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EMRS PGT Physics Mock Test - 9 - EMRS MCQ


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30 Questions MCQ Test - EMRS PGT Physics Mock Test - 9

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EMRS PGT Physics Mock Test - 9 - Question 1

Chromosomes are present in ________

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 1

Concept:

The nucleus of the Cell

  • The cell is the basic building block of all living beings. 
  • The nucleus is the special structure located generally at the center of the cell. 
  • The nuclear membrane separates the cytoplasm from the nucleus. 
  • The nucleus contains a central part called nucleolus and chromosomes. 
  • Chromosomes and nucleolus coexist in the nucleus. Chromosomes are not present in the nucleolus.


Chromosomes and Genes

  • Chromosomes carry genes and help in the inheritance or transfer of characters from the parents to their children. 
  • The chromosomes can be seen only when the cell divides.
  • The credit for the discovery of chromosomes goes to Strasburger as he first described the chromosome structure seen in the nucleus during cell division.
  • Usually, chromosomes are rod-shaped, elongated, or dot-like in shape with sizes varying from 0.5 to 32 micrometer.
  • In humans, 23pairs of chromosomes are found i.e. 46 in numbers.


Conclusion:

  • Chromosomes are present in the nucleus of the cell. So, all the given options are wrong. 
  • The correct option is None of these.

Additional Information

  • The cell membrane is also known as the plasma membrane. 
    • It is a porous structure that allows the exit and entry of certain materials according to its requirement. 
    • This is the major function of the cell membrane. 
  • The cytoplasm is between the cell and the nucleus.
    • Cell organelles like mitochondria, Golgi bodies, ribosomes, etc. are present in the cytoplasm. 
    • Mitochondria is called the powerhouse of cells and is responsible for cellular respiration. 
    • vacuole is open space between cell which is used for storing food. 
  • Plastids are double-membrane organelles found in the plant cell. They contain pigments that help the plant in photosynthesis. 
EMRS PGT Physics Mock Test - 9 - Question 2

Who led the company's army against Siraj-ud-daulah at Plassey?

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 2

The correct answer is Robert Clive.

Key Points

When Alivardi Khan died in 1756, Sirajuddaulah became the nawab of Bengal.

  • The Company was worried about his power and keen on a puppet ruler who would willingly give trade concessions and other privileges.
  • So it tried, though without success, to help one of Sirajuddaulah’s rivals become the nawab.
  • An infuriated Sirajuddaulah asked the Company to stop meddling in the political affairs of his dominion, stop fortification, and pay the revenues.
  • After negotiations failed, the Nawab marched with 30,000 soldiers to the English factory at Kassimbazar, captured the Company officials, locked the warehouse, disarmed all Englishmen, and blockaded English ships.
  • Then he marched to Calcutta to establish control over the Company’s fort there.


Important Points

  • On hearing the news of the fall of Calcutta, Company officials in Madras sent forces under the command of Robert Clive, reinforced by naval fleets.
  • Prolonged negotiations with the Nawab followed.
  • Finally, in 1757, Robert Clive led the Company’s army against Sirajuddaulah at Plassey. 
  • The Battle of Plassey became famous because it was the first major victory the Company won in India.


Thus, it is clear that Robert Clive led the company's army against Sirajudallah at Plassey.

Additional Information

  • James Mill was a famous economist and political philosopher from Scotland.
  • The Permanent Settlement of Bengal was brought into effect by the East India Company headed by Governor-General Lord Cornwallis in 1793.
  • Lord Dalhousie devised a policy that came to be known as the Doctrine of Lapse.
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EMRS PGT Physics Mock Test - 9 - Question 3

The idea of a Constituent Assembly was given by:

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 3

The correct answer is  M.N Roy.

Key Points

  • The idea of Constituent Assembly was given by Manabendra Nath Roy​ or M.N.Roy
  • In 1934, M.N.Roy put forth the idea of the Constituent Assembly.
  • The constituent assembly was formed in 1946 on the basis of the cabinet mission plan.
  • Temporary Chairman - Dr. Sachchidananda Sinha.
  • Permanent Chairman - Dr. Rajendra Prasad 
  • Vice Chairman - Harendra Kumar Mukherjee
  • Constitutional adviser - B. N. Rau
  • Dr. B.R Ambedkar was the head of the Drafting Committee.
  • Constitution was adopted by Constituent Assembly on 26 November 1949.
  • It became effective on 26 January 1950.

Additional Information

  • The Indian Constituent Assembly represented fully representative of the States and Provinces in India.
  • Initially, the number of members was 389, after the partition 299 members left.
  • Out of this 299, 229 were from the British provinces and 70 were nominated from the princely states.
  • It aimed at providing opportunities to each and every community.
  • Representatives from princely states and British Indians were also a part of it.
EMRS PGT Physics Mock Test - 9 - Question 4
Which planet is known as Blue Planet?
Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 4

The correct answer is Earth.

Key Points

  • From the sun, it is the third planet.
  • Life existed only on this planet.
  • Around 4.5 billion years ago, the earth was formed.
  • Inside the solar system, the earth is a rocky planet.
  • Earth moves around the sun due to the large mass of the sun.
  • In space, the earth also turns around.
  • At different times, a different part of the earth is faced by the sun.
  • A large amount of liquid water is found only on the earth.
  • Water covers around 74 percent area of the earth.
  • From different places, the earth's water came.
  • Of all the rocky planets, the earth is the largest.
  • As compared to Jupiter, it is very small.

Hence, the Earth is known as a blue planet.

EMRS PGT Physics Mock Test - 9 - Question 5

Select the option that is related to the third word in the same way as the second word is related to the first word.

Abduct : Kidnap :: Fierce : ?

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 5

The logic followed is:

Abduct and Kidnap are synonyms.

Similarly,

Fierce and Violent are synonyms.

Hence, the correct answer is "Violent".

EMRS PGT Physics Mock Test - 9 - Question 6

Sandhya is sister of Praveena. How is Praveena’s father’s sister’s mother related to Sandhya?

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 6

Preparing the family tree using the following symbols:

A possible tree diagram will be:

Praveena’s father’s sister’s mother is the grandmother of Sandhya.

Hence, "Grandmother" is the correct answer.

EMRS PGT Physics Mock Test - 9 - Question 7

Select the number which can be placed at the sign of the question mark (?) from the given alternatives.

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 7

The pattern followed is:

Top right number = multiplication of top left number and bottom number 

In fig 1:

729 = 81 × 9

729 = 729

In fig 2:

512 = 64 × 8

512 = 512

Similarly,

In fig 3:

? = 49 × 7

? = 343 

Hence, the correct answer is "343".

EMRS PGT Physics Mock Test - 9 - Question 8

Find out which answer figures will exactly make up the question figure?

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 8

EMRS PGT Physics Mock Test - 9 - Question 9

Direction: Read the following information carefully and answer the questions that follow.
A blacksmith has five iron articles A, B, C, D and E each having a different weight.
I. A weight is twice as much as of B.
II. B weight is four and half times as much as of C.
III. C weight is half times as much as of D.
IV. D weight is half as much as of E.
V. E weight is less than A but more than C.

Q. E is heavier than which of the following two articles?

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 9

According to question,
A's weight is twice as much as of B.
1. A = 2B.
B's weight is four and half times as much as of C.
2. B = 4.5C
C's weight is half times as much as of D.
3. C = D/2.
D's weight is half as much as of E.
4. D = E/2.
E weight is less than A but more than C.
5. A > E > C
from 1 and 2
6. A = 2B = 9C
from 6 and 3
7. A = 2B = 9C = 4.5D
from 7 and 4
8. A = 2B = 9C = 4.5D = 2.25E
so from 8 and 5
A > B > E > D > C
E is heavier than D and C.

EMRS PGT Physics Mock Test - 9 - Question 10

 What is an electronic page in a presentation called?

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 10
Answer:
The correct answer is C: Slide.
Explanation:
In a presentation, an electronic page is referred to as a slide. A slide is a single page within a presentation that contains text, images, charts, and other visual elements. It is used to convey information and support the presenter's message.
Here are the details about the options mentioned:
A: Page Preview - This term refers to a view that shows an overview of all the slides in a presentation, allowing the presenter to navigate through them.
B: Handout - A handout is a printed document that contains a selection of slides from a presentation. It is typically given to the audience for reference or note-taking.
C: Slide - This is the correct term for an electronic page in a presentation. Each slide represents a distinct piece of content and contributes to the overall flow and structure of the presentation.
D: e-Slide - This term is not commonly used to refer to an electronic page in a presentation. The term "slide" is more widely recognized and understood.
In conclusion, the correct term for an electronic page in a presentation is a slide.
EMRS PGT Physics Mock Test - 9 - Question 11

Teaching aids can create positive environment by

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 11

Teaching aids are helpful for teachers as well as for pupils. The use of such techniques encourages teacher; it makes teaching easier and effective, and teachers invest more in their lessons. It also generates interest of students in the topic; hence they pay more attention. Also such techniques can be used as a supplement for verbal and visual instructions. So all the statements are correct.

