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Bihar STET Paper 2 Chemistry Mock Test - 8 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test - Bihar STET Paper 2 Chemistry Mock Test - 8

Bihar STET Paper 2 Chemistry Mock Test - 8 for Bihar PGT/TGT/PRT 2024 is part of Bihar PGT/TGT/PRT preparation. The Bihar STET Paper 2 Chemistry Mock Test - 8 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 2 Chemistry Mock Test - 8 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 2 Chemistry Mock Test - 8 below.
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*Multiple options can be correct
Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 1

In which of the following processes, does the value of magnetic moment change ?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 1

(a) CO (14e), no unpaired electron, magnetic moment = 0
CO+ (13e), One electron is lost from bonding melecular orbital unpaired electron = 1, magnetic moment =
(b)  (15e) Unpaired electron = 1, magnetic moment =
(13e) Unpaired electron = 1, magnetic moment =
(c) Zn, Zn2+, unpaired electron = 0
(d) O2 (16e), unpaired electron = 2, magnetic moment =
, unpaired electron = 1, magnetic moment =

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 2

Electron gain enthalpy is most negative for:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 2

The negative electron gain enthalpy of fluorine is less than that of chlorine. It is due to small size of fluorine atom. As a result, there are strong interelectronic repulsions in the relatively small 2p orbitals of fluorine and thus, the incoming electron does not experience much attraction.

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Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 3

Comprehension Type

Direction (Q. Nos. 16-18) This section contains a paragraph, describing theory, experiments, data, etc.
Three questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

Consider the following sequence of reaction,

Q. 

The structure of compound B is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 3

B is an alcohol formed by the attack of Grignard's reagent on acetone. Hence, alcohol must have the skeleton


Also, R is C7H11 with two degree of unsaturation it must be cyclohexenyl methyl not cyclohexyl methyl.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 4

According to MO theory which of the following lists ranks the nitrogen species in terms of increasing bond order?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 4

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 5

25.3 g of sodium carbonate, Na2CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, Na+ and carbonate ions, are respectively. (At. mass of carbon = 40) 

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 5


= 2.53/106   2.59 × 10-2  5.9 × 10-2
0.238 × 0.25          = 1.18 × 10-3

250 ml - 0.238

= 0.955

0.955  0.955 

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 6

For which of the following parameters the structural isomers C2H5OH and CH3OCH3 would be expected to have the same values?

[AIEEE 2004]

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 6

Vapor density = Molecular weight/2

As both the compounds have same molecular weights, both will have the same vapour density. Hence, gaseous density of both ethanol and dimethyl ether would be same under identical conditions of temperature and pressure. The rest of these three properties; Vapour pressure, boiling point and heat of vaporization will differ as ethanol has hydrogen bonding whereas ether does not.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 7

Solid X is a very hard electrical insulator in solid as well as in molten state. It melts at extremely high temperature. Solid X is a

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 7

Covalent solid doesnot conduct electricity in molten and solid state.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 8

Consider the reactions

(A) H2O2 + 2HI → I2 +2H2
(B) HOCl + H2O2 → H3O + Cl - -  + O2

 Which of the following statements is correct about H2O2 with reference to these reactions? Hydrogen perioxide is ________.

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 8

H2O2 is an oxidizing agent in 1st reaction and Reducing agent in 2nd reaction.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 9

What is the major product in the following reaction?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 9

In oxymercuration-demercuration reaction, Markownikoff's addition of H2O takes place with HO- added to carbon where more stable carbocation could be formed.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 10

The flow of current is possible in Daniel cell only

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 10

The flow of current in a Daniel cell or any other electrochemical cell is due to the movement of electrons from the anode to the cathode. This happens through an external circuit connecting the two electrodes.

  • Electron Transfer: In a Daniel cell, the zinc (Zn) electrode is oxidized to zinc ions (Zn2+), releasing two electrons. These electrons then move through the external circuit to the copper (Cu) electrode, reducing the copper ions (Cu2+) to copper atoms. However, the transfer of electrons does not occur directly from Zn to Cu2+ in the solution. Instead, it happens via the external circuit. Therefore, option A is incorrect.

 

  • Potential Difference: The potential difference between the two electrodes in a Daniel cell is what drives the flow of current. When zinc is oxidized at the anode, it leaves behind electrons, creating a negative charge. At the same time, the reduction of copper ions at the cathode absorbs electrons, creating a positive charge. This difference in charge creates a potential difference or voltage that causes the electrons to flow from the anode to the cathode, generating current. Therefore, option B is correct.

 

  • Salt Bridge: A salt bridge is a device used to complete the circuit in a Daniel cell by allowing the flow of ions between the two half-cells. This maintains the electrical neutrality within the half-cells, enabling the reaction to continue. However, it does not directly facilitate the flow of current, which is driven by the potential difference between the electrodes. Therefore, option C is incorrect.
  • Platinum Wire: While a wire, such as one made of platinum, is needed to connect the two electrodes and provide a path for the electrons to move, it is not the presence of the wire itself that allows for the flow of current. Rather, it is the potential difference between the electrodes. Therefore, option D is incorrect.

In conclusion, the flow of current in a Daniel cell is possible if there is a potential difference between the copper and zinc electrodes. This potential difference drives the movement of electrons from the anode to the cathode, generating current.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 11

A definite amount of solid NH4HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm pressure. NH4HS decomposes to give NH3 and H2S and at equilibrium total pressure in flask is 0.84 atm. The equilibrium constant for the reaction is :

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 11



Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 12

The enthalpies of fusion for all reactions are

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 12

The enthalpies of fusion for all reactions are always positive because melting of a solid is an endothermic process in which heat is supplied to the reaction Hence the sum of enthalpies of the product is greater than the sum of enthalpies of the reactant.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 13

Ozone can be detected by using

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 13

Ozone is detected by using Hg.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 14

Kc forthe decomposition of NH4HS(s) is 1.8x 10-4 at 25°C.

If the system already contains [NH3] = 0.020 M, then when equilibrium is reached, molar concentration are

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 14

 NH4HS (s)  ⇋ NH3 (g) + H2S (g)
Initial    1                   -               -
At eqm     1-x                 x+0.02     x
Kc = [NH3][H2S]   (Since NH4HS is solid, we ignore it.)
1.8×10-4    = (x+0.02)(x)
x2+0.02x-1.8×10-4 = 0
Applying quadratic formula; x = -0.02+√{(0.02)2-4×1.8×10-4}
= 0.033-0.020/2 = 0.0065
Therefore, concn of NH3 at equilibrium = x+0.020 = 0.0265
concn of H2S at equilibrium = x = 0.0065
So, option b is correct

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 15

Direction (Q. Nos. 17) Choice the correct combination of elements and column I and coloumn II are given as option (a), (b), (c) and (d), out of which ONE option is correct.

Match the compounds/ions having underlined atoms of different oxidation number (in Column I) with values (in Column II).



Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 15

(i) CaOCI2 has



Oxidation number = + 6
Oxidation number = - 2
(ii) → (p,u)


(iii) → (q.v)


Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 16

ΔHvap = 30 kJ mol-1 and ΔSvap = 75 J mol-1 K-1. Thus, temperature of the vapour at 1 atm is

[IIT JEE 2004]

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 16

Vapour pressure is equal to atmospheric pressure ,it means the substance is at boiling point
At boiling point, liquid and Gas are in equilibrium. Therefore dG=0
dG = H - TdS
dG = 0
⇒H = TdS
⇒T = H/dS
⇒ T = 30 103/75 = 400K

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 17

For the reaction, at 1000° C

ΔG° = - 24 kJ mol-1,  = 0.0030 atm.

Q. Hence, ΔG at this temperature is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 17

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 18

How many primary amines are possible for the formula C4H11N?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 18

Four primary amines are possible with the molecular formula C4H11N.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 19

Azide ion exhibits an (N—N) bond order of 2 and may be represented by resonance structures I, II and III given below :

Select the correct statement(s) about more contributions, 

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 19

Structure with least formal charge on each atom, makes greater contributions. Also, structures with at least one neutral atom is also favoured II and III identical.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 20

The nature of positive rays depends on?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 20
  • The nature of positive rays produced in a vacuum discharge tube depends upon the nature of the gas-filled.
  • The positive rays consist of positive ions obtained by removing one or more electrons from gas molecules.
Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 21

The following mechanism has been proposed for the reaction of NO with Br2 to form NOBr :
NO(g) + Br2 (g)   NOBr2 (g)
NOBr2 (g) + NO (g) → 2 NOBr (g)
If the second step is the rate determining step, the order of the reaction with respect to NO (g) is -

[AIEEE 2006]

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 21

The correct answer is option c
NO(g)+Br2(g)     ⇌NOBr2(g)
NOBr2(g)+NO(g) 2NOBr(g)[rate determining step]
Rate of the reaction (r)= K[NOBr2][NO]
Where [NOBR2]=Kc[NO][Br2]
r=K.Kc.[NO][Br2][NO]
r=K’[NO]2[Br2].
The order of the reaction with respect to
NO(g)=2.
 

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 22

An aqueous solution contains 0.01 M RNH2 (Kb= 2 × 10-6) & 10-4 M NaOH.

The concentration of OH- is nearly:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 22



x2  +  10–4 x – 2 × 10–8 = 0
x = 10–4
[OH–] = x + 10–4
= 2 × 10–4

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 23

The way in which students bring their finding to others and apply their understanding to new and unfamiliar circumstances grows out of

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 23

The way in which students bring their finding to others and apply their understanding to new and unfamiliar circumstances, grows out of excitement for what they have accomplished. Student would be excited to reveal his finding.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 24

The primary duty of the teacher is to

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 24

Teachers play the most crucial role in moulding the behaviour of learners. This shaping of behaviour is achieved through planning and dedication.

The Primary duties of a teacher include:

  • to achieve all-round development of students by guiding the students in their learning process.
  • to provide motivation for learning.
  • to stimulate learners in order to realize their optimum potential.
  • to plan the teaching and learning process to suit the needs of the students.
  • to promote learning by providing a conducive environment.
  • to encourage learners to become active learners.

Although imparting knowledge and values into the students are important duties of a teacher. However all round development of students is the most important and vital duty of a teacher.

Thus, the primary duty of the teacher is to help in all round development of the students.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 25

The process of evaluation uses several methods because

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 25

Teachers use different evaluation methods because different subjects require different methods of assessment like science can be assessed by practical exams and languages can be assessed by evaluating verbal ability and fluency.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 26
Activity-based learning means __________.
Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 26

Activity-based learning as the name suggests actively involves learners in the construction and re-construction of knowledge based on his or her individual experiences. It is known as the learning by doing method. The activity approach takes you a little more time to prepare than a lecture or a demonstration. But the activity approach will not add to your burden. Rather, it will promote and support you by providing a range of appropriate educational material and ideas, and orientation on the creative use of the same. And the rewards for both you and your students will be significant and satisfying.

Key Points

The four steps to practicing activity-based learning are:  

Planning:  It is important to identify the learning objectives that would be achieved through the planned activity.

  • Now you need to make a list of and arrange for the various resources that may be required—material, learning resources, volunteers, etc.
  • Plan for debriefing/discussion after the activity should also be developed by you. You will also require to have an idea about how will you assess, not only the learners but also the effectiveness of the activity.

Conducting the Activity While conducting the activity, as a facilitator, you may need to work in the following phases:

  • Initiate the Activity: Introduce the activity and inform the children about the purpose or objective of the activity, their role in it, the time duration, and evaluation details if any.
  • Proceed with the Activity: Once you have initiated, your main role is to ensure that children can meaningfully do what they are expected to do. Remember, encouraging all children are required to keep them motivated and involved.
  • End the Activity: This phase is important to consolidate the learnings. This may require that the students reflect on the experiences and derive learnings relevant to the identified objective. If it is not done, sometimes the children are unable to relate the activity to essential learning. The teacher can also conclude by suggesting the linkages of the activity to real-life situations, and further direction. This phase is crucial for establishing links between what children experienced and what they read in their text-book.

Reflecting on the Process: This phase is for the teacher to take her own notes and learnings from the experience of conducting the activity. Thus you must spend some time reflecting on what worked well and what did not, and why? These notes/reflections will help you improve the design, planning, and conducting activity in the future.

Revising: As a result of reflection, the teacher often realizes the benefits and strengths of conducting the activity. An objective analysis of the experience also reveals the scope for improving the same activity for the next time.

Hence, we can conclude that Activity-based learning means learning by doing.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 27

Which of the following sentences is true about learning?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 27

Learning is effective in an environment that is emotionally positive and satisfying to learners. Any learner who is emotionally unstable may not be able to learn anything. The teacher must make the environment conducive for students to study and learn efficiently.
Errors made by the students do not indicate that no learning has taken place. Instead, they are the windows through which a teacher can understand the thought process of the students.
Learning is affected by emotional factors at any stage. Emotions change over time as the child matures, and in response to changing environmental interactions. The kind of learning that takes place at different emotional levels also differs.
Learning involves physical, social and emotional activity also.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 28

Gagan Shakti 2024 exercise, recently conducted by Indian Air Force at which place?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 28

The Indian Air Force (IAF) is set to conduct ‘Gagan Shakti-2024’, the nation’s largest air military exercise, involving all Air Force stations. Held every five years, it will commence on April 1, 2024, at Pokhran’s field firing range. Approximately 10,000 airmen will participate, with maneuvers spanning the Western and Northern fronts. The Indian Army is aiding logistical support, ensuring synergy across sectors for operational rail mobilization.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 29

The concept of 'seed germination' can be taught best by

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 29

The activity will help the students to gain first-hand experience. This helps in better retention of the concepts.

Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 30

To draw and understand maps, which of the following abilities is/are required to be developed in primary level students?
A. Understanding of relative positions of places
B. Understanding of relative distances and directions of places
C. Understanding of symbols and the scale
D. Drawing precisely according to the scale

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 8 - Question 30

The students are required to understand the relative positions and relative distances of places. They must know how to use the scale and symbols. Drawing precisely according to the scale is not important.

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