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Test: Ionisation of Water - NEET MCQ


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10 Questions MCQ Test - Test: Ionisation of Water

Test: Ionisation of Water for NEET 2024 is part of NEET preparation. The Test: Ionisation of Water questions and answers have been prepared according to the NEET exam syllabus.The Test: Ionisation of Water MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Ionisation of Water below.
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Test: Ionisation of Water - Question 1

Which of the following is more acidic? A solution with pH 5 or a solution with pH 3

Detailed Solution for Test: Ionisation of Water - Question 1

We know that pH equals to - log[H+] or the value of pH is inversely proportional to the concentration of H+.  So more the value of pH, less the solution be acidic.

Test: Ionisation of Water - Question 2

Ionic product of water is

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Test: Ionisation of Water - Question 3

 Which one of the following is the approximate pH of 0.01 M solution of NaOH at 298 k?

Detailed Solution for Test: Ionisation of Water - Question 3

First off, since NaOH is a strong base, it will dissociate completely into Na+ and OH-. Thus, we know that we have 0.01 M OH-.

However, we do not know anything about the concentration of H+. Fortunately, we do not need to, as pH + pOH = 14. So, if we find pOH, we can solve for pH. p is a mathematical function equivalent to -log. So, pH actually means -log[H+] (Note that brackets indicate concentration of).

pOH = -log 0.01M OH-

pOH = 2

pH + 2 = 14

pH = 12

This result makes sense, since a solution of strong base should have a high pH.

Test: Ionisation of Water - Question 4

A 0.10 M solution of a weak acid, HX, is 0.059% ionized. Evaluate Ka for the acid.

Detailed Solution for Test: Ionisation of Water - Question 4

Since the acid is only 0.059% ionized, therefore the concentration of ions in solution = 0.1 x 0.059 / 100 = 0.000059

 

Ka = [H+] [X] / [HX] = (0.000059)2 / 0.1 = 3.5 x 10-8

Test: Ionisation of Water - Question 5

 In a sample of pure water, only one of the following statements is always true at all conditions of temperature and pressure.

Detailed Solution for Test: Ionisation of Water - Question 5

The correct answer is Option D.
The concentration of OH- will always equal the concentration of H3O+.
PV = nRT, where R is a constant, and n is the quantity of gas measured in mols. The pH of a substance is related to the concentration of H+,
so if we raise or lower the Temperature or Pressure of pure water, we will alter the Volume (or concentration) of H3O+ and OH- ions. As we alter the concentrations we alter the pH and pOH. The only answer that is true no matter what the volume or concentration may be is D
 

Test: Ionisation of Water - Question 6

The pH of 10-8 molar solution of HCl in water is:

Detailed Solution for Test: Ionisation of Water - Question 6

If we use the relation, pH = – log [H3O+], we get pH equal to 8. But this is not correct because an acidic solution cannot have pH greater than 7. It may be noted that in very dilute acidic solution, when H+ concentrations from acid and water are comparable, the concentration of H+ from water cannot be neglected.

Therefore,

Test: Ionisation of Water - Question 7

 Which one of the following is correct for a solution in which [H+] = 10-8 M.

Test: Ionisation of Water - Question 8

Which one of the following is a wrong derivation?

Test: Ionisation of Water - Question 9

Value of pH is determined by

Detailed Solution for Test: Ionisation of Water - Question 9
The pH measurement electrode is made of special glass which, due to its surface properties, is particularly sensitive to hydrogen ions. The pH measurement electrode is filled with a buffer solution which has a pH value of 7.
Test: Ionisation of Water - Question 10

The pH of a 0.02 M solution of an unknown weak acid is 3.7. What is the pKa of this acid?

Detailed Solution for Test: Ionisation of Water - Question 10

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