Class 6 Exam  >  Class 6 Tests  >  Test: Perimeter and Area - 2 - Class 6 MCQ

Test: Perimeter and Area - 2 - Class 6 MCQ


Test Description

10 Questions MCQ Test - Test: Perimeter and Area - 2

Test: Perimeter and Area - 2 for Class 6 2024 is part of Class 6 preparation. The Test: Perimeter and Area - 2 questions and answers have been prepared according to the Class 6 exam syllabus.The Test: Perimeter and Area - 2 MCQs are made for Class 6 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Perimeter and Area - 2 below.
Solutions of Test: Perimeter and Area - 2 questions in English are available as part of our course for Class 6 & Test: Perimeter and Area - 2 solutions in Hindi for Class 6 course. Download more important topics, notes, lectures and mock test series for Class 6 Exam by signing up for free. Attempt Test: Perimeter and Area - 2 | 10 questions in 15 minutes | Mock test for Class 6 preparation | Free important questions MCQ to study for Class 6 Exam | Download free PDF with solutions
Test: Perimeter and Area - 2 - Question 1

If the area of a square carpet is 81 sq m, what is the length of one side?

Detailed Solution for Test: Perimeter and Area - 2 - Question 1

Step 1: Use the formula for the area of a square.

The formula for the area A of a square is:

A = side length × side length

Step 2: Solve for the side length.

To find the side length, take the square root of the area:

side length = √A = √81 = 9 meters

The length of one side of the square carpet is 9 meters.

Test: Perimeter and Area - 2 - Question 2

A triangle has sides of length 3 cm, 4 cm, and 5 cm. What is the perimeter of the triangle?

Detailed Solution for Test: Perimeter and Area - 2 - Question 2

Step 1: Use the formula for the perimeter of a triangle.

The perimeter P of a triangle is the sum of the lengths of its three sides:

P = Side 1 + Side 2 + Side 3

Step 2: Substitute the given values.

Substitute the given side lengths:

P = 3 + 4 + 5 = 12 cm

The perimeter of the triangle is 12 cm.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Perimeter and Area - 2 - Question 3

A rectangle has a length of 7 m and a breadth of 5 m. What is the area of the rectangle?

Detailed Solution for Test: Perimeter and Area - 2 - Question 3
Area of a rectangle = Length × Breadth = 7 m × 5 m = 35 sq m.
Test: Perimeter and Area - 2 - Question 4

A field is shaped like a square and has a perimeter of 120 m. What is the area of the field?

Detailed Solution for Test: Perimeter and Area - 2 - Question 4

To calculate the area of the square field, we first need to find the length of one side. The formula for the perimeter P of a square is:

P = 4 × side length

Given:

Perimeter P = 120 m

We can solve for the side length:

side length = P/4 = 120/4 = 30 m

Now, to find the area A of the square, we use the formula:

A = side length2

Substitute the value of the side length:

A = 302 = 900 sq m

So, the area of the field is 900 square meters.

Test: Perimeter and Area - 2 - Question 5

The area of a rectangle is 72 sq m and its length is 12 m. What is the width?

Detailed Solution for Test: Perimeter and Area - 2 - Question 5

The area of a rectangle is calculated by multiplying its length and width.
Given:

  • Area = 72 sq m
  • Length = 12 m

The formula for area is:

Area = Length × Width

Substitute the given values:

72 = 12 × Width

Solve for Width:

Width = 72/12 = 6 m

So, the correct answer is A: 6 m.

Test: Perimeter and Area - 2 - Question 6

A rectangle has a length of 15 m and a perimeter of 50 m. What is the breadth of the rectangle?

Detailed Solution for Test: Perimeter and Area - 2 - Question 6

Perimeter of a rectangle = 2 × (Length + Breadth).
Given 50 m = 2 × (15 m + Breadth).
Solving for Breadth, transposed 2 to L.H.S. , We get 

50/2 m = 15m + Breadth
25m = 15m + Breadth
10m = Breadth

Test: Perimeter and Area - 2 - Question 7

If the perimeter of a rectangle is 36 m and the length is 10 m, what is the width?

Detailed Solution for Test: Perimeter and Area - 2 - Question 7

Perimeter of a rectangle = 2 × (Length + Width).
Given 36 m = 2 × (10 m + Width).
Solving for Width, we get Width 
36/2m = 10m + Width
18m = 10m + Width
8m = Width

Test: Perimeter and Area - 2 - Question 8

What is the perimeter of a square with a side length of 4 cm?

Detailed Solution for Test: Perimeter and Area - 2 - Question 8

The perimeter of a square is calculated using the formula:

Perimeter = 4 × Side length

Given: Side length = 4 cm

Substitute the value into the formula:

Perimeter = 4 × 4 = 16 cm

So, the correct answer is C: 16 cm.

Test: Perimeter and Area - 2 - Question 9

The perimeter of the figure

Detailed Solution for Test: Perimeter and Area - 2 - Question 9

To find the perimeter of the given figure, we need to add the lengths of all the sides:

The sides are given as: 3 cm, 4 cm, 6 cm, 2 cm, 3 cm.

Now, add them together:

3 + 4 + 6 + 2 + 3 + 2 = 20 cm

The perimeter of the figure is 20 cm.

Test: Perimeter and Area - 2 - Question 10

If the perimeter of a rectangle is 20 cm and its length is 6 cm, what is its breadth?

Detailed Solution for Test: Perimeter and Area - 2 - Question 10

The perimeter of a rectangle is given by the formula:

Perimeter = 2 × (Length + Breadth)

Given:

  • Perimeter = 20 cm
  • Length = 6 cm

Substitute the values into the formula:

20 = 2 × (6 + Breadth)

Divide both sides by 2:

10 = 6 + Breadth

Now, solve for Breadth:

Breadth = 10 − 6 = 4 cm

So, the correct answer is B: 4 cm.

Information about Test: Perimeter and Area - 2 Page
In this test you can find the Exam questions for Test: Perimeter and Area - 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Perimeter and Area - 2, EduRev gives you an ample number of Online tests for practice

Top Courses for Class 6

Download as PDF

Top Courses for Class 6