Test: Roman Numerals - 2 - CTET & State TET MCQ

The Roman numeral that can never be subtracted is V.

• C − X = 100 − 10 = 90 = XC is correct.
• XI - IX = (10 + 1) − (10 − 1) = 11 − 9 = 2 ≠ XX is  wrong.
• DC − C = 500 + 100 − 100 = 500 = D is correct,    
• LXI − LIX = (50 + 10 + 1) − [50 +(10 − 1)] = 61 − 59 = 2 = II is correct,

To convert the Roman numeral CDXC to its Arabic numeral representation, let's break it down:

• C = 100
• D = 500
• XC = 90

When a smaller numeral precedes a larger one, you subtract the smaller from the larger. So:

• CD = 500 - 100 = 400
• XC = 90

Adding these values together:

• CDXC = 400 + 90 = 490

So, the correct Arabic representation for the numeral CDXC is: 490

The greatest number formed is DCLX = 660 and the least is CDXL = 440. Their difference is 220 = CCXX.

• 37 = XXXVII which can be made with 10 match sticks.
• 39 = XXXIX ® 9 match sticks
• 27 = XXVII ®  8 match sticks
• 35 = XXXV = 8 match sticks

The greatest 3-digit number is 999 = 900 + 90 + 9 = (1000 − 100) + (100 − 10) + (10 − 1)
999 = (M−C)+(C−X)+(X−I)
Rewrite the terms after subtraction,
⇒999 = CM+XC+IX
Join the terms,
⇒ 999 = CMXCIX.

25 + 14 = 39 = XXV + XIV = XXXIX  
∴ 7 symbols are needed.

There is difference of ten.

IV = 5 - 1 = 4

So, 4  is the required Arabic representation.

[10 + 30 = 40]

19, 21, 24 and 25.
except 24 all are even

• 516 < DCVI is correct as DCVI = 500 + 100 + 5 + 1 = 606           
• CCLVII = 100 + 100 + 50 + 5 + 1 + 1 = 257 ≠ 256
• CDVIII = (500 − 100) + 5 + 1 + 1 + 1 = 400 + 8 = 408
• MD = 1500

0 has no Roman numeral.

XI = 10 + 1 = 11

So, 11 is the Arabic representation for the numeral XI.

XXIII = 10 + 10 + 1 + 1 + 1 = 23

There is difference of one.

[15 - 5 = 10]

There are 7 basic numerals in Roman numeration system. They are l, V, X, L, C, D and M.

IXIV is meaningless.

There is difference of five.