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PCM - Mock Test (May 31) - JEE MCQ


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30 Questions MCQ Test - PCM - Mock Test (May 31)

PCM - Mock Test (May 31) for JEE 2024 is part of JEE preparation. The PCM - Mock Test (May 31) questions and answers have been prepared according to the JEE exam syllabus.The PCM - Mock Test (May 31) MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for PCM - Mock Test (May 31) below.
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PCM - Mock Test (May 31) - Question 1

A ball is thrown upward with an initial velocity V0 from the surface of the earth. The motion of the ball is affected by a drag force equal to mv2 (where m is mass of the ball, v is its instantaneous velocity and  is a constant). Time taken by the ball to rise to its zenith is:

Detailed Solution for PCM - Mock Test (May 31) - Question 1

PCM - Mock Test (May 31) - Question 2

A particle is moving with speed v = b along positive x-axis. Calculate the speed of the particle at time t = .
(Assume that the particle is at origin t = 0)

Detailed Solution for PCM - Mock Test (May 31) - Question 2

v = b

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PCM - Mock Test (May 31) - Question 3

The trajectory of a projectile near the surface of the Earth is given as y = 2x - 9x2. If it was launched at an angle θ0 with speed v0, then
(g = 10 ms-2)

Detailed Solution for PCM - Mock Test (May 31) - Question 3

y = xtan ... (1)
Given equation of the trajectory is y = 2x - 9x2.
 ... (2)
Comparing equations (1) and (2), we get
tanθ = 2 and R = 



cosθ = 
  = cos-1
 
 
 u2
 
 =  m/s
Therefore,  and 

PCM - Mock Test (May 31) - Question 4

A particle moves in one dimension from rest under the influence of a force that varies with the distance travelled by the particle as shown in the figure. The kinetic energy of the particle after it has travelled 3 m is:

Detailed Solution for PCM - Mock Test (May 31) - Question 4

According to work energy theorem,
Work done by force on the particle = Change in KE
Work done = Area under F-x graph


W = KEfinal - KEinitial = 6.5
KEinitial = 0
KEfinal = 6.5 J

PCM - Mock Test (May 31) - Question 5

The position vector of a particle changes with time, according to the relation, . What is the magnitude of the acceleration at t = 1?

Detailed Solution for PCM - Mock Test (May 31) - Question 5

PCM - Mock Test (May 31) - Question 6

The velocity (v) and time (t) graph of a body in a straight line motion is shown in the figure. The point S is at 4.333 seconds. The total distance covered by the body in 6 s is

Detailed Solution for PCM - Mock Test (May 31) - Question 6

Distance = 
= 37/3 m

PCM - Mock Test (May 31) - Question 7

A small ball of mass m is thrown upward with velocity u from the ground. The ball experiences a resistive force mkv2, where v is its speed. The maximum height attained by the ball is:

Detailed Solution for PCM - Mock Test (May 31) - Question 7






On solving:

PCM - Mock Test (May 31) - Question 8

A clock has a continuously moving second's hand of 0.1 m length. The average acceleration of the tip of the hand (in units of ms-2) is of the order of

Detailed Solution for PCM - Mock Test (May 31) - Question 8

PCM - Mock Test (May 31) - Question 9

A particle moves such that its position vector r(t) = cos ωt i + sin ωt j, where ω is a constant and t is time. Then which of the following statements is true for the velocity vector v(t) and acceleration vector a(t) of the particle?

Detailed Solution for PCM - Mock Test (May 31) - Question 9

 is perpendicular to  and  is directed towards the origin.

PCM - Mock Test (May 31) - Question 10

Ship A is sailing towards north-east with velocity  km/hr where  points east and  north. Ship B is at a distance of 80 km east and 150 km north of Ship A and is sailing towards west at 10 km/hr. A will be at minimum distance from B in:

Detailed Solution for PCM - Mock Test (May 31) - Question 10

If we take the position of ship 'A' as origin, then positions and velocities of both ships can be given as:





Time after which distance between them will be minimum,


Where 


PCM - Mock Test (May 31) - Question 11

When a car is at rest, its driver sees raindrops falling on it vertically. When driving the car with speed v, he sees that raindrops are coming at an angle 60° from the horizontal. On further increasing the speed of the car to (1 + β)v, this angle changes to 45°. The value of β is close to

