UP PGT Chemistry Mock Test - 2 - UPTET MCQ

α and π bonds exist.
Oxidation number of N = + 3 it can be increased to +5 (maximum) and decreased to -3 (minimum) HNO₂ is also a ’ligand.

HNO₂ is also the complexing agent 

In the first example (CN^-, N₂, C₂^2-) we have 14 electrons. In second (PO₄^3-, SO₄^2-, ClO_4^-) we have 50 electrons. In the third (BO₃^3-, CO₃^2-,NO₃^-), we have 32 electrons. While n last case, although we have 32 electrons in CO₃^2- and NO₃- but SO₃^2- has 42 electrons. So, the last case has no isoelectronic species.

From aniline by diazotisation followed by heating the diazonium salt with HBF₄

NaCl Solution : pH is the, pH   of water.

pH at 25°C <7

According to option A chiral compound at least have one chiral carbon but compounds other than carbon and also chiral like NCl Br I is chiral. According to option b a compound containing only one ka kalakaron is always is always correct that is statement is true it is the minimum requirement for a carbon atom to become chiral. Efficiency is not necessary to be true all the time compound will not be superimposable on its Mirror image. And for option d a plane of symmetry is sufficient but not a mandatory to give achiral compound.

Due to intermolecular H-bonding at two terminals boiling point of glycol is maximum.

Species with (zero) bond order will not exist.
Electrons in orbital

 

The correct answer is option A

The cells will be arranged as such 9 : 4: 1.

Explanation:

• The equilibrium constant that is used here is represented with k.

• The smaller the value of k the higher will be the value of energy according to Gibbs.

• So, 1 has the highest Gibbs free energy while 9 has the least.

• This is the energy of a chemical reaction.

• It is represented by G.

=21.97mg = 22mg

 if reduction potential of metal ion is greater then O₂/H₂O couple, the ion is stable in water. So Co³⁺ is stable in water

Non metallic oxides are acidic.

In structure (a), octet of N-atom is not complete. In all the other structures, octets of N and all the O-atoms are complete.

Isoelectronic are the species having same number of electrons.
A positive charge means the shortage of an electron.

∆G = ∆H - T∆S
For opt (c), ∆G = 48000 - 400(135)
= 48000 - 54000
= -6000
∆G is -ve
Therefore reaction is spontaneous.

Option b: Decrease concentration of sample four times and measure the optical rotation. Explanation:

• Optical rotation is directly proportional to concentration (specific rotation = observed rotation/concentration).
• If you decrease the concentration of the chiral compound in the sample, the observed optical rotation will decrease proportionally.
• If the initial observed rotation is indeed +60° and not -300°, decreasing the concentration will still result in a positive rotation, but it will be lower.

The other options are less likely to provide useful information in this context.

For hydrogen atom =  2.18 x 10⁻¹⁸J atom⁻¹ =−E_1(H)

-COOH is carboxyl group.

As per the notations of the IUPAC nomenclature, the 101^st element is named as Unnilunium. When the Einstenium was bombarded with alpha particles, Mendelevium was discovered and named after Dmitri Mendeleev.

18 MH₂SO₄ means18 mol L^-1.
1000 mL of H₂S0₄ solution has H₂SO₄ = 18 mol
= 18 x98g
Also, 1000 m L = 1000 x 1.8 g H₂SO₄ solution
Thus, (1000 x 1.8)g H₂SO₄ solution has H₂SO₄ =18 x 98 g

Emission (n₂ = 5 to n₁ = 2) is called Balmer series and appears in visible region.

CN^- → CNO^-
4+ x = -1      4+ x-2 = -1
∴ x = -5    ∴ x = -3   
Oxidation number increases. This is oxidation.

CN^- → CNO^- + 2e^-

1 and 2 are non-superimposable mirror images of each other. So, according to the options given, 1 and 2 are enantiomers of each other.