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Test: Isomerism - NEET MCQ


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10 Questions MCQ Test - Test: Isomerism

Test: Isomerism for NEET 2024 is part of NEET preparation. The Test: Isomerism questions and answers have been prepared according to the NEET exam syllabus.The Test: Isomerism MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Isomerism below.
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Test: Isomerism - Question 1

The number of isomers of C6H14 is:

Detailed Solution for Test: Isomerism - Question 1

C6H14 indicates saturated hydrocarbon i.e., an alkane. There are 5 chain isomers possible with this formula i.e., one linear, two monosubstituted, two distubstituted. Here are the isomers of C6H14 

Test: Isomerism - Question 2

2-chloropropane and 1-chloropropane exhibit ____________ isomerism.

Detailed Solution for Test: Isomerism - Question 2
  • When two or more compounds have the same molecular formula but the different position of functional groups are substituents, they are called positional isomers and the phenomenon is called position isomerism.
  • Here 2-chloropropane and 1-chloropropane differ in position so they exhibit position isomerism.
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Test: Isomerism - Question 3

The alkene that exhibits geometrical isomerism is

Detailed Solution for Test: Isomerism - Question 3

2-Butene exist as cis and trans isomers. The cis-isomer has the two methyl groups on the same side and the trans-isomer has the two methyl groups on opposite sides.

What is the relationship between trans-2-butene and cis-2 ...

Due to restricted rotation around double bond it exhibits geometrical isomerism.

Test: Isomerism - Question 4

Which of the following given compounds can exhibit tautomerism?

Detailed Solution for Test: Isomerism - Question 4
  • Tautomerism is a type of isomerism in which a molecule can exist in two different forms (tautomers) that are in equilibrium and can interconvert into each other by the migration of hydrogen atom or proton.
  • In all three compounds, Hydrogen can migrate, and keto from can get converted into enol form. So, All three compounds I, II, and III can exhibit tautomerism.

Hence, the Correct Option is B

Test: Isomerism - Question 5

The isomer of ethanol is:

Detailed Solution for Test: Isomerism - Question 5

The isomer of ethanol(CH3-CH2-OH) is dimethyl ether(CH3-O-CH3). This is a functional isomer of ethanol.

Explanation:

  • Functional isomers are the ones with the same molecular formula but different functional groups.
  • The molecular formula for dimethyl ether is C2H6O similar to ethanol.
  • Dimethyl ether has the structural formula CH3OCH3 and ethanol has the structural formula CH3CH2OH.
  • Therefore, dimethyl ether is the functional isomer of ethanol as both have the same molecular formula but one is ether and the other is alcohol. 
Test: Isomerism - Question 6

 Geometrical and Optical isomerism are types of:

Detailed Solution for Test: Isomerism - Question 6

Two molecules are described as stereoisomers if they are made of the same atoms connected in the same sequence, but the atoms are positioned differently in space.
Additional Information: Stereoisomers can be subdivided into: 
(i) Optical isomers: Optical isomers are those two compounds with the same chemical formula such that their mirror images are not superimposable on each other. Depending on the direction they rotate the plane of polarised light in a polarimeter, we have two forms of optical isomers. They are:

  • Dextro Isomer: This rotates to right.
  • Laevo Isomer: This rotates to left.

An example is butan-2-ol. It has four different groups attached to its second carbon atom.

(ii) Geometric isomers: In the case of disubstituted complexes, the substituted groups could either be adjacent or opposite to each other. This leads to geometric isomerism. Thus, we can prepare square planar complexes such as [Pt(NH3)4Cl2]  in two forms, cis and trans. When the chlorine atoms are adjacent to each other, we get the cis form. When two chlorine atoms are opposite, we get the trans-form.
coordination number

Test: Isomerism - Question 7

Which among the following defines Meso forms of isomers?

Detailed Solution for Test: Isomerism - Question 7

Meso forms of isomers are single compounds and their molecules are achiral hence they cannot be separated into pairs.

Additional Information: A meso compound or meso isomer is a non-optically active member of a set of stereoisomers, at least two of which are optically active. This means that despite containing two or more stereogenic centers, the molecule is not chiral. 

Test: Isomerism - Question 8

C3H6O represents an aldehyde and a ketone, is a type of:

Detailed Solution for Test: Isomerism - Question 8

The aldehyde and ketone that can be represented by molecular formula C3​H6​are propanal and propanone respectively.

Aldehyde - Propanal - CH3​CH2​CHO

Ketone - Propanone - CH3​COCH3​

These two carbon compounds are called functional isomers. They do not have the same physical properties since their functional group is different.

When hydrogen is present on one side of C=O group and other side is R, (RCHO), then it is an aldehyde group. When R is present on both sides of C=O group, then it is a ketone.

Test: Isomerism - Question 9

What is the specific rotation if its observed rotation is given as 3x, its length is given as x and density is given as 3/y?

Detailed Solution for Test: Isomerism - Question 9

The specific rotation is given by the expression observed rotation/length X density, here as observed rotation is given as 3x and its length is given as x, while the density is 3/y, the specific rotation equals 3x/x(y/3) = y.

Test: Isomerism - Question 10

Acetaldehyde and ethenol show ____________

Detailed Solution for Test: Isomerism - Question 10
  • The compounds acetaldehyde and ethenol exhibit tautomerism.
  • Tautomerism is a special type of functional isomerism which arises in carbonyl compounds containing α-hydrogen atom, it is a change of keto form to enol form.
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