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BEL Trainee Engineer Electronics Mock Test - 10 - Electronics and Communication Engineering (ECE) MCQ


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30 Questions MCQ Test - BEL Trainee Engineer Electronics Mock Test - 10

BEL Trainee Engineer Electronics Mock Test - 10 for Electronics and Communication Engineering (ECE) 2025 is part of Electronics and Communication Engineering (ECE) preparation. The BEL Trainee Engineer Electronics Mock Test - 10 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The BEL Trainee Engineer Electronics Mock Test - 10 MCQs are made for Electronics and Communication Engineering (ECE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for BEL Trainee Engineer Electronics Mock Test - 10 below.
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BEL Trainee Engineer Electronics Mock Test - 10 - Question 1

Which of the following BCD code, is a sequential code and therefore can be used for arithmetic operations as well as has six invalid states 0000, 0001, 0010, 1101, 1110 and 1111?

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 1
  • Excess 3 code is a 4-bit code.
  • It can be derived from the BCD code by adding ‘3’ to each coded number. Thus, in excess 3 code 0011 is added to each BCD number.
  • It is an un-weighted code.
  • It is a self-complimenting code i.e. the 1’s complement of an excess three number is the excess 3 code for the 9’s complement of the corresponding decimal number.
BEL Trainee Engineer Electronics Mock Test - 10 - Question 2

A series RLC circuit with capacitor initially charged to voltage Vo as shown in the figure. The current i(t) is -

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 2

Solution

Concept

For ; t > 0sec

  • the following circuit is converted into its S domain equivalent 
  • The circuit current is calculated I(s)
  • The time-domain equivalent i(t) is calculated

Calculation

For t ≤ 0s, capacitor voltage V0=1volt

Inductor current I0= 0 Amp

From the S domain equivalent of the circuit 

We have the current

Can also be written in the form

Using inverse Laplace transform we have

⇒ i(t) = e−t sin t u(t) Amp

Hence the correct answer is option 2

BEL Trainee Engineer Electronics Mock Test - 10 - Question 3

The Eddy current loss is proportional to the

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 3

Concept:

  • When an alternating magnetic field is applied to a magnetic material, an emf is induced in the material itself according to Faraday’s law of Electromagnetic induction.
  • Since the magnetic material is a conducting material, these EMF’s circulates current within the body of the material. These circulating currents are called Eddy currents. They are produced when the conductor experiences a changing magnetic field.

Eddy current loss in the transformer is given by:

Pe = Ke Bm2. t2. f2. V Watts

Where;

K - coefficient of eddy current. Its value depends upon the nature of magnetic material

Bm - Maximum value of flux density in Wb/m2

t - Thickness of lamination in meters

f - Frequency of reversal of the magnetic field in Hz

V - Volume of magnetic material in m3

From the above formula we conclude that the Eddy current loss is proportional to the square of the frequency.
BEL Trainee Engineer Electronics Mock Test - 10 - Question 4

What is the maximum frequency of modulating signal in FM system, if it has 8 significant sidebands, and the maximum bandwidth is 32 kHz?

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 4

Concept:

WBFM is given as:

Actual BW of WBFM is ∞ so to Bandlimit WBFM signal all of its significant lower-order sidebands retained and higher-order insignificant sidebands should be eliminated.

Calculation:

BW = 32 KHz

Given FM system has 8 sidebands (significant) i.e. 8 sidebands on the positive side of frequency & 8 sidebands on the negative side of the frequency

So, It has sidebands up to order ‘8’.

According to carson rule:

Significant sideband upto order of (β + 1) has B.W

BW = (β + 1) 2f­m

So,

32 = 8 × 2 fm

fm = 2 kHz

BEL Trainee Engineer Electronics Mock Test - 10 - Question 5

A voltmeter has resistance of 2000 Ω, when it is connected across a DC circuit its power consumption is 2 mW. Suppose this voltmeter is replaced by a voltmeter of 4000 Ω resistance, the power consumption will be:

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 5

The correct answer is option "4"
Concept:

The  power consumption is given by 

P =V/ R watts as the voltage across it will be constant.

where 

V is voltage in Volts

R is the resistance

Calculation:

R1 = 2000 Ω

P1 =  2 mW

P = V2/R1

V2 = PR1 = 2 × 10-3 × 2000 = 4 V

V = 2 V

for R2 = 4000 Ω

P = V2/R2

= 22 / 4000 = 1 mW

BEL Trainee Engineer Electronics Mock Test - 10 - Question 6

The impedance of a parallel RLC network is Z(s) = , the value of R, L and C are respectively

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 6

Concept:

The parallel RLC circuit in 's' domain is represented as:

Dividing numerator and denominator by RLC:

..............(i)

Calculation:

Given, Z(s) = .............(ii)

Comparing equations (i) and (ii), we get:

R = 10 Ω 

BEL Trainee Engineer Electronics Mock Test - 10 - Question 7

Consider the purely resistive circuit as shown in Fig. where, VS is the source voltage, RS is the source resistance, RL is the load resistance and IL is the load current. The current at maximum power is equal to _______ of the maximum current.

