KVS PGT/TGT/PRT Exam  >  KVS PGT/TGT/PRT Tests  >  KVS PGT Chemistry Mock Test - 3 - KVS PGT/TGT/PRT MCQ

KVS PGT Chemistry Mock Test - 3 - KVS PGT/TGT/PRT MCQ


Test Description

30 Questions MCQ Test - KVS PGT Chemistry Mock Test - 3

KVS PGT Chemistry Mock Test - 3 for KVS PGT/TGT/PRT 2024 is part of KVS PGT/TGT/PRT preparation. The KVS PGT Chemistry Mock Test - 3 questions and answers have been prepared according to the KVS PGT/TGT/PRT exam syllabus.The KVS PGT Chemistry Mock Test - 3 MCQs are made for KVS PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for KVS PGT Chemistry Mock Test - 3 below.
Solutions of KVS PGT Chemistry Mock Test - 3 questions in English are available as part of our course for KVS PGT/TGT/PRT & KVS PGT Chemistry Mock Test - 3 solutions in Hindi for KVS PGT/TGT/PRT course. Download more important topics, notes, lectures and mock test series for KVS PGT/TGT/PRT Exam by signing up for free. Attempt KVS PGT Chemistry Mock Test - 3 | 180 questions in 180 minutes | Mock test for KVS PGT/TGT/PRT preparation | Free important questions MCQ to study for KVS PGT/TGT/PRT Exam | Download free PDF with solutions
KVS PGT Chemistry Mock Test - 3 - Question 1

संधि की दृष्टि से असुमेलित का चयन कीजिए -

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 1

सही उत्तर 'लोक + एषण = लोकएषणा' है।

Key Points
  • दिए गए विकल्पों में असुमेलित 'लोक + एषण = लोकएषणा' है।
  • 'लोक + एषणा' का सही सुमेल 'लोकैषणा (अ + ए = ऐ)' होता है।
  • यह 'वृद्धि स्वर संधि' का उदाहरण है।
  • इसमें अ या आ के बाद ए या ऐ आए तो ‘ऐ’ और ओ और औ आए तो औ हो जाता हो।

अन्य विकल्प-

  • मातृ + इच्छा = मात्रिच्छा - यण स्वर संधि
  • लघु + उत्तर = लघूत्तर - दीर्घ स्वर संधि
  • सु + समा = सुषमा - व्यंजन स्वर संधि

Additional Information

KVS PGT Chemistry Mock Test - 3 - Question 2

नीचे दिए गए शब्दों का सही संधि वाला विकल्प पहचानिए?

धर्म + अर्थ

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 2

सही उत्तर धर्मार्थ है।

Key Points

  • धर्म + अर्थ= धर्मार्थ
  • नियम- अ + अ= आ
  • धर्मार्थ में "दीर्घ स्वर संधि" है।
  • धर्मार्थ शब्द का अर्थ- धर्म हेतु किया गया।
  • उदाहरण- सेठजी कोई भी काम धर्मार्थ करते हैं।

Additional Informationसंधि - दो शब्दों के मेल से जो विकार (परिवर्तन) होता है उसे संधि कहतेहैं।
संधि के तीन प्रकार हैं - 1. स्वर, 2. व्यंजन और 3. विसर्ग

1 Crore+ students have signed up on EduRev. Have you? Download the App
KVS PGT Chemistry Mock Test - 3 - Question 3

Who determines the minimum support price in India?

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 3

The correct answer is The Commission for Agricultural Costs and Prices.

  • Based on the recommendations of the Commission for Agricultural Costs and Prices, the Department of Agriculture and Co-operation, Government of India, declares Minimum Support Prices (MSP) for 22 crops before their sowing seasons.

Key Points

  • The CACP is an attached office of the Ministry of Agriculture and Farmers Welfare, formed in 1965.
  • It is a statutory body that offers separate reports recommending prices for Kharif and Rabi seasons.

Additional Information

  • Cost of farming at three levels:
    • A2: All the types of cash expenditure to create the crop like seeds, manure, chemicals, labour costs, fuel costs and irrigation costs.
    • A2+FL: It includes A2 plus an imputed value of unpaid family labour.
    • C2: Under C2, the estimated land rent and the cost of interest on the money taken for farming are added to A2 and FL.
  • On 18th November 2004, the Union government formed the National Commission on Farmers (NCF) with MS Swaminathan as its chairman.
  • The main purpose of the committee was to come up with a sustainable farming system, make farm commodities cost-competitive and more profitable.
KVS PGT Chemistry Mock Test - 3 - Question 4
How many main organs are there in United Nations Organization?
Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 4

The correct answer is Six.

