Test: Number Play - 1 - Class 6 MCQ

To find the missing number, we can start by adding the given numbers and then subtracting this sum from 38,800:

• Sum of the given numbers: 25,000 + 13,000 + 400 + 400 = 38,800
• The sum of the given numbers is already 38,800.

This means the missing number is 0. However, since 0 is not listed as an option, it seems there might be an issue with the problem or options provided.

A 12-hour clock displays time using the hours 1 through 12, with two cycles for AM and PM. In this format, any time beyond 12:59 would require adjustment.

Let's analyze the options:

• A: 4:44 – This is a valid time on a 12-hour clock (4:44 AM or PM).
• B: 10:10 – This is a valid time on a 12-hour clock (10:10 AM or PM).
• C: 13:13 – This is NOT a valid time on a 12-hour clock, because 13:13 corresponds to 1:13 PM on a 12-hour clock, and times on a 12-hour clock range only from 1 to 12 for the hour.
• D: 12:12 – This is a valid time on a 12-hour clock (12:12 AM or PM).

Therefore, the correct answer is C: 13:13.

The Collatz Conjecture operates under the following rules:

• If the number is even, divide it by 2.
• If the number is odd, multiply it by 3 and add 1.

Starting with the number 12:

• 12 is even, so divide it by 2: 12 ÷ 2 = 6
• 6 is even, so divide it by 2: 6 ÷ 2 = 3

The next number after 6 is 3.

Thus, the correct answer is A: 3.

The 2-digit numbers between 10 and 99 start at 10 and end at 99. To find how many 2-digit numbers are in this range, we subtract the smallest 2-digit number (10) from the largest (99) and then add 1:

99 − 10 + 1 = 90

So, there are 90 two-digit numbers between 10 and 99.

Therefore, the correct answer is C: 90.

Kaprekar's process involves the following steps:

1. Take any four-digit number (with at least two distinct digits).
2. Rearrange the digits to form the largest and smallest possible numbers.
3. Subtract the smaller number from the larger number.
4. Repeat the process with the resulting number.

Step-by-Step Process:

Starting with 4176:

7641 - 1467 = 6174

• Arrange the digits of 4176 to form the largest and smallest numbers:
  • Largest: 7641
  • Smallest: 1467
• Subtract the smallest from the largest:

After applying Kaprekar's process to 4176, we arrive at 6174.

The result of applying Kaprekar's process to 4176 is 6174.

Let's find the fourth number in the Collatz sequence starting from 21.

Steps:

1. 21 is odd, so multiply by 3 and add 1:
   21 × 3 + 1 = 64
2. 64 is even, so divide by 2:
   64 ÷ 2 = 32
3. 32 is even, so divide by 2:
   32 ÷ 2 = 16
4. 16 is even, so divide by 2:
   16 ÷ 2 = 8

Sequence:

The sequence starting from 21 is: 21 → 64 → 32 → 16

The fourth number in the sequence is 16.