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Test: Profit & Loss- 1 - CAT MCQ


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10 Questions MCQ Test - Test: Profit & Loss- 1

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Test: Profit & Loss- 1 - Question 1

A feeding bottle is sold for Rs. 150. Sales tax accounts for one-fifth of this and profit one-third of the remainder. Find the cost price of the feeding bottle. 

Detailed Solution for Test: Profit & Loss- 1 - Question 1

Sales tax = 150 / 5 = 30
∵ SP contains Rs. 30 component of sales tax.
Of the remainder (150 – 30 = 120) 1/3rd is the profit.
Thus, the profit = 120 / 3 = 40
Hence, Cost price = 120 – 40 = 80

So option B is correct

Test: Profit & Loss- 1 - Question 2

E owns a house worth Rs. 20,000. He sells it to R at a profit of 25%. After some time, R sells it back to E at 25% loss. Find E’s loss or gain per cent.

Detailed Solution for Test: Profit & Loss- 1 - Question 2

CP = 20000
Profit = 25/100 of 20000 = 5000
SP = Profit + CP = 25000

New transaction

CP= 25000
Loss = 25% of 25000 = 6250
SP = CP - Loss = 18750

P's gain = 1250
TOTAL gain = 6250
Total gain % = 6250/20000 × 100 = 625/20 = 31.25%

So option C is correct

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Test: Profit & Loss- 1 - Question 3

125 toffees cost Rs. 75. Find the cost of one million toffees if there is a discount of 40% on the selling price for this quantity.

Detailed Solution for Test: Profit & Loss- 1 - Question 3

The cost per toffee = 75 / 125 = Rs. 0.6 = 60 paise.
Cost of 1 million toffees = 600000.
∵ There is a discount of 40% offered on this quantity.
Thus, the total cost for 1 million toffees is 60% of 600000 = 360000 

So option C is correct

Test: Profit & Loss- 1 - Question 4

A man sells a TV set for Rs. 33000 and makes a profit of 10%. He sells another TV at a loss of 20%. If on the whole, he neither gains nor loses, find the selling price of the second TV set.

Detailed Solution for Test: Profit & Loss- 1 - Question 4

Let's denote the cost price of the first TV as CP1, the cost price of the second TV as CP2, and the selling price of the second TV as SP2.

The man makes a profit of 10% on the first TV, so we can write the selling price of the first TV as:

SP1 = CP1 + 10% of CP1
33000 = CP1 + 0.1 * CP1
33000 = 1.1 * CP1
CP1 = 33000 / 1.1
CP1 = 30000

He sells the second TV at a loss of 20%, so we can write the selling price of the second TV as:

SP2 = CP2 - 20% of CP2
SP2 = 0.8 * CP2

Since he neither gains nor loses on the whole, the total cost price equals the total selling price:

CP1 + CP2 = SP1 + SP2

We already know the values of CP1 and SP1, so we can substitute them in the equation:

30000 + CP2 = 33000 + SP2

We also know that SP2 = 0.8 * CP2, so we can substitute that as well:

30000 + CP2 = 33000 + 0.8 * CP2

Now, we can solve for CP2:

0.2 * CP2 = 3000
CP2 = 15000

Now that we have the cost price of the second TV, we can find its selling price using the relation we found earlier:

SP2 = 0.8 * CP2
SP2 = 0.8 * 15000
SP2 = 12000

So the selling price of the second TV set is Rs. 12000.

Test: Profit & Loss- 1 - Question 5

E sold at table to R at a profit of 25%.R sold the same table to S for Rs. 90 thereby making a profit of 20%. Find the price at which E bought the table from Z if it is known that Z gained 25% in the transaction.

Detailed Solution for Test: Profit & Loss- 1 - Question 5

R sold the table at 20% profit at Rs. 90. Thus R's cost price x 1.2 = 90
R’s Cost price = Rs. 75

We also know that E sold it to R at 25% profit.
Thus, E’s Cost price x 1.25 = 75
⇒ E’s cost price = 60

So option D is correct

Test: Profit & Loss- 1 - Question 6

A man sells an article at 10% above its cost price. If he had bought it at 15% less than what he paid for it and sold it for Rs. 33 less, he would have gained 10%. Find the cost price of the article.

Detailed Solution for Test: Profit & Loss- 1 - Question 6

S.P. at 10% profit = Rs.(110y/100) = 11y/10
New C.P. of article = 85y/100 = 17y/20
S.P. = Rs.(17y/20 * 110/100)
New S.P. of article = Rs. 187/200

According to Question,
11y/10 - 187y/200 = 33
33y/200 = 33
y = 200

So option B is correct

Test: Profit & Loss- 1 - Question 7

E sells a car priced at Rs. 1,80,000. He gives a discount of 5% on the first Rs. 1,00,000 and 12.5% on the remaining Rs. 80,000. His competitor R sells a car on the same market priced at Rs. 1,80,000. If he wants to be competitive what percent discount should R offer on the marked price.

Detailed Solution for Test: Profit & Loss- 1 - Question 7

The total discount offered by E = 5% on 1,00,000 + 12.5% on 80,000 = 5,000 + 10,000 = 15,000.

If R wants to be as competitive, he should also offer a discount of Rs. 15,000 on 1,80,000.

Discount percentage = (15000/180000) x 100= 8.33% discount.

So option B is correct

Test: Profit & Loss- 1 - Question 8

A dishonest dealer marks up the price of his goods by 20% and gives a discount of 10% to the customer. Besides, he also cheats both his supplier and his buyer by 100 grams while buying or selling 1 kilogram. Find the percentage profit earned by the shopkeeper.

Detailed Solution for Test: Profit & Loss- 1 - Question 8



Test: Profit & Loss- 1 - Question 9

I sell 16 sheep at a gain of 12.5% and 20 more at a certain gain percent. If 1 gain 25% on the whole, how much percent gain did I make on the latter number?

Detailed Solution for Test: Profit & Loss- 1 - Question 9

On the whole I gain 25%
Therefore, I should get the cost price of 36 × 125/100 = 45 sheep.
But I sell the first lot at a gain of 12.5%
Hence by selling 16 sheep, I get the cost price of 16 × 112.5/100 = 18 sheep.
Therefore, I should get the cost price of 45-18=27 sheep by selling the second lot of 20.
Hence my gain there should be 7/20 × 100 = 35

Test: Profit & Loss- 1 - Question 10

A farmer buys 240 cows. He sells some of them at a gain of 20% and the remaining at a gain of 30%. If he gains 28% on the whole, then how many did he sell at a gain of 20%?

Detailed Solution for Test: Profit & Loss- 1 - Question 10

Let him sell x cows at the gain of 20% and y cows at a gain of 30%.

Therefore, 0.2x + 0.3y = -0.28(x + y)

⇒ y = 4x, Therefore, x + 4x = 240 ⇒ x = 48.

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