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Test: Arun Sharma Based Level 2: Percentages - CAT MCQ


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15 Questions MCQ Test - Test: Arun Sharma Based Level 2: Percentages

Test: Arun Sharma Based Level 2: Percentages for CAT 2024 is part of CAT preparation. The Test: Arun Sharma Based Level 2: Percentages questions and answers have been prepared according to the CAT exam syllabus.The Test: Arun Sharma Based Level 2: Percentages MCQs are made for CAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Arun Sharma Based Level 2: Percentages below.
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Test: Arun Sharma Based Level 2: Percentages - Question 1

Because of the budget presented by Yashwant Sinha, the price of sugar increased by 40%. The Verma family reduced its consumption so that expenditure on sugar is up by 12%. If the total consumption of sugar before the rise in price was 50 kg. What is the present consumption of sugar (in kg)?

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 1

Original price = Rs 100
Expenditure = Rs 50 x 100= Rs 5000 Expenditure after rise = Rs 5600 Then, 140 x x = 5600
X= 40

Test: Arun Sharma Based Level 2: Percentages - Question 2

Out of 51,600 candidates who appeared in an examination, 35% failed, while 15% passed with honours. What is the number of candidates who passed the examination, but failed to obtain honours, assuming that no student who has failed can obtain honours?

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 2

total candidates=51600

35% failed=35*51600/100=18060

therefore 65 % are passed

65% of 51600=33540

while 15% passed with honour

15%of 33540=5031

therefore

total no of student passed with no honour= 33540-5031

= 28509

No of student passed with no honour= 28509

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Test: Arun Sharma Based Level 2: Percentages - Question 3

A locomotive engine runs at a speed of 50 km/h when no compartment is attached to it. For every new compartment that is attached to it, the speed of the train is reduced by 10% of the earlier speed. At most, how many compartments can be attached so that the train can cover a distance of 180 km in a maximum of 8 hours?

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 3

Let n = number of components attached, Vn = speed of train when ‘n ’ compartments are attached

V0 = 50 
V1 = 45

V2 = 40.5 and so on

At n = 7, we get the answer.

Test: Arun Sharma Based Level 2: Percentages - Question 4

If the price of an article rose by 25% every odd year and fell by 20% every even year, what would be the percentage change after 180 years?

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 4

Let the original price = Rs 100

Price after 1st year = Rs 125

Price after 2nd year = Rs 100

Hence, after 180 year, there will be no change in the price

Test: Arun Sharma Based Level 2: Percentages - Question 5

In an examination, 80% students passed in philosophy and 70% students passed in maths. At the same time 15% failed in both the subjects. If 390 students passed in both the subjects, how many students appeared in the examination?

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 5

15% failed in both the subjects ⇒ 85% passed in at least one of the subjects.

So, percentage of students passing both the subjects = 80 + 70 - 85 = 65%
So, 65% = 390 ⇒ 100% = 600

Test: Arun Sharma Based Level 2: Percentages - Question 6

In the recent census report of Patna, it was found that 40% of total male adult population and 55% of total female adult population is married. What percentage of total adult population of Patna is married? (Polygamy is not in practice in Patna.)

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 6

Test: Arun Sharma Based Level 2: Percentages - Question 7

In an election, 10% of the voters on the voter’s list did not cast their votes and 60 voters cast their ballot papers blank. There were only two candidates. The winner was supported by 47% of all voters in the list and he got 380 votes more than his rival. The number of voters on the list were

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 7

Test: Arun Sharma Based Level 2: Percentages - Question 8

One-third of Mayank’s marks in history equals his marks in geography. If he obtained 180 marks in two subjects together, how much marks did he get in geography?

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 8

x +y = 180           (1)
x - 3 y = 0            (2)
Solving the equations, we get x = 135, y = 45

Test: Arun Sharma Based Level 2: Percentages - Question 9

The entry fee in an exhibition was Rs 10. Later this was reduced by 25%, which increased the sale of tickets by 20%. Find the percentage increase in the number of visitors.

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 9
  • Initial entry fee = Rs 10
  • Let us assume there were 100 people who were attending the exhibition
  • Now the ticket price has been reduced by 25%
  • Current price = Rs 7.5
  • And now the number of people has increased to 120
  • Now lets suppose 'y' people are attending the exhibition now
  • therefore , 7.5 x y = 120
  • y = 160
  • Percentage change = ((160 - 100) / 100) x 100
  • = 60%
  • Correct Answer- Option C
Test: Arun Sharma Based Level 2: Percentages - Question 10

An electrical contractor purchased a certain amount of wire, 10% of which was stolen. After using 85% of the remainder he had 47.25 m of wire left. How much wire did he purchase?

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 10

Test: Arun Sharma Based Level 2: Percentages - Question 11

There were only two contestants A and B in the recent assembly election in Bihar at Raghopur constituency. B got 50% of the votes that A got. Had A got 200 votes less, there would have been a tie. What is the total number of votes polled?

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 11

Let A's votes be x and B's votes be y. We are given:

1. y = 0.5x (B got 50% of the votes that A got)
2. x - 200 = y (Had A got 200 votes less, there would have been a tie)

Now we can substitute the first equation into the second equation:

x - 200 = 0.5x
0.5x = 200
x = 400

Now we can find y using the first equation:

y = 0.5 * 400
y = 200

So the total number of votes polled is x + y = 400 + 200 = 600.

Test: Arun Sharma Based Level 2: Percentages - Question 12

A is an alloy of tin and copper and B is an alloy of copper and zinc. A has 30% copper while B has 50% copper, x gm of A is mixed with 30 gins of B to form another alloy which has 45% copper. What is the value of x?

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 12

Test: Arun Sharma Based Level 2: Percentages - Question 13

One litre of water is evaporated from 6 litres of solution containing 4% of sugar. The percentage of sugar in the remaining solution is

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 13

Test: Arun Sharma Based Level 2: Percentages - Question 14

There are 1,10,000 books at Khuda Baksh Oriental Public Library, 40% of which are science books. It was decided to add 20,000 new books to the library. How many of the new books should be science books in order to bring the percentage of science books in the library equal to 45%?

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 14

Test: Arun Sharma Based Level 2: Percentages - Question 15

In a tournament, a team has played 40 matches so far and won 30% of them. If they win 60% of the remaining matches, their overall win percentage will be 50%. Suppose they win 90% of the remaining matches, then the total number of matches won by the team in the tournament will be

Detailed Solution for Test: Arun Sharma Based Level 2: Percentages - Question 15

Initially number of matches = 40

Now matches won = 12

Now let remaining matches be x

Now number of matches won = 0.6x

Now as per the condition :


24 +1.2x = 40 + x
0.2x=16
x=80
Now when they won 90% of remaining = 80(0.9) =72
So total won = 84

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