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Class 6 Exam  >  Class 6 Tests  >  Test: Perimeter and Area - 2 - Class 6 MCQ

Test: Perimeter and Area - 2 - Class 6 MCQ


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10 Questions MCQ Test - Test: Perimeter and Area - 2

Test: Perimeter and Area - 2 for Class 6 2024 is part of Class 6 preparation. The Test: Perimeter and Area - 2 questions and answers have been prepared according to the Class 6 exam syllabus.The Test: Perimeter and Area - 2 MCQs are made for Class 6 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Perimeter and Area - 2 below.
Solutions of Test: Perimeter and Area - 2 questions in English are available as part of our course for Class 6 & Test: Perimeter and Area - 2 solutions in Hindi for Class 6 course. Download more important topics, notes, lectures and mock test series for Class 6 Exam by signing up for free. Attempt Test: Perimeter and Area - 2 | 10 questions in 15 minutes | Mock test for Class 6 preparation | Free important questions MCQ to study for Class 6 Exam | Download free PDF with solutions
Test: Perimeter and Area - 2 - Question 1
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If the area of a square carpet is 81 sq m, what is the length of one side?

Detailed Solution for Test: Perimeter and Area - 2 - Question 1
The side length of the square = √Area = √81 sq m = 9 m.
Test: Perimeter and Area - 2 - Question 2
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The length and breadth of a rectangle are in the ratio 3:2. If the perimeter of the rectangle is 30 m, what is the length?

Detailed Solution for Test: Perimeter and Area - 2 - Question 2
Let the length be 3x and the breadth be 2x. Perimeter = 2 × (Length + Breadth) = 2 × (3x + 2x) = 10x. Given 10x = 30 m, so x = 3. Length = 3x = 9 m.
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Test: Perimeter and Area - 2 - Question 3
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A triangle has sides of length 3 cm, 4 cm, and 5 cm. What is the perimeter of the triangle?

Detailed Solution for Test: Perimeter and Area - 2 - Question 3
The perimeter of a triangle = sum of all its sides = 3 cm + 4 cm + 5 cm = 12 cm.
Test: Perimeter and Area - 2 - Question 4
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A rectangle has a length of 7 m and a breadth of 5 m. What is the area of the rectangle?
Detailed Solution for Test: Perimeter and Area - 2 - Question 4
Area of a rectangle = Length × Breadth = 7 m × 5 m = 35 sq m.
Test: Perimeter and Area - 2 - Question 5
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A field is shaped like a square and has a perimeter of 120 m. What is the area of the field?
Detailed Solution for Test: Perimeter and Area - 2 - Question 5
Side length of the square = Perimeter / 4 = 120 m / 4 = 30 m. Area = Side length × Side length = 30 m × 30 m = 900 sq m.
Test: Perimeter and Area - 2 - Question 6
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The area of a rectangle is 72 sq m and its length is 12 m. What is the width?
Detailed Solution for Test: Perimeter and Area - 2 - Question 6
Area of a rectangle = Length × Width. Width = Area / Length = 72 sq m / 12 m = 6 m.
Test: Perimeter and Area - 2 - Question 7
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A rectangle has a length of 15 m and a perimeter of 50 m. What is the breadth of the rectangle?
Detailed Solution for Test: Perimeter and Area - 2 - Question 7

Perimeter of a rectangle = 2 × (Length + Breadth).
Given 50 m = 2 × (15 m + Breadth).
Solving for Breadth, transposed 2 to L.H.S. , We get 

50/2 m = 15m + Breadth
25m = 15m + Breadth
10m = Breadth

Test: Perimeter and Area - 2 - Question 8
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If the perimeter of a rectangle is 36 m and the length is 10 m, what is the width?
Detailed Solution for Test: Perimeter and Area - 2 - Question 8

Perimeter of a rectangle = 2 × (Length + Width).
Given 36 m = 2 × (10 m + Width).
Solving for Width, we get Width 
36/2m = 10m + Width
18m = 10m + Width
8m = Width

Test: Perimeter and Area - 2 - Question 9
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What is the perimeter of a square with a side length of 4 cm?
Detailed Solution for Test: Perimeter and Area - 2 - Question 9
The perimeter of a square is calculated by multiplying the length of one side by 4. So, Perimeter = 4 × 4 cm = 16 cm.
Test: Perimeter and Area - 2 - Question 10
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If the perimeter of a rectangle is 20 cm and its length is 6 cm, what is its breadth?
Detailed Solution for Test: Perimeter and Area - 2 - Question 10
Perimeter of a rectangle = 2 × (Length + Breadth). Given 20 cm = 2 × (6 cm + Breadth). Solving for Breadth, Breadth = (20 cm / 2) - 6 cm = 4 cm.
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