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 7

Maximum power transfer theorem:

Maximum power transfer theorem states that " In a linear bilateral network if the entire network is represented by its Thevenin's equivalent circuit then the maximum power transferred from source to the load when the load resistance is equal to the Thevenin's resistance.

1)  If source impedance is complex then load impedance has to be a complex conjugate of source impedance for maximum power transfer to occur.

2) Maximum efficiency is not related to maximum power transfer.

3) If the source and load impedances are matched then there are no reflections but maximum power transfer.

Proof: 

Let's consider variable resistive load and Thevenin's equivalent network as shown below,

 

Apply KVL, for the above circuit

VS - IL RS - IL RL = 0

Where

VS is the source or Thevenin's voltage, IL is the load current, RL is the load resistance, RS is the source or Thevenin's resistance

V= I(RS + RL)

IL = Vs / (Rs + RL)

P = ILRL

For maximum power transfer, RL = RS

Then the maximum power transferred is given by

Properties of maximum power transfer theorem:

  • This theorem is applicable only for linear networks i.e networks with R, L, C, transformer, and linear controlled sources as elements.
  • The presence of dependent sources makes the network active and hence, MPPT is used for both active as well as passive networks.
  • This theorem is applicable when the load is variable.

Calculation:

For the given circuit, maximum power transfers at RL = Rs

The current at this condition is, 

The maximum value of current occurs at R = 0 and it is given by, 

Therefore, the current at maximum power is equal to 50% of the maximum current.

BEL Trainee Engineer Electronics Mock Test - 10 - Question 8
If radiation resistance is 200 Ω and operating with 6 A of current at 4 GHz frequency, then what is the power radiated by an antenna?
Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 8

Radiated power(P) is a measure of how much power is radiated by an antenna when the antenna is connected to a transmitter.

Radiated resistance(R) is the component of  antenna resistance that accounts for the power radiated into space and is equal in ohms.

Power radiated by an antenna is calculated by using formula,

P= I2× R

P = (6 × 6) × 200

P = 36 × 200

P = 7200 W

BEL Trainee Engineer Electronics Mock Test - 10 - Question 9

Attenuation per unit length in a coaxial cable with frequency_____.

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 9

More from LMS

For a coaxial cable, the propagation constant is expressed as:

This can be written as:

Γ = α(ω) + β(ω)

R is the resistance per unit length

L is the inductance per unit length

G is the conductance per unit length

C is the capacitance per unit length, ω is the angular frequency = 2πf.

α(ω) and β(ω) are the attenuation and phase constants.

∴ The attenuation per unit length in a coaxial cable increases with an increase in frequency.

BEL Trainee Engineer Electronics Mock Test - 10 - Question 10
A signal of 10 kHz bandwidth is to be transmitted through a channel that introduces 20 dB loss and white noise of two-sided power spectral density 10-9 W/Hz. The minimum received output SNR should be 40 dB. Find the minimum transmitter power if the message is sent by SSB.
Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 10

Concept:-

For SSB the output SNR is:-

Calculation:-

Given,

 

fm = 10 kHz

Channel loss = 20 dB

∴ Si = 104 × 10-9 × 2 × 10 × 103

= 0.2 W

Required minimum signal strength at the receiver input

Si = 0.2 W

Required minimum signal strength at the transmitter output:-

Si × 20 dB = 0.2 × 102 = 20 W

Important note:-

For DBS-C, signal energy available in sideband = 

Then, required minimum output SNR

BEL Trainee Engineer Electronics Mock Test - 10 - Question 11

​What is the resolution of 4­-digit digital measuring instrument? 

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 11

Concept:

Resolution: It is the smallest increment an instrument can detect and display.

  • The resolution for the 'N' bit digital voltmeter is given by:
  • The range of an instrument is the sum of the smallest and the largest number it can display.

Explanation:

For 4­-digit, the smallest and the largest number that can be displayed is:

Range = 1

Resolution = 10-4 = 0.0001

In percentage, the resolution is 0.01%

BEL Trainee Engineer Electronics Mock Test - 10 - Question 12
Which of the following functions has unity as its Fourier transform, Laplace transform and Z – transform?
Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 12

Impulse function is exist only at t= 0 and the area under impulse function is unity

|t=0 = 1

|t=0 = 1

Discrete time Laplace transform is Z- transform.

= |n=0 = 1
BEL Trainee Engineer Electronics Mock Test - 10 - Question 13

According to Gauss theorem, the surface integral of the normal component of electric field intensity E̅ over closed surface containing charge Q is

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 13

CONCEPT:

Gauss law:

  • According to this law, the total flux linked with a closed surface called Gaussian surface is 1/ϵo times the charge enclosed by the closed surface.

  • This law is applicable to all the closed surfaces.
  • According to this law, the total flux linked with a closed surface called Gaussian surface is 1/ϵo times the charge enclosed by the closed surface.
  • So this law is applicable to all the closed surfaces. Hence, option 2 is correct.
BEL Trainee Engineer Electronics Mock Test - 10 - Question 14

Assertion A): In satellite communication, uplink and downlink frequencies are kept different.

Reason R): The uplink frequency is chosen to be of lower value than the down link frequency.

Choose the correct answer:

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 14

In satellite communication, uplink and downlink frequencies are kept different.

Uplink frequency > Downlink frequency

Hence, option C is correct.

Explanation:

  • The transmission of a signal from the first earth station to satellite through a channel is called uplink​.
  • The transmission of a signal from the satellite to the second earth station through a channel is called the downlink.
  • Uplink frequency is the frequency at which, the first earth station is communicating with the satellite.
  • The satellite transponder converts this signal into another frequency and sends it down to the second earth station.
  • This frequency is called Downlink frequency. In a similar way, the second earth station can also communicate with the first one

In the atmosphere, the attenuation is directly proportional to frequency.

Since the satellite cannot afford to have high powers downlink is sent at lower frequencies, while the station at earth can afford to transmit at high frequencies.

BEL Trainee Engineer Electronics Mock Test - 10 - Question 15

Companding is used to

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 15

The smaller the signal strength, the stronger it is hit by the quantization process. Companding is used to protect these small strength signals from quantization noise.

Companding:

  • Companding, also known as Companded PCM, is a non-uniform quantization technique.
  • It is implemented to improve the signal to quantization noise ratio of weak signals.
  • The compression of the signal at the transmitter and expansion at the receiver is combined to be called companding. This is shown in the form of a block diagram:

           

  • Companders like A-law and μ-law Companders are used in PCM to compress signals before input to the ADC in the transmitter stage and expand it after the input to DAC at the receiver.
BEL Trainee Engineer Electronics Mock Test - 10 - Question 16
Mobile communication technology is built with ________.
Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 16

The correct answer is option 4.

Concept:

    Mobile communication refers to the use of technology that enables us to communicate with people in various areas without the need for a physical connection (wires or cables). Our lives are made simpler by mobile communication, which saves us time and effort. Mobile communication technology is built with protocols, speed, and services.

  • Multiplexing is used in mobile communication protocols to transfer data. Multiplexing is a technique for combining numerous digital or analog signals into a single signal that may be sent across a data channel.
  • Mobile Communications Services refers to a variety of retail services that allow Subscribers to interact with others while on the go, such as voice communications, short messages, e-mail, voice mailbox access, and the Internet.
  • Mobile Communication Implementation Techniques to Improve Last-Mile High-Speed FSO Communication. It Improvements can also be seen in speed. The network connectivity or the accessibility was much improved in accuracy and speed.

Hence the correct answer is All the above.

BEL Trainee Engineer Electronics Mock Test - 10 - Question 17

CRC in computer network can be used for ________?

  1. Error correction
  2. Error detection
Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 17
  • A frame check sequence (FCS) refers to an error-detecting code added to a frame in a communications protocol

Layer 2 Frame Format:

Ethernet Frame Format consists of Cyclic Redundancy Check (CRC) in Frame check sequence Field used for error-detection, but CRC can also be used for error correction.

BEL Trainee Engineer Electronics Mock Test - 10 - Question 18

Which of the following is the principle of operation of fibre-optic cable?

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 18

The principle of operation of fibre-optic cable is Reflection.

