Test: Kinetic Theory - 1 - JEE MCQ

At 0K temperature we know that there is no molecular motion, that is the KE of the particles gets 0. Thus we can say the combined KE of a gaseous system is zero, but as there combined mass cant be zero thus the combined of the square of velocities of the particles is zero, which means that the root mean square velocity of the gas is zero.

D is the derived expression.

n is the number of moles.

In option A, v is inversely proportional to mass. Hence, the condition of the question is seen accurately in that option.

According to kinetic theory of gases, 0K is that temperature at which for an ideal gas the internal energy is zero because at 0K nearly all molecular motion stops.

We know that,
C_p=c_v+R
E=3Rt/2
also,
E=C_v
c_p=R+3RT/2
=5/2 RT
=2.5R

We know that PV=nRT also PM=dRT
So in the equation The value of R depends on P , V , n , T , d , M
except atomicity 
 so the ans is A

Translational (KE) per unit volume

KE = f/2 KT