Test: Standing Waves - JEE MCQ

A node is a point along the medium of no displacement. The point is not displaced because destructive interference occurs at this point.

As we know, f=v/2l
Now, it will act as one end and one end closed.
So, f₀=v/2l’=v/4½=v/2l=f

Let L be a length of the pipe,
The fundamental frequency of closed pipe is
v₂​=ν​/4L                                         .....(i)
where ν is the speed of sound in air.
Fundamental frequency of open pipe of same length is
v_​1=ν/2L​                                            .....(ii)
After dividing v₁ with v₂,
v₁/v₂= ν/2L/ ν​/4L
v₁=2v₂

If there are exactly 90 vibrations in 60.0 seconds, then there is a frequency of 1.5 Hz. The diagram shows 1.5 waves in 6.0-meters of rope; thus, the wavelength is 4.0 meters. Now use the equation v=f*w to calculate the speed of the wave. Proper substitution yields 6.0 m/s.