HTET TGT Maths Mock Test - 1 - HTET MCQ

'Education-of-all-in-schools-for-all' is a tagline for Inclusive education.
Inclusive education is a platform that promotes and believes that every child should get equal opportunity irrespective of caste, creed, colour, religion and whether a child is a normal or special case. 
It mainly focuses on providing education to special children, along with children with non-special needs. It welcomes special-needs children to promote equality.
Hence, the correct answer is, 'Inclusive education.

Fluency, elaboration, originality and flexibility are associated with divergent thinking. Divergent thinking is creating multiple ideas, unique possible solutions, or ideas of a problem in a short period. Fluency, elaboration, originality, and flexibility are the dimensions of Divergent thinking and are associated with giftedness. Divergent thinking is important in the creative thinking process. Guilford (1986) considered creative thinking as involving divergent thinking, consisting of four elements: fluency, flexibility, originality, and elaboration. 
Thus, this is the correct answer. 

Gifted students have some advanced mental potential as compared with other children. Hence, they should be asked to spend more time on questions dealing with creating so that their extraordinary abilities can be channelled into discovering new ways to solve a problem.
Hence, this is the correct answer.

Children think that everything around them, including toys, is alive. This example points to a prominent characteristic of the preoperational stage called ‘animism’ by Piaget. It is a result of egocentric thinking and refers to the tendency of children to assign humanistic qualities to inanimate things.

• They believe that non-living things have desires and think, feel, and act like them.
• A logical consequence of animistic thinking is the strong emotional response towards non-living objects―talking to their toys, taking care of them, and expressing their feelings towards them.

Progressive education advocates that young learners should be given the freedom to learn according to their preferences and likes

सही उत्तर 'मेरा यह सोचना, सही निकला' है।

• मेरा यह सोचना कि लोकेश प्रतिभाशाली छात्र है, सही निकला। इस वाक्य में ‘मेरा यह सोचना’ 'सही निकला' प्रधान उपवाक्य है।
• किसी वाक्य में जो उपवाक्य किसी पर आश्रित नहीं होता अर्थात् स्वतंत्र होता है एवम् उसकी क्रिया मुख्य होती है, वह मुख्य या प्रधान उपवाक्य कहलाता है।
• जैसे – मोदी जी ने कहा कि अच्छे दिन आएँगे।
• इस वाक्य में ‘मोदी जी ने कहा’प्रधान उपवाक्य है।

Key Points

• उपवाक्य: ऐसा पदसमूह, जिसका अपना अर्थ हो, जो एक वाक्य का भाग हो और जिसमें उदेश्य और विधेय हों, उपवाक्य कहलाता हैं।
• उपवाक्यों के आरम्भ में अधिकतर कि, जिससे, ताकि, जो, जितना, ज्यों-त्यों, चूँकि, क्योंकि, यदि, यद्यपि, जब, जहाँ इत्यादि होते हैं।
• उपवाक्य दो तरह के होते हैं – प्रधान उपवाक्य, आश्रित उपवाक्य।
• आश्रित उपवाक्य: दूसरे उपवाक्य पर आश्रित होता है।
• आश्रित उपवाक्य क्योंकि, कि, यदि, जो, आदि से आरंभ होते हैं।
• जैसे –मोदी जी ने कहा कि अच्छे दिन आएँगे।
• इस वाक्य में "कि अच्छे दिन आएँगे।" आश्रित उपवाक्य है क्योंकि यह उपवाक्य "मोदी जी ने कहा" उपवाक्य पर आश्रित है।

Answer: D

Explanation:

• The boys have class at 8:00 am, so they need to wake up earlier than 7:30 am to make it on time.
• The modal verb "have to" expresses necessity or obligation, making it the most appropriate choice.
• Option A "would" indicates a possibility or a preference, but not an obligation.
• Option B "can't" is a negative form of "can" and indicates impossibility, which is not the intended meaning.
• Option C "could" indicates a possibility or an ability, not an obligation.

We can say that ,
The above given sentence is given in Passive Voice :-
Use structure “subject + auxiliary + past participle + by + object”
I have been promised a bicycle by my father.
Therefore , option C will be correct answer .

x% of a = y% of b
z × x% of a = z × y% of b

Hence, Option C is correct.

U is the mother of P and R is the brother of P. So, U is mother of R.

Checking Statement I:
Using the above references, we get the following arrangement:

Since there is no information about the position of Bhanu so we cannot find the person who sits on the immediate right of Bhanu.

Hence, data in statement I alone is not sufficient.
Checking Statement II:
Using the above references, we get the following arrangement:

Clearly, Prakash sits on the immediate right of Bhanu.

Hence, data in statement II alone is sufficient.

Hence, Option B is correct.

From Statement 1:

We have, S sits third to the right of N and third to the left of M.

 From the statement, M sits at the extreme right end.

From Statement 2:

We have, X sits in the middle of the line.

Y sits second to the right of X.

Z sits fifth to the left of W, who is the neighbor of Y.

From the statement, W sits at the extreme right end.

Hence option B is correct.

Hence, Option B is correct.

The sequence is a combination of two series:
I. 3, 5, 7, 9
II. 6, 20, 42, (____)

Consider II sequence
1st term = 6
2nd term = 6 + 14 = 20
3rd term = 20 + 14 = 34

Thus, the missing term is 4th term = 34 + 14 = 48

r% of r = 49
r² = 49 × 100
r = 7 × 10 = 70
Hence, Option B is correct.

Total no. of outcomes=52
No. of ace cards=4
No. of non-ace cards=48
Probability of getting a non-ace card = No. of favourable outcomes / total no. of outcomes
=48/52=12/13

Given, A dice is thrown once. So,

Total number of outcomes (n) = 6

Number of prime numbers = {2, 3,5}

So, Favorable number of outcomes (m) = 3

Thus, probability of getting a prime number = m/n = 3/6 = 1/2

The two numbers that add up to 14, and multiply to 45 and 9 and 5.

(x+5)(x+9)

In a triangle with one angle being 90 degrees (which the tree makes with the ground) and the other being 45 degrees (the angle of elevation), the 3rd angle is bound to be 45 degrees (180 - 90 - 45 = 45). 

We also know that sides opposite to equal angles are equal.

Hence, the height of the tree will also be 4m.

If the coefficient of x² is zero , then the equation is not a quadratic equation , its a linear equation. So its necessary condition for the quadratic equation. 

Given that PQRS and ABCD are rectangle and Q is the mid pt of AC.

Since PQRS and ABCD are rectangle, every angle would be of 90°.

Consider AD and PQ.

angle ADP = 90°
angle QPC = 90°

Now, angle ADP lies corresponding to angle QPC and are equal.

If corresponding angles are equal, then the lines are parallel


=> AD || PQ

Now consider ∆ADC.

Q is the midpoint of AC (Given)
AD || PQ (shown above)

We know that,
line drawn parallel from the midpoint of a side, to other side, bisects the third side.

Hence, P would be the midpoint of DC

Hence, DP = PC

We know Probability law which is law of  complement
Which is P(not A)=1-P(A)
Where P(A)=⅖
P(not A)=1-⅖=3/5

The basic structure of mathematics includes arithmetic, algebra, geometry, and trigonometry that helps in learning the techniques to handle abstractions and structures.

• The teaching of mathematics must develop attitudes to think, reason, analyze, and articulate logically.
• The nature of mathematics highly influences the nature of the teaching-learning process in mathematics.

Key Points

Nature of mathematics:

• Each mathematical concept can be described in the terms of precision which is one of the main characteristics of mathematics.
• Precision in mathematics deals with accuracy and exactness and leaves no scope for doubt and ambiguity. So, mathematics is considered the science of precision, accuracy, and exactness.
• Mathematics uses symbols, numbers, figures, and objects to form concepts, terms, signs, formulas, etc. It uses its own language to express complicated abstract ideas and generalizations to solve problems.
• Mathematics has universal applicability as mathematical knowledge is used in almost every aspect of our life such as money exchange, computing wages, determining areas of fields, and in construction of houses, etc.

Hint

• Mathematics involves intuitive methods of teaching-learning like learning through discovery which is a method of inquiry-based instruction.
• Intuitive methods are used in mathematics to develop the minds of students so that they can use their insight and intuition to go beyond the textbook to find relationships and organize mathematical structures.

Hence, it is concluded that "mathematics does not involve any intuitive method" is not correct with regard to the nature of mathematics.

The general form of a linear equation in one variable is: ax+b=c where a and b are constants and x is a variable.

So, in a linear equation the degree is 1 i.e., highest power in the variable is 1.
But in ax⁴+bx²+c=0 highest power for x is 4. Hence, it is not linear.

If the outer bisectors of the angle B and angle C meet at a point O outer side of the triangle, then ∠BOC = 90° - ∠A/2 = 90° - 70°/2 = 55°