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Test: Kinetic Theory - 1 - JEE MCQ


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10 Questions MCQ Test - Test: Kinetic Theory - 1

Test: Kinetic Theory - 1 for JEE 2024 is part of JEE preparation. The Test: Kinetic Theory - 1 questions and answers have been prepared according to the JEE exam syllabus.The Test: Kinetic Theory - 1 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Kinetic Theory - 1 below.
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Test: Kinetic Theory - 1 - Question 1

At absolute zero temperature may be defined as that temperature at which

Detailed Solution for Test: Kinetic Theory - 1 - Question 1

At 0K temperature we know that there is no molecular motion, that is the KE of the particles gets 0. Thus we can say the combined KE of a gaseous system is zero, but as there combined mass cant be zero thus the combined of the square of velocities of the particles is zero, which means that the root mean square velocity of the gas is zero.

Test: Kinetic Theory - 1 - Question 2

Pressure exerted by an ideal gas molecule is given by the expression

Detailed Solution for Test: Kinetic Theory - 1 - Question 2

D is the derived expression.

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Test: Kinetic Theory - 1 - Question 3

If the r.m.s speed of oxygen at NTP is x m/s. If the gas is heated at constant pressure till its volume is four fold, what will be its final temperature and r.m.s speed?

Detailed Solution for Test: Kinetic Theory - 1 - Question 3


Test: Kinetic Theory - 1 - Question 4

The perfect gas equation is PV = nRT where n is the

Detailed Solution for Test: Kinetic Theory - 1 - Question 4

n is the number of moles.

Test: Kinetic Theory - 1 - Question 5

In a mixture of ideal gases at a fixed temperature the heavier molecule has the lower average speed. This is easiest to conclude from the equation

Detailed Solution for Test: Kinetic Theory - 1 - Question 5

In option A, v is inversely proportional to mass. Hence, the condition of the question is seen accurately in that option.

Test: Kinetic Theory - 1 - Question 6

According to kinetic theory of gases, 0K is that temperature at which for an ideal gas

Detailed Solution for Test: Kinetic Theory - 1 - Question 6

According to kinetic theory of gases, 0K is that temperature at which for an ideal gas the internal energy is zero because at 0K nearly all molecular motion stops.

Test: Kinetic Theory - 1 - Question 7

The kinetic energy of one mole of an ideal gas is E=3/2 RT. Then Cρ will be

Detailed Solution for Test: Kinetic Theory - 1 - Question 7

We know that,
Cp=cv+R
E=3Rt/2
also,
E=Cv
cp=R+3RT/2
=5/2 RT
=2.5R

Test: Kinetic Theory - 1 - Question 8

Value of gas constant, R for one mole of a gas is independent of the

Detailed Solution for Test: Kinetic Theory - 1 - Question 8

We know that PV=nRT also PM=dRT
So in the equation The value of R depends on P , V , n , T , d , M
except atomicity 
 so the ans is A

Test: Kinetic Theory - 1 - Question 9

The pressure exerted by an ideal gas is numerically equal to _________ of the mean kinetic energy of translation per unit volume of the gas.

Detailed Solution for Test: Kinetic Theory - 1 - Question 9

Translational (KE) per unit volume

Test: Kinetic Theory - 1 - Question 10

The average kinetic energy of a molecule in an ideal gas is

Detailed Solution for Test: Kinetic Theory - 1 - Question 10

KE = f/2 KT

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