Detailed Solution for PCM - Mock Test (May 31) - Question 11



 = tan60° ... (i)
 = tan45° ... (ii)

Dividing (i) by (ii), we get



∵ tan60° =  and tan45° = 1

∴ 

∴ 

∴ 

∴  = 1.73 - 1 = 0.73 ... (Since  = 1.73)

PCM - Mock Test (May 31) - Question 12

A projectile is projected with velocity of 25 m/s at an angle θ with the horizontal. After t seconds its inclination with horizontal becomes zero. If R represents horizontal range of the projectile, the value of θ will be
[use g = 10 m/s2]

Detailed Solution for PCM - Mock Test (May 31) - Question 12

PCM - Mock Test (May 31) - Question 13

A modern grand-prix racing car of mass m is travelling on a flat track in a circular arc of radius R with a speed v. If the coefficient of static friction between the tyres and the track is μs, then the magnitude of negative lift FL acting downwards on the car is:
(Assume forces on the four tyres are identical and g = acceleration due to gravity)

Detailed Solution for PCM - Mock Test (May 31) - Question 13

PCM - Mock Test (May 31) - Question 14

A projectile is launched at an angle '' with the horizontal with a velocity 20 ms-1. After 10 s, its inclination with horizontal is ''. The value of tan will be: (g = 10 ms-2)

Detailed Solution for PCM - Mock Test (May 31) - Question 14



vx = ux = 20cos
vy = 20sin - 10 × 10

= tan - 5sec

PCM - Mock Test (May 31) - Question 15

Two projectiles are thrown with same initial velocity making an angle of 45° and 30° with the horizontal, respectively. The ratio of their respective ranges will be

Detailed Solution for PCM - Mock Test (May 31) - Question 15

Let projection speed = u
Horizontal range for projectile = u2 sin 2θ/g

PCM - Mock Test (May 31) - Question 16

A particle starts from the origin at t = 0 with an initial velocity of 3.0 m/s and moves in the x-y plane with a constant acceleration (6.0 + 4.0) m/s2. The x-coordinate of the particle at the instant when its y-coordinate is 32 m is D metres. The value of D is:

Detailed Solution for PCM - Mock Test (May 31) - Question 16


t = 4 s
x = 3 × 4 + 1/2× 6 × 42 = 60

PCM - Mock Test (May 31) - Question 17

A particle moves such that its position vector r(t) = cos ωt i + sin ωt j, where ω is a constant and t is time. Then which of the following statements is true for the velocity vector v(t) and acceleration vector a(t) of the particle?

Detailed Solution for PCM - Mock Test (May 31) - Question 17

 is perpendicular to  and  is directed towards the origin.

PCM - Mock Test (May 31) - Question 18

A girl standing on road holds her umbrella at 45° with the vertical to keep the rain away. If she starts running without umbrella with a speed of 15√2 kmh-1, the rain drops hit her head vertically. The speed of rain drops with respect to the moving girl is:

Detailed Solution for PCM - Mock Test (May 31) - Question 18

According to the question:


PCM - Mock Test (May 31) - Question 19

Motion of a particle in x-y plane is described by a set of following equations x = 4 sinm and y = 4 sin(t) m. The path of particle will be

Detailed Solution for PCM - Mock Test (May 31) - Question 19

Given:


x = 4 cos(ωt)
y = 4 sin(ωt)
Eliminate 't' to find the relation between x and y.
x2 + y2 = y2 cos2ω t + y2 sin2t = 42
x2 + y2 = 42
The particle is moving in a circular motion with radius 4 m.

PCM - Mock Test (May 31) - Question 20

A person moved from A to B on a circular path as shown in figure. If the distance travelled by him is 60 m, then the magnitude of displacement would be: (Given cos135° = -0.7)

Detailed Solution for PCM - Mock Test (May 31) - Question 20

Given,
Distance covered = 60 m
Angle covered = 135°



Displacement = 


 47 m

*Answer can only contain numeric values
PCM - Mock Test (May 31) - Question 21

A circular disc of mass M and radius R is rotating about its axis with angular speed . If another stationary disc having radius R/2 and same mass M is dropped co-axially on to the rotating disc, gradually both discs attain constant angular speed . The energy lost in the process is p% of the initial energy. Value of p is _____.


Detailed Solution for PCM - Mock Test (May 31) - Question 21



Let the moment of inertia of the bigger disc be I = .

*Answer can only contain numeric values
PCM - Mock Test (May 31) - Question 22

A ball of mass 10 kg moving with a velocity 10√3m/s along the x-axis, hits another ball of mass 20 kg which is at rest. After the collision, the first ball comes to rest while the second ball disintegrates into two equal pieces. One piece starts moving along the y-axis with a speed of 10 m/s. The second piece starts moving at an angle of 30° with respect to the x-axis. The velocity of the ball moving at 30° with x-axis is x m/s. The configuration of pieces after collision is shown in the figure below. The value of x to the nearest integer is ______.


Detailed Solution for PCM - Mock Test (May 31) - Question 22

*Answer can only contain numeric values
PCM - Mock Test (May 31) - Question 23

If the initial velocity in horizontal direction of a projectile is unit vector  and the equation of trajectory is y = 5x(1 - x), the y component vector of the initial velocity is _______ . (in integers)
(Take g = 10 m/s2)


Detailed Solution for PCM - Mock Test (May 31) - Question 23

ux = 1
y = 5x(1 - x)

For initial y-component of velocity,

*Answer can only contain numeric values
PCM - Mock Test (May 31) - Question 24

A car is moving on a plane inclined at 30° to the horizontal with an acceleration of 10 ms-2 parallel to the plane upward. A bob is suspended by a string from the roof of the car. The angle (in degree) which the string makes with the vertical is __________. (in integers)


Detailed Solution for PCM - Mock Test (May 31) - Question 24



Tan ( + 30°) = 

tan + 
2 tan =  = 
Tan  = 
 = 30°

*Answer can only contain numeric values
PCM - Mock Test (May 31) - Question 25

In the given figure, the angle of inclination of the inclined plane is 30°. Find the horizontal velocity V0 (in m/s) so that the particle hits the inclined plane perpendicularly. Given, H = 9 m, g = 10m/s2


Detailed Solution for PCM - Mock Test (May 31) - Question 25

  ----- (1)

By equation (1) and (2), we get

PCM - Mock Test (May 31) - Question 26

Which of the following is not a Dobereiner triad -

Detailed Solution for PCM - Mock Test (May 31) - Question 26

In Doberiner’s triad, mass of the middle element should be the average of the first and last element. In option b, Atomic massCa is not equal to the mean of atomic mass of Mg and Sr.

PCM - Mock Test (May 31) - Question 27

Which of the following set of elements obeyes Newland’s octave rule -

Detailed Solution for PCM - Mock Test (May 31) - Question 27

Because Be Mg and Ca have same chemical properties.

PCM - Mock Test (May 31) - Question 28

Which of the following will not form crystalline structure with oppositely charged ions

Detailed Solution for PCM - Mock Test (May 31) - Question 28

H+ ions doesn't form crystals because it hasn't any electrons .

PCM - Mock Test (May 31) - Question 29

Which is not anomalous pair of elements in the Medeleeves periodic table -

Detailed Solution for PCM - Mock Test (May 31) - Question 29

In Mendeleev’s periodic table, the elements are arranged in the increasing order of their atomic masses. In some places, this order has been ignored.

(a) Ar and K:  The atomic mass of argon is 40 and that of potassium is 39, But argon is placed beforepotassium in the periodic table.

(b) Co and Ni: The positions of cobalt and nickel are not in proper order. Cobalt (at. wt. = 59.9) is placed before nickel (at. wt. = 58.6).

(c) Te and I: Tellurium (at. wt. = 127.6) is placed before iodine (at. wt = 126.9).

(d) Thorium (at, wt. =232.12) is placed before protactinium (at. Wt = 231).

So, Al and Si is not the anomalous pair  of elements in the Mendeleev's periodic table.

PCM - Mock Test (May 31) - Question 30

Elements in the same vertical group of the periodic table have same

Detailed Solution for PCM - Mock Test (May 31) - Question 30

The periodic table also has a special name for its vertical columns. Each column is called a group. The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons.

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