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Test: Rate law and rate constant - JEE MCQ


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15 Questions MCQ Test - Test: Rate law and rate constant

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Test: Rate law and rate constant - Question 1

The reaction  2N₂O₅ ⇌ 2N₂O₄ + O₂ is

Detailed Solution for Test: Rate law and rate constant - Question 1

It is bimolecular first order reaction since Rate ∝ [N2O5]

Test: Rate law and rate constant - Question 2

In a certain polluted atmosphere containing O3 at a steady concentration of 2.0 x 10-6 M, the hourly production of O3 by all sources was estimated as 7.2 x 10-15 M. If the only mechanism for destruction of O3 in the second-order reaction is

2O3 → 3O2

then rate constant for destruction reaction, defined by the rate law for - Δ[O3]/Δf is x * 10-7 M-1 s-1 . What is the value of x?

Detailed Solution for Test: Rate law and rate constant - Question 2



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Test: Rate law and rate constant - Question 3

Only One Option Correct Type

This section contains 2 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct

For a reversible reaction, net rate is 

(dx/dt) ​= k1​[A]2[B]−1−k2​[C]

hence given reaction is 

Detailed Solution for Test: Rate law and rate constant - Question 3

2A - B →C (reversible)

For a forward reaction, (dx/dt)f = k1[A]2 [B]-1
For a backward reaction, (dx/dt)b = k2[C]

Net rate = (dx/dt)f - (dx/dt)= k1[A]2 [B]-1 - k2[C]

Test: Rate law and rate constant - Question 4

Reaction kinetics deals with the study of

Detailed Solution for Test: Rate law and rate constant - Question 4

Reaction kinetics deals with the study of rate of reaction, their mechanism and the factors which affects the rate of reaction. It specifies all the general characteristics of a chemical reaction.

Test: Rate law and rate constant - Question 5

The rate constants for a reaction at 400 K and  500 K are  2.60 x 10-5 s-1 and  2.60 x 10-3 s-1,respectively. The activation energy of the reaction in kJmol-1 is ______

Detailed Solution for Test: Rate law and rate constant - Question 5

Test: Rate law and rate constant - Question 6

A reaction rate constant is given by k=1.2×1014 e−25000/RTsec−1. It means

Detailed Solution for Test: Rate law and rate constant - Question 6




Equation of straight line
slope

Test: Rate law and rate constant - Question 7

The time required for 10% completion of a first order reaction at 298K is equal to that required for its 25%   completion at  308K If the preexponential factor for the reaction is 3.56 x 109 s-1, the activation energy at 318K is:

Detailed Solution for Test: Rate law and rate constant - Question 7

Let the initial concentration
Final concentration at
Final concentration at
Substituting the values in the 1 st order rate reaction
...(i)
...(ii)
From (i) and (ii)
Substituting the value in the following relation


Test: Rate law and rate constant - Question 8

In a reaction A → Products, when start is made from 8.0 × 10−2 M of A, half-life is found to be 120 minute. For the initial concentration 4.0 × 10−2 M, the half-life of the reaction becomes 240 minute. The order of the reaction is:

Detailed Solution for Test: Rate law and rate constant - Question 8

Test: Rate law and rate constant - Question 9

For the reaction A + B⟶ products, it is observed that:
(1) On doubling the initial concentration of A only, the rate of reaction is also doubled and
(2) On doubling the initial concentrations of both A and B, there is a change by a factor of 8 in the rate of the reaction. The rate of this reaction is given by:

Detailed Solution for Test: Rate law and rate constant - Question 9

When concentration of A is doubled, rate is doubled. Hence order with respect to A is one. When concentrations of both A and B are doubled, rate increases by 8 times hence order with respect to B is 2.
∴ rate = k[A]1[B]2

Test: Rate law and rate constant - Question 10
The order of a reaction, with respect to one of the reacting component , is zero. It implies that:
Detailed Solution for Test: Rate law and rate constant - Question 10
Let us consider a reaction,
rate
It is given that order of reaction w.r.t. component is zero.
Hence, rate
i.e., rate becomes independent of the concentration of .
Test: Rate law and rate constant - Question 11

The rate law for the reaction below is given by the expression k[A][B]
A + B → Product 
If the concentration of B is increased from 0.1 to 0.3 mole, keeping the value of A at 0.1 mole, the rate constant will be:

Detailed Solution for Test: Rate law and rate constant - Question 11

Test: Rate law and rate constant - Question 12
The half-life of a reaction is inversely proportional to the square of the initial concentration of the reactant. Then the order of the reaction is
Detailed Solution for Test: Rate law and rate constant - Question 12

We know that
i.e. Thus reaction is of order
Test: Rate law and rate constant - Question 13
Consider the two hypothetical reactions given below:
I Products,
II Products,
The half-lives of both the reactions are the same, equal to when molar concentration of the reactant is in each case. If these reactions are started at the same time taking of the reactant in each case, the ratio after will be :
Detailed Solution for Test: Rate law and rate constant - Question 13
Units of indicate that reaction is of second order and reaction is first order. For reaction, , first , second



Test: Rate law and rate constant - Question 14
The rate of a reaction increases four-fold when the concentration of reactant is increased 16 times. If the rate of reaction is when the concentration of the reactant is The rate constant of the reaction will be
Detailed Solution for Test: Rate law and rate constant - Question 14
Rate


Test: Rate law and rate constant - Question 15
A chemical reaction was carried out at and . The rate constants were found to be and respectively. then
Detailed Solution for Test: Rate law and rate constant - Question 15
The rate constant doubles for rise in temperature. For rise, the rate constant will be 4 times or
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