Test: Introduction To Probability - JEE MCQ

Above information has no common element in three of them and U of three sets forms sample set . Therefore option C is correct.

Intersection of two sets A ∩ B is the set of those elements which are common to both A and B. i.e., which belong to both ‘A and B’. 
If A and B are two events, then the set A ∩ B denotes the event ‘A and B’.

Compound Event If an event has more than one sample point it is called a compound event, for example, S = {HH, HT} is a compound event.

Elements {2,4,6,8,10}
A person draws two slips from the box, one after the other, without replacement:
Sample Space ={(2,4) (2,6) (2,8) (2,10) (4,2) (4,6) (4,8) (4,10) (6,2) (6,4) (6,8) (6,10) (8,2) (8,4) (8,6) (8,10) (10,2) (10,4) (10,6) (10,8)}

If 2/7 is probability of event A then the probability of an event not A is 1-(2/7) i.e.,    probability of not A is 5/7

After the experiment, the result of the random experiment is known. An outcome is a result of a random experiment. The set of all possible outcomes is called the sample space.

Probability that Amit will qualify the exam(E) = 0.06
Probability that Priyanka will qualify the exam(F) = 0.12
Probability that both will qualify the exam P(E⋂F) = 0.02
P(EUF) = P(E) + P(F) - P(EUF)
= 0.06 + 0.12 - 0.02   = 0.16
P(E’⋂F’) = 1 - P(EUF)
⇒ 1 - 0.16
= 0.84

These are the only 6 possible outcomes:1,2,3,4,5,6.

Mutually exclusive means no common event.
if 2 comes on either dive then sum can't be greater than 8.It will always less than or equal to 8.
So mutually exclusive.

Probability of getting atleast one green = 1- probability of getting no green = 1-(30C₅/60C₅) = 4367/4484