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Test: Stability of complex ion, Crystal Field Theory - JEE MCQ


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20 Questions MCQ Test - Test: Stability of complex ion, Crystal Field Theory

Test: Stability of complex ion, Crystal Field Theory for JEE 2024 is part of JEE preparation. The Test: Stability of complex ion, Crystal Field Theory questions and answers have been prepared according to the JEE exam syllabus.The Test: Stability of complex ion, Crystal Field Theory MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Stability of complex ion, Crystal Field Theory below.
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Test: Stability of complex ion, Crystal Field Theory - Question 1

, find the value of ?

Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 1
Here, has zero oxidation state, as has zero oxidation state in the compound.
So, at zero oxidation state the electronic configuration of is
that means has 6 valencies, as in this state is stable due to half-filled orbitals. Now, for 6 valencies, is required. Therefore, The compound is .
Hence, the correct option is (2).
Test: Stability of complex ion, Crystal Field Theory - Question 2

Statement Type

Direction (Q. No. 25) This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

Q. 

Statement I : Mn(π— C3H5)(CO)4, obey effective atomic number rule.

Statement II : π-allyl ligand act as a 3e- donor.

Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 2

In Mn(π -C3H5) (CO)4
Mn= 25
π-C3H5 = 3
4 (CO) = 8
Hence, EAN = 36
Hence, π-C3H5 ligand acts as a 3-electron donor and complex obey effective atomic number rule.

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Test: Stability of complex ion, Crystal Field Theory - Question 3

In Mn2(CO)10, the number of CO molecules in between the metal atoms are


Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 3

Mn(CO)5 is radical with 17-electron configuration. Therefore, it undergoes dimerisation through the formation of M—M single bonds and complex their valence shells to avoid ligand-ligand repulsion the Mn(CO)5 units acquire staggered configuration.

Test: Stability of complex ion, Crystal Field Theory - Question 4
The correct order for wavelengths of absorption in the visible region for the following complexes will be
Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 4
Complexes, (I) ,
(II) and (III) are made of and ligands and respectively. The field strength order of the ligands is

So, the order CFSE values:
We know, or
So, the order of wavelength of absorption in visible region will be,
Test: Stability of complex ion, Crystal Field Theory - Question 5
Which will give a white precipitate with in aqueous solution
Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 5

Test: Stability of complex ion, Crystal Field Theory - Question 6
For the reaction of the type
Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 6
For the reaction of the type
, larger the stability
constant, the higher the proportion of that exists in solution.
Test: Stability of complex ion, Crystal Field Theory - Question 7

Amongst and , which are the colourless species?
(atomic number of Ti = 22, Co = 27, Cu = 29, Ni = 28)

Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 7

and and
Both ion do not have any unpaired electron in d orbital to (promote) transition. Hence no absorption of energy is there.
So they are colorless species.

Test: Stability of complex ion, Crystal Field Theory - Question 8

InFe(CO)s, the Fe-C bond possesses

Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 8

there is metal to ligand back bonding in Fe-C bond of the organometallic compound
So it possesses both and characters.

Test: Stability of complex ion, Crystal Field Theory - Question 9
The crystal field splitting energy for octahedral and tetrahedral complexes is related as
Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 9
The crystal field splitting in tetrahedral complexes is lower than that in octahedral complexes, and
Test: Stability of complex ion, Crystal Field Theory - Question 10

Calculate the magnetic moment of ion .

Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 10

Test: Stability of complex ion, Crystal Field Theory - Question 11
For octahedral complex, which of the following configurations of metal cation cannot exist in high spin and low spin forms?
Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 11
In and octahedral complexes number of unpaired at central metal atom/ion never changes, therefore for such octahedral complexes terms high spin and low spin not used.
Test: Stability of complex ion, Crystal Field Theory - Question 12

Which of the following complex ions has electrons that are symmetrically filled in both and orbitals ?

Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 12

Symmetrically filled t2 g and eg are those, which contain equal distribution of electrons. 

Test: Stability of complex ion, Crystal Field Theory - Question 13

Which of the following statements related to crystal field splitting in octahedral coordination entities is incorrect?

Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 13

is a strong field ligand and form low spin complexes thus

Test: Stability of complex ion, Crystal Field Theory - Question 14
Among the following species the one which causes the highest as a ligand is:
Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 14
Following is the order of increasing value of for the ligands.
Test: Stability of complex ion, Crystal Field Theory - Question 15
The increasing order of crystal field splitting strength of the given ligands is
Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 15
In general, the ligands can be arranged in a series in the order of increasing field strength as
Test: Stability of complex ion, Crystal Field Theory - Question 16
Incorrect match is :
Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 16
Hybridization High or
low spin is not defined because is an example of system of configuration.
Test: Stability of complex ion, Crystal Field Theory - Question 17
Which of the following carbonyls will have the strongest bond ?
Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 17
As positive charge on the central metal atom increases, the less readily the metal can donate electron density into the orbitals of CO ligand (donation of electron density into orbitals of result in weakening of bond ). Hence, the bond would be strongest in
Test: Stability of complex ion, Crystal Field Theory - Question 18
Which of the following does not have a metal carbon bond?
Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 18
Triethoxyaluminium has no Al-C linkage
Test: Stability of complex ion, Crystal Field Theory - Question 19
If the crystal field splitting energy of a tetrahedral complex of the type is , what is the crystal field splitting energy with respect to an octahedral complex, ?
Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 19
The crystal field splitting in the tetrahedral field is smaller than in the octahedral field.
For most purposes the relationship between tetrahedral and octahedral crystral field splitting may be represented as :

If the CFSE of tetrahedral complex of is , the CFSE of octahedral complex will be .
Test: Stability of complex ion, Crystal Field Theory - Question 20
The for complex is . The for will be:
Detailed Solution for Test: Stability of complex ion, Crystal Field Theory - Question 20
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