CAT Exam  >  CAT Tests  >  Test: Arun Sharma Based Level 1: Percentages - CAT MCQ

Test: Arun Sharma Based Level 1: Percentages - CAT MCQ


Test Description

15 Questions MCQ Test - Test: Arun Sharma Based Level 1: Percentages

Test: Arun Sharma Based Level 1: Percentages for CAT 2024 is part of CAT preparation. The Test: Arun Sharma Based Level 1: Percentages questions and answers have been prepared according to the CAT exam syllabus.The Test: Arun Sharma Based Level 1: Percentages MCQs are made for CAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Arun Sharma Based Level 1: Percentages below.
Solutions of Test: Arun Sharma Based Level 1: Percentages questions in English are available as part of our course for CAT & Test: Arun Sharma Based Level 1: Percentages solutions in Hindi for CAT course. Download more important topics, notes, lectures and mock test series for CAT Exam by signing up for free. Attempt Test: Arun Sharma Based Level 1: Percentages | 15 questions in 15 minutes | Mock test for CAT preparation | Free important questions MCQ to study for CAT Exam | Download free PDF with solutions
Test: Arun Sharma Based Level 1: Percentages - Question 1

What fraction is equal to 57.12% (approximately)?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 1

Test: Arun Sharma Based Level 1: Percentages - Question 2

a% of a + b% of b = 2% of ab, then what percentage of a is b?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 2

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Arun Sharma Based Level 1: Percentages - Question 3

The height of a triangle is increased by 30%. What can be the maximum percentage increase in length of the base, so that the increase in area is restricted to a maximum of 90%?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 3

Test: Arun Sharma Based Level 1: Percentages - Question 4

The length of rectangle is increased by 30% and the breadth is decreased by 25%. What is the percentage change in the area of the rectangle due to this?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 4

Test: Arun Sharma Based Level 1: Percentages - Question 5

At an election, the candidate who got 60% of the votes cast won by 200 votes. Find the total number of voters on the voting list, if 66.67% people cast their vote and there were no invalid votes.

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 5

Test: Arun Sharma Based Level 1: Percentages - Question 6

A man spends 25% of his money on food. After spending 50% of the remaining, he is left with Rs 375. How much money was with that man initially?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 6

Assume that he had initially Rs 100.

After spending on food, money left = Rs 75

After spending 50% of Rs 75, he had Rs 37.5

 

Test: Arun Sharma Based Level 1: Percentages - Question 7

The total of male and female populations in a city increased by 25% from 1970 to 1980. During the same period, the male population increased by 40% while the female population increased by 20%. From 1980 to 1990, the female population increased by 25%. In 1990, if the female population is twice the male population, then the percentage increase in the total of male and female populations in the city from 1970 to 1990 is

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 7

Let us solve this question by assuming values(multiples of 100) and not variables(x).

Since we know that the female population was twice the male population in 1990, let us assume their respective values as 200 and 100.

Note that while assuming numbers, some of the population values might come out as a fraction(which is not possible, since the population needs to be a natural number). However, this would not affect our answer, since the calculations are in ratios and percentages and not real values of the population in any given year.

Now, we know that the female population became 1.25 times itself in 1990 from what it was in 1980.
Hence, the female population in 1980 = 200/1.25 = 160 Also, the female population became 1.2 times itself in 1980 from what it was in 1970.
Hence, the female population in 1970 = 160/1.2 = 1600/12 = 400/3

Let the male population in 1970 be x. Hence, the male population in 1980 is 1.4x.

Now, the total population in 1980 = 1.25 times the total population in 1970.
Hence, 1.25 (x + 400/3) = 1.4x + 160
Hence, x = 400/9.
Population change = 300 - 400/9 - 400/3 = 300 - 1600/9 = 1100/9
percentage change = 

Test: Arun Sharma Based Level 1: Percentages - Question 8

In a mixture of 100 litres of milk and water, 25% of the mixture is milk. How much water should be added to the mixture, so that milk becomes 20% of the mixture?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 8

Test: Arun Sharma Based Level 1: Percentages - Question 9

An amount is lent at y% p.a. simple interest for two years. Instead, had it been lent at 2y% p.a. simple interest for y more years, then the interest would have been five times the earlier interest. Find the value of y.

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 9


Test: Arun Sharma Based Level 1: Percentages - Question 10

Find the least number of integral years in which a sum of money invested at 20% compound interest per annum will become more than double itself.

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 10

Given Data:

Compound Interest Rate (r): 20% or 0.20

The sum of money is more than doubled.

Concept:

The formula for compound interest is A = P(1+r/n)(nt), where P is the principal amount, r is the annual interest rate, n is the number of times interest is compounded per year, t is the time the money is invested for in years. When compounded annually (n=1), this simplifies to A = P(1+r)t.

Solution:

We know that the formula for compound interest, when compounded annually, is A = P(1 + r)^t. Here, we want to find the smallest whole number for time t so that A > 2P.

Substituting A as 2P and r as 0.20 into the formula, we get, ⇒ 2 = (1 + 0.20)t ⇒ 2 = 1.20t

We can now try different values for t until we reach a number where 1.20t > 2.

Using t = 1, we get 1.201 = 1.20 which is not greater than 2.

Using t = 2, 1.202 = 1.44 which is not greater than 2.

Using t = 3, 1.203 = 1.728 which is not greater than 2.

Using t = 4, 1.204 = 2.0736 which is greater than 2.

Therefore, the least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is 4 years.

Test: Arun Sharma Based Level 1: Percentages - Question 11

Shyam invests ₹₹40000 in some shares in the ratio 1:4:5 which pay dividends of 10%, 15% and 25% (on his investment) for that year respectively. Find his dividend income.

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 11

Test: Arun Sharma Based Level 1: Percentages - Question 12

The salary of Ajay is 10% more than that of Vivek. Find by what percentage is the salary of Vivek less than that of Ajay?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 12

Test: Arun Sharma Based Level 1: Percentages - Question 13

A, B and C donate 8%, 7% and 9%, of their salaries, respectively to a charitable trust. The salaries of A and B are same and the difference between their donations is 259. The total donation of A and B is 1185 more than that of C. The total donation of A and C is what percentage of the total salaries of A, B and C?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 13

Let salaries of A and B be Rs. x and salary of C be Rs. y, then

8x/100 – 7x/100 = 259

⇒ x/100 = 259

⇒ x = 25900

Salaries of A and B is Rs. 25900.

Donation of A and B = 25900 × (8 + 7)/100 = 25900 × 15/100 = 3885

Donation of C = 3885 – 1185 = 2700

y × (9/100) = 2700

⇒ y = 30,000

Sum of salaries of A, B and C = 25900 + 25900 + 30000 = 81800

Donation of A = 259 × (8/100) = 2072

Total donation of A and C = 2072 + 2700 = 4772

Percentage of total donation of total salaries of A, B and C = (4772/81800) × 100 = 5.8%

Short Trick:

Let salaries of A, B be 100%

⇒ 8% – 7% = 259

⇒ 1% = 259

⇒ 8% = 2072

⇒ 15% = 3885

⇒ 100% = 25900

Donation of C = 3885 – 1185 = 2700

⇒ 9% = 2700

⇒ 100% = 30,000

Total donation of A and C = 2072 + 2700 = 4772

Total salaries of A, B and C = 25900 + 25900 + 30000 = 81800

∴ Required percentage = 4772/81800 × 100 = 5.8%

Test: Arun Sharma Based Level 1: Percentages - Question 14

In solution of sugar and water the ratio of sugar and water by weight is 1:4. This solution is heated and in the process it loses 50% weight. What is the ratio of weight of sugar and water in the final mixture?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 14

Weight of solution = (1+4) = 5 units weight of sugar = 1 unit weight of water after heating =1.5 units Required ration =1 : 1.5 = 2 : 3

Test: Arun Sharma Based Level 1: Percentages - Question 15

Dataman Infosys Systems is a Lucknow-based software company which is growing tremendously. It doubled its turnover in 1998 from Rs 50 crores in 1997. Then it tripled its turnover in 1999 and grew by 50% in 2000. What is the turnover at the end of 2000?

Detailed Solution for Test: Arun Sharma Based Level 1: Percentages - Question 15

Turnover in 1998 = Rs 100 cr Turnover in 1999 = Rs 300 cr Turnover in 2000 = Rs 450 cr

Information about Test: Arun Sharma Based Level 1: Percentages Page
In this test you can find the Exam questions for Test: Arun Sharma Based Level 1: Percentages solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Arun Sharma Based Level 1: Percentages, EduRev gives you an ample number of Online tests for practice

Top Courses for CAT

Download as PDF

Top Courses for CAT