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UP PGT Physics Mock Test - 2 - UPTET MCQ


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30 Questions MCQ Test - UP PGT Physics Mock Test - 2

UP PGT Physics Mock Test - 2 for UPTET 2024 is part of UPTET preparation. The UP PGT Physics Mock Test - 2 questions and answers have been prepared according to the UPTET exam syllabus.The UP PGT Physics Mock Test - 2 MCQs are made for UPTET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for UP PGT Physics Mock Test - 2 below.
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UP PGT Physics Mock Test - 2 - Question 1

Weightlessness is:

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 1

Weight becomes zero in a freefall or when the total force on your body is zero. For example, in a freely falling lift the contact force on your body is zero, so the weighing​ machine would show zero reading. So you are weightless.

UP PGT Physics Mock Test - 2 - Question 2

The work done in moving a positive test charge qo from infinity to a point P at a distance r from the charge q is

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 2

Definition based

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UP PGT Physics Mock Test - 2 - Question 3

In the system shown in the adjoining figure, the acceleration of the 1 kg mass is 

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 3

Suppose a be the downward acceleration of the 4 kg mass, therefore, 2 a    is the upward acceleration of the I kg mass. Hence, equations of motion are:

Adding, after multiplying the equation (i) by 2.

Thus, the acceleration of the mass
a 1 kg is g/2 upwards.

 

UP PGT Physics Mock Test - 2 - Question 4

Given the instantaneous value of current from a.c. source is I = 8 sin 623t. Find the r.m.s value of current​

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 4

Compare the given eqn. with the standard from I=I0sinωt
I0=8, Irms=I0/√2=8/√2=5.656A

UP PGT Physics Mock Test - 2 - Question 5

Given below is the plot of a potential energy function U(x) for a system, in which a particle is in one dimensional motion, while a conservative force F(x) acts on it. Suppose that Emech = 8 J, the incorrect statement for this system is:

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 5

Emech. = 8 J
(A) At x > x4, U = constant = 6 J
K = Emech. - U = 2 J = constant
(B) At x < x1, U = constant = 8 J
K = Emech - U = 8 - 8 = 0 J
The particle is at rest.
(C) At x = x2, U = 0 ⇒ Emech. = K = 8 J
K.E. is greatest and the particle is moving at fastest speed.
(D) At x = x3, U = 4 J
U + K = 8 J
K = 4 J

UP PGT Physics Mock Test - 2 - Question 6

The graph drawn with object distance along abscissa & image as ordinate for a convex lens is

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 6

In a convex lens,  (1/v)−(1/u)=(1/f)​
Or (1/v)​−(1/f)​=(1/u)​ where u is always negative and f is always positive.
(1/v)​=(1/f)​−(1/u)​
So, as u is increased 1/u will decrease and  (1/f)​−(1/u)​  will increase, so, 1/v​ increases or v decreases.
So, its graph will be a hyperbola

UP PGT Physics Mock Test - 2 - Question 7

In a Fresnel’s biprism experiment, the two coherent sources are obtained by:

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 7

When a light travels from one medium to another then deviation in the path of light known as refraction. And in the prism surrounding medium is air and material medium is glass due to the change of medium refraction will occur in prism.

UP PGT Physics Mock Test - 2 - Question 8

The resultant amplitude in interference with two coherent source depends upon _

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 8

Two sources are said to be coherent if there always exists a constant phase difference between the waves emitted by these sources. But when the sources are coherent, then the resultant intensity of light at a point will remain constant and so interference fringes will remain stationary.

UP PGT Physics Mock Test - 2 - Question 9

The relative error in a physical quantity raised to the power k is:

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 9

The relative error in a physical quantity raised to the power k is the k times the relative error in the individual quantity.

Suppose Z = A2,
Then,
ΔZ/Z = (ΔA/A) + (ΔA/A) = 2 (ΔA/A).
Hence, the relative error in A2 is two times the error in A.

UP PGT Physics Mock Test - 2 - Question 10

Photon has a charge of

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 10

A photon is massless, has no electric charge, and is a stable particle. In vacuum, a photon has two possible polarization states. The photon is the gauge boson for electromagnetism, and therefore all other quantum numbers of the photon (such as lepton number, baryon number, and flavour quantum numbers) are zero.
 