Key Points

  • In an optical fiber, the information is passed through light, which must not escape outside of it.
  • This phenomenon of confining the light inside the optical fiber is termed as Total internal reflection.
  • For this, the construction and material used to ensure that the total internal reflection of light takes place to prevent the escape of it.

Principle:

  • When light travels from a high refractive index medium to a low-refractive-index medium, it is refracted away from the normal as shown:

          

  • At a certain angle θi, there is no refracted wave and the wave is totally internally reflected  (θ= 90°).
  • This angle is called a critical angle.
  • Inside an optical fiber, we have a high refractive index core (n1) and low refractive index cladding (n2).
  • This results in the propagation of waves inside a fiber through total internal reflection phenomenon.
BEL Trainee Engineer Electronics Mock Test - 10 - Question 19
Which of the following is used in main memory?
Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 19

The correct answer is DRAM.

Key Points

  • DRAM:
    • It is dynamic random access memory and is widely used as a computer's main memory. Hence, Option 2 is correct.
    • Each DRAM memory cell is made up of a transistor and a capacitor within an integrated circuit, and a data bit is stored in the capacitor.
  • DDR-RAM:
    • It stands for Double Data Rate Synchronous Dynamic Random-Access Memory.
    • These are the computer memory that transfers the data twice as fast as regular chips like SDRAM chips because DDR memory can send and receive signals twice per clock cycle as a comparison.
  • SRAM:
    • It stands for Static Random Access Memory.
    • It is a form of a semiconductor.
    • It is widely used in microprocessors, general computing applications, and electronic devices.
    • The SRAM is volatile in nature which means the data stored in it gets all wiped out once the power supply is cut.
    • SRAM is comprised of flip-flops. 
  • PRAM:
    • In computer science, a parallel random-access machine is a shared-memory abstract machine.
    • As its name indicates, the PRAM is intended as the parallel-computing analogy to the random-access machine.
BEL Trainee Engineer Electronics Mock Test - 10 - Question 20

Direction: In this question, you need to replace the underlined part of the sentence with the most suitable idiom / expression given as option.

The press saw the event as a sign of future happening that augured the resumption of diplomatic relations between the two countries.

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 20

Straw in the wind: something believed to be a sign or warning of a future event.
Shot in the arm: something that has a sudden and positive effect on something, providing encouragement and new activity.
Stroke of luck: a fortunate occurrence that could not have been predicted or expected.
Plain sailing: smooth and easy progress in a process or activity.
Hence, the correct answer is option A. 

BEL Trainee Engineer Electronics Mock Test - 10 - Question 21

FTP can be run on:

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 21

FTP can be run on the following operating systems:
- Unix: FTP can be run on Unix operating systems. Unix is a family of multitasking, multiuser computer operating systems that are widely used for servers and workstations.
- Linux: FTP can be run on Linux operating systems. Linux is an open-source operating system that is based on the Unix operating system.
- Dos/Windows: FTP can be run on Dos/Windows operating systems. DOS (Disk Operating System) is an operating system that was popular in the early days of personal computers, while Windows is a widely used operating system developed by Microsoft.
Therefore, the correct answer is option B: Linux, as FTP can be run on Linux operating systems. However, it is important to note that FTP can also be run on Unix and Dos/Windows operating systems, so option D is also correct.
Overall, FTP is a versatile protocol that can be run on various operating systems, allowing users to transfer files between computers over a network.
BEL Trainee Engineer Electronics Mock Test - 10 - Question 22

Device having the largest storage capacity is:-

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 22

Computer stores data on specific memory depending on the importance of that data in processing, frequency of uses of that data, and volume of data being stored. There are two types of memory have been discussed Primary memory and secondary memory:

1) Hard- Disk:

  • sometimes abbreviated as a hard driveHD, or HDD.
  • It is a non-volatile data storage device.
  • Consists of a rigid platter made of aluminum alloy or glass and coated with magnetic material.
  • The single platter is 10-20mm thick with separate read and write heads.
  • It can store up to 2 Terabyte (TB) data.
  • It is rectangular with a length of 3 to 6 inches and the same width with a thickness of 2 to 3 inches.

2) CD-ROM:

  • Thin round plastic plate with one side shining that store the information.
  • It is writable only once.
  • It is economical.
  • Used to take the backup of files.
  • The files cannot be deleted accidentally or by a virus.
  • It can store up to 650 Megabyte (MB) data or information.