Key Points

​Therefore, The United Nation have Six organ body. 

Important Points

  • ​The United Nations is an intergovernmental organization.
  • The stated purposes are to maintain international peace and security, develop friendly relations among nations, and achieve international cooperation.
  • The United Nations (UN) main organs are— the General Assembly, the Security Council, the Economic and Social Council, the Trusteeship Council and the Secretariat, and the International Court of Justice.
    • Founded: 24 October 1945
    • Headquarters: New York, New York, United States
    • Secretary general: António Guterres
KVS PGT Chemistry Mock Test - 3 - Question 5
Pataliputra was the capital of ___________.
Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 5

The correct answer is Pataliputra.

Key Points

  • Pataliputra was the capital of the Mauryan Empire.
  • The empire lasted from 321 to 185 BCE.
  • The Mauryan Empire was founded by Chandragupta Maurya and the most popular ruler of the empire was Ashoka.
  • Mauryan dynasty had three important rulers:
    • Chandragupta
    • Bindusara
    • Ashoka

 Thus, we can say that Pataliputra was the capital of the Mauryan Empire.

Additional Information

  • The most important cities of the empire were the capital Pataliputa, Ujjain and Taxila.
KVS PGT Chemistry Mock Test - 3 - Question 6

The process of converting ammonia into nitrates is called:

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 6

The correct answer is Nitrification.

Key Points

  • The process of conversion of ammonia into nitrate nitrogen is called nitrification.
  • It is done in two steps- Nitrite formation, Nitrate formation.
  • Nitrite formationAmmonia are oxidized to nitrites by Nitrococcus, Nitrosomonas.

Additional Information

  • The nitrogen cycle has four steps-
    • Nitrogen Fixation- Conversion of molecular nitrogen into the inorganic nitrogenous compound.
    • Ammonification- Conversion of the dead organic nitrogenous compound into ammonia.
    • Nitrification- Oxidation of ammonia into nitrates.
    • Denitrification- Nitrites or nitrates converts back into molecular nitrogen.

KVS PGT Chemistry Mock Test - 3 - Question 7

The advantage of internet to a teacher is 

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 7

The Internet (or internet) is the global system of interconnected computer networks that uses the Internet protocol suite (TCP/IP) to communicate between networks and devices. 

Key Point

The advantage of the internet to a teacher:

  1. Access to more information: the internet is a repository of information. A teacher can explore knowledge through using this facility
  2. Update knowledge: For a teacher, it is more desirable to deliver updated knowledge. Internet is the only source to get fresh and updated information at a faster rate.
  3. Bridge the communication gaps: the internet helps to overcome communication in the classroom and also outside the class
  4. Convenience and flexibility: they can adopt different teaching-learning styles and reduce suffering from test anxiety or have difficulty concentrating in a busy classroom.

Important Points

The other advantages of the internet in education are:

  • Provide education in remote areas
  • Widen the area of knowledge
  • Provide a cost-friendly system
  • Facilitate more than one course through ODL
  • Increase the interest of students in higher education
  • Provide free and easily accessible study materials, etc.

Therefore, the advantage of the internet to a teacher is he can update his knowledge and enrich it.

KVS PGT Chemistry Mock Test - 3 - Question 8

 Which of the following compounds will exhibit cis-trans isomerism? 

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 8

The compounds with each doubly bonded carbon attached to two different groups (like Cab=Cab, Cab=Ccd) exhibit geometrical isomerism i.e., cis and trans forms. The geometrical isomerism arises due to restricted rotation of double bond.

However, even though there is restricted rotation for triple bond, alkynes do not exhibit geometrical isomerism, since the triply bonded carbons are attached to one group each only.

KVS PGT Chemistry Mock Test - 3 - Question 9

Why ice is a crystalline compound?

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 9

Crystalline compounds are those in which particles/molecules are arranged in proper order as in ice particles/water molecules are arranged in a cage-like ordered manner so this ordered structure is called a crystalline compound.

KVS PGT Chemistry Mock Test - 3 - Question 10

                                                  Passage I

A constant current of 30 A is passed through an aqueous solution of NaCl for a time of 1.00 h.

Thus Cl2 formed under STP condition is 

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 10

At anode 2Cl- —-±>Cl2+2e-
At cathode 2Na+ +2e- ——-> 2Na.
So 2 Faraday of electricity is required to liberate 1 mole = 22.4 liters of Cl2 at STP.
Amount of current passed
= 30 x 60 x 60=108000 coulombs.
So 108000 coulombs will liberate =108000/(96500 x2) = 0.5596 moles Cl2.
No.of liters of Chlorine liberated at STP
= 0.5596 x 22.4 = 12.53 liters.

KVS PGT Chemistry Mock Test - 3 - Question 11

In which of the following, is hydrogen peroxide not stored?

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 11

Hydrogen peroxide, represented by H2O2, is stored in acetanilide or sodium pyrophosphate, the presence of traces of alcohol, which slows down the rate of decomposition of hydrogen peroxide (H2O2).

KVS PGT Chemistry Mock Test - 3 - Question 12

What is the major formed in the reaction?

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 12

For option a
12 = [Ne]3s2 , 20 = [Ar]4s2 , 4 = [He]2s2 , 88 = [Ra]7s2.
For option b
8 = [He]2s22p4 , 16 = [Ne]3s23p4 , 34 = [Ar]4s23d104p4 , 2 = 1s2
We can see that only in option a, the last electrons enter in similar group. So, option a is correct.
Similarly we can check for option c and d as done above. However they won't fall in the same group.

KVS PGT Chemistry Mock Test - 3 - Question 13

The enthalpy of combustion of methane, graphite and dihydrogen at 298 K are - 890.3 kJ mol-1, - 393.5 kJ mol-1 and - 285.8 kJ mol-1 respectively. Enthalpy of formation of CH4(g) will be

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 13


KVS PGT Chemistry Mock Test - 3 - Question 14

Primary alcohol can easily be prepared from primary alkyl halide via SN2 reaction with aqueous NaOH. However, similar method does not work for the preparation of tertiary alcohol. Which reaction can be used for the efficient preparation of tertiary alcohol {tertiary butanol) from tertiary butyl bromide?

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 14

KVS PGT Chemistry Mock Test - 3 - Question 15

Which one of the following has a linear shape?

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 15

The correct answer is Option B.

Xe has an electronic configuration of 5s25p6
In XeF2, there are two bonding pairs and three lone pairs of electrons. So acc. to VSEPR theory, the structure would be trigonal bipyramidal to avoid electron pair repulsions.(sp3d)
In XeF4, the structure would be square planar. There are four pairs of bonding electrons and two lone pairs in the molecule. The hybridisation would be sp3d2
XeOF4 has an octahedral geometry due to sp3d2 hybridization. One trans position is occupied by a lone pair giving pyramid shape to the molecule.
Thus  XeF2 has sp3d hybridization.

KVS PGT Chemistry Mock Test - 3 - Question 16

In the modern periodic table, which period contains 32 elements?

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 16
  • There are a total of 7 periods in the periodic table.
  • The sixth period of the periodic table contains 32 elements.
  • It is beginning with cesium and ends with radon.
  • Lead (Pb) is currently the last stable element whereas all subsequent elements are radioactive.
KVS PGT Chemistry Mock Test - 3 - Question 17

The metal that can not be obtained by electrolysis of an aqueous solution of its salt is

[JEE Main 2014]

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 17

In electro chemical series (ECS),

thus, Ca2+ ion is not reduced to C a instead, H2O is reduce d to H2

Ag, Cu and Cr are below H in ECS (E°reduction > 0), thus they are reduced to metals on electrolysis.

Note In ECS, Ca, H, Cr, Cu elements lying above H are better reducing agents thus are easily oxidised.

KVS PGT Chemistry Mock Test - 3 - Question 18

At 87°C, the following equilibrium is established

H2(g) + S(s)  H2S(g) Kp = 7 × 10-2

If 0.50 mole of hydrogen and 1.0 mole of sulfur are heated to 87°C in 1.0 L vessel, what will be the partial pressure of H2S at equilibrium ?