UP PGT Physics Mock Test - 2 - Question 11

A pair of stationary and infinitely long bent wires is placed in the X-Y plane as shown in figure. The wires carry currents of 10 A each as shown. The segments L and M are along thex-axis. The segments P and Q are parallel to the y-axis such that OS = OR = 0.02 m. Find the magnetic induction at the origin O.

                                               

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 11

As point O is along the length of segments L and M, so the field at O due to these segments will be zero. 
Also, point O is near one end of a long wire.
The resultant field at O, BR​=BP​+BQ​, this field will be into the plane paper.
⇒BR​= μ0I/4π​​RO​+​​ μ0I/4πSO​
But, RO=SO=0.02m
Hence, BR​=2× (μ0/4π) ​​×(10/0.02)=2×10−7 (10/0.02) ​=10−4Wb m−2

UP PGT Physics Mock Test - 2 - Question 12

Two strips of metal are riveted together at their ends by four rivets, each of diameter 6.0 mm. What is the maximum tension that can be exerted by the riveted strip if the shearing stress on the rivet is not to exceed 6.9 × 107Pa? Assume that each rivet is to carry one quarter of the load.

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 12

UP PGT Physics Mock Test - 2 - Question 13

A horizontal force of 10 N is necessary to just hold a block stationary against a wall. The coefficient of friction between the block and the wall is 0.2. The weight of the block is      

[AIEEE 2003]

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 13

Let R be the normal contact force by wall on the block.

R = 10 N
fL = w and f = μR
∴ μR = w
or w = 0.2 x 10 = 2N

UP PGT Physics Mock Test - 2 - Question 14

In an RLC circuit, which of the following is always used as a vector reference?

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 14

In an RLC circuit, the voltage is always used as a reference and according to the phase of the voltage, the phase of the other parameters is decided.

*Multiple options can be correct
UP PGT Physics Mock Test - 2 - Question 15

The magnetic field due to a current carrying circular loop of radius 3 cm at a point on the axis at a distance of 4 cm from the centre is 54 μT. What will be its value at the centre of loop?

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 15

The magnetic field at a point on the axis of a circular loop at a distance x from centre is,

UP PGT Physics Mock Test - 2 - Question 16

A wheel of moment of inertia 0.40 kg-m2 is making 2100 rotations per minute. The wheel is brought to a complete stop in 2 seconds. The angular acceleration of the wheel is

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 16

CONCEPT:

  • Angular velocity (ω): How fast the angular position or orientation of an object changes with time or How fast an object rotates or revolves relative to another point is known as angular velocity.
    • Angular velocity in terms of RPM (revolutions per minute) 

ω = 2 π f / 60

where ω is in terms of radian per second and f is in revolution per minute.

  • Angular acceleration (α): The rate of change of angular velocity is known as angular acceleration.

The relation between α and changing ω is given by: 

ω1 = ω0 + α t

where ω1 is the final angular velocity, ω0 is the initial angular velocity α is the angular acceleration.

CALCULATION:

Given that f0 = 2100 rpm; f1 = 0 rpm; t = 2 sec.

ω0 = 2 π f0 / 60 = 2 π 2100 / 60 = 70π 

ω1 = 0

ω1 = ω0 + α t

0 = 70π + α 2

α = -35π rad/sec2

So the correct answer is option 1.

UP PGT Physics Mock Test - 2 - Question 17

If a ball of mass 1 kg makes a head-on collision with a ball of an unknown mass initially at rest such that the ball rebounds to one third of its original speed, what is the mass of the other ball?

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 17

As the balls collide head-on and no other external force is acting, momentum of the system realins conserve and so will be the energy of the system (i.e. KE)
Thus we get for the mass of other ball be m and initial velocity of mass 1 be v
1 x v = 1 x -v/3 + m x V         -1
For some V that is velocity of m after collision.
Also  ½ 1 x v2 =  ½ 1 x v2 /9 +  ½ m x V2                -2
Now from eq 1 we get mV = 4v/3
And from eq 2 we get  mV2  = 8v2 /9
Thus we get V =  (8v2 /9) / (4v/3)
=  2v/3
Thus we get m x 2v/3 = 4v/3
So m = 2kg

UP PGT Physics Mock Test - 2 - Question 18

Two point charges A and B, having charges +Q and –Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomes

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 18

In case I :


In Case II :


From equations (i) and (ii),

UP PGT Physics Mock Test - 2 - Question 19

Measurement of a physical quantity is essentially the:

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 19

The Measurement of a given quantity is essentially an act or result of comparison between a quantity whose magnitude (amount) is unknown, with a similar quantity whose magnitude (amount) is known, the latter quantity being called a Standard.

UP PGT Physics Mock Test - 2 - Question 20

A lamp is connected in series with a capacitor and connected to an AC source. As the capacitance value is decreased.

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 20

When frequency decreases, capacitive reactance XC​=1/2πνC​ increases and hence impedance in the circuit Z=√(R2+XC2​)​ increases and so current I=V/Z​ decreases. As a result, the brightness of the bulb is reduced.
 

UP PGT Physics Mock Test - 2 - Question 21

Damping in galvanometers is based oUpdate Questionn

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 21

Explanation : The coil of galvanometer is wound on a light metal frame. When the coil and frame rotate in the field of the permanent magnet, the eddy current set up in the frame oppose the motion so that the coil returns to zero quickly.

UP PGT Physics Mock Test - 2 - Question 22

A constant voltage is applied between the two ends of a uniform metallic wire. Some heat is developed in it. The heat developed is doubled if

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 22

KEY CONCEPT : The heat produced is given by

Thus heat (H) is doubled if both length (l) and radius (r) are doubled.

UP PGT Physics Mock Test - 2 - Question 23

The number of turns in a long solenoid is 500. The area of cross-section of solenoid is 2 × 10-3 m2. If the value of magnetic induction, on passing a current of 2 amp, through it is 5 × 10-3 tesla, the magnitude of magnetic flux connected with it in webers will be

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 23

Φ=BAN
=5x10-3x2x10-3x500
=5x10-3x1000x10-3
=5x10-3

UP PGT Physics Mock Test - 2 - Question 24

The angular velocity (in rad/s) of a body rotating at N r.p.m. is

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 24

Angular velocity is defined as the rate of change of angular displacement with respect to time. It is usually expressed by a Greek letter ω (omega).
Mathematically, angular velocity,
ω =dθ/dt
If a body is rotating at the rate of N r.p.m. (revolutions per minute), then its angular velocity,
ω = 2πΝ / 60 rad/s

*Multiple options can be correct
UP PGT Physics Mock Test - 2 - Question 25

A long solenoid has 200 turns per cm and carries a current i. The magnetic field at its centre is 6.28 × 10–2 Weber/m2. Another long solenoid has 100 turns per cm and it carries a current i/3 . The value of the magnetic field at its centre is

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 25

UP PGT Physics Mock Test - 2 - Question 26

The process by which heat is transferred from one place to another without heating the intervening medium is known as

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 26

Radiation alludes to the mechanism in which heat is transmitted without any physical contact between objects. It uses electromagnetic waves for transfer of heat.

UP PGT Physics Mock Test - 2 - Question 27

The magnetic flux linked with a coil is changed from 1 Wb to 0.1 Wb in 0.1 second. The induced emf is​

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 27

Change n in magnetic flux Δϕ=0.1−1=−0.9 Weber
Time taken  Δt=0.1 sec
So, emf induced in the coil  E=− Δϕ​/Δt
⟹ E=− (−0.9)​/ 0.1=9 Volts
Hence option C is the correct answer.

UP PGT Physics Mock Test - 2 - Question 28

A spherical hole is made in a solid sphere of radius R. The mass of the original sphere was M.The gravitational field at the centre of the hole due to the remaining mass is

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 28

By the principle of superposition of fields

Here  = net field at the centre of hole due to entire mass

 = field due to remaining mass

 = field due to mass in hole = 0

UP PGT Physics Mock Test - 2 - Question 29

According to Huygens construction relation between old and new wave fronts is

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 29

The Huygens-Fresnel principle states that every point on a wavefront is a source of wavelets. These wavelets spread out in the forward direction, at the same speed as the source wave. The new wavefront is a line tangent to all of the wavelets.
The correct answer is option B.

UP PGT Physics Mock Test - 2 - Question 30

Three physical quantity having dimensions [ML-1T-2] are:

Detailed Solution for UP PGT Physics Mock Test - 2 - Question 30

Pressure = Force/Area = ML1T-2/ L2 = [M L-1 T-2]
Stress = Force/Area   = ML1T-2/ L2 = [ML-1T-2]
Coefficient of elasticity = Stress/Strain = [ML-1T-2]

Hence, the correct answer is C. 

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