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Bihar STET Paper 1 Mathematics Mock Test - 8 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test - Bihar STET Paper 1 Mathematics Mock Test - 8

Bihar STET Paper 1 Mathematics Mock Test - 8 for Bihar PGT/TGT/PRT 2025 is part of Bihar PGT/TGT/PRT preparation. The Bihar STET Paper 1 Mathematics Mock Test - 8 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 1 Mathematics Mock Test - 8 MCQs are made for Bihar PGT/TGT/PRT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 1 Mathematics Mock Test - 8 below.
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Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 1

A pair of angles is called linear pair if sum of two adjacent angles is:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 1

Two angles form a linear pair if they have; 

A common arm

A common vertex

Their interiors do not overlap

The sum of two angles is 180°.

Therefore, linear pair of angles are adjacent angles whose non-common arms are opposite rays. 


Note: 

All adjacent angles do not form a linear pair.

Linear Pair of angles
From the above figure we can observe; OX and OY are two opposite rays and ∠XOZ and ∠YOZ are the adjacent angles. Therefore, ∠XOZ and ∠YOZ form a linear pair. 
If you measure ∠XOZ and ∠YOZ with the help of the protractor, you will find the sum of their measures equal to 180°.

Thus, the sum of the angles in a linear pair is 180°.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 2

The 21st term of the AP whose first two terms are -3 and 4, is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 2

a1=-3,
a2=4,
d=4-(-3)=7,
a21=?,
a21=a+(n-1)d
=-3+(21-1)7
= -3+(20)(7)
= -3+140
=137

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 3

DIRECTION : In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion : Total surface area of the cylinder having radius of the base 14 cm and height 30 cm is 3872 cm2 .

Reason : If r be the radius and h be the height of the cylinder, then total surface area = (2prh +2pr2).

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 3
Total surface area = 2prh +2pr2

= 2p r (h + r)

= 3872 cm2

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 4

A quadratic equation whose one root is 3 is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 4

x = 3 satisfies only the equation x2−5x+6 = 0
As (3)2−5×3+6 = 0
⇒ 9−15+6 = 0
⇒ 15−15 = 0
⇒ 0 = 0
⇒ L.H.S. = R.H.S.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 5

A kite is flying at a height of 60m from the level ground, attached to a string inclined at 30° to the horizontal. The length of the string is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 5


Let kite is flying at a height AB = 60 m and angle of elevation = 30°
To find: Length of the string AC

Therefore, the length of string is 120 m.  B C

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 6

Direction: India's national animal Tiger (which has also been under the radar of the government as its population declined in the country) has witnessed an increase in its population.

A survey was done by the Ministry of Environment, Forests and Climate change, according to which tiger population is on rise at the rate of 6 per cent every year from 2006 and 2018.

Pranav has found a report on status of tigers in India in last 100 years. He has some queries as follow :

Q. What is the total decline in number of tigers between 1960 to 2007?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 6
Number of tigers in 1960 = 18,000

Number of tigers in 2007 = 1,411

Decrease in number of tigers = 18,000 – 1,411 = 16,589

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 7

Directions: In the following questions, a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:

Assertion: x2 +7x+12 has no real zeroes.
Reason: A quadratic polynomial can have at the most two zeroes.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 7

The assertion is false because the quadratic equation x+ 7x + 12 can be factored as (x + 3)(x + 4), which means it has two real zeros (-3 and -4). The reason is true because a quadratic polynomial indeed can have at most two zeros, but it doesn't directly relate to the assertion being true or false.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 8

The length of the diagonal of the square is 10 cm. The area of the square is:​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 8

If side of square is 'a', then √2a = 10 Squaring both sides, 2a=100 a= 50 Area is 50 sqcm.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 9

The LCM of 24, 60 and 150 is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 9

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 10

The length of each side of a rhombus is 10cm and one of its diagonal is of length 16cm. The Length of the other Diagonal is:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 10
Firstly we know that diagonal of rhombus bisects each other. thus half of diagonal =8cm.
by pythagoras theorem we find another half of diagonal.that is 6 cm
as we diagonals bisect other thus another diagonal
=2×6=12cm
Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 11

If the height of the tower is √3 times of the length of its shadow, then the angle of elevation of the sun is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 11

Let the length of the shadow be x meters.
Then the height of the tower be √3x meter 

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 12

A quadratic polynomial whose zeroes are - 3 and 6, is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 12

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 13

Expansion and simplification of 8(3h - 4) + 5(h - 2) gives

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 13

Now, 8 (3h - 4) + 5 (h - 2)

= 24h - 32 + 5h - 10, the expansion

= 24h + 5h - 32 - 10

= 29h - 42, the simplification

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 14

If 8 is a root of the equation x2 – 10x + k = 0, then the value of k is:​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 14

Let, p(x) = x²-10x+k
since, 8 is the root of p(x)
∴ p(8) = 0
8²-10(8)+k = 0
64-80+k = 0
-16+k = 0
⇒ k = 16 .

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 15

What value/s can x take in the expression k(x – 10) (x + 10) = 0 where k is any real number.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 15

k(x – 10) (x + 10) =0
⇒ either k=0
Or x-10=0
Or x+10=0
Since we don’t know the value of k 
So either x-10=0
x=10
Or x+10=0
x=-10
So values of x can be 10,-10

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 16

Direction: India's national animal Tiger (which has also been under the radar of the government as its population declined in the country) has witnessed an increase in its population.

A survey was done by the Ministry of Environment, Forests and Climate change, according to which tiger population is on rise at the rate of 6 per cent every year from 2006 and 2018.

Pranav has found a report on status of tigers in India in last 100 years. He has some queries as follow :

Q. In which year, number of tigers were minimum?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 16
In 2007, number of tigers were minimum.
Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 17

The area surrounded by a conical tent is 4526 m2. If the cost of canvas is Rs. 17 per square meter, then find the total cost of canvas.​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 17

total cost = area of canvas used x cost of per meter square canvas

= 4526 x 17 

= Rs. 76942

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 18

In a triangle ABC if ∠A = 53° and ∠C = 44° then the value of ∠B is:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 18
B=180-(A+C) B=180-53+44 B=180-97 B=83
Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 19

The value of 101 x 99 is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 19

(100+1)×(100 - 1) it is the formula of a²-b² so, (100)² -(1)² = 10000-1 = 9999.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 20

The fourth term of an A.P. is 4. Then the sum of the first 7 terms is :

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 20

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 21
National Education Policy (NEP) 2020 recommends the study of foreign languages as ________.
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 21

All languages will be taught with high quality to all students; a language does not need to be the medium of instruction for it to be taught and learned well. The teaching of all languages will be enhanced through innovative and experiential methods, including through gamification and apps, by weaving in the cultural aspects of the languages - such as films, theatre, storytelling, poetry, and music - and by drawing connections with various relevant subjects and with real-life experiences.

Key Points

  •  In addition to high-quality offerings in Indian languages and English, foreign languages, such as Korean, Japanese, Thai, French, German, Spanish, Portuguese, and Russian, will also be offered at the secondary level, for students to learn about the cultures of the world and to enrich their global knowledge and mobility according to their own interests and aspirations.
  • It can be studied as an additional option.

Thus, it is concluded that National Education Policy (NEP) 2020 recommends the study of foreign languages as additional options at the secondary stage.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 22

The basis of the project or an activity-based method is going from:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 22

The teaching method is a way to put theory into practice. It generally describes the pedagogy of children, general principles, and management strategies that are to be used through the whole teaching-learning process. It helps to ease the learning pace of students.

Key Points

The project method or activity-based method is based on learning by doing.

  • These methods make learning realistic and experimental.
  • It aims to make students think independently and is a target-driven activity based on the challenge, fostering success and efficient cooperation.
  • These methods follows the maxims of teaching like known to unknow, seen to unseen, simple to complex, concrete to abstract.
  • Learning by doing and experiencing the consequences of one's own actions. 
  • To enhance the skills and understanding of the learners as they gain knowledge by engaging with the contents and experiences.