EMRS PGT Physics Mock Test - 9 - Question 12

Which of the following is a teacher's training technique for learning teaching skills?

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 12

The term 'micro teaching' was coined by Dwight Allen of the Stanford University. This is an innovative teacher training technique and focuses on developing teaching skills. This is highly individualised training skill. Micro teaching can also be defined as a teaching technique especially used in teachers' pre-service education to train them systematically by allowing them to experiment main teacher behaviours. By the help of this technique, teacher candidates can experiment and learn each of the teaching skills by breaking them into smaller parts and without encountering chaotic environment of the crowded classes.
In the original process, a teacher is asked to prepare a short lesson (usually 20 minutes) for a small group of learners who may not have been his/her own students. This is then recorded on video. After the lesson, the teacher, teaching colleagues, a master teacher and the students together view the video recording and comment on what they see happening, referencing the teacher's learning objectives. Watching the video and getting comments from colleagues and students provide teachers with an often intense "under the microscope" view of their teaching.

EMRS PGT Physics Mock Test - 9 - Question 13

A teaching aid cannot

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 13

A teaching aid cannot prevent behavioural problems. Proper psychological treatment is required to deal with behavioural problems. Teaching aid is a means used by teachers for facilitating learning among pupils. They reinforce learning and do not address any behavioural problems.

EMRS PGT Physics Mock Test - 9 - Question 14

The radius of curvature for a convex lens is 40 cm, for each surface. Its refractive index is 1.5. The focal length will be 

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 14

Let the radius of curvature of the convex lens are denoted as
For a convex lens
R1=+40cm [As it is towards right]
R2=-40cm [As it is towards left]
The refractive index of the lens [µ]=1.5
Let f is the focal length of the lens.
From lens maker's formula we know that –
1/f=[µ-1] [1/R1-1/R2]
1/f=[1.5-1][1/40-(1/-40)]
1/f=0.5 x (2/40)
1/f=1/40
f=40cm
Hence, the focal length of the lens is 40 cm.

EMRS PGT Physics Mock Test - 9 - Question 15

Two point charges -1 × 10-6 C and 4 × 10-6 C separated by 3 m distance have zero field location of

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 15


x=l/[ √(q2/q1)-1]
=3/√[(4x10-6/1x10-6)-1]
= (3/2)-1
=3
So, 3m away from -1x10-6C

EMRS PGT Physics Mock Test - 9 - Question 16

The field lines for single negative charge are:

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 16

Conventionally, field lines originate from a positive point charge and terminate at negative charge

EMRS PGT Physics Mock Test - 9 - Question 17

Which of the following appliance works on the principle of moments.

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 17

In beam balance we consider the torque at centre of beam which is moment of force at its each end.

EMRS PGT Physics Mock Test - 9 - Question 18

Which of the following is a characteristic of conservative forces?

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 18

Conservative forces are capable of converting potential energy into kinetic energy. When an object is at a higher potential energy, such as a ball at the top of a hill, a conservative force, like gravity, can cause it to move downward and convert its potential energy into kinetic energy. However, conservative forces themselves do not convert energy into other forms, such as thermal energy. The conversion of mechanical energy to thermal energy is typically associated with non-conservative forces, like friction.

EMRS PGT Physics Mock Test - 9 - Question 19

 A particle of mass m is at rest at the origin at time t = 0. It is subjected to a force F(t) = F0e-bt in the x-direction. Its speed v(t) is depicted by which of the following curves? 

[AIEEE 2012]

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 19

As the force is exponentially decreasing, so its acceleration, i.e., rate of increase of velocity will decrease with time. Thus, the graph of velocity will be an increasing curve with decreasing slope with time.

EMRS PGT Physics Mock Test - 9 - Question 20

Positive and negative point charges of equal magnitude are kept at locations ( 0,0,a/2) and (0,0,-a/2) respectively. The work done by the electric field when another positive point charge is moved from (-a,0,0) to (0,a,0) is 

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 20

+Q charge is moving on equatorial line of dipole as shown in figure, since on equatorial line V=0,
Hence the potential difference is zero. So, W=0

EMRS PGT Physics Mock Test - 9 - Question 21

A block has been placed on an inclined plane. The slope angle θ of the plane is such that the block slides down the plane at a constant speed. The coefficient of kinetic friction is equal to  

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 21


At a constant speed means, acceleration is 0. Therefore, using formula
a = g( sinθ - ucosθ)
0 = g(sinθ - u cosθ)
ucosθ = sinθ
u = sinθ/cosθ
u= tanθ
Hence D is correct.

EMRS PGT Physics Mock Test - 9 - Question 22

Read the following statements carefully :

Y : The resistivity of a semiconductor decreases with increases of temperature.

Z : In a conducting solid, the rate of collision between free electrons and ions increases with increase of temperature.

Select the correct statement from the following

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 22

In case of semiconductor Resistivity∝1​/temperature
In this case as temperature increases electrons jump to conduction band resistance decreases R∝ρ(Resistivity) so resistivity also decreases and current increases.
Vibration of electrons increases with rise in temperature and hence collision between ions and electrons increases with temperature.

EMRS PGT Physics Mock Test - 9 - Question 23

"Readiness for learning" refers to:

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 23

"Readiness for learning" refers to the cognitive level of students in the learning continuum. Readiness for learning means how a person seeks out knowledge on their own. This trait in students stimulates maximum achievement. Motivation, inspiration, or the dreams to accomplish a goal helps a lot to achieve this readiness for learning in life.
Hence, the correct answer is, 'Present cognitive level of students in the learning continuum.'

EMRS PGT Physics Mock Test - 9 - Question 24

Two blocks A and B masses 2m and m, respectively, are connected by a massless and inextensible string. The whole system is suspended by a massless spring as shown in the figure. The magnitudes of acceleration of A and B, immediately after the string is cut, are respectively.        

                

 [JEE 2006]

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 24

Before the string is cut the force applied by the spring is 3mg and tension in string is mg
Once the spring is cut, the tension comes to zero suddenly,
Thus acceleration of block b gets g downwards,
Whereas acceleration of a becomes g/2 upwards because the force from the spring is still the same at the moment the string is cut.

EMRS PGT Physics Mock Test - 9 - Question 25

Which of the following tools/methods does National Education Policy 2020 propose for assessment of children?

(i) Role plays

(ii) Group work

(iii) Portfolios

(iv) Projects

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 25

Education Policy lays particular emphasis on the development of the creative potential of each individual. It is based on the principle that education must develop not only cognitive capacities - both the ‘foundational capacities ’of literacy and numeracy and ‘higher-order’ cognitive capacities, such as critical thinking and problem solving – but also social, ethical, and emotional capacities and dispositions.

National Education Policy 2020-

According to NEP 2020, A good educational institution is one in which every student feels welcomed and cared for, where a safe and stimulating learning environment exists, where a wide range of learning experiences are offered, and where good physical infrastructure and appropriate resources conducive to learning are available to all students.

Key Points Some important fundamental principles of the NEP 2020 are- 

  • Establishment of the linkage of the concepts with the environment or we can say that the linkage of the school with the home.
  • It includes the overall development of the leader, it covers all three aspects as Cognitive domain, affective domain, and psychomotor domain.
  • It will include Progress of the Child in Inquiry-Based Learning, Quiz, Projects Roleplay, Group Work, Portfolios, etc, as part of the assessment of the students.
  • Promoting self-assessment and the peer assessment done by the student in the classroom.
  • Making board examination low stake and less stressful by focusing on Logic and Core Competencies
  • It emphasizes group work as well as individual work, NEP 2020 links the study to the curriculum.
  • Hence we conclude that all the objectives given in the question are correct for the assessment of the student.

Important Points  There are many changes in the assessment of the child, proposed in NEP 2020:

  • Continuous Tracking Of Learning Outcome Of Each Child.
  • Board Examinations to be made more flexible with an assessment of essential skills.
  • Assessment to focus on core concepts, higher-order, and foundational skills 
  • AI-based soft wares to help track the progress of students to enable them to make optimal career choices.
  • National Assessment Centre (PARAKH) will bring greater synergy to board examinations.
  • Self Assessment & Peer Assessment.
  • National Testing Agency (NTA) will work to offer a Common Aptitude Test of high quality to eliminate the need for coaching for these exams. 
EMRS PGT Physics Mock Test - 9 - Question 26

In the following question, a sentence has been given in Active/Passive Voice. Out of the four alternatives suggested, select the one which best expresses the same sentence in Passive/Active Voice.

Q. Does he want this?

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 26

Rule- The object in the active voice becomes the subject in the passive voice and the subject in the active voice becomes the object in the passive voice.This is valid in both ways (Active to passive and vice-versa). Further, the verb is changed to the past participle form
Thus, option 1 is correct.

EMRS PGT Physics Mock Test - 9 - Question 27

In the following question, a sentence has been given in Direct/Indirect speech. Out of the four alternatives suggested, select the one which best expresses the same sentence in the Indirect/Direct speech.

Q. He said, "I am doing the work."

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 27

Rule- If the reporting verb is in the past tense, the verb in the reported speech is changed to the corresponding past form.  
Thus, the sentence is changed to the corresponding past form. 

EMRS PGT Physics Mock Test - 9 - Question 28

निम्नलिखित प्रश्न में, चार विकल्पों में से उस विकल्प का चयन करें जो दिए गए वाक्य के भेद का सबसे अच्छा विकल्प हो ।

जुग जुग जिओ।

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 28
जुग जुग जिओ मे वाक्य के भेद का सबसे अच्छा विकल्प इच्छावाचक है।
EMRS PGT Physics Mock Test - 9 - Question 29

निम्नलिखित वाक्य में प्रधान उपवाक्य है:

मेरा यह सोचना कि लोकेश प्रतिभाशाली छात्र है, सही निकला।

Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 29

सही उत्तर 'मेरा यह सोचना, सही निकला' है

  • मेरा यह सोचना कि लोकेश प्रतिभाशाली छात्र है, सही निकला। इस वाक्य में ‘मेरा यह सोचना’ 'सही निकला' प्रधान उपवाक्य है।
  • किसी वाक्य में जो उपवाक्य किसी पर आश्रित नहीं होता अर्थात् स्वतंत्र होता है एवम् उसकी क्रिया मुख्य होती है, वह मुख्य या प्रधान उपवाक्य कहलाता है।
  • जैसे – मोदी जी ने कहा कि अच्छे दिन आएँगे।
  • इस वाक्य में ‘मोदी जी ने कहा’प्रधान उपवाक्य है।

Key Points

  • उपवाक्य: ऐसा पदसमूह, जिसका अपना अर्थ हो, जो एक वाक्य का भाग हो और जिसमें उदेश्य और विधेय हों, उपवाक्य कहलाता हैं।
  • उपवाक्यों के आरम्भ में अधिकतर कि, जिससे, ताकि, जो, जितना, ज्यों-त्यों, चूँकि, क्योंकि, यदि, यद्यपि, जब, जहाँ इत्यादि होते हैं।
  • उपवाक्य दो तरह के होते हैं – प्रधान उपवाक्य, आश्रित उपवाक्य
  • आश्रित उपवाक्य: दूसरे उपवाक्य पर आश्रित होता है।
  • आश्रित उपवाक्य क्योंकि, कि, यदि, जो, आदि से आरंभ होते हैं।
  • जैसे –मोदी जी ने कहा कि अच्छे दिन आएँगे।
  • इस वाक्य में "कि अच्छे दिन आएँगे।" आश्रित उपवाक्य है क्योंकि यह उपवाक्य "मोदी जी ने कहा" उपवाक्य पर आश्रित है।
EMRS PGT Physics Mock Test - 9 - Question 30
राम ने आसानी से शिव-धनुष तोड़ दिया'- वाक्य है;
Detailed Solution for EMRS PGT Physics Mock Test - 9 - Question 30

'राम ने आसानी से शिव-धनुष तोड़ दिया'- वाक्य है- विधानवाचक वाक्य

Key Points

  • विधानवाचक- ऐसे वाक्य जिनसे किसी काम के होने या किसी के अस्तित्व का बोध हो। इन्हें विधिवाचक वाक्य भी कहते हैं।

उदाहरण-

  • ममता ने खाना खा लिया।
  • हिंदी हमारी राष्ट्रभाषा है।

Additional Information

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