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 18





KVS PGT Chemistry Mock Test - 3 - Question 19

If Ksp for HgSO4 is 6.4 × 10-5, then solubility of this substance in mole per mis

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 19


Ksp = S2
⇒ 6.4 × 10–5 = S2
⇒ S = 8 × 10–3 mole/L
S = 8 × 10–3 × 103 mole/m3
⇒ S = 8 mole/m3

KVS PGT Chemistry Mock Test - 3 - Question 20

Pick out the most reactive alkyl halide for an SN1 reaction.

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 20

Tertiary halide would be most reactive in SN1 reaction.

KVS PGT Chemistry Mock Test - 3 - Question 21

Phenyl magnesium bromide reacts with methanol to give -   

[AIEEE 2006]

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 21

The reaction of methanol with phenyl magnesium bromide is:

CH3OH + C6H5MgBr → C6H6 + Mg(OCH3)Br

A mixture of benzene and Mg(OMe)Br is obtained.

The correct option is A.

KVS PGT Chemistry Mock Test - 3 - Question 22

Solubility of KCI is maximum in

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 22

KCI is an ionic compound. Force of attraction (F) between K+


Greater the value of D, smaller the value of F, hence larger the solubility.
Note D for CH3OCH3 is least out of given solvents, thus solubility is minimum.

KVS PGT Chemistry Mock Test - 3 - Question 23

The principle involved in paper chromatography is:

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 23
  • Partition chromatography because the substances are partitioned or distributed between liquid phases. 
  • The two phases are water held in pores of the filter paper and the other phase is a mobile phase that passes through the paper.
KVS PGT Chemistry Mock Test - 3 - Question 24

 The correct order of in creasing order of radiiions Br, F-, O2- and S2-  is as follow

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 24

Atomic and ionic radii increase down the group due to increasing number of quantum shells.

KVS PGT Chemistry Mock Test - 3 - Question 25

 In the third period of the periodic table the element having smallest size is        

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 25

Atomic size decreases across the period.
Cl has a smaller size than Ar due to the inert nature atoms exist as single atoms.

KVS PGT Chemistry Mock Test - 3 - Question 26

Glucose solution is one molal. Glucose present in 1 kg glucose solution is

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 26

Glucose solution is one molal. Thus, 1000 g water (solvent) has glucose = one mole = 180 g

Total mass of solution = 1000 +180 = 1180 g

1180 g of solution has glucose = 180 g 

∴ 1000 g of solution has glucose =
180 x 1000/1180 = 152.5 ≈ 153g  

KVS PGT Chemistry Mock Test - 3 - Question 27

A hydrocarbon X is optically. X upon hydrogenation gives an optically inactive alkane Y. Which of the following pair of compounds can be X and Y respectively?

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 27

The correct answer is Option B.
The optically active hydrocarbon X is 3-methyl-1-pentene CH2=CH−CH(CH3)CH2CH3​. On catalytic hydrogenation, it forms 3-methyl pentane CH3CH2CH(CH3)CH2CH3, which is optically inactive.

KVS PGT Chemistry Mock Test - 3 - Question 28

Number of chiral centers are:

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 28


Number of chiral centers = 2

KVS PGT Chemistry Mock Test - 3 - Question 29

A resistance of 50Ω is registered when two electrodes are suspended into a beaker containing a dilute solution of a strong electrolyte such that exactly half of the them are submerged into solution. If the solution is diluted by adding pure water (negligible conductivity) so as to just completely submerge the electrodes, the new resistance offered by the solution would be

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 29

the k is halved while the A is doubled. Hence R remain 50 Ω.

KVS PGT Chemistry Mock Test - 3 - Question 30

1 c.c. of 0.1N HCl is added to 99 CC solution of NaCl. The pH of the resulting solution will be

Detailed Solution for KVS PGT Chemistry Mock Test - 3 - Question 30

Volume of resulting solution = 100 ml

View more questions
Information about KVS PGT Chemistry Mock Test - 3 Page
In this test you can find the Exam questions for KVS PGT Chemistry Mock Test - 3 solved & explained in the simplest way possible. Besides giving Questions and answers for KVS PGT Chemistry Mock Test - 3, EduRev gives you an ample number of Online tests for practice

Top Courses for KVS PGT/TGT/PRT

Download as PDF

Top Courses for KVS PGT/TGT/PRT