Important Point

The whole knowledge travels from known to unknown, concrete to abstract, simple to complex, and from seen to unseen. The same principle is applied in classroom teaching and is the very aim of education at the highest level.

From concrete to abstract:

  • The abstract is confusing, difficult to understand, and subjective. The acquisition of new knowledge may become a simpler task when it is supported with concrete examples, objects, and events.

Hence we can say that the basis of the project or an activity-based method is going from concrete to abstract.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 23

Mrs. Sharma makes her assessment useful and interesting. She does this by

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 23

Mrs. Sharma makes her assessment useful and interesting by using various ways to collect the information. Each way provides a different piece of information or same information with some additional inputs. For example, a written question paper gives us the idea of the person's knowledge, an oral assessment gives us an idea of the person's verbal ability and articulation, and activities may prove useful in testing child's ability to apply the knowledge practically. Activities also make assessment interesting for children.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 24

The process of evaluation uses several methods because

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 24

Teachers use different evaluation methods because different subjects require different methods of assessment like science can be assessed by practical exams and languages can be assessed by evaluating verbal ability and fluency.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 25

Learning disabilities can interfere with learning basic skills such as reading, writing and/or math. These can arise due to all listed reasons except:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 25

Learning disabilities are neurologically-based processing problems. These processing problems can interfere with learning basic skills such as reading, writing and/or math. They can also interfere with higher level skills such as organisation, time planning, abstract reasoning, long or short term memory and attention. They are not caused due to the method of teaching used by the teacher. They may be present due to improper brain development, or infection in brain, etc. Constant fights amongst parents also lead to mental strain and anxiety in students, which may lead to learning disabilities.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 26

Which of the following is NOT a characteristic of a teacher-centered approach?

A. The students are writing down the dictation given by the teacher.

B. The students are developing different models using clay and paper in groups.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 26

teacher-centered approach is one where activities in the classroom are controlled by the teacher. In teacher-centered education, students put all of their focus on the teacher. The teacher leads the activity in the classroom and provides necessary information.

Key Points

  • It focuses on the discipline of students.
  • The emphasis is given to the right answer by students.
  • The teacher gives instructions while students only listen to teacher not give any responses.
  • Courses prescribed for a class can be completed in a time because all activities are controlled by the teacher.
  • Power is primarily with teachers and the teacher is the only person who will give instructions and students will follow the instructions.
  • Acquisition of knowledge is focused.

So, in a teacher-centered approach, the student will not develop the ability to develop the ability to create different models using clay and paper in the group. because the teacher-centered approach focuses on imparting the knowledge and students passively grasp the knowledge.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 27

To draw and understand maps, which of the following abilities is/are required to be developed in primary level students?
A. Understanding of relative positions of places
B. Understanding of relative distances and directions of places
C. Understanding of symbols and the scale
D. Drawing precisely according to the scale

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 27

The students are required to understand the relative positions and relative distances of places. They must know how to use the scale and symbols. Drawing precisely according to the scale is not important.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 28

If the ratio of the width to the length of a rectangle is 2 : 3 and the area of the rectangle is 54 cm2, what is the difference between its width and length?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 28

Let the widh = 2x
Length = 3x
2x × 3x = 54
x = 3 cm
Hence, Option A is correct.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 29

In the given, AB || CD. Then X is equal to:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 29

Through O, draw a line l parallel to both AB and CD. Then
∠1 = 45° (alt. ∠S)
and ∠2 = 30° (alt. ∠S)
∴ ∠BOC = ∠1 + ∠2 = 45° + 30° = 75°
So, X = 360° – ∠BOC = 360° – 75° = 285°
Hence X = 285°.

Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 30

Rohit walked 30m towards South, took a left turn and walked 50m, again he took a left turn and walked 30m. How far is he from the starting point?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 8 - Question 30

i) Rohit walked 30m towards South.
ii) Took a left turn and walked 50m
iii) Again he took a left turn and walked 30m.
Drawing the Diagram as per the given information:

AB = CD = 50m
Thus we can see he is 50m far from the starting point.
Hence, the correct answer is "50m".

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