3) DVD-ROM:

  • It is a DVD based CD.
  • Digital Versatile Disc-Read Only Memory is a digital optical disc data storage format invented and developed in 1995 and released in late 1996.
  • The medium can store any kind of digital data.
  • It can store up to 4 Gigabyte (GB) information

4) Arithmetic-logic unit (ALU)

  • It is the part of a computer processor (CPU) that carries out arithmetic and logic operations on the operands in computer instruction words.
  • In some processors, the ALU is divided into two units, an arithmetic unit (AU) and a logic unit (LU).

Hence, the Device having the largest storage capacity is Hard Disk.

BEL Trainee Engineer Electronics Mock Test - 10 - Question 23
What is the main folder on a storage device called?
Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 23

The correct answer is option i.e Root Directory.

Key Points

  • The root directory is the top-level directory of a file system.
    • The root directory contains all other folders in the drive or folder.
    • The default root directory in Windows is C:\.

Additional Information

  • A database is a data structure that store organised information electronically in a computer system 
    • Microsoft Access is an application used for database purposes.
  • A cell is the intersection of row and column.
BEL Trainee Engineer Electronics Mock Test - 10 - Question 24
What is the full form of the term 'DBMS' used in Computer Science?
Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 24

The correct answer is Database Management System.Key Points

  • The full form of the term 'DBMS' is Database Management System.
  • A database is a systematic collection of data.
  • They support electronic storage and manipulation of data. 
  • Databases make data management easy. 
  • Database Management System (DBMS) is a collection of programs which enables its users to access database, manipulate data, reporting and representation of data. It also helps to control access to the database. 
  • Database Management Systems are not a new concept and as such, had been first implemented in the 1960s.

Additional Information

Important Abbreviations:

BEL Trainee Engineer Electronics Mock Test - 10 - Question 25

Which of the following is not an archive format?

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 25

The correct answer is .xlsx.

  • .xlsx is the default XML-based file format for Excel 2010 and Excel 2007.
  • Tar, Zip, rar are archive formats.

Additional Information

  • An archive format is the file format of an archive file.
  • Some file types and file extensions are as follows.

BEL Trainee Engineer Electronics Mock Test - 10 - Question 26

Select the odd letter from the given alternatives

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 26

The logic is :

1) BEH

2) KNR

3) GJM

4) TWZ

Hence, 'KNR' is the odd letter.

BEL Trainee Engineer Electronics Mock Test - 10 - Question 27

Which answer figure will complete the pattern in the question figure?

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 27

BEL Trainee Engineer Electronics Mock Test - 10 - Question 28
‘Knife’ is related to ‘Cut’, in the same way as ‘Pen’ is related to ___________.
Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 28

‘Knife’ is related to ‘Cut’, means we use knife for cutting.

Similarly,

We use pen for writing.

Hence, Write is the correct answer.

BEL Trainee Engineer Electronics Mock Test - 10 - Question 29

A square paper is folded in a particular manner and a punch is made. When unfolded the paper appears as given below:
Find out the manner in which the paper is folded and punch is made from the responses given:
Question Figure

Answer figure

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 29

Explanation:

Which is basically similar to option c

BEL Trainee Engineer Electronics Mock Test - 10 - Question 30

Directions: Read the given information carefully and answer the questions given beside:

A certain number of people are sitting in a row watching F1 racing. All of them are facing towards the south direction. The distance between any two adjacent persons is the same. 
The number of people sitting between A and C is the same as the number of people sitting between X and C. At most 25 people are sitting in a row. X is an immediate neighbour of D, who sits on one of the ends. Two people are sitting between A and Z. The number of people sitting between D and C is the same as the number of people sitting between C and Y. C sits fourth to the right of Z. The number of people sitting to the right of A is the same as the number of people sitting to the left of Z.

Q. How many seats are there to the left of C

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 10 - Question 30

Following the common explanation, we get “7 seats are there to the left of C”.
Hence, option D is correct.
Final Arrangement:

Common Explanation:
References:
1. Two people are sitting between A and Z.
2. C sits fourth to the right of Z.
3. The number of people sitting to the right of A is the same as the number of people sitting to the left of Z.
4. The number of people sitting between A and C is the same as the number of people sitting between X and C.
5. X is an immediate neighbour of D, who sits on one of the ends.
6. The number of people sitting between D and C is the same as the number of people sitting between C and Y.
7. At most 25 people are sitting in a row.
Inferences:
From reference 1, we get two possible cases.
From reference 7, case2 was eliminated.
Hence, Case 1 is the final arrangement.

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