JEE Exam  >  JEE Tests  >  Test: Rate law and rate constant - JEE MCQ

Test: Rate law and rate constant - JEE MCQ


Test Description

15 Questions MCQ Test - Test: Rate law and rate constant

Test: Rate law and rate constant for JEE 2024 is part of JEE preparation. The Test: Rate law and rate constant questions and answers have been prepared according to the JEE exam syllabus.The Test: Rate law and rate constant MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Rate law and rate constant below.
Solutions of Test: Rate law and rate constant questions in English are available as part of our course for JEE & Test: Rate law and rate constant solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Rate law and rate constant | 15 questions in 20 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
Test: Rate law and rate constant - Question 1

The reaction is

Detailed Solution for Test: Rate law and rate constant - Question 1

It is bimolecular first order reaction since Rate ]

Test: Rate law and rate constant - Question 2

In a certain polluted atmosphere containing O3 at a steady concentration of 2.0 x 10-6 M, the hourly production of O3 by all sources was estimated as 7.2 x 10-15 M. If the only mechanism for destruction of O3 in the second-order reaction is

2O3 → 3O2

then rate constant for destruction reaction, defined by the rate law for - Δ[O3]/Δf is x * 10-7 M-1 s-1 . What is the value of x?

Detailed Solution for Test: Rate law and rate constant - Question 2



1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Rate law and rate constant - Question 3

Only One Option Correct Type

This section contains 2 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct

For a reversible reaction, net rate is 

hence given reaction is 

Detailed Solution for Test: Rate law and rate constant - Question 3

2A - B →(reversible) C

For a forward reaction, (dx/dt)f = k1[A]2 [B]-1
For a backward reaction, (dx/dt)b = k2[C]

Net rate = (dx/dt)f - (dx/dt)= k1[A]2 [B]-1 - k2[C]

Test: Rate law and rate constant - Question 4

Reaction kinetics deals with the study of

Detailed Solution for Test: Rate law and rate constant - Question 4

Reaction kinetics deals with the study of rate of reaction, their mechanism and the factors which affects the rate of reaction. It specifies all the general characteristics of a chemical reaction.

Test: Rate law and rate constant - Question 5
The rate constants for a reaction at and are and ,respectively. The activation energy of the reaction in is ______
Detailed Solution for Test: Rate law and rate constant - Question 5
The rate constants for a reaction at and are and ,respectively. The activation energy of the reaction in is ______
Test: Rate law and rate constant - Question 6

A reaction rate constant is given by It means

Detailed Solution for Test: Rate law and rate constant - Question 6




Equation of straight line
slope

Test: Rate law and rate constant - Question 7
The time required for completion of a first order reaction at is equal to that required for its completion at . If the preexponential factor for the reaction is , the activation energy at is:
Detailed Solution for Test: Rate law and rate constant - Question 7
Let the initial concentration
Final concentration at
Final concentration at
Substituting the values in the 1 st order rate reaction
...(i)
...(ii)
From (i) and (ii)
Substituting the value in the following relation


Test: Rate law and rate constant - Question 8

In a reaction A → Products, when start is made from 8.0 × 10−2 M of A, half-life is found to be 120 minute. For the initial concentration 4.0 × 10−2 M, the half-life of the reaction becomes 240 minute. The order of the reaction is:

Detailed Solution for Test: Rate law and rate constant - Question 8

Test: Rate law and rate constant - Question 9

For the reaction A + B⟶ products, it is observed that:
(1) On doubling the initial concentration of A only, the rate of reaction is also doubled and
(2) On doubling the initial concentrations of both A and B, there is a change by a factor of 8 in the rate of the reaction. The rate of this reaction is given by:

Detailed Solution for Test: Rate law and rate constant - Question 9

When concentration of A is doubled, rate is doubled. Hence order with respect to A is one. When concentrations of both A and B are doubled, rate increases by 8 times hence order with respect to B is 2.
∴ rate = k[A]1[B]2

Test: Rate law and rate constant - Question 10
The order of a reaction, with respect to one of the reacting component , is zero. It implies that:
Detailed Solution for Test: Rate law and rate constant - Question 10
Let us consider a reaction,
rate
It is given that order of reaction w.r.t. component is zero.
Hence, rate
i.e., rate becomes independent of the concentration of .
Test: Rate law and rate constant - Question 11

The rate law for the reaction below is given by the expression k[A][B]
A + B → Product 
If the concentration of B is increased from 0.1 to 0.3 mole, keeping the value of A at 0.1 mole, the rate constant will be:

Detailed Solution for Test: Rate law and rate constant - Question 11

Rate constant is independent of concentration.

Test: Rate law and rate constant - Question 12
The half-life of a reaction is inversely proportional to the square of the initial concentration of the reactant. Then the order of the reaction is
Detailed Solution for Test: Rate law and rate constant - Question 12

We know that
i.e. Thus reaction is of order
Test: Rate law and rate constant - Question 13
Consider the two hypothetical reactions given below:
I Products,
II Products,
The half-lives of both the reactions are the same, equal to when molar concentration of the reactant is in each case. If these reactions are started at the same time taking of the reactant in each case, the ratio after will be :
Detailed Solution for Test: Rate law and rate constant - Question 13
Units of indicate that reaction is of second order and reaction is first order. For reaction, , first , second



Test: Rate law and rate constant - Question 14
The rate of a reaction increases four-fold when the concentration of reactant is increased 16 times. If the rate of reaction is when the concentration of the reactant is The rate constant of the reaction will be
Detailed Solution for Test: Rate law and rate constant - Question 14
Rate


Test: Rate law and rate constant - Question 15
A chemical reaction was carried out at and . The rate constants were found to be and respectively. then
Detailed Solution for Test: Rate law and rate constant - Question 15
The rate constant doubles for rise in temperature. For rise, the rate constant will be 4 times or
Information about Test: Rate law and rate constant Page
In this test you can find the Exam questions for Test: Rate law and rate constant solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Rate law and rate constant, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE