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Test: Werner's theory and Valence Bond Theory - JEE MCQ


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20 Questions MCQ Test - Test: Werner's theory and Valence Bond Theory

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Test: Werner's theory and Valence Bond Theory - Question 1

is a strong field ligand. This is due to the fact that

Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 1
Cyanide ion is strong field ligand because it is a pseudohalide ion, pseudohalide ions are stronger coordinating ligand & they have the ability to form bond from pseudohalide to the metal and bond (from the metal to pseudohalide).
Test: Werner's theory and Valence Bond Theory - Question 2

Which one of the following complexes is an outer orbital complex
Atomic nos

Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 2
Complex Hybridization of central atom (inner)
(inner)
(inner)
(outer)
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Test: Werner's theory and Valence Bond Theory - Question 3

In the complex [SbF5] hybridisation is present Geometry of the complex is

Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 3
has hybridization and shows square pyramidal geometry
Test: Werner's theory and Valence Bond Theory - Question 4

An anion solution gives a white ppt with solution. The ppt. dissolves in dil. ammonia due to the formation of

Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 4


Test: Werner's theory and Valence Bond Theory - Question 5
Which of the following is incorrect regarding spectrochemical series?
Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 5
According to spectrochemical series
Test: Werner's theory and Valence Bond Theory - Question 6

The spin only magnetic moment of [MnBr4]x− is 5.9BM. The geometry of the complex and x respectively are

Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 6

B. M.

Thus, will have five unpaired electrons so will be in +2 state with being weak- field ligands.
Thus, for

Test: Werner's theory and Valence Bond Theory - Question 7
Which of the following are inner orbital complex (i.e., involving hybridisation) and is paramagnetic in nature?
Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 7
and are inner orbital
complexes and paramagnetic while is diamagnetic in nature.
Test: Werner's theory and Valence Bond Theory - Question 8
Which of the following is organo-metallic compound?
Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 8
is an organometallic compound due to Ti directly attached to C- atom
Test: Werner's theory and Valence Bond Theory - Question 9
The geometries of the ammonia complexes of and , respectively, are
Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 9
octahedral
square planar
tetrahedral
Test: Werner's theory and Valence Bond Theory - Question 10

exhibits temperature dependent magnetic behaviour (paramagnetic/diamagnetic). The coordination geometries of in the paramagnetic and diamagnetic states are respectively

Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 10

In both states (paramagnetic and diamagnetic) of the given complex, Ni exists as whose electronic configuration is .

In the above paramagnetic state the geometry of the complex is giving tetrahedral geometry. The diamagnetic state is achieved by pairing of electrons in orbital.

Thus the geometry of the complex will be giving square planar geometry.

Test: Werner's theory and Valence Bond Theory - Question 11

Which of the following complex compound(s) is/are paramagnetic and low spin?
(I)
(II)
(III)
(IV)
Choose the correct code:

Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 11

in

low spin complex Ni in

low and high spin complex is applicable for to configuration
in

low spin complex

Test: Werner's theory and Valence Bond Theory - Question 12
An aqueous solution of titanium chloride, when subjected to magnetic measurement, measured zero magnetic moment. Assuming the octahedral complex in aqueous solution, the formulae of the complex is:
Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 12

Coordination number octahedral complex Ti is in oxidations state no unpaired electrons
magnetic moment B.M.
Test: Werner's theory and Valence Bond Theory - Question 13

Which of the following statement is not true for the reaction given below?

Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 13

 [Cu(NH3)4]2+ has square planar structure and is paramagnetic. 

Test: Werner's theory and Valence Bond Theory - Question 14

Atomic number of and are 24, 26 and 27 respectively. Which of the following inner orbital octahedral complexes are paramagnetic?

Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 14

Oxidation state of

Since, is a strong field ligand, it will cause pairing of electrons in ,
So, there is one unpaired electron in -orbital of which makes the compound paramagnetic.

Test: Werner's theory and Valence Bond Theory - Question 15
The shape of is
Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 15
Shape of is square planar.
Test: Werner's theory and Valence Bond Theory - Question 16

Which of the following statements is incorrect?

Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 16

is diamagnetic as oxalate is a strong ligand causing pairing of electrons in thereby leading to hybridisation.

Test: Werner's theory and Valence Bond Theory - Question 17

An octahedral complex of is diamagnetic. The hybridisation involved in the formation of the complex is:

Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 17


Octahedral and Diamagnetic

Test: Werner's theory and Valence Bond Theory - Question 18
The correct statement about the magnetic properties of and is
Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 18
Both are paramagnetic, the only difference is that is a strong field ligand whereas is a weak field ligand.
Test: Werner's theory and Valence Bond Theory - Question 19
Nickel combines with a uninegative monodentate ligand to form a diamagnetic complex . The hybridization involved and the number of unpaired electrons present in the complex is respectively:
Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 19
Monodentate ligand is uninegative and hence, the oxidation number of Ni in is .
The electronic configuration of is .
If the compound is diamagnetic it means all the electrons are paired. Hence, there will be one orbital empty and one orbital empty.
The hybridisation involved in the formation of complex is .
Test: Werner's theory and Valence Bond Theory - Question 20
Prussian blue is a deep blue pigment containing and ions. It has the formula . How many and ions are there per formula unit?
Detailed Solution for Test: Werner's theory and Valence Bond Theory - Question 20
Prussian blue is a deep blue pigment is
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