KVS TGT Math Mock Test - 1 - KVS PGT/TGT/PRT MCQ

The Buddhist Monuments at Sanchi are located in the state of Madhya Pradesh. These monuments, including stupas, temples, and monasteries, date back to the 3rd century BCE and are significant for their association with Buddhism and Emperor Ashoka. Sanchi is an important pilgrimage site for Buddhists and showcases the architectural and artistic achievements of ancient India.

Laxminarayan Temple, also known as the Birla Mandir, is situated in Delhi and is dedicated to Lord Vishnu.

Largest Auditorium in India: Sri Shanmukhananda Hall (Mumbai)
Some key points about Sri Shanmukhananda Hall and why it is considered the largest auditorium in India:
- Located in Mumbai, Sri Shanmukhananda Hall is a renowned auditorium known for its grandeur and capacity.
- Capacity: The auditorium can accommodate around 3,500 people, making it one of the largest in India.
- Infrastructure: The hall boasts a spacious stage and excellent acoustics, which enhance the overall experience for both performers and the audience.
- Cultural hub: Sri Shanmukhananda Hall is not only known for hosting various cultural events but also for promoting and preserving Indian classical music and dance forms.
- History: The hall was inaugurated in 1952 and has since been a significant venue for cultural activities and performances.
- Facilities: The auditorium is equipped with modern amenities, including comfortable seating, sound systems, and lighting arrangements, ensuring a top-notch experience for visitors.
- Events: Sri Shanmukhananda Hall has witnessed numerous prestigious events, including concerts, dance recitals, theater shows, and conferences.
Overall, Sri Shanmukhananda Hall in Mumbai stands out as the largest auditorium in India due to its impressive capacity, infrastructure, cultural significance, and state-of-the-art facilities.

Data Transfer Rate for USB 2.0:

• USB 2.0: The data transfer rate for USB 2.0 is 480 Mbps (megabits per second).

Explanation:

• USB 2.0: USB 2.0 is a widely used standard for connecting devices to a computer. It is an upgraded version of USB 1.1 and offers faster data transfer speeds.


• Data Transfer Rate: The data transfer rate refers to the speed at which data can be transmitted between devices through the USB connection.


• 480 Mbps: USB 2.0 supports a maximum data transfer rate of 480 Mbps. This means that data can be transferred at a speed of up to 480 megabits per second.


• Comparison: The other options provided (512 Mbps and 520 Mbps) are not correct as they do not match the actual data transfer rate of USB 2.0.

Summary:

Therefore, the correct answer is option A: 480 Mbps. USB 2.0 has a data transfer rate of 480 Mbps, allowing for faster and more efficient data transfer between devices.

Adolescence is the process of growing up from childhood into adulthood. Psychologists have given some age range, 13 to 18 years, for this period. The World Health Organisation (WHO) has given this range from 10 to 19 years. During this stage, the daydreaming is very high.

Key Points Day-dreaming means to live in a world of fantasy - a world of imagination devoid of any reality. It is 'building castle in the air'. It is more prevalent when one goes into his/her own shell when one withdraws.

• It is the main characteristic of adolescence.
• During adolscence, the students adopt in day-dreaming are heroic.
• It is a mental activity than a physical.
• It is a normal active common practice.
• We all are engaged in day-dreaming at one time or the other.
• It gives us a sort of relaxation in this world of competition and tension. But, if it crosses a limit, it becomes pathological; and some adolescents fall in this category. Then, it leads to maladjustment.

Hence, we can conclude that It involves more physical activity than mental is not true about Day Dreaming among adolescents.

Vygotsky is known as the proposer of social constructivism. Social Constructivism approach talks of the importance of social interaction and context in learning. He believes that learning is social in nature. Through interactions, children shared their views and make their own meanings.

 Key Points

• Vygotsky's theory emphasizes that social interactions can facilitate learners' progression to more advanced ways of thinking and problem-solving.
• Collaborative projects are best for assessing students.
• The Zone of Proximal Development hypothesis of Lev Vygotsky serves as the foundation for collaborative learning.
• It is important for fostering critical thinking abilities, with research suggesting that group participation helps kids remember knowledge better.
• Enables deeper thinking in the classroom through peer-to-peer learning.
• According to collaborative learning theory, group learning aids in the development of students' leadership, self-management, oral communication, and higher-level cognitive abilities.
• Additionally, students get the chance to hone their leadership and planning abilities.

Hence, it is concluded that according to the social constructivist theory of Lev Vygotsky, collaboration project methods are appropriate for assessing students.

