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Bihar STET Paper 2 Physics Mock Test - 10 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test - Bihar STET Paper 2 Physics Mock Test - 10

Bihar STET Paper 2 Physics Mock Test - 10 for Bihar PGT/TGT/PRT 2024 is part of Bihar PGT/TGT/PRT preparation. The Bihar STET Paper 2 Physics Mock Test - 10 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 2 Physics Mock Test - 10 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 2 Physics Mock Test - 10 below.
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Bihar STET Paper 2 Physics Mock Test - 10 - Question 1

Find the true statement.

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 1

The magnetic susceptibility of diamagnetic materials doesn’t depend upon temperature. This is often because there’s an outsized barrier between the bottom state and therefore the excited states of diamagnetic substances. Hence, it remains constant during the change of temperature. All the other statements are false.

Bihar STET Paper 2 Physics Mock Test - 10 - Question 2

Kinetic theory relates measurable properties.

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 2

Explanation:Kinetic theory explains the behaviour of gases based on the idea that the gas consists of rapidly moving atoms or molecules. It also relates measurable properties of gases such as viscosity, conduction and diffusion with molecular parameters, yielding estimates of molecular sizes and masses.

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Bihar STET Paper 2 Physics Mock Test - 10 - Question 3

Let nr and nb be respectively the number of photons emitted by a red bulb and a blue bulb of equal power in a given time.

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 3

Since, Pr​=Pb​ 
r for red and b for blue.
Pr​=Pb​
or, nr​× (hc/λr)  ​=nb​× (hc​/λb)​
or,  ​(nr/nb)​​= λr​​/λb
Since, the wavelength of red bulb is greater than the wavelength of blue bulb.
or,  nr​>nb

*Answer can only contain numeric values
Bihar STET Paper 2 Physics Mock Test - 10 - Question 4

A bob of mass m, suspended by a string of length ℓ1 is given a minimum velocity required to complete a full circle in the vertical plane. At the highest point, it collides elastically with another bob of mass m  suspended by a string of length ℓ2, which is initially at rest. Both the strings are mass-less and inextensible. If the second bob, after collision acquires the minimum speed required to complete a full circle in the vertical plane, the ratio ℓ1/ℓ2 is.


Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 4

Bihar STET Paper 2 Physics Mock Test - 10 - Question 5

In which of the models An atom has a nearly continuous mass distribution?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 5

An atom has a nearly continuous mass distribution in Thomson’s model, but has a highly non-uniform mass distribution in Rutherford’s model.

Bihar STET Paper 2 Physics Mock Test - 10 - Question 6

If the force acting on a point charge kept on the axis of an electric dipole is F, what will be the amount of force if the distance of the point charge is doubled from the dipole?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 6

If the distance of a point charge, kept on the axis of a dipole, is sufficiently large than the separation between the charges of a dipole, then it can be shown that electric field E at a distance r from the dipole varies as E α 1/r3. Now if the distance becomes 2r, electric field intensity will decrease by a factor of 23=8 times. Therefore the force F will now become F/8.

Bihar STET Paper 2 Physics Mock Test - 10 - Question 7

A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will be

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 7

L =0.14
E=100sin(100t)
⇒XL​=wL​=100×0.1
=10Ω
⇒io​=Eo/XL​=100/10​=10A
⇒i=io​sin(100t− π/2​)
⇒i=−io​sin[(π/2)​−100]
So we get
⇒i=−10cos(100t)A
therefore, option D is correct.

Bihar STET Paper 2 Physics Mock Test - 10 - Question 8

An angular ring with inner and outer radii R1 and R2 is rolling without slipping with a uniform angular speed. The ratio of the forces experienced by the two particles situated on the inner and outer parts of the ring,  is                                               

[AIEEE 2005]

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 8

Since ω is constant, v would also be constant.
So, no net force or torque is acting on ring. The force experienced by any particle is only along radial direction, or we can say the centripetal force.

The force experienced by inner part, F1 = mω2Rand the force experienced by outer part, 

*Answer can only contain numeric values
Bihar STET Paper 2 Physics Mock Test - 10 - Question 9

In the circuit in figure we have ε1 = ε2 = 100V, R1 = 20Ω, R2 = 10 Ω, R3 = 40 Ω and R4 = 30 Ω. Find the reading of the ammeter (in A). Disregard the resistance of the battery and the ammeter.


Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 9


Bihar STET Paper 2 Physics Mock Test - 10 - Question 10

The SI unit of the universal gravitational constant G is

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 10

We know that,       g = G. m1 m2 / r2
Where we know g has dimensions of acceleration
Thus [G] = [ g.r2 /m1 m2]
= N m2kg-2

Bihar STET Paper 2 Physics Mock Test - 10 - Question 11

Consider a thin square sheet of side L and thickness t, made of a material of resistivity ρ. The resistance between two opposite faces, shown by the shaded areas in the figure is

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 11

We know that R=ρ l/a

Where l is the length of the conductor through which the current flows and a is the area of cross section.

Here l = L and a = L × t

∴ R is independent of L

Bihar STET Paper 2 Physics Mock Test - 10 - Question 12

Estimate the distance for which ray optics is good approximation for an aperture of 4 mm and wavelength 400 nm.

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 12

Here,
Aperture, a = 4 mm = 4 × 10-3 m
Wavelength, λ = 400 nm = 400 × 10-9 m = 4 × 10-7 m 

Ray optics is good approximation upto distances equal to Fresnel's distance (ZF).
Fresnel's distance is given by,

Bihar STET Paper 2 Physics Mock Test - 10 - Question 13

A rectangular loop and a circular loop are moving out of a uniform magnetic field region to a field-free region with a constant velocity v as shown in fig. In which loop do you except  the induced EMF to be constant during the passage out of the field region if the field is normal to the loops.

 

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 13

Explanation:The induced EMF is expected to be constant in the case of a rectangular loop. In case of a circular loop, the rate of change of area of the loop during the passage out of the field region is not constant, whereas it is constant for rectangular loop.

Bihar STET Paper 2 Physics Mock Test - 10 - Question 14

The quantity which remains unchanged during the flight of an oblique projectile is

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 14

As there is no horizontal acceleration is present in oblique projection horizontal component of velocity is constant

Bihar STET Paper 2 Physics Mock Test - 10 - Question 15

Four liters of a diatomic ideal gas ( λ =1.4) confined to a cylinder is subject to a closed cycle. Initially, the gas is at 1.00 atm and at 300 K. First, its pressure is tripled under constant volume. Then, it expands adiabatically to its original pressure. Finally, the gas is compressed isobarically to its original volume. Find the temperature at the end of the cycle

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 15

Bihar STET Paper 2 Physics Mock Test - 10 - Question 16

An electric dipole is placed at an angle of 30° with an electric field intensity 2 × 105 N/C. It experiences a torque equal to 4 N m. The charge on the dipole, if the dipole length is 2 cm, is

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 16

Torque on a dipole kept in external electric field is given by the expression,

Bihar STET Paper 2 Physics Mock Test - 10 - Question 17

What is the main source of energy of the sun?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 17

Like most stars, the sun is made up mostly of hydrogen and helium atoms in a plasma state. The sun generates energy from a process called nuclear fusion. During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons.

Bihar STET Paper 2 Physics Mock Test - 10 - Question 18

Derived units:

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 18

Derived units are units which may be expressed in terms of base units by means of mathematical symbols of multiplication and division.
Example: the SI derived unit of area is the square metre (m​​​​​​2), and the SI derived unit of density is the kilogram per cubic metre (kg/m3 or kg m​​​​​​-3).

The names of SI units are written in lowercase.

Bihar STET Paper 2 Physics Mock Test - 10 - Question 19

Davisson and Germer experiment proves the

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 19

The Davisson-Germer experiment demonstrated the wave nature of the electron, confirming the earlier hypothesis of deBroglie. Putting wave-particle duality on a firm experimental footing, it represented a major step forward in the development of quantum mechanics. The Bragg law for diffraction had been applied to x-ray diffraction, but this was the first application to particle waves.

Bihar STET Paper 2 Physics Mock Test - 10 - Question 20

Vectors can be added by

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 20

Explanation:Vector addition is the operation of adding two or more vectors together into a vector sum. The so-called parallelogram law gives the rule for vector addition of two or more vectors. For two vectors, the vector sum is obtained by placing them head to tail and drawing the vector from the free tail to the free head.

Bihar STET Paper 2 Physics Mock Test - 10 - Question 21

A non-planar loop of conducting wire carrying a current I is placed as shown in the figure. Each of the straight sections of the loop is of length 2a. The magnetic field due to this loop at the point P(a, 0, a) points in the direction

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 21

NOTE : If we take individual length for the purpose of calculating the magnetic field in a 3-Dimensional figure then it will be difficult.
Here a smart choice is divide the loop into two loops.
One loop is ADEFA in y-z plane and the other loop will be ABCDA in the x – y plane.

We actually do not have any current in the segment AD. By choosing the loops we find that in one loop we have to take current from A to D and in the other one from D to A. Hence these two cancel out the effect of each other as far as creating magnetic field at the concerned point P is considered.
The point (a, 0, a) is in the X-Z plane.
The magnetic field due to current in ABCDA will be in + ve Z-direction.

NOTE : Due to symmetry the y-components and xcomponents will cancel out each other.
Similarly the magnetic field due to current in ADEFA will be  in x-direction.

∴ The resultant magnetic field will be

Bihar STET Paper 2 Physics Mock Test - 10 - Question 22

The distance of distinct vision of a person is 50 cm. He wants to read a book placed at 25 cm. What should be the focal length of the spectacles?​

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 22

'u' should be the least distance of distinct vision.
U=-25cm
V=-50
(1/f)=(1/v)-(1/u)
=(-1/50) + (1/25)
=1/50
F=50cm
Hence a convex lens of focal length 50cm should be used.
 

Bihar STET Paper 2 Physics Mock Test - 10 - Question 23

In constructing a large mobile, an artist hangs an aluminum sphere of mass 6.0 kg from a vertical steel wire 0.50 m long and 2.5 × 10−3 cm2in cross-sectional area. On the bottom of the sphere he attaches a similar steel wire, from which he hangs a brass cube of mass 10.0 kg. Compute the elongation.

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 23

Hence 1.6 mm upper, 1.0 mm lower is correct.

Bihar STET Paper 2 Physics Mock Test - 10 - Question 24

A concave mirror gives an image three times as large as the object placed at a distance of 20 cm from it. For the image to be real, the focal length should be

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 24

Given, u=−20cm
m=−3⇒−v/u ​=−3
v=−60cm
1/f=(1/v​)+(1/u)​=(-1/60)​−(1/20)​=−1−3/60​
f=−60/4​=−15cm
 

Bihar STET Paper 2 Physics Mock Test - 10 - Question 25

Mrs. Geeta wants to foster creativity and imagination power of her students. Which of the teaching aids given below can play a vital role in fulfilling this role?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 25

Flannel boards can be used to foster creativity and imagination power of the students. These boards can be used to display creativity of the students. They also provide a better opportunity to develop lessons.

Bihar STET Paper 2 Physics Mock Test - 10 - Question 26
Which of the following method is based on learning-central approach of Education?
Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 26

A learner-centered approach places the learner at the center of the learning process, emphasizing active engagement and personalized learning.

Key Points

  • Activity-based scaffolding is an approach to teaching that involves breaking down complex tasks into smaller, more manageable parts and providing support as needed to help students develop the skills they need to complete those tasks independently.
  • Activity-based scaffolding is particularly effective for helping students develop complex skills and knowledge.

Thus, it is based on  is based on the learner-centered approach of Education.

Additional Information

  • Lecturing-demonstration is a teaching method in which the teacher presents information to the students, often using visual aids or hands-on demonstrations.
  • Joyful method is not a commonly used term in education, but it may refer to teaching methods that emphasize fun and engagement in the learning process.
  • Inductive method is a teaching method that involves presenting specific examples and then drawing general conclusions based on those examples.
Bihar STET Paper 2 Physics Mock Test - 10 - Question 27
What instructional adaptations should a teacher make while working with students who are ‘Visually Challenged’?
Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 27

The child with Special Need: Also known as a specially-abled child, a child with special needs is the one who needs special attention and requires necessities that other children do not. There are many types of special needs one of which is for visually impaired children.

  • A visually challenged child is the one who has a problem seeing with the naked eyes or is not able to see completely.

Important Points

Instruction adaptations that a teacher can follow while working with students who are ‘visually challenged’ are:

  • Should speak clearly and audibly to help them learn through listening or auditory learning
  • Use a lot of touches and feel materials.
    • Make use of material adaptations according to the individual needs, the actual degree of functional vision, presence of any other disabilities
    • Using a variety of tactile materials like rough or smooth, cold or hot, wet or dry, vibrate or stationary helps the students to touch, feel, and understand the differences between the materials
  • Break the entire learning process into smaller units
  • Provide ample time for the challenged learner to learn in his/her own way
  • Provide support and independence wherever necessary
  • Braille, tactile symbols, large prints, recorded materials, etc. can be used as teaching aids for visually challenged learners
  • A touch and feel tool for the visually challenged person

Hence, we can conclude that a teacher should speak clearly and use a lot of touches and feel materials while working with students who are ‘Visually Challenged’.

Bihar STET Paper 2 Physics Mock Test - 10 - Question 28
Which of these is/are an advantages/s of activity-based learning?
Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 28

Activity-based learning is a ‘learner-centred’ approach in the teaching-learning process. In this approach, the ‘learner’ or ‘child’ and not the ‘teacher’ is the main focus of the educational program. It emphasizes ‘learning’ rather than ‘teaching’.

  • Activity-based learning integrates multiple methods of teaching like Demonstration, Role-play, Brainstorming, Project method, Debate, etc.
  • Activity-based learning brings the real issues and problems from day-to-day life in classroom settings.
  • It provide provides opportunities to apply multiple senses.
  • It includes all objects, events, natural phenomena and social surroundings in the teaching-learning process.
  • It clarifies abstract concepts, develops concrete thinking and brings reality in real settings.
  • During activity-based learning, the learners use his/her multiple senses to understand the concepts and enhance learning.
  • It arouses the child’s interests, abilities, and needs during the learning process.

Hence, we conclude that all the above points are the advantages of the activity-based learning.

Bihar STET Paper 2 Physics Mock Test - 10 - Question 29

Which case is famous for the definition of basic structure of the Indian Constitution?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 29
  • Kesavananda Bharati Case is a landmark case where the Supreme Court defined the basic structure of the Indian Constitution. The judgement for this case was delivered on April 24, 1973.
  • The case is also known as the Fundamental Rights Case. The Supreme Court asserted its right to strike down amendments to the constitution that were in violation of the fundamental architecture of the constitution.
Bihar STET Paper 2 Physics Mock Test - 10 - Question 30

30 liters of water is added to a 120 liters mixture containing 40% of alcohol. What is the percentage concentration of alcohol in the resultant mixture?

Detailed Solution for Bihar STET Paper 2 Physics Mock Test - 10 - Question 30

Alcohol = 40% of 120 = 48

Hence, Option C is correct.

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