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Class 9 Exam  >  Class 9 Tests  >  Olympiad Test: Number System- 1 - Class 9 MCQ

Olympiad Test: Number System- 1 - Class 9 MCQ


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10 Questions MCQ Test - Olympiad Test: Number System- 1

Olympiad Test: Number System- 1 for Class 9 2024 is part of Class 9 preparation. The Olympiad Test: Number System- 1 questions and answers have been prepared according to the Class 9 exam syllabus.The Olympiad Test: Number System- 1 MCQs are made for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Number System- 1 below.
Solutions of Olympiad Test: Number System- 1 questions in English are available as part of our course for Class 9 & Olympiad Test: Number System- 1 solutions in Hindi for Class 9 course. Download more important topics, notes, lectures and mock test series for Class 9 Exam by signing up for free. Attempt Olympiad Test: Number System- 1 | 10 questions in 15 minutes | Mock test for Class 9 preparation | Free important questions MCQ to study for Class 9 Exam | Download free PDF with solutions
Olympiad Test: Number System- 1 - Question 1
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Which of the following is the correct binary representation of the given octal number (463)?

Detailed Solution for Olympiad Test: Number System- 1 - Question 1
Octal number 463 is converted to binary as follows: 4 -> 100, 6 -> 110, 3 -> 011. Therefore, the binary representation is 100 110 011.
Olympiad Test: Number System- 1 - Question 2
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Convert the hexadecimal number 2F8A into its equivalent octal form.

Detailed Solution for Olympiad Test: Number System- 1 - Question 2
Hexadecimal 2F8A converts to octal as: 2 -> 002, F -> 017, 8 -> 010, A -> 012. So, the octal equivalent is 12722.
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Olympiad Test: Number System- 1 - Question 3
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What is the decimal equivalent of the binary number 1010101?

Detailed Solution for Olympiad Test: Number System- 1 - Question 3
Binary 1010101 converts to decimal as: 1 * 2^6 + 0 * 2^5 + 1 * 2^4 + 0 * 2^3 + 1 * 2^2 + 0 * 2^1 + 1 * 2^0 = 85.
Olympiad Test: Number System- 1 - Question 4
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Which of the following is the correct octal representation of the binary number 1011010?
Detailed Solution for Olympiad Test: Number System- 1 - Question 4
Binary 1011010 converts to octal as: 1 -> 1, 011 -> 3, 010 -> 2. So, the octal representation is 172.
Olympiad Test: Number System- 1 - Question 5
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Convert the decimal number 1234 into its hexadecimal form.
Detailed Solution for Olympiad Test: Number System- 1 - Question 5
Decimal 1234 converts to hexadecimal as: 1234 / 16 = 77 remainder 2, 77 / 16 = 4 remainder 13 (D in hexadecimal). So, the hexadecimal equivalent is 4D2.
Olympiad Test: Number System- 1 - Question 6
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What is the binary equivalent of the hexadecimal number ABCD?
Detailed Solution for Olympiad Test: Number System- 1 - Question 6
Hexadecimal ABCD converts to binary as: A -> 1010, B -> 1011, C -> 1100, D -> 1101. So, the binary equivalent is 1010 1011 1100 1101.
Olympiad Test: Number System- 1 - Question 7
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Convert the octal number 7654 into its decimal form.
Detailed Solution for Olympiad Test: Number System- 1 - Question 7
Octal 7654 converts to decimal as: 7 * 8^3 + 6 * 8^2 + 5 * 8^1 + 4 * 8^0 = 7 * 512 + 6 * 64 + 5 * 8 + 4 = 4029.
Olympiad Test: Number System- 1 - Question 8
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What is the octal equivalent of the binary number 11011101?
Detailed Solution for Olympiad Test: Number System- 1 - Question 8
Binary 11011101 converts to octal as: 110 -> 6, 111 -> 7, 01 -> 1. So, the octal equivalent is 375.
Olympiad Test: Number System- 1 - Question 9
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Which of the following is the correct hexadecimal representation of the octal number 567?
Detailed Solution for Olympiad Test: Number System- 1 - Question 9
Octal 567 converts to hexadecimal as: 5 -> 5, 6 -> 6, 7 -> 7. So, the hexadecimal representation is 2D7.
Olympiad Test: Number System- 1 - Question 10
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Convert the hexadecimal number FEDCBA98 into its equivalent binary form.
Detailed Solution for Olympiad Test: Number System- 1 - Question 10
Hexadecimal FEDCBA98 converts to binary as: F -> 1111, E -> 1110, D -> 1101, C -> 1100, B -> 1011, A -> 1010, 9 -> 1001, 8 -> 1000. So, the binary equivalent is 1111 1110 1100 1101 1011 1010 1001 1000.
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