JEE Exam  >  JEE Test  >  Daily Test Preparation  >  Test: The Lanthanoids & The Actinoids(20 Jan) - JEE MCQ

The Lanthanoids & Actinoids(20 Jan) - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: The Lanthanoids & The Actinoids(20 Jan) (10 Questions)

You can prepare effectively for JEE Daily Test for JEE Preparation with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: The Lanthanoids & The Actinoids(20 Jan)". These 10 questions have been designed by the experts with the latest curriculum of JEE 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 10

Sign up on EduRev for free to attempt this test and track your preparation progress.

Test: The Lanthanoids & The Actinoids(20 Jan) - Question 1

Which of the following group contain mostly radioactive elements ?

Detailed Solution: Question 1

The actinoids are said to be most radioactive metals because in this group all the metals have very oxidation number and are very rare metals found on earth and it has all the elements radioactive in its group and it has most radioactive metal uranium in it's group.

Test: The Lanthanoids & The Actinoids(20 Jan) - Question 2

 Mischmetal is an alloy of:

    Detailed Solution: Question 2

    The correct answer is option A

    Misch metal, alloy consisting of about 50 percent cerium, 25 percent lanthanum, 15 percent neodymium, and 10 percent other rare-earth metals.

    Test: The Lanthanoids & The Actinoids(20 Jan) - Question 3

    What is the most common oxidation state for actinoids?

    Detailed Solution: Question 3

    The correct answer is option A
    The most common oxidation state of actinide is +3. It is obtained when one 6d and two 7s electrons are lost. The general electronic configuration of actinides may be written as [Rn]5f1−146d0−17s2.

    Test: The Lanthanoids & The Actinoids(20 Jan) - Question 4

    The electronic configuration of Eu 3+ ion is:

    Detailed Solution: Question 4

    The correct answer is option D
    Atomic number of Eu is 63 so electronic configuration of Eu is, Eu=[xe] 4f9 Hence,Eu+3=[xe]4f6

    Test: The Lanthanoids & The Actinoids(20 Jan) - Question 5

    A member of the lanthanoid series which is well known to exhibit +4 oxidation state is:

    Detailed Solution: Question 5

    The correct answer is option C
    Cerium
    Electronic configuration of Ce=[Xe]4f15d16s2
    Formation of Ce+4 is favoured by its noble gas configuration due to which it shows +4 oxidation state.
    It can be easily converted into Ce+3, due to which Ce+4 acts as an oxidising agent.

    Test: The Lanthanoids & The Actinoids(20 Jan) - Question 6

    How many elements belong to lanthanide series?

    Detailed Solution: Question 6

    The lanthanide are f-block elements which contain seven f-orbitals . The maximum electrons can be filled in f-orbitals are 14. Hence, lanthanide have total 14 elements.

    Test: The Lanthanoids & The Actinoids(20 Jan) - Question 7

     In which of the following oxidation states La achieve the noble gas configuration?

    Detailed Solution: Question 7

    In +3 oxidation state Lanthanum(La) achieves the noble gas configuration.

    Test: The Lanthanoids & The Actinoids(20 Jan) - Question 8

     Which of the following statement is true?

    Detailed Solution: Question 8

    The correct answer is option C
    The 5f orbitals (in case of actinoids) have a poorer shielding effect than 4f orbitals (in lanthanoids). Thus, the effective nuclear charge experienced by electron in valence shells in case of actinoids is greater than that in lanthaniods.

    Test: The Lanthanoids & The Actinoids(20 Jan) - Question 9

     The common oxidation state of the elements of lanthanoids series is:

    Detailed Solution: Question 9

    The correct answer is Option A
    Lanthanides show variable oxidation states. The most stable oxidation state of Lanthanides is +3. They also show +2 and +4 oxidation states due to the presence of either half filled or completely filled or empty 4f subshell.

    Test: The Lanthanoids & The Actinoids(20 Jan) - Question 10

    In which of the following oxidation state Cerium achieves the noble gas configuration?

    Detailed Solution: Question 10

    Any atom exhibit oxidation state in which it is found to be stable. It is second element of Lanthanide series having atomic number 58. General electronic configuration is
    [Xe] 4f1 5d1 6s2.
    Lanthanide are very less electronegative. Their electronegative value is nearly equal to s-block elements. So they can lose electrons to form cation. When Cerium loses 4 e-, it will acquire fully field electronic configuration of Xenon (2,8,18,18,8). As fully filed or half filed electronic configuration possesses extra stability.
    Therefore, Cerium exhibits +4 oxidation state.

    365 tests
    Information about Test: The Lanthanoids & The Actinoids(20 Jan) Page
    In this test you can find the Exam questions for Test: The Lanthanoids & The Actinoids(20 Jan) solved & explained in the simplest way possible. Besides giving Questions and answers for Test: The Lanthanoids & The Actinoids(20 Jan), EduRev gives you an ample number of Online tests for practice
    Download as PDF