Mislearning means to learn incorrectly or to acquire incorrect knowledge. The best feedback about mislearning is obtained through diagnostic testing.

Important Points

Diagnostic testing:

• when a patient comes to a doctor, the doctor initially puts some questions to the patient to gather some basic information’s about the disease and then uses other techniques to get more related information to identify the disease and its probable cause(s). After careful analysis of these data, he prescribes the medicines as remedial treatment. Similarly, In the field of education, the diagnosis has many such implications. Difficulties in learning occur frequently at all levels and among pupils of both high and low mental ability.
• In order to handle such cases, the teacher also uses similar techniques like a doctor to diagnose the relative strengths and weaknesses of the pupil in the specific area of study, analyse the causes for the same and then provides remedial measures as per necessity.
• Diagnostic test is a test used to diagnose strength and weakness of the learning in certain areas of study whereas diagnostic evaluation is centered on the schooling process such as the curriculum program, administration, and so on.
• When learning difficulties that are left unresolved by the standard corrective prescriptions of formative evaluation and a pupil continues to experience failure despite the use of prescribed alternative methods of instruction, then a more detailed diagnosis is indicated.

Key Points

Features of diagnostic testing:

• The diagnostic test takes up where the formative test leaves off.
• A diagnostic test is a means by which an individual profile is examined and compared against certain norms or criteria.
• The diagnostic test focuses on an individual’s educational weakness or learning deficiency and identifies the gaps in pupils.
• Diagnostic test is more intensive and act as a tool for analysis of Learning Difficulties.
• Diagnostic test is more often limited to low ability students.
• Diagnostic tests pinpoints the specific types of error each pupil is making and searches for underlying causes of the problem.
• Diagnostic test helps us to identify the trouble spots and discovered those areas of students weakness that are unresolved by formative test.

Lesson plans also have a great effect on the teaching process. It provides clarity on the decisions to be made to help students move toward learner goals. It provides a professional base for the work at hand, namely, teaching. It makes them feel that the teacher is well-organized and is concerned about their learning.

Key Points While preparing a lesson plan on the topic 'Agriculture" Frame objectives will be your first step.

Thus, it is concluded that preparing a lesson plan on the topic 'Agriculture" Frame objectives will be your first step.      

In the teaching-learning process, visually impaired children suffer from an issue with sight or vision but when they are facilitated with the right training and tools, they develop a good literacy ability. ​

Key Points

Let's look at some strategies for adapting materials for students with visual impairments:

• Text: The kind of text adaptations you make will depend on your students' individual needs and preferences. Some examples are braille, large print, assistive devices, tactile books, and audiobooks.
• Braille: Some students may read braille, in which case you should include a variety of braille books in your classroom library. Another option is to purchase braille-print books, which have both braille and printed text on each page so that sighted students and adults can read along with students who have visual impairments.
• Large Print Books and Assistive Devices: Large print books can be helpful for students with limited vision. Some students may also wish to use their assistive devices to help them view regular print.
• Tactile globe: In spite of the importance of the globe as an educational and cultural tool, for visually impaired users, common globes are just spherical objects. Although there are commercially available globes for visually impaired users. These globes have convex and concave features on the surface denoting coastlines and country borders which will useful for visually impaired students. 
• Screen reading software: Screen readers are software programs that allow blind or visually impaired users to read the text that is displayed on the computer screen with a speech synthesizer or braille display.

Hint 

• Books with small prints will not help visually impaired students and will hinder the learning of visually impaired students.

Hence, we can conclude that the books with small print will NOT be beneficial for a student with visual impairment.

The National Education Policy 2020 proposes various reforms in school education as well as higher education including technical education. A number of action points/activities for implementation in school education as well as higher education are mentioned in the National Education Policy 2020.

Key Points As per National education policy 2020:

• School education must focus on facilitating multiple pathways to learning involving Formal, and non-formal education.
• New Curricular and Pedagogical Structure (5+3+3+4) and ensuring quality early childhood care and education for all children between 3-6 years.
• No hard separations between arts and sciences, between curricular and extra-curricular activities, and between vocational and academic streams.
• Hence we conclude that to facilitate learning for all students, with special emphasis on SDGs, the scope of school education will be broadened to facilitate multiple pathways to learning involving Formal, and non-formal education.

Important Points  Details of the salient features of NEP 2020 are as follows-

• Establishing National Mission on Foundational Literacy and Numeracy.
• Emphasis on promoting multilingualism and Indian languages.
• Assessment reforms - Board Exams on up to two occasions during any given school year, one main examination and one for improvement.
• Setting up of a new National Assessment Centre, PARAKH (Performance Assessment, Review, and Analysis of Knowledge for Holistic Development).

Answer:

<DBC = 38°

Step-by-step explanation:

Given:

ABCD is a parallelogram .

AC,BD diagonals intersecting at "O".

<DAC = 32°, <AOB = 70°

Proof:

i) AB//DC , AC is a transversal.

<DAC = <BCA = 32°

/* Alternate angles */

ii) In ∆BCO , CO extended to A.

Sum of interior opposite angles = Exterior angle at O

=> <BCA + <OBC = <AOB

=> <BCA + <DBC = <AOB

=> 32° + <DBC = 70°

=> <DBC = 70°-32°

=> <DBC = 38°

Given that PQRS and ABCD are rectangle and Q is the mid pt of AC.

Since PQRS and ABCD are rectangle, every angle would be of 90°.

Consider AD and PQ.

angle ADP = 90°
angle QPC = 90°

Now, angle ADP lies corresponding to angle QPC and are equal.

If corresponding angles are equal, then the lines are parallel


=> AD || PQ

Now consider ∆ADC.

Q is the midpoint of AC (Given)
AD || PQ (shown above)

We know that,
line drawn parallel from the midpoint of a side, to other side, bisects the third side.

Hence, P would be the midpoint of DC

Hence, DP = PC

X=50,x+y=127(exterior angle theorem)50+y=127y=127-50y=77

We know Probability law which is law of  complement
Which is P(not A)=1-P(A)
Where P(A)=⅖
P(not A)=1-⅖=3/5

Angle acb = 75 ( linear pair) Ab= Ac hence angle B= angle c in triangle ABC angle a+B+c= 180. angle B+ c = 150 hence angle c a= 30

We have a quadratic equation: 

If we have standard equation ax² + bx + c  then D = b² - 4ac

a= 2, b= -√5, c= 1

D = (-√5)² - (4x2x1)

D= 5 - 8

D = -3

As the value of D<0 so there is no real root

Surface area of a cube = 96 cm²
Surface area of a cube = 6 (Side)² = 96 ⇒  (Side)² = 16
⇒ (Side) = 4 cm
[taking positive square root because side is always a positive quantity]
Volume of cube = (Side)³ = (4)3 = 64 cm³
Hence, the volume of the cube is 64 cm³.

Let one zero of the equation be x
Then, other would be 2x
As we know,
x × 2x = 18
x² = 9
x = 3, -3
Case 1:
If x = 3, 2x = 6
Therefore, -k = sum of roots = 9
⇒ k = -9
Case 2:
If x = -3, 2x = -6
Therefore, -k = -9
⇒ k = 9
So, k can be 9,-9. Therefore, option 'b' is correct.

2x+15+3x-25=180
[co interior angles]
5x-10=180
5x=190
x=38
option d is right answer

Clearly, there are 52 cards, out of which there are 12 face cards.

P (getting a face card) = 12/52 = 3/13.

Theorem: Angles opposite to equal sides of an isosceles triangle are equal.

Trigonometric ratio  is correct.

Let one zero of the given polynomial be athen the other zero be 
⇒ k + 4 = 3k ⇒ 2k = 4 ⇒ k = 2

Number of consonants = 21
Number of total outcomes = 26
∴ Required Probability = 21/26

Number of workers = x

Number of workers when increased by 2 = x + 2

∴ Number of boxes prepared by the workers

(x + 2) = (x + 3) [2 + 3 (x + 2)

= 7 [2 + 3 × 7] [∵ x = 5]

= 7 × 23

= 161.

Mode=L+ 
Where L=lower limit of the modal class =40
f1= modal class frequency.=7
f2 = just after the modal class frequency.=6
f0 = just previous the modal class frequency=3
C = Class size=15
Mode=40+ * 15 = 40 + 12 = 52

Given:

BE = CD

Concept Used:

When 2 sides of a triangle are equal, then it is isosceles.

When 2 angles and 1 side of 2 triangles is equal, then both the triangles are similar.

Calculations:

In △ABE and △ACD,

BE = CD (Given)

∠BEA = ∠CDA (90° each)

∠BAE = ∠CAD (Common Angle)

∠ABE = ∠ACE (By Sum angle property)

⇒ △ABE is similar to △ACD

⇒ AB = AC

∴ If the altitudes from two vertices of a triangle to the opposite sides are equal, then the triangle is isosceles.