In a certain polluted atmosphere containing O3 at a steady concentration of 2.0 x 10-6 M, the hourly production of O3 by all sources was estimated as 7.2 x 10-15 M. If the only mechanism for destruction of O3 in the second-order reaction is
2O3 → 3O2
then rate constant for destruction reaction, defined by the rate law for - Δ[O3]/Δf is x * 10-7 M-1 s-1 . What is the value of x?
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For a reversible reaction, net rate is
hence given reaction is
In a reaction A → Products, when start is made from 8.0 × 10−2 M of A, half-life is found to be 120 minute. For the initial concentration 4.0 × 10−2 M, the half-life of the reaction becomes 240 minute. The order of the reaction is:
For the reaction A + B⟶ products, it is observed that:
(1) On doubling the initial concentration of A only, the rate of reaction is also doubled and
(2) On doubling the initial concentrations of both A and B, there is a change by a factor of 8 in the rate of the reaction. The rate of this reaction is given by:
The rate law for the reaction below is given by the expression k[A][B]
A + B → Product
If the concentration of B is increased from 0.1 to 0.3 mole, keeping the value of A at 0.1 mole, the rate constant will be: