + PE = 0
KE = - PE which is enough for the body to leave the system (here, Earth)

Let R be the normal contact force by wall on the block.

R = 10 N
f_L = w and f = μR
∴ μR = w
or w = 0.2 x 10 = 2N

Explanation:By convention phasor diagrams are made to show the rotation of phasor in counterclockwise direction with constant speed

CONCEPT:

• Angular velocity (ω): How fast the angular position or orientation of an object changes with time or How fast an object rotates or revolves relative to another point is known as angular velocity.
  • Angular velocity in terms of RPM (revolutions per minute) 

ω = 2 π f / 60

where ω is in terms of radian per second and f is in revolution per minute.

• Angular acceleration (α): The rate of change of angular velocity is known as angular acceleration.

The relation between α and changing ω is given by: 

ω₁ = ω₀ + α t

where ω₁ is the final angular velocity, ω₀ is the initial angular velocity α is the angular acceleration.

CALCULATION:

Given that f₀ = 2100 rpm; f₁ = 0 rpm; t = 2 sec.

ω₀ = 2 π f₀ / 60 = 2 π 2100 / 60 = 70π 

ω₁ = 0

ω₁ = ω₀ + α t

0 = 70π + α 2

α = -35π rad/sec²

So the correct answer is option 1.

We know, the gravitational force 
,
This is valid when R is the centre to centre distance between the two masses M and m.
At a distance r < R, the mass of Earth cannot be taken as M.

The new mass (M'):
The mass of earth will be contained for a radius r. Let us assume that the mean density of the earth is ρ and that earth is a sphere with a radius equal to the distance r. We know, mass = density × volume

Therefore the gravitational force, F = 

Hence the gravitational force, F ∝ r

A vertical plane passing through the axis of a freely suspended or pivoted magnet is known as magnetic meridian of Earth. The vertical plane passing through the geographical North Pole and South Pole at a given place is known as the geographical meridian of that place.

Second law of motion gives:

There are three rules for determining how many significant figures are in a number: 

• Non-zero digits are always significant.
• Any zeros between two significant digits are significant.
• A final zero or trailing zeros in the decimal portion ONLY are significant.

Keeping these rules in mind, we can say that there are 4 significant digits.

The First minimum is located at the place where the central maximum ends. And the first minimum spreads further upto half the fringe width.

We know that PE + KE = TE = constant
Hence at the extremis TE = PE = ½ kz²  
Where z is amplitude and k is shm constant.
Thus when KE = ⅓ PE
We get PE = ¾ TE =  ½ kz²
Hence we get  ½ kx² = ¾  ½ kz²
We get x/z = √3/4 
= 1.73 / 2
= .87
Thus we get x is 87 percent of the amplitude.

Area under F-t curve = change in momentum = 2 x (-2) + 1 x 4 = -4 + 4 = 0  

The difterent torces acting on mass m are shown in the adjoining figure. Acceleration of the system

We know that,
Phase difference=K× path difference. K=2π/ λ.
Therefore, phase difference=(2π/ λ) ×( λ/3)=2π/3=120 degree.

In case of a meter bridge

For finding the value of R

For finding the value of ΔR

Therefore, R = (60 ± 0.25)Ω

Explanation:atomic hypothesis that all things are made of atoms—little particles that move around in perpetual motion, attracting each other when they are a little distance apart, but repelling upon being squeezed into one another.

The relative error in a physical quantity raised to the power k is the k times the relative error in the individual quantity.

Suppose Z = A²,
Then,
ΔZ/Z = (ΔA/A) + (ΔA/A) = 2 (ΔA/A).
Hence, the relative error in A² is two times the error in A.

The Measurement of a given quantity is essentially an act or result of comparison between a quantity whose magnitude (amount) is unknown, with a similar quantity whose magnitude (amount) is known, the latter quantity being called a Standard.

• We know that with retardation of a car with an initial speed of 60 kmph stops after 20m.
• We know that v² = 2as  (third equation of motion). Thus we get that for some constant retardation, stopping distance is proportional to the square of the initial speed.
• Hence when the initial speed is 120kmph we get,
  s = 20 x (120/60)²
  s = 80 m

Explanation:A displacement is vector that is the shortest path length from the initial to the final position of the body. It is not always eqaul to path length. It can be zero and -ve also.

Magnetic field due to current in wire 1 at point P distant r from the wire is

 (directed perpendicular to the plane  of paper, inwards)

The force exerted due to this magnetic field on current element i₂ dl is

dF = i₂ dl B sin 90°