Test: Strength of Solutions - JEE MCQ

Molality = moles of solute / kg of solvent.

1 ppm is equivalent to 1 part out of 1 million (10⁶) parts.
∴ Mass percent of 15 ppm chloroform in water 

⇒ 1.5 x 10^-3 g chloroform present in 100 g water
Thus, 15g chloroform will be present in water 

Molecular mass of glycerine = 92 g
Molecular mass of water = 18 g

No. of moles of glycerine = 46/92 = 0.5 moles
No. of moles of water = 36/18 = 2 moles

Thus, Mole fraction of glycerine = No. of moles of glycerine/(No. of moles of glycerine + No. of moles of water) = 0.5/(2 + 0.5)  = 0.20

12.5% w/w means 12.5 g in 100 g of solution.

Weight of solvent = 100 g – 12.5 g = 87.5 g.
Number of moles of sulphuric acid = 12.5/ 98 = 0.127 mol

⇒ molality = 0.127 x 1000/87.5 = 1.45 m

When both the solute and solvent are in solid state, then the solution is called a solid solution or solid sol.

Solid Sol includes gems, photochromic glass, alloys, ruby stone, coloured glass, vision glasses, etc.

In 3M there will be 3 moles per litre therefore in 3 litres there will be 9 moles.

We use parts per million to express the concentrations of solutions that contain very, very small amounts, often called trace amounts, of a given solute.

More specifically, a solution's concentration in parts per millions tells you the number of parts of solute present for every

10⁶ = 1,000,000

parts of solution. You can thus say that a 1 ppm solution will contain exactly 1 g of solute for every 10⁶g of solution.

In your case, you know that you have

in exactly
300.0 g = 3.000 ⋅ 10²g solution

This means that you can use this known composition as a conversion factor to scale up the mass of the solution to 10⁶g

Since this represents the mass of lead present in exactly 10⁶g of solution, you can say that the solution has a concentration of

The molecular weight of NaCl is 58.44 g/mol

So, one mole of NaCl weighs 58.44 g.

A 2.5 M solution is 2.5 moles per liter (Molarity is just the number of moles per liter).

Therefore, 0.5 L would contain 1.25 mol. Hence, you would need 1.25 × 58.44 g = 73 g.

The molarity of a resulting solution is given by

Mole fraction of third component is 1 - (0.6 + 0.32) = 0.08.
Since ethyl chloride has highest mole fraction so it is the solvent.