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Test: Collision Theory, Energy of Activation - JEE MCQ


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20 Questions MCQ Test - Test: Collision Theory, Energy of Activation

Test: Collision Theory, Energy of Activation for JEE 2024 is part of JEE preparation. The Test: Collision Theory, Energy of Activation questions and answers have been prepared according to the JEE exam syllabus.The Test: Collision Theory, Energy of Activation MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Collision Theory, Energy of Activation below.
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Test: Collision Theory, Energy of Activation - Question 1

A first order reaction is half-completed in 45 minutes. How long does it need for of the reaction to be completed?

Detailed Solution for Test: Collision Theory, Energy of Activation - Question 1
further

hours.
Test: Collision Theory, Energy of Activation - Question 2

 At a certain temperature, the first order rate constant k1 is found to be smaller than the second order rate constant k2. If the energy of activation E1 of the first order reaction is greater than energy of activation E2 of the second order reaction, then with increase in temperature.

Detailed Solution for Test: Collision Theory, Energy of Activation - Question 2

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Test: Collision Theory, Energy of Activation - Question 3

A reaction which is of first order w.r.t. reactant , has a rate constant . If we start with , when would [A] reach the value of

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Test: Collision Theory, Energy of Activation - Question 4
The rate of a first order reaction is at concentration of the reactant. The halflife of the reaction is
Detailed Solution for Test: Collision Theory, Energy of Activation - Question 4
For a first order reaction, Products
or

Further,
Test: Collision Theory, Energy of Activation - Question 5
For a first order reaction the reaction rate at reactant concentration of is found to be . The half life period of the reaction is
Detailed Solution for Test: Collision Theory, Energy of Activation - Question 5
Given
Rate
For a first order reaction Rate

Test: Collision Theory, Energy of Activation - Question 6
A reaction proceeds by first order, of this reaction was completed in 32 min. The time required for completion is
Detailed Solution for Test: Collision Theory, Energy of Activation - Question 6
Given: reaction gets completed in 32
Thus,


Now we can use this value of to get the value of time required for completion of reaction

Test: Collision Theory, Energy of Activation - Question 7
In the reaction , rate constant is . If we start with of A then conc. of and B after 10 minuter are respectively.
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Test: Collision Theory, Energy of Activation - Question 8
The half life for the virus inactivation if in the beginning of the virus is inactivated per minute is (Given: The reaction is of first order)
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For the first order reaction for small finite change


Test: Collision Theory, Energy of Activation - Question 9
At , if the rate constant of a first order reaction is , the time to reduce the initial concentration of the reactant to in seconds is :
Detailed Solution for Test: Collision Theory, Energy of Activation - Question 9
To find the time taken for the concentration of the reactant to reduce to th, we use the formula:

Given , we have:

Solving for , we get approximately 500 seconds.
Test: Collision Theory, Energy of Activation - Question 10
The rate constant of a reaction with a virus is . Time required for the virus to become inactivated is
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Test: Collision Theory, Energy of Activation - Question 11
A Geigger Muller counter is used to study the radioactive process. In the absence of radioactive substance , it counts 3 disintegration per second (dps). At the start in the presence of , it records 23 dps; and after 10 min 13 dps,
(i) What does it count after
(ii) What is the halflife of A?
Detailed Solution for Test: Collision Theory, Energy of Activation - Question 11
In the absence of dps is zero error, hence
Initial count
After
After
recorded
(50\% fall in
Test: Collision Theory, Energy of Activation - Question 12
The rate equation for a reaction,

is Rate . If the initial concentration of the reactant is mol , the half-life period of the reaction is
Detailed Solution for Test: Collision Theory, Energy of Activation - Question 12
For a zero order reaction
Test: Collision Theory, Energy of Activation - Question 13
Half-lives of first-order and zeroth order reactions are same. Ratio of rates at the start of nreaction is
Detailed Solution for Test: Collision Theory, Energy of Activation - Question 13
zeroth
first


Test: Collision Theory, Energy of Activation - Question 14
The plot of concentration of the reactant Vs time for a reaction is a straight line with a negative slope. The reaction follows a rate equation of
Detailed Solution for Test: Collision Theory, Energy of Activation - Question 14
Plots of conc. [A] Vs time, t
Test: Collision Theory, Energy of Activation - Question 15
The reaction is started with of L. After 30 and 90 minutes and of respectively are left. The order of the reaction is
Detailed Solution for Test: Collision Theory, Energy of Activation - Question 15
After every 30 minutes the amount is reduced to therefore is 30 minutes. In 90 minutes the amount is reduced to i.e. Here True for 1st order reaction.
Test: Collision Theory, Energy of Activation - Question 16
The plot that represents the zero order reaction is:
Detailed Solution for Test: Collision Theory, Energy of Activation - Question 16
For a zero order, rate of reaction does not change with time.
Test: Collision Theory, Energy of Activation - Question 17

For a first order reaction, a plot of log(a−x) against time is a straight line with a negative slope equal to

Detailed Solution for Test: Collision Theory, Energy of Activation - Question 17


or

Test: Collision Theory, Energy of Activation - Question 18
In the presence of an acid, the initial concentration of cane sugar was reduced from to in 5 hours and from to in 10 hours. The reaction is of :
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Test: Collision Theory, Energy of Activation - Question 19

For the decomposition of at , the following data were obtained

The order of reaction is :

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Dividing eq. (i) by eq. (ii),

Test: Collision Theory, Energy of Activation - Question 20

The hypothetical reaction follows the following mechanism , The order of the overall reaction is

Detailed Solution for Test: Collision Theory, Energy of Activation - Question 20

;
(Fast);
(Slow)
Rate law put value of from Ist reaction since is intermediate

Rate law equation
Order

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