BITSAT Mock Test - 2 - JEE MCQ

Let f' be the frequency observed by the observer,
v₀ be the velocity of the observer, v_s be the velocity of the source,
v be the velocity of the sound and f be the actual frequency.

When two vectors are perpendicular to each other, then their dot product is zero.

Potential gradient of the potentiometer wire is
V/cm
Emf of the cell is
, l = 30 cm

In the expression, we have minimum three significant figures, hence answer should be up to three significant figures.
Rounding off the result 1.612979, we have

Velocities of light in two different mediums are given.

a = F/(M₁ + M₂)
Force (on mass M₁) = M₁ × a = M₁F/(M₁ + M₂)

In DC capacitors behave as open circuit, so current will pass through the resistances.
V_CD = V_C - V_D, V_AD = V_A - V_D, V_AC = V_A - V_C
V_C - V_D = (V_A - V_D) - (V_A - V_C)
V_CD = V_AD - V_AC    

Current in the main circuit is
= 1.2 A
Thus, the potential difference across AB is:

Also, the potential difference across AD is:

Effective capacitance is:

Since the capacitors are in series, charge Q is the same and is given by:


Therefore, the potential difference across AC is:

Thus, the potential difference between points C and D is:

Hence, the correct choice is (1).

The acceleration due to gravity at a height h above the surface of Earth is given by

For h = 32 km, we can use

Base BOH is dissociated as follows.

So, dissociation constant of BOH base,

At equilibrium,
K_b =
Given, and [BOH] = 0.01 M
Thus,

According to de-Broglie relation,

h = 6.62 x 10^-34 kgm²s^-1
KE = 13.6 x 1.602 x 10^-19 J
KE =
v =
= 2.18824 x 10⁶ m/s

= 0.3328 x 10^-9 m = 0.3328 nm

E.C. of Cr (Z = 24) is

Thus, number of electrons with l = 1 is 12
and number of electrons with l = 2 is 5
Note: Chromium shows exceptional configuration, [Ar], 3d⁵, 4s¹ so as to acquire a stable configuration of half-filled 3d orbitals.

a = 5 cm
V = (5 × 10^-8)³ cm³
Molecular mass, M = 56 + 16 = 72 g mol^-1

z = 4.18 4
Four molecules of ferrous oxide, FeO per unit cell, means that 4Fe²⁺ and 4O^2- ions are present in each unit cell.
Hence, FeO forms a CCP lattice.

Problem figure (2) is the mirror image of problem figure (1), but with inverse operations. Hence, to get the missing figure, the operations in problem figure (3) will become opposite, that is, '÷' will become '×' and vice versa.
Hence, option 4 is the correct answer.

Uma is taller than Poonam and Sonika, but shorter than Qurashi and is the second tallest. Waseem plays chess with Sonika and is the fourth tallest.

Qurashi does not play golf. The shortest does not play hockey and the tallest does not play golf. Uma is taller than Poonam and Sonika, but shorter than Qurashi and is the second tallest. Varun is shorter than Sonika, but only taller than Poonam. Risha is taller than Tanvi who is shorter than sonika.

Varun does not play hockey or golf.

The passage emphasises the importance of wetlands. Hence, statement 'a' is correct. Nowhere does the passage mention that tidal wetlands are less prone to degradation than non-tidal wetlands. Hence, we cannot say whether the author disagrees with statement 'b'. Statement 'c' is directly contradicted by the third paragraph,which states - 'With the growth of education, people have started understanding ecological processes and their attitudes towards wetlands have changed. They have recognised the ecological significance of the wetlands...' This means awareness filtered across the general populace. So, option 4 is the correct answer.

Each letter of the first group is replaced by its successor in the English alphabet to get the second group. Hence, fhJ will become giK to replace the question mark (?).

Here, the second sentence is the result of the first. Burden of frequent elections leads to the concept of 'one nation, one election'.
Use of 'however' and 'in lieu' in options a and b are not correct as they are used to create a contrasting meaning when we have to talk about two different sides. So only c is correct; As the development process is impeded and huge burden is imposed on a nation's human resources by frequent elections, the president of the country has proposed the concept of 'one nation, one election'.

Let 2n be the total number of terms
∴ S_2n = 5 [T₁ + T₃ + ... + T_{2n - 1}]
where T₁, T₃ ... T_{2n - 1} are terms occupying odd places
⇒ = 5[a + ar² + ... + ar^{2n - 2}]
[Sum of G.P., where a is first term and r is common ratio]
⇒ = 5a[1 + r² + ... + r^{2n - 2}]
⇒
⇒ 1 =
⇒ 1 + r = 5
∴ r = 4

The equation of the circle touching the co-ordinate axes is
x² + y² - 2cx - 2cy + c² = 0
i.e. (x - c)² + (y - c)² = c² ...(1)
This touches the line
...(2)
i.e.
i.e. 4x + 3y - 12 = 0 ...(3)
Perpendicular distance between centre (c, c) and line is

⇒
⇒ 7c - 12 = 5c or - 5c
⇒ 7c - 12 = 5c or 5c
⇒ c = 6 or c = 1
Hence, c = 1, 6

x² - 2y² - 2x + 8y - 1 = 0
or,
Comparing it with the general equation of hyperbola, we get
a² = 6 and b² = 3
Eccentricity for hyperbola is given by 'e' =
e =