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Bihar STET Paper 2 Physics Mock Test - 6 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test - Bihar STET Paper 2 Physics Mock Test - 6

Bihar STET Paper 2 Physics Mock Test - 6 for Bihar PGT/TGT/PRT 2025 is part of Bihar PGT/TGT/PRT preparation. The Bihar STET Paper 2 Physics Mock Test - 6 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 2 Physics Mock Test - 6 MCQs are made for Bihar PGT/TGT/PRT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 2 Physics Mock Test - 6 below.
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Bihar STET Paper 2 Physics Mock Test - 6 - Question 1

RMS value of ac i = i1 cos wt + i2 sin wt will be

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 1

I=(I1)cosωt+(I2)sinωt
(I2)mean=I12cos2ωt+I22sin2ωt+I1I2cosωtsinωt
I12×(1/2)×i22×(1/2)+2I1I2×0
Irms=√(i2)mean=√(I12+I22/2)=(1/√2)( I12+I22)1/2

Bihar STET Paper 2 Physics Mock Test - 6 - Question 2

A block is moving on an inclined plane making an angle 45º with horizontal and the coefficient of friciton is μ. the force required to just push it up the inclined plane is 3 times the force requried to just prevent it from sliding down. If we define N = 10μ, then N is

[jee 2011]


Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 2


Bihar STET Paper 2 Physics Mock Test - 6 - Question 3

A particle of charge q and mass m moves in a circular orbit of radius r with angular speed ω . The ratio of the magnitude of its magnetic moment to that of its angular momentum depen ds on

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 3

The angular momentum L of the particle is given by

 

Bihar STET Paper 2 Physics Mock Test - 6 - Question 4

In an Inelastic Collision,

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 4

Kinetic Energy is transferred to other forms of energy—such as thermal energy, potential energy, and sound—during the collision process. After collision if recovery of kinetic energy is less than % then it is called inelastic collision i.e.. some part of kinetic energy is not recover. So that in an inelastic collision the total kinetic energy after the collision is less than before the collision

Bihar STET Paper 2 Physics Mock Test - 6 - Question 5

A rotating calcite crystal is placed over an ink dot. On seeing through the crystal one finds:

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 5

In calcite crystal there is a phenomenon of double refraction. So, we see one dot as a stationary object whereas the other being refracted at a little displaced position seems to be rotating about the first dot.

Bihar STET Paper 2 Physics Mock Test - 6 - Question 6

If the voltage across the electrodes of a cathode ray tube is 500 volts then energy gained by the electrons is

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 6

Voltage across the electrodes of a cathode ray gun, V=500V
Charge of the electron=1.6x10-19
Energy=eV
E= 1.6x10-19 x 500
E=800 x 10-19 J
E=8 x 10-17 J

Bihar STET Paper 2 Physics Mock Test - 6 - Question 7

The speed of plane electromagnetic waves is maximum in

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 7

The speed of any electromagnetic waves in free space is the speed of light c = 3x108 m/s. Electromagnetic waves can have any wavelength λ or frequency f as long as λf = c.

Bihar STET Paper 2 Physics Mock Test - 6 - Question 8

The electric field at a distance 3R/2 rom the centre of a charged conducting spherical shell of radius R is E. The electric field at a distance R/2 from the centre of the sphere is

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 8

Electric field inside the charged spherical shell is zero as there is no charge inside it.

Bihar STET Paper 2 Physics Mock Test - 6 - Question 9

Which of the given statements are correct for a conservative force field

(p) The total mechanical energy is conserved.
(q) The work done around a closed path is zero.
(r) Gain in kinetic energy = Loss in potential energy.

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 9

CONCEPT:

  • Conservative force: A force is conservative if the work done by the force in displacing an object from one point to another point is independent of the path followed by the object and depends only on the endpoints.
  • Electrostatic forces, gravitational forces, elastic forces, magnetic forces, etc and are examples of conservative forces.
  • Non-conservative forces: A force is said to be non-conservative if work done by or against the force in moving a body from one position to another, depends on the path followed between these two positions.
  • Examples:  Frictional force, Viscous force, Airdrag, etc.

EXPLANATION:

  • Suppose a particle starts at A and a force Fext is acting on it. The particle is moved around the loop using the same force, Fext
  • Suppose the particle eventually ends up at A itself then the entire displacement of the particle is zero which means the total work done is zero.
  • A total work of one zero means there is no expenditure of energy which means the total energy is conserved. Hence statement p is correct
  • The total displacement of a particle in a closed loop is zero, which means the total work done is zero. Hence statement q is correct.
  • The total mechanical energy of a system is given by 

⇒ Total energy = Potential Energy + Kinetic energy

  • From the statement p, it is clear that if the total work done is zero it means the energy is conserved.
  • Which means Gain in kinetic energy = Loss in Potential Energy. Hence option r is correct.
Bihar STET Paper 2 Physics Mock Test - 6 - Question 10

A resistance of 5 ohm and an inductance of 50 mH are connected in series with an a. c. I = 100 sin (100 t). What is the phase difference between the instantaneous current and voltage?​

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 10

Cosφ=R/Z=R/√R2/ ω2L2=5/√(25+(50)2x (0.1)2)
=5/√(25+25)=1/√2
⇒φ=π/4

Bihar STET Paper 2 Physics Mock Test - 6 - Question 11

An observer looks at a tree of height 15 metre with a telescope of magnifying power 10. To him, the tree appears

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 11

The magnifying power of a telescope tells us how much closer an object appears when viewed through the telescope. If a telescope has a magnifying power of 10, it means the object appears 10 times nearer than it actually is. So, a tree at a certain distance will seem to be at one-tenth of its real distance from the observer.

Magnification of a telescope is given by:
M= θio​ ​​
10= (h/di)/(h/do​) ​​
10= do​​/di​
Distance of image, di​=do​​/10

This does not mean the tree appears taller; rather, its apparent distance is reduced by a factor of 10, making it appear 10 times nearer.

Bihar STET Paper 2 Physics Mock Test - 6 - Question 12

In the pulley-block arrangement shown in figure. Find the relation between acceleration of block A and B. 

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 12

x1 + x2 = l1

Differentiating with respect to time,  we get v1 + v3 = 0

 Again differentiating w.r.t. time, 

Bihar STET Paper 2 Physics Mock Test - 6 - Question 13

Which of the statements is true for p-type semiconductors?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 13

In a p-type semiconductor, the holes are the majority carriers, while the electrons are the minority carriers. A p-type semiconductor is obtained when trivalent atoms, such as aluminium, are doped in silicon atoms.

*Multiple options can be correct
Bihar STET Paper 2 Physics Mock Test - 6 - Question 14

A conducting rod PQ of length L = 1.0 m is moving with a uniform speed v = 20 m/s in a uniform magnetic field B = 4.0 T directed into the paper. A capacitor of capacity C = 10 mF is connected as shown in figure. Then

            

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 14

According to Fleming’s right-hand rule induced current flows from Q to P.
Hence P is at higher potential and Q is at lower potential. 
Therefore, A is positively charged and B is negatively charged.
Hence:
qA​=+800μC and qb​=−800μC

Bihar STET Paper 2 Physics Mock Test - 6 - Question 15

The magnitude of displacement of a particle moving in a circle of radius a with constant angular speed w varies with time t as

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 15

If a particle is moving with angular velocity=ω
Its angle of rotation is given by ωt 
Now displacement= length of line AB
Position vector of a particle is given by
R =iacosωt + jasinωt
Ro=ai
displacement =R−Ro
=a(cosωt−1)i+asinωj
d=√[(a(cosωt-1))2+(asinω)2]
=a√(2(1-cosωt))=a√(2×2(sinωt/2)2)=2asinωt/2

Bihar STET Paper 2 Physics Mock Test - 6 - Question 16

At a certain place, the acceleration due to gravity is determined using a simple pendulum. The length of the pendulum is 25.0 cm and a stopwatch with least count is 1 s measures the time taken by the pendulum for 40 oscilations to be 50 s. the accuracy in the measurement of g is:

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 16

Bihar STET Paper 2 Physics Mock Test - 6 - Question 17

A trolley of mass 200 kg moves with a uniform speed of 36 km/h on a frictionless track. A child of mass 20 kg runs on the trolley from one end to the other (10 m away) with a speed of 4 ms−1 relative to the trolley in a direction opposite to the its motion, and jumps out of the trolley. How much has the trolley moved from the time the child begins to run?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 17

Explanation:
Mass of troly M = 200Kg
mass of child m = 20Kg
speed of trolley v = 36Km/hr=36 x 5/18 = 10m/s
Let v' be the final velocity of the trolley with respect to the ground.
Final velocity of the boy with respect to the ground = v,−4
from conservation of linear momentum

Time taken by the boy to run t = 10/4 = 2.5 sec
Distance moved by the trolley = vt = 10.36 x 2.5 = 25.9 m

Bihar STET Paper 2 Physics Mock Test - 6 - Question 18

In a class individual learners differ from each other in terms of:

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 18

The rate of development of an individual child is different from that of another child. This principle is known as the ‘principle of individual differences’. For instance, some children may learn to walk in 8 months, while some may take more than a year to start walking. 

It is important for teachers to know variables such as physical characteristics, intelligence, perception, gender, ability, learning styles, which are individual differences of learners. An effective and productive learning-teaching process can be planned by considering these individual differences of students.

Bihar STET Paper 2 Physics Mock Test - 6 - Question 19
According to NEP‐2020, National Research Foundation (NRF) may be established to
Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 19

The NRF (National Research Foundation) will be governed, independently of the government, by a rotating Board of Governors consisting of the very best researchers and innovators across fields.

Key Points

  •  The goal of the NRF will be to enable a culture of research to permeate through our universities.
  • The primary activities of the NRF will be to:
    •  fund competitive, peer-reviewed grant proposals of all types and across all disciplines.
    •  seed, grow and facilitate research at academic institutions.
    • act as a liaison between researchers and relevant branches of government as well as industry; so as to allow breakthroughs to be optimally brought into policy and/or implementation.
    • recognize outstanding research and progress.

Thus, it is concluded that According to NEP‐2020, National Research Foundation (NRF) may be established to enable a culture of research to permeate through universities.

Bihar STET Paper 2 Physics Mock Test - 6 - Question 20

Which of the following is not a part of universal design for learning guidelines?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 20

Multiple means of discrimination is not a part of universal design for learning guidelines.

Bihar STET Paper 2 Physics Mock Test - 6 - Question 21
A good teacher is one who –
Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 21

Teachers are the most important resources in educational settings. They are the key figures for any changes required in the educational field.

A good teacher is one who teaches in an interesting manner so that children enjoy learning because when a teacher makes learning interesting and enjoyable, it helps learners in the:

  • participating willingly and happily.
  • retaining information for a longer period.
  • assimilating concepts easily and effectively.
  • nurturing their curiosity in the learning process.
  • enhancing skills and understanding of the concept.

Hence, it could be concluded that a good teacher is one who teaches in an interesting manner so that children enjoy learning.

Bihar STET Paper 2 Physics Mock Test - 6 - Question 22
What is the name  of the approach which refers to teacher statements that encourage students to elaborate on an answer - either their own or another students?
Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 22

Related to teacher questioning is the use of teacher probes. Probing or delving occurs when a student does not respond to a teacher's question. Probes are teacher assists that support the student to answer.

Key Points  Probing:

  • Probing helps students to clarify their thinking, surface their reasoning, and explore alternative perspectives or solutions.
  • A probing question makes a student think more deeply about the topic at hand, thereby engaging him/her in more cognitively rigorous instruction.
  • This is especially important for lower-achieving students who may have begun to doubt their own capabilities and withhold effort.
  • Seeing their teachers make a special effort to help them can enhance students’ self-confidence and willingness to exert effort in learning.
  • The question stems that follow are examples of teacher probes that can support students to think more deeply.

Hence, the approach that encourages students to elaborate on an answer - either their own or another student is called probing.

Additional Information

  • Structuring is defined by Hospel and Galand (2016) as “the amount and the clarity of information given to students about how to satisfy teachers' expectations and achieve the desired educational outcomes.
  • Teacher task orientation is a key behavior that refers to how much classroom time the teacher devotes to the task of teaching.
    • The more time dedicated to the task of teaching a specific topic, the greater the opportunity students have to learn.
  • Remediation is also colloquially known as “re-teaching,” as it assumes that the student has been introduced to concepts previously but has not yet mastered them.
    • Remediation enables teachers to spot blind spots in students' learning and quickly assess and correct them.
Bihar STET Paper 2 Physics Mock Test - 6 - Question 23

Spontaneity is the hallmark of which of the following sessions?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 23

Brainstorming is a creative group work in which group members produce large number of ideas quickly on a given topic or problems for subsequent evaluation. In this method, anyone can exchange remarks with anyone except that the participants are not allowed to criticize the ideas. Sometimes, quantity of ideas is more important than quality. Spontaneity is the hallmark of brainstorming sessions. On the spot ideas are expected.

Bihar STET Paper 2 Physics Mock Test - 6 - Question 24
What are the changes required to be made in RTE 2009 as per NEP 2020?
Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 24

The National Education Policy (NEP) was approved by the Union Cabinet in July 2020 and aims to implement various improvements to the Indian educational system from the school level to the college level.

Key Points

  • According to NEP 2020, Children from 3 to 18 years old will have access to a free and compulsory high-quality education.
  • This implies that all children between the ages of 3 and 18 will be entitled to receive a quality education from the government, regardless of their socioeconomic status.
  • Everyone has access to get-quality education for all children from the age of 3-18 years instead of 6-14 years as per the RTE 2009.

 Therefore, the Arrangement of free and compulsory education for 3-18-year-old students are the changes required to be made in RTE 2009 as per NEP 2020.

Additional Information

  • Right to Education Act (RTE) provided free and compulsory education to children between the age group of 6-14 years in 2009 and enforced it as a fundamental right under Article 21-A.
  • India became one of 135 countries to make education a fundamental right of every child when the Act came into force on 1 April 2010.
Bihar STET Paper 2 Physics Mock Test - 6 - Question 25

Mr. Ajay mostly takes aid of black board for explaining tough topics. By doing so he is aiming at
a. making his subject interesting
b. simplifying the tough topics
c. keeping the speed of the lecture moderate

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 25

All the statements are correct. Black board is a primary teaching aid in a classroom. It makes the subject interesting for pupils. It also simplifies the tough topics and keeps the pace of the lecture moderate as it encourages writing while talking and hence making teaching effective.

Bihar STET Paper 2 Physics Mock Test - 6 - Question 26

How does NEP 2020 address the issue of school infrastructure development?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 26

NEP 2020 encourages private investment in school infrastructure development to improve facilities and resources.

Bihar STET Paper 2 Physics Mock Test - 6 - Question 27

What is ‘Stargate’, recently mentioned in the news?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 27

Microsoft and OpenAI are jointly embarking on a $100 billion project to create “Stargate,” an AI supercomputer. Scheduled for launch in 2028, it follows OpenAI’s AI upgrade in 2022. The project aims to surpass existing data centers’ capabilities by 100 times. Divided into five phases, with Stargate as the fifth, a smaller fourth-phase supercomputer is slated for release in 2026. Significant costs will be allocated to acquiring essential AI chips.

Bihar STET Paper 2 Physics Mock Test - 6 - Question 28

Which of the following is known as `Blue Planet`?  

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 28

Around 71 for each penny of Earth is secured with water. Earth is the main planet where water can exist in fluid structure.

Bihar STET Paper 2 Physics Mock Test - 6 - Question 29

In the villages of Bihar, many farmers do bee-keeping and collect honey to earn extra money. The best time to start bee-keeping is:

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 29

The tradition of bee-keeping in Bihar is very old. The period of October to December is considered as the best to start bee-keeping because at that time number of flowering and crop plants is more. So bees will get nectar and pollen easily to increase the production of honey. There was a setback to the bee-keeping industry in the 1980s due to the disease caused by the Thai sacbrood virus.
Hence, the correct answer is, 'October to December.'

Bihar STET Paper 2 Physics Mock Test - 6 - Question 30

Pipes M and N can fill a tank in 30 and 120 minutes respectively. If both the pipes are opened together, in how many minutes will the tank be filled?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 6 - Question 30


Hence, Option B